PL/SQL :: How To Calculate Days Between Two Dates Of One Timestamps Field
Sep 25, 2012
how to caluclate days between two dates of single timestamp filed and with this
query
Select * from m_activity_transaction where actn_opp_id in (
Select actn_opp_id from m_activity_transaction where ACTN_ACTV_ID = 218
Group by actn_opp_id
[code]...
and i nedd to caluclate no.of days between two dates like 27-JAN-12 11.06.20.000000 AM and 08-FEB-12 05.32.54.000000 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
I want Oracle stored function/procedure to calculate number of working days between two dates. We need to exclude Firdays and Saturdays as there are weekend holidays and also exclude official holidasy that lie between two dates.
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
setting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.
CODESELECT To_Date(need_date, 'YYYYMMDD') Need_Dt, To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Biggest_Date, To_Date(need_date, 'YYYYMMDD') - To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Date_Diff
FROM tableT
WHERE need_date <= (Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END)
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
Is there a way to query an oracle database in an automated fashion by a timestamp field based on current timestamp, like: 04/29/08 00:00:00 - 72 hours?
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
I have a table with starting date and ending date.
I want to fetch monthwise days for given two dates
IE starting 25/12/2009 ending 25/03/2010
Result should like below.
Dec-09 7 Jan-10 31 Feb-10 28 Mar-10 25
I have tried this but it is not giving me the result which want..
select to_char(thedate,'mon-yy') mnth,count(to_char(thedate,'mon-yy')) days from (SELECT TRUNC(to_date('25/12/2009','dd/mm/yyyy'),'Y')+ROWNUM-1 THEDATE FROM ( SELECT 1 just_a_column FROM dual CONNECT BY LEVEL <= 366
In my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
here I need to exclude the Dates which comes on 'saturday' and 'sunday' and also the common holiday..Here it is '01-May-2012' and I need the output like the following,
create or replace function getDate(p_joing_date Date,p_sysdate) Return Date; IS v_compltd_mnths; BEGIN SELECT into v_compltd_mnths MONTHS_BETWEEN(TO_DATE('sysdate','MM-DD-YYYY'), TO_DATE('joing_date','MM-DD-YYYY') ) "Months"FROM DUAL; return v_compltd_mnths; END;
I need a similar function to determinate difference between two dates, but i need other business hours; Monday - Friday: 9:00 - 21:00 (this is OK)Saturday: 09:00 - 14:00 (and this is my problem, how to add this condition in this function)
I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.
The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:
select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL)) from dwt_dvt_work_time where dwt_create_date > sysdate - 30 and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id
Here's the function: CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE) RETURN NUMBER IS total_days NUMBER(11,2); holiday_days NUMBER(11,2); [code]....
The data in one of the temporary table has been compiled as below. Number of Days elapsed between two transaction dates is required to be computed and multiplied with the balance. There can be multiple number of same transaction dates. When previous date and the current transaction dates are same the resulting number of day difference should be 0. But when they are different the difference between them is to be computed. On the last day of the Financial Year i.e. '31/03' of any year the difference day should be shown as 1 so as to make 365 or 366 days in a year. Simply deducting d1 from d2 on 31st will not be suffice as the difference is one day less.
SQL> SELECT distinct a.legacy_product_code FROM im_polprdmap_pukka a where a.new_product_code like '%GIFT%'; LEGACY_PRODUCT_CODE ------------------- GIFT25 GFTPF21NP GIFT21/H GIFT21//
[code]...
I need to calculate a field taking the numeric part of the above filed.How can i write this?
I know I can add a check constraint for m,t,w,r,f,s,u How can I add a constraint that will allow any combination of the above. For example it would allow m or mf, or mwf Someone said it could be done with trim but I can not figure it out.
If i want to know the status of the ship on the date '22/01/2010' It has to show as 'anchorage', becoz on '25/01/2010' only it came to berthing from anchorage. How to write a query to achieve this.
I know how to select the last N sets of rows, using DENSE_RANK - where multiple rows have the same timestamp but I want to only select those rows which do NOT have the top 2 unique timestamps.
i.e.:
SELECT * FROM ( SELECT DENSE_RANK() OVER (ORDER BY myTimestamp DESC) DENSE_RANK, HISTORYID, USER_ID, myTimestamp, STATUS, FROM TXN_HIST) WHERE DENSE_RANK > 2 order by myTimestamp DESC, HISTORYID, USER_ID;
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
Split a date into new dates according to black out dates!
Here is my tables:
CREATE TABLE travel ( start_date, end_date ) AS SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;
[code]....
I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.
Note: Travel Date can be between 0000-01-01 - 9999 12 31
Sample:
Travel Date:
Travel | START DATE | END DATE T | 2011 01 04 | 2011 12 11
Black Out Dates:
BO | START DATE | END DATE A | 2010 11 01 | 2011 02 11 B | 2011 01 20 | 2011 02 15 C | 2011 03 13 | 2011 04 10 D | 2011 03 20 | 2011 06 29
Excepted Result:
New Travel | START DATE | END DATE X1 | 2011 02 16 | 2011 03 12 X2 | 2011 06 30 | 2011 12 11
Visually:
Travel Date : -----[--------------------------]--
A : --[------]------------------------- B : ------[---]------------------------ C : --------------[---]---------------- D : ----------------[------]-----------
Travel Date : -[--------------------------------]--
BO Date A : ----[------]------------------------- BO Date B : -------------------------[---]------- BO Date C : ----------------[---]---------------- BO Date D : ------------------[------]-----------
Result X1 : -[-]------------------------------- Result X2 : -----------[--]-------------------- Result X3 : -----------------------------[--]--
