Finding Individual Dates Having Dates Plus 2 Days

Jan 26, 2011

I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.

Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.

If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.

seq date
------------------------------
101.01.10

205.01.10
306.01.10

410.01.10
512.01.10

613.01.10
714.01.10
815.01.10

916.01.10
1018.01.10

1119.01.10
1220.01.10
1321.01.10

1423.01.10

1526.01.10
1627.01.10

1729.01.10
1831.01.10

The result should be (Don't use Pl/Sql)

seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10

After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).

I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.

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SQL & PL/SQL :: Finding Individual Dates Having Date Plus 2 Days

Jan 26, 2011

I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.

Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.

If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.

seq date
------------------------------
101.01.10

205.01.10
306.01.10

410.01.10
512.01.10

613.01.10
714.01.10
815.01.10

916.01.10
1018.01.10

1119.01.10

[Code]...

The result should be (Don't use Pl/Sql)

seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10

After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).

I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.

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SQL & PL/SQL :: Days Between Dates

Mar 14, 2012

I have not defined the table ( I only have privileges to query data).

I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).

Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).

I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)

clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.

The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.

SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days

FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a

[Code]....

I am getting a mess of a result of the kind:

cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8

I need my result to look like:

cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.

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Jan 14, 2008

What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?

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Apr 28, 2010

I have a table with starting date and ending date.

I want to fetch monthwise days for given two dates

IE starting 25/12/2009 ending 25/03/2010

Result should like below.

Dec-09 7
Jan-10 31
Feb-10 28
Mar-10 25

I have tried this but it is not giving me the result which want..

select to_char(thedate,'mon-yy') mnth,count(to_char(thedate,'mon-yy')) days from
(SELECT TRUNC(to_date('25/12/2009','dd/mm/yyyy'),'Y')+ROWNUM-1 THEDATE
FROM ( SELECT 1 just_a_column
FROM dual
CONNECT BY LEVEL <= 366

[code].....

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Nov 13, 2011

I want function return me how many days Thursday and Friday between two dates.

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Apr 18, 2013

i want to create function to show number of days between to days such as number of Friday days between to dates

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Is there an Oracle date function that ignores public bank holidays and calculates working days only?

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PL/SQL :: Finding Difference Between Two Dates In Hh:mm:ss Format

Sep 20, 2012

I am running some SQL to try to find how long, in hours:mins:seconds a concurrent request in Oracle EBS takes to run.

I have a basic start here:

SELECT fcr.actual_start_date start_
, fcr.actual_completion_date end_
, fcr.actual_completion_date - fcr.actual_start_date diff_1
-- , TO_CHAR(fcr.actual_completion_date, 'HH24:MI:SS') - TO_CHAR(fcr.actual_start_date, 'HH24:MI:SS') diff_
FROM applsys.fnd_concurrent_requests fcr
[code].......    

I'd really like to get the difference expressed in hours, minutes and seconds. I tried:

, TO_CHAR(fcr.actual_completion_date, 'HH24:MI:SS') - TO_CHAR(fcr.actual_start_date, 'HH24:MI:SS') diff_But that doesn't work - I get an ORA-01722: invalid number error.

I also tried:

, TO_CHAR(fcr.actual_completion_date - fcr.actual_start_date, 'DD-MON-YYYY HH24:MI:SS') diff_But got an ORA-01481: invalid number format model error

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Sep 11, 2010

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what if i select y? it will override three files

what if i select n? default option

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Sep 25, 2012

how to caluclate days between two dates of single timestamp filed and with this

query
Select * from m_activity_transaction where actn_opp_id in (
Select actn_opp_id from m_activity_transaction where ACTN_ACTV_ID = 218
Group by actn_opp_id

[code]...

and i nedd to caluclate no.of days between two dates like 27-JAN-12 11.06.20.000000 AM and 08-FEB-12 05.32.54.000000 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.

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Mar 17, 2011

I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.

The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:

select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL))
from dwt_dvt_work_time where dwt_create_date > sysdate - 30
and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id

Here's the function:
CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE)
RETURN NUMBER
IS total_days NUMBER(11,2);
holiday_days NUMBER(11,2);
[code]....

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May 22, 2010

The data in one of the temporary table has been compiled as below. Number of Days elapsed between two transaction dates is required to be computed and multiplied with the balance. There can be multiple number of same transaction dates. When previous date and the current transaction dates are same the resulting number of day difference should be 0. But when they are different the difference between them is to be computed. On the last day of the Financial Year i.e. '31/03' of any year the difference day should be shown as 1 so as to make 365 or 366 days in a year. Simply deducting d1 from d2 on 31st will not be suffice as the difference is one day less.

----------------------------------------------------------------------------------------- -------
Transaction Narration DebitCreditBalanceNo of DaysProduct
DateDifference
----------------------------------------------------------------------------------------- --------
01/04/2009Opening Balance 45020450277346654
17/06/2009ByAmt5044521253424
29/06/2009By Amt1004352156678912
02/12/2009By Amt424310119476000
[code]....

improve the above code and get the desired output result.

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Feb 17, 2010

I want Oracle stored function/procedure to calculate number of working days between two dates. We need to exclude Firdays and Saturdays as there are weekend holidays and also exclude official holidasy that lie between two dates.

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Mar 10, 2011

Split a date into new dates according to black out dates!

Here is my tables:

CREATE TABLE travel
(
start_date,
end_date
)
AS
SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;

[code]....

I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.

Note: Travel Date can be between 0000-01-01 - 9999 12 31

Sample:

Travel Date:

Travel | START DATE | END DATE
T | 2011 01 04 | 2011 12 11

Black Out Dates:

BO | START DATE | END DATE
A | 2010 11 01 | 2011 02 11
B | 2011 01 20 | 2011 02 15
C | 2011 03 13 | 2011 04 10
D | 2011 03 20 | 2011 06 29

Excepted Result:

New Travel | START DATE | END DATE
X1 | 2011 02 16 | 2011 03 12
X2 | 2011 06 30 | 2011 12 11

Visually:

Travel Date : -----[--------------------------]--

A : --[------]-------------------------
B : ------[---]------------------------
C : --------------[---]----------------
D : ----------------[------]-----------

Result :

X1 : -----------[--]--------------------
X2 : -----------------------[--------]--

Sample 2:

Travel Date : -[--------------------------------]--

BO Date A : ----[------]-------------------------
BO Date B : -------------------------[---]-------
BO Date C : ----------------[---]----------------
BO Date D : ------------------[------]-----------

Result X1 : -[-]-------------------------------
Result X2 : -----------[--]--------------------
Result X3 : -----------------------------[--]--

How can I do it using PL SQL ?

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Oct 22, 2003

How can I select all of the dates between two dates? For example, given the start date 12/2/2003 and the end date 12/5/2003 I want to return:

12/2/2003
12/3/2003
12/4/2003
12/5/2003

Is there a built in function for this? Is there a way for a function to return multiple rows? It has to be a function because I need to use it within other SQL statements.

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Aug 5, 2010

I am newbie to oracle and using oracle 10g as database. I want to get dates between two dates .... let me give an example
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something like "select date..or whatever from dual where date between 1-Aug-2010 and 31-Aug-2010 " like this type or other.

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Nov 9, 2010

I want the dates between 2 dates. Suppose i give the dates 01-jan-2010 and 31-jan-2010 and i need the following output.

01-jan-2010
02-jan-2010
03-jan-2010
.
.
.
.
31-jan-2010

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Sep 17, 2008

I got all the month_numbers when i did this

[/b]select distinct t.f_month_number
from time_dim t
where
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)[b]

but when i add

select distinct t.f_month_number,p.start_date,round(replace(p.total_sal,',','')/12,2) as Monthly_sal
from time_dim t, employee p
where
t.f_date = p.start_date and
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)

i got only one month value.

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Jan 23, 2013

I am looking to subtract two columns and get the difference.

select to_char('06-NOV-2012 20:00','DD-MON-YYYY HH24:MI') - to_char(systimestamp,'DD-MON-YY HH24:MI') from dual;
select to_char('06-NOV-2012 20:00','DD-MON-YYYY HH24:MI') - to_char(systimestamp,'DD-MON-YY HH24:MI') from dual
*
ERROR at line 1:

ORA-01722: invalid number

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Dec 7, 2012

I am looking for a query to find out minimun and maximum rates of an item with corresponding dates. findout a query to get the required result.

Here is sample data

CREATE TABLE scott.item_rate
(
code VARCHAR2(3),
rate NUMBER(10,4),
vdate DATE
);

[Code]..

COD RATE VDATE
--- ---------- ---------
001 108.97 25-MAY-12
001 108.97 07-APR-12
001 105 05-DEC-12
001 105 11-OCT-12
001 91 02-JUL-10
001 1 05-JUL-10
001 1 31-AUG-10

7 rows selected.

The required result is

CODE MIN_RATE MIN_DATE MAX_RATE MAX_DATE

001 1 05-JUL-10 108.97 25-MAY-12

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Jul 13, 2010

I need to aggregate the data based the two dates criteria.

I have two tables

1. Table1
Number Date1 Date2
1 10-Jun-2010 30-Jun-2010
2 10-Feb-2010 30-Feb-2010
----------------------------------
2. Table2
Number Date Revenue
1 11-Jun-2010 100
1 09-Jun-2010 100
1 12-Jun-2010 100
2 11-Feb-2010 100
2 12-Feb-2010 100
2 13-Feb-2010 100
......................
......................
So on

Output:

Number Revenue Date2
1 200 30-Jun-2010
2 300 30-Feb-2010

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Dec 21, 2011

below is the table and data

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insert into bday values('jeffery','0110');
insert into bday values('boss','1231');
insert into bday values('raj','1225');

[Code]...

the BDATE column is in the form "mmdd".

I just want to select the name between 2 dates ( not including years). lets say between sysdate and sysdate+20, i.e

select to_char(sysdate,'dd-mon'),to_char(sysdate+25,'dd-mon') from dual;

TO_CHAR(SYSDATE,'DD-MON') TO_CHAR(SYSDATE+25,'DD-MON')
21-dec 15-jan

but when I run the below query, it is not showing me 'january' data

select name from bday
where to_date(bdate,'mm/dd') between sysdate and sysdate+25;

o/p comes as:
NAME BDATE
boss 1231
raj 1225

but the actual o/p should be:

NAME BDATE
boss 1231
raj 1225
jeffery 0110

it seems to me that because of year change the rows are not displayed.how to handle this in single SQL

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Sep 24, 2012

for the below table

create table RM_TR_INVESTMENT
(
  AS_ON_DT                DATE not null,
  EXP_ID                  NUMBER(10) not null,
  BO_REF_ID               VARCHAR2(30),
  FO_REF_ID               VARCHAR2(30),
  BK_PRODUCT_ID           VARCHAR2(20),
  BK_INV_TYPE_ID          VARCHAR2(20),
 [code]....

I want to find the sum of NP_AMT_CCY where difference between Start_Dt and Maturity_Dt >= 14 days and <=28 days.How can I build the query for the above statement ?

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Jan 28, 2013

I'm trying to use a PIVOT on the following data set:

ID      STATUS_DESC         PAY_STATUS         PAID_DATE                          TRANSACTION_TYPE                               TRANSACTION_DESC                   DEBIT                                  TOTAL
--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
9876        In Progress       2nd Payment Made       11-DEC-12 19.38.57       Card Payment                                 Payment 2                             349                             349
9876   In Progress   2nd Payment Made       06-DEC-12 14.33.57       Card Payment                                 Payment 1                             100                             100

However I'm still getting two rows as per the below. Ideally all data should be on a single row.

ID      STATUS_DESC   PAY_STATUS        PAYMENT_1_DATE            PAYMENT_1_AMT            PAYMENT_2_DATE             PAYMENT_2_AMT            TOTAL
--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
9876        In Progress       2nd Payment Made       06-DEC-12 14.33.57       100                                                                                                                           100
9876        In Progress       2nd Payment Made                                                                                      11-DEC-12 19.38.57            349                                   349

I have constructed my pivot using the following on the outer select:

PIVOT (MAX (insert_timestamp) AS paid_date
,SUM (debit) AS amt

FOR transaction_desc IN ('Payment 1' AS payment_1,
'Payment 2' AS payment_2)) ;

I've used MAX to pivot the date and also tried using NVL on the insert_timestamp but still no luck.

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SELECT ...

NVL(COUNT(DISTINCT CASE WHEN TX.DATE_OF_FIRST_VISIT BETWEEN TO_DATE(TX.DATE_OF_FIRST_VISIT,'MM-YYYY') AND ADD_MONTHS(TO_DATE(TX.DATE_OF_FIRST_VISIT,'MM-YYYY'),12) THEN (TX.CLINIC_ID||TX.PATIENT_UNIQUE_ID)END),0) AS "YEAR_1"

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Mar 10, 2012

My homework requires me to create a booking table for a hotel and I have created the table but I'm having trouble inserting the dates.

This is my table:

DROP TABLE BookingDM CASCADE CONSTRAINTS PURGE;
CREATE TABLE BookingDM (
hNo NUMBER(3),
gNo NUMBER(5),
dFrom DATE NOT NULL,
[code]......

This is the first set I'm attempting to insert
hNo = 148
gNo = 11169
dFrom = 09/03/2009
dTo = 09/10/2009
rNo = 202

This is my attempt to insert the set:

SQL> INSERT INTO BookingDM VALUES('148', '11169', '09/03/2009', '09/10/2009', '202');
INSERT INTO BookingDM VALUES('148', '11169', '09/03/2009', '09/10/2009', '202')
*
ERROR at line 1:
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I need my dates to be in the format "MM/DD/YYYY".

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Mar 9, 2013

ii have written a query like thi:

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the above query returns me a resultset which gives me number of bags sold in every month, but it does not sort the month in their chronological order. i want to sort my resultset in ascending order of month s.,means jan-feb-march-apr-may ams so on...QUOTE

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I need to store a date that will always be x years before the current date. Is doing something like

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Sep 21, 2004

I am wondering how can I select data between two dates (ie from 08/12/2004 to today?)

Name DateS
Bob 08/11/2004
Tom 08/12/2004
Bill 09/21/2004 <-- today

return

Tom 08/12/2004
Bill 09/21/2004

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