Number Of Days Between Dates?
Jan 14, 2008What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
View 1 RepliesWhat I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
View 1 Repliesi want to create function to show number of days between to days such as number of Friday days between to dates
View 13 Replies View RelatedThe data in one of the temporary table has been compiled as below. Number of Days elapsed between two transaction dates is required to be computed and multiplied with the balance. There can be multiple number of same transaction dates. When previous date and the current transaction dates are same the resulting number of day difference should be 0. But when they are different the difference between them is to be computed. On the last day of the Financial Year i.e. '31/03' of any year the difference day should be shown as 1 so as to make 365 or 366 days in a year. Simply deducting d1 from d2 on 31st will not be suffice as the difference is one day less.
----------------------------------------------------------------------------------------- -------
Transaction Narration DebitCreditBalanceNo of DaysProduct
DateDifference
----------------------------------------------------------------------------------------- --------
01/04/2009Opening Balance 45020450277346654
17/06/2009ByAmt5044521253424
29/06/2009By Amt1004352156678912
02/12/2009By Amt424310119476000
[code]....
improve the above code and get the desired output result.
I want Oracle stored function/procedure to calculate number of working days between two dates. We need to exclude Firdays and Saturdays as there are weekend holidays and also exclude official holidasy that lie between two dates.
View 7 Replies View RelatedI want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
1220.01.10
1321.01.10
1423.01.10
1526.01.10
1627.01.10
1729.01.10
1831.01.10
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
I have a table with starting date and ending date.
I want to fetch monthwise days for given two dates
IE starting 25/12/2009 ending 25/03/2010
Result should like below.
Dec-09 7
Jan-10 31
Feb-10 28
Mar-10 25
I have tried this but it is not giving me the result which want..
select to_char(thedate,'mon-yy') mnth,count(to_char(thedate,'mon-yy')) days from
(SELECT TRUNC(to_date('25/12/2009','dd/mm/yyyy'),'Y')+ROWNUM-1 THEDATE
FROM ( SELECT 1 just_a_column
FROM dual
CONNECT BY LEVEL <= 366
[code].....
I want function return me how many days Thursday and Friday between two dates.
View 1 Replies View RelatedIs there an Oracle date function that ignores public bank holidays and calculates working days only?
View 4 Replies View RelatedIn my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
what if i select y? it will override three files
what if i select n? default option
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
[Code]...
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
how to caluclate days between two dates of single timestamp filed and with this
query
Select * from m_activity_transaction where actn_opp_id in (
Select actn_opp_id from m_activity_transaction where ACTN_ACTV_ID = 218
Group by actn_opp_id
[code]...
and i nedd to caluclate no.of days between two dates like 27-JAN-12 11.06.20.000000 AM and 08-FEB-12 05.32.54.000000 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.
The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:
select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL))
from dwt_dvt_work_time where dwt_create_date > sysdate - 30
and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id
Here's the function:
CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE)
RETURN NUMBER
IS total_days NUMBER(11,2);
holiday_days NUMBER(11,2);
[code]....
Is there any Oracle query I can run to determine the "number of days since the last backup"? SQL Server provides this data but I cant seem to find the equivalent for Oracle. Looks like there may be some information like this via RMAN tables and if so I want to create the simplest query possible to obtain that information.
View 3 Replies View Relatedsetting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.
CODESELECT
To_Date(need_date, 'YYYYMMDD') Need_Dt,
To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Biggest_Date,
To_Date(need_date, 'YYYYMMDD') - To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Date_Diff
FROM tableT
WHERE
need_date <= (Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END)
ORDER BY Date_Diff ASC
We have a requirement where we need to pay allowance for the employees based on their number of working days. Say for example if an employee worked from 03/Mar/2012 to 05/Apr/2012.
We have a fixed value for per month 300 Dirhams. But the Number of Days on March s 31 and Number of days in April is 30. So per day allowance for March day would be 300/31 and April would be 300/30.
We are looking for logic opr query which calculates first eh number of days in each month ( across months) and then calculate as below
Number of Working days in March is 31 - 3 + 1 = 29
Allowance A1 = (300 * 29 )/31
Number of Working days in April is 5 ( this also needs to find logical I am guess )
Allowance A2 = (300 * 5 )/30
Then A1 + A2.
The A(n) would be the total allowance where provided the number of month across.
There is a attendance table having structure(empid number,signtime datetime)It has data of attendance of employees:
What is the right sql to show employees detail attendance according to the no of days attendance . i.e.(According to the maximum no of attendance first and so on)
suppose: 3 employees abc,bbc,cca abc has 20 days of attendance ,bbc has 21 days,cca has 19 days..The report like this:
bbc 1/5/12 10:30
abc .....
then
cca
according to the no of attendannce
I have been trying to construct a query in Oracle that allows me to do the following:
For example if I have the data below:
EmpNo DOB SickDays
Alex 445 15/06/1985 7
Tom 778 22/08/1981 4
James 992 07/10/1978 5
I need to write and a query to lists the employee number and the amount of days sick that they have had and also add a column that compares the number of sick days to the average number of suck days by ALL employees.
I can calculate the average sick days etc, but It wont see to allow me to find the difference between that and the amount of sick days that each person has had. I have tried this many ways and have not been able to come up with a solution.
SQL> SELECT MAX (upd_time), MIN (upd_time), COUNT (serial)
FROM (SELECT * FROM trans
UNION ALL
SELECT * FROM trans_archive);
MAX(UPD_T MIN(UPD_T COUNT(SERIAL)
--------- --------- -------------
23-OCT-13 01-JAN-11 5289261
I need to calculate seconds between MAX (upd_time) and MIN (upd_time) and then calculate trans/sec. Number of trans COUNT (serial).
SQL> desc trans;
Name Null? Type
----------------------------------------- -------- ----------------------------
SERIAL NOT NULL NUMBER(11)
UPD_TIME NOT NULL DATE
MESSAGE NOT NULL VARCHAR2(255 CHAR)
ENTITY_TABLE NOT NULL VARCHAR2(32 CHAR)
ACTION NOT NULL VARCHAR2(12 CHAR)
[code]....
trans_archive the same DDL.
my first try to get intervall between max and min date in secons:
SQL> SELECT EXTRACT (DAY FROM (MAX (UPD_TIME) - MIN (UPD_TIME))) * 24 * 60 * 60
+ EXTRACT (HOUR FROM (MAX (UPD_TIME) - MIN (UPD_TIME))) * 60 * 60
+ EXTRACT (MINUTE FROM (MAX (UPD_TIME) - MIN (UPD_TIME))) * 60
+ EXTRACT (SECOND FROM (MAX (UPD_TIME) - MIN (UPD_TIME)))
DELTA
FROM (SELECT * FROM TRANS
UNION ALL
SELECT * FROM TRANS_ARCHIVE);
SELECT EXTRACT (DAY FROM (MAX (UPD_TIME) - MIN (UPD_TIME))) * 24 * 60 * 60
*
ERROR at line 1:
ORA-30076: invalid extract field for extract source
SELECT emp.emp_id, emp.ename, TRUNC (attendancedatetime),
TRUNC ( ( 86400
* (MAX (attendancedatetime) - MIN (attendancedatetime))
)
/ 60
)
- 60
[Code]...
Following is the out put:
EMP_IDENAME Date Min Hrs
10013Javed Iqbal09/20/2011 00:00:0036.007.00
10013Javed Iqbal09/21/2011 00:00:0027.007.00
10013Javed Iqbal09/22/2011 00:00:0049.007.00
10013Javed Iqbal09/23/2011 00:00:000.000.00
10013Javed Iqbal09/24/2011 00:00:000.000.00
i need the TOtal sum of Minutes and Hrs e.g 7+7+7=21 and also minutes but if minutes total increase from 60 minutes then it should add to hrs .how to get sum.
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
View 7 Replies View Relatedwant to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
Split a date into new dates according to black out dates!
Here is my tables:
CREATE TABLE travel
(
start_date,
end_date
)
AS
SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;
[code]....
I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.
Note: Travel Date can be between 0000-01-01 - 9999 12 31
Sample:
Travel Date:
Travel | START DATE | END DATE
T | 2011 01 04 | 2011 12 11
Black Out Dates:
BO | START DATE | END DATE
A | 2010 11 01 | 2011 02 11
B | 2011 01 20 | 2011 02 15
C | 2011 03 13 | 2011 04 10
D | 2011 03 20 | 2011 06 29
Excepted Result:
New Travel | START DATE | END DATE
X1 | 2011 02 16 | 2011 03 12
X2 | 2011 06 30 | 2011 12 11
Visually:
Travel Date : -----[--------------------------]--
A : --[------]-------------------------
B : ------[---]------------------------
C : --------------[---]----------------
D : ----------------[------]-----------
Result :
X1 : -----------[--]--------------------
X2 : -----------------------[--------]--
Sample 2:
Travel Date : -[--------------------------------]--
BO Date A : ----[------]-------------------------
BO Date B : -------------------------[---]-------
BO Date C : ----------------[---]----------------
BO Date D : ------------------[------]-----------
Result X1 : -[-]-------------------------------
Result X2 : -----------[--]--------------------
Result X3 : -----------------------------[--]--
How can I do it using PL SQL ?
How can I select all of the dates between two dates? For example, given the start date 12/2/2003 and the end date 12/5/2003 I want to return:
12/2/2003
12/3/2003
12/4/2003
12/5/2003
Is there a built in function for this? Is there a way for a function to return multiple rows? It has to be a function because I need to use it within other SQL statements.
I need to know if a customer appears at least 4 consecutive days. Here's an example of data
CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
123 , 2010/10/10
456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
My Table structure is
SL# Start_ts
1 7/31/2012 3:53:42.864070 AM
2 7/26/2012 2:13:58.280928 PM
3 7/25/2012 2:13:41.692569 PM
4 7/21/2012 2:13:26.821070 PM
5 7/18/2012 2:13:07.827278 PM
6 7/13/2012 2:05:35.023520 PM
Question
How to select last 10 days rows only (from sysdate)
Error
1) SQL> select * from Test where to_date(start_ts, 'DD-MON-YYYY HH24:MI:SS') > to_date(sysdate, 'DD-MON-YYYY HH24:MI:SS')-10 ; (or)
2) SQL> select * from Test where to_date(start_ts, 'MM/DD/YYYY HH24:MI:SS') > to_date(sysdate, 'MM/DD/YYYY HH24:MI:SS')-10 ;
ORA-01858: a non-numeric character was found where a numeric was expected
[Code]...
Our "client" is delivering data that contains an "age" field. However, they've put the AGE in DAYS instead of years, while our system can only work with years. So I needed to convert the age to years.
We are getting 2 parameters: LOWAGE and HIGHAGE (both in days). However, for the same "test" (laboratory test), we are also getting some other records
eg:
TEST 1 lowage = 0 upperage = 5 OTHER values = xxx
TEST 1 lowage = 6 upperage = 100 OTHER values = yyy
So if the person would be 5 years or less, the values xxx would apply. If they are 6 years and older, the yyy values apply. Now, the problem is that we are not getting this data in years, but in days. And whichever function I try, the upperage from the first test also seems to be equal to the lowerage from the second test. And this gives an error, because both would apply to this person....
I've tried stuff like:
age/365
age/365.25 (leap years)
trunc(months_between(sysdate+ranges.lowerage,sysdate)/12)
i have an employee table where there is a column called join date. Now i have to select the employee according to the days. Means how many employee joined on Monday/Tuesday etc.
View 17 Replies View RelatedI have the following in my select statement and I am getting the days like 1130, 50, 60 etc
round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS
Now I want this to convert these days into months like
1.10 this denotes (one month 10 days)
1.25 this denotes (one month 25 days)
2.05 this denotes (two months 5 days)
I know I am using old Oracle but what to do my company is not spending to upgrade.
i want create a report like this
location sysdate refdate No_of_days SL1(0-90) SL2(91-180) SL3(>180)
So when no. of days between (0-90) data put in SL1
And when no. of days between (91-180) data put in sl2
I want to achieve this only in single query.