Server Administration :: Overlapping Days Between 3 Date Ranges To Determine Active / Inactive Days
Sep 2, 2011
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
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Apr 5, 2011
want to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
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Jul 19, 2010
I am working in development environment which has only 150 gb db size but suddenly it is raised to 250gb within 10 days i want to see which user did what in my database.How we can see what task made what in past 10 days.
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Oct 27, 2010
I killed some 70 sessions which where inactive couple of days ago using alter system kill session(sid,serial#) immediate;
But even after killing them it still exists in the v$session view when I query select sid,serial# from v$session where username is not null; It has the same sid and serial#....I tried killing them every now and then but it still shows those exists
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Oct 16, 2010
My problem is only on Some Saturday's my Oracle server's Load average goes high (more than 300 ).
-- oracle version 11.2.0.1.0
-- runs on Sun solaris 10
-- Sun fire V 440
-- Sun storEdge 3315 connected to the server.
Same setup is working find with higher volumes without any problem but only on saturday's, that too not on all saturdays, some specific saturdays the load average goes high.
At the time nothing will be processed from the application side and the cpu utilisation goes high upto 95 %.
I am sending necessary information as follows.
vmstat 6 10
kthr memory page disk faults cpu
r b w swap free re mf pi po fr de sr s0 s1 s3 s4 in sy cs us sy id
3 0 0 28660024 6513408 285 212 2044 2 2 0 0 0 17 0 42 830 3469 1380 22 5 74
125 0 0 29027480 6156256 2 6 34 0 0 0 0 0 5 0 10 791 53770 30278 83 17 0
125 0 0 29027680 6157496 29 140 21 1 1 0 0 0 5 0 9 786 52756 30309 83 17 0
116 0 0 29031600 6159896 24 125 0 0 0 0 0 7 3 0 5 819 54081 31069 83 17 0
[code]....
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Jun 3, 2010
I am studying Oracle® Database VLDB and Partitioning Guide 11g Release 2 (11.2),
ORA-14767: Cannot specify this interval with existing high boundsby giving an example other than given in the above mentioned document.
the example given in the document is as follows:
To increase the interval for date ranges, then you need to ensure that you are at a relevant boundary for the new interval. For example, if the highest interval partition boundary in your daily interval partitioned table transactions is January 30, 2007 and you want to change to a monthly partition interval, then the following statement results in an error:
CREATE TABLE transactions
( id NUMBER
, transaction_date DATE
, value NUMBER)
PARTITION BY RANGE (transaction_date)
[code]/...
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Jul 7, 2012
Tables
--------
ROWID START_DATEEND_DATE
101/26/2012 00:00:0001/31/2012 00:00:00
201/26/2012 00:00:0002/02/2012 00:00:00
302/03/2012 00:00:0003/31/2012 00:00:00
How to find out the days difference in sql query, start date of next records and end date of previous records as highlighted on blue color
query out put should give as below
start_date + next record ,end_date - Previous records should give the difference of
6
1
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Jan 24, 2007
I have a Employee data as below with EID and DOB
EID DOB
----------------------
1 03/01/1950
2 14/01/1950
3 27/01/1950
4 02/02/1950
5 04/03/1950
6 12/03/1950
7 28/03/1950
8 28/02/1951
9 08/03/1951
10 28/03/1951
I need a query to display the birth date of all emp in such a way that if i run a query today the dob which lies between today & today+15 days data must be displayed.
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Sep 11, 2010
In my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
what if i select y? it will override three files
what if i select n? default option
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Jan 26, 2011
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
[Code]...
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
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Mar 13, 2013
I am trying to get the last 7 days of record from today date, this query runs every night and I always want the last 7 days. Example - today is 3/13/2013 so I want record from 3/7/2013 to 3/13/2013 and tomorrow it would be 3/8/2013 to 3/14/2013
Here is my query, dont mind the ****,$$$ or ####
SELECT INFORMENT.PRODUCT_OFFER_PURCHASE.*******_#######, INFORMENT.INVOLVED_PARTY.INVOLVED_PARTY_ID, To_Char(INFORMENT.PRODUCT_OFFER_PURCHASE.DATE_ADDED, 'YYYYMMDD'), INFORMENT.DEPOSIT_$$$$$$$.BAL_LEDGER_CURRENT, INFORMENT.PRODUCT_OFFER_PURCHASE.INTEREST_RATE, To_Char(INFORMENT.PRODUCT_OFFER_PURCHASE.DATE_OPEN, 'YYYYMMDD'), To_Char(INFORMENT.PRODUCT_OFFER_PURCHASE.DATE_CLOSE, 'YYYYMMDD'), INFORMENT.PRODUCT_OFFER_PURCHASE.*******_STATUS_CODE, [code]..........
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Jul 5, 2011
I need to identify a due date for a transaction (date) that should be completed within 15 working days from the date of the transaction date. For example, a request is submitted on Wednesday, December 29th 2010. This request should be then 'answered' on Thursday, January 20th 2011 at the latest.
I have a table that identify the status of every calendar day between 1960 to 2060; fields are: calendar day, calendar year, ..., day of week, week day flag, holiday flag.
In my example above, January 1st and 2nd are weekend days and Monday, January 3rd is an holiday.
How do I go getting all (calendar day + 15 working days) for all days of the year?
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Apr 19, 2010
how can we change the color of active & inactive Tab canvas dynamically. I am using Dev Suite 10gR2
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Nov 22, 2012
when I was analyzing high CPU utilization issue, I saw that the most of the top PID's were INACTIVE in database. But it was utilizing more than 4% CPU. how it is utilizing CPU without doing any work in database?
PID USERNAME SIZE RSS STATE PRI NICE TIME CPU PROCESS/NLWP
24013 oracle 2167M 1581M sleep 53 0 0:01:53 20% oracle/1
13260 oracle 2167M 1580M sleep 30 0 0:01:16 14% oracle/1
24399 oracle 2167M 1582M sleep 59 0 0:03:01 4.2% oracle/1
11509 oracle 2178M 1593M sleep 59 0 0:02:10 2.8% oracle/11
[code].....
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Jun 1, 2010
I'm trying to work out how to take a table like this:
IDDate
12502-Feb-07
12516-Mar-07
12523-May-07
12524-May-07
12525-May-07
33302-Jan-09
33303-Jan-09
33304-Jan-09
33317-Mar-09
And display the data like this:
IDPeriodPeriod StartPeriod End
125102-Feb-0702-Feb-07
125216-Mar-0716-Mar-07
125323-May-0725-May-07
333102-Jan-0904-Jan-09
333217-Mar-0917-Mar-09
As you can see, it's split the entries into date ranges. If there is a 'lone' date, the 'period start' and the 'period end' are the same date.
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Mar 4, 2010
I am using 10.2.0.4 oracle database on Solaris 10. We are running some Peoplesoft upgrade on one of the database from last 6-7 hours. The status of the session is INACTIVE from couple of hours. And the sql_id is null for these sessions.
select sid,serial#,STATUS,to_char(logon_time,'DD-MON_YY HH24:MI:SS') from v$session where username like '%&usern%' ORDER BY 4 DESC;
533 2234 INACTIVE 04-MAR_10 01:59:02
525 5919 ACTIVE 04-MAR_10 01:54:50
534 4186 INACTIVE 04-MAR_10 01:05:15
520 2320 INACTIVE 04-MAR_10 00:29:44
[code].....
While when i see the current sql from the v$active_session_history, it keep on changing after every 10-15 minutes. Using below query to find the sql_text for the session from v$active_session_history.
select sql_id, sql_text
from v$sql
where sql_id in (
select sql_id
from v$active_session_history
where session_id=511
[code].....
We have not faced issue like this during Peoplesoft upgrade. what could be the reason that the status is not changing while the base sqls keep on changing after every 10 minutes.
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Oct 18, 2010
I need to know if a customer appears at least 4 consecutive days. Here's an example of data
CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
123 , 2010/10/10
456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
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Mar 14, 2012
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
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Nov 16, 2013
I use Oracle 11.2.0.3.I have APPOINTMENT table:(ID NUMBER PK , FROM_TIME TIMESTAMP , TILL_TIME TIMESTAMP , NOTE VARCHAR2 (200))I want to prevent end users from making an appointment that overlaps with other appointments. I created this trigger:
Create or replace TRIGGER "APPOINTMENT_CK"
BEFORE
INSERT OR UPDATE ON APPOINTMENT FOR EACH ROW
BEGIN
IF
[code]....
But, it looks like I cannot use column name here.
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Jun 28, 2012
CREATE TABLE CONTRACT
(
EQT VARCHAR2(10 BYTE),
SUBTYP VARCHAR2(3 BYTE),
FROM_DT DATE,
TO_DT DATE
);
[Code]....
The data in contract and lease table show like below.
contract
EQT SUBTYPFROM TO
ABCD100000DRY1/1/20121/7/2012
ABCD100000DCH1/7/20121/21/2012
ABCD100000GAZ1/21/2012
lease
EQT CONTRACTFROM TO
ABCD100000LS11/2/20121/10/2012
ABCD100000LS21/10/20121/17/2012
ABCD100000LS31/17/2012
Now required output should be
EQT SUBTYP CONTRACTFROM TO
ABCD100000DRY 1/1/20121/2/2012
ABCD100000DRYLS11/2/20121/7/2012
ABCD100000DCHLS11/7/20121/10/2012
ABCD100000DCHLS21/10/20121/17/2012
ABCD100000DCHLS31/17/20121/21/2012
ABCD100000GAZLS31/21/2012
The period for contracts should be in sequential order and should not overlap and if contract does not exist for that date period, then it should return NULL.
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Jan 14, 2008
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
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Aug 2, 2012
My Table structure is
SL# Start_ts
1 7/31/2012 3:53:42.864070 AM
2 7/26/2012 2:13:58.280928 PM
3 7/25/2012 2:13:41.692569 PM
4 7/21/2012 2:13:26.821070 PM
5 7/18/2012 2:13:07.827278 PM
6 7/13/2012 2:05:35.023520 PM
Question
How to select last 10 days rows only (from sysdate)
Error
1) SQL> select * from Test where to_date(start_ts, 'DD-MON-YYYY HH24:MI:SS') > to_date(sysdate, 'DD-MON-YYYY HH24:MI:SS')-10 ; (or)
2) SQL> select * from Test where to_date(start_ts, 'MM/DD/YYYY HH24:MI:SS') > to_date(sysdate, 'MM/DD/YYYY HH24:MI:SS')-10 ;
ORA-01858: a non-numeric character was found where a numeric was expected
[Code]...
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May 11, 2012
Our "client" is delivering data that contains an "age" field. However, they've put the AGE in DAYS instead of years, while our system can only work with years. So I needed to convert the age to years.
We are getting 2 parameters: LOWAGE and HIGHAGE (both in days). However, for the same "test" (laboratory test), we are also getting some other records
eg:
TEST 1 lowage = 0 upperage = 5 OTHER values = xxx
TEST 1 lowage = 6 upperage = 100 OTHER values = yyy
So if the person would be 5 years or less, the values xxx would apply. If they are 6 years and older, the yyy values apply. Now, the problem is that we are not getting this data in years, but in days. And whichever function I try, the upperage from the first test also seems to be equal to the lowerage from the second test. And this gives an error, because both would apply to this person....
I've tried stuff like:
age/365
age/365.25 (leap years)
trunc(months_between(sysdate+ranges.lowerage,sysdate)/12)
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Jun 8, 2010
i have an employee table where there is a column called join date. Now i have to select the employee according to the days. Means how many employee joined on Monday/Tuesday etc.
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Nov 21, 2011
I have the following in my select statement and I am getting the days like 1130, 50, 60 etc
round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS
Now I want this to convert these days into months like
1.10 this denotes (one month 10 days)
1.25 this denotes (one month 25 days)
2.05 this denotes (two months 5 days)
I know I am using old Oracle but what to do my company is not spending to upgrade.
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Nov 2, 2010
i want create a report like this
location sysdate refdate No_of_days SL1(0-90) SL2(91-180) SL3(>180)
So when no. of days between (0-90) data put in SL1
And when no. of days between (91-180) data put in sl2
I want to achieve this only in single query.
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Oct 9, 2013
I want to find the months and days between 2 dates. For Eg. Date-1 : 25-Aug-2013Date-2 : 23-Oct-2013 If we consider every month as 30 days it should give 25-Aug-2013 to 30-Aug-2013 = 6 days 01-Sep-2013 to 30-Sep-2013 = 1 Month 23-Oct-2013 to 30-Oct-2013 = 8 days Total = 1 month and 14 days
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Mar 30, 2013
I have two field date from and date to... i want to enter an employee in date range that range should not be enter again.
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Jan 8, 2013
I would the query to do the following:
1. Make the jobname distinct, because it keeps giving me multiple entries for each jobname
2. Add the the start_time of SOD_start_data9_UAT1 to end_time fodba_MUAT1 to get the combined duration
3. CONCAT jobnames SOD_start_data9_UAT1 and end_time fodba_MUAT1
4. Generate the last seven days batch run times
5. Generate a report into .csv format and email out
6. I have access to sqlplus and plsql developer
select distinct JOBNAME, schedtab
, to_char(to_timestamp(trim(timestmp)
, 'YYYYMMDDHH24MISS') - numtodsinterval(elaptime / 100
, 'SECOND'), 'YYYY-MM-DD HH24:MI:SS') as start_time
[code]...
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Aug 5, 2010
I want to pull out the output only when Day is 1 and 2 and 3. I don't want if either Day is 1 or Day is 2 or Day is 3 is present.
Test Case
--Creat Table
create table dummy_name
(name varchar2(5) not null,
day number(3) not null);
--Insert Values
insert into dummy_name values ('A', 1);
insert into dummy_name values ('B', 2);
insert into dummy_name values ('C', 3);
insert into dummy_name values ('B', 1);
insert into dummy_name values ('B', 2);
insert into dummy_name values ('C', 1);
[code]...
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