I want to find the months and days between 2 dates. For Eg. Date-1 : 25-Aug-2013Date-2 : 23-Oct-2013 If we consider every month as 30 days it should give 25-Aug-2013 to 30-Aug-2013 = 6 days 01-Sep-2013 to 30-Sep-2013 = 1 Month 23-Oct-2013 to 30-Oct-2013 = 8 days Total = 1 month and 14 days
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I have the following in my select statement and I am getting the days like 1130, 50, 60 etc
round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS
Now I want this to convert these days into months like
1.10 this denotes (one month 10 days)
1.25 this denotes (one month 25 days)
2.05 this denotes (two months 5 days)
I know I am using old Oracle but what to do my company is not spending to upgrade.
how to find out queries bases on elapsed time from the window of 3 Months
DBA_HIST_SQLSTAT and DBA_HIST_SQLTEXT
I have a customers table like
ORDER_ID CUSTOMER_ID ORDER_DATE
__________________________________
1 | 100 |25-JAN-13
2 | 100 |25-JAN-13
3 | 100 |24-JAN-13
4 | 101 |23-JAN-13
5 | 101 |22-JAN-13
6 | 102 |21-JAN-13
7 | 102 |21-JAN-13
I would like to find the customer_ids who placed orders for two days.
1) First Problem:
Difference in hours is supposed to be 35 but it comes as 34.When i manually find the difference in days and multiply by 24 it comes as 34.999999999 and floor converts it as 34.. But when i execute the difference between dates alone and convert to 24 it shows as 35. So when i apply floor to this, it should be 35 instead of 34 right?
SQL> select (to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
2 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss'))
3 from dual
4 ;
[code].....
1) Second Problem:
For the following query, difference of the dates in minutes is 2100.. so mod(2100,60) should give 0 but it's giving 60.. Separately if if put mod(2100,60) it is giving as 0 only.
SQL> SELECT MOD(((to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
2 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss')) * 1440),
3 60) AS duration,
4 (to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
5 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss')) * 1440 as diffinmin
[code]....
We have a requirement where we need to pay allowance for the employees based on their number of working days. Say for example if an employee worked from 03/Mar/2012 to 05/Apr/2012.
We have a fixed value for per month 300 Dirhams. But the Number of Days on March s 31 and Number of days in April is 30. So per day allowance for March day would be 300/31 and April would be 300/30.
We are looking for logic opr query which calculates first eh number of days in each month ( across months) and then calculate as below
Number of Working days in March is 31 - 3 + 1 = 29
Allowance A1 = (300 * 29 )/31
Number of Working days in April is 5 ( this also needs to find logical I am guess )
Allowance A2 = (300 * 5 )/30
Then A1 + A2.
The A(n) would be the total allowance where provided the number of month across.
Main Aim : To find all those id's who have taken all the tests within a rolling window of 45 days.
I have a table "MBS_FIRST_DATE" with the following data :This table has the patients who have the test along with the first date..This table is derived such that it has only one record with the first date of the test irrespective of the test.
create table MBS_FIRST_DATE
(
medical_record_number VARCHAR2(600),
requested_test_name VARCHAR2(39),
result_date DATE
[code]..
Process :will be explaining with a patient id :
1) Consider the patient 1001274 from mbs_first_date table.
2) This patient has an date of July 08th 2008 & test SBP from first table. (keep this test an an anchor).
3) For the patient above loop through the all_recs table with test & result date ordered for the patient. (excluding SBP)
4) The first record we have is CHL with 08/05/2009 (May 8th 2009)..
5) Since this record is not within 45 days from SBP date for the patient..we go to the next record of SBP for the patient.
6) The next record for SBP is 11/05/2009 (May 11th 2009) .
7) Consider the CHL date again which is with 08/05/2009 (May 8th 2009)..
Since both are within 45 days ..store both the values keeping SBP date as an anchor date as it's the test that's having minimum date from table 1. Even though there is one more CHL date which is within 45 days from SBP we don't care about it.
9) Go to the next test for the same patient which is DBP..
10) The DBP first date is July 08th 2008..
11) Since it's not within 45 days from previously stored SBP date (11/05/2009) ignore the record.
12) GO to the next record which is 10/05/2009..as this is within 45 days from SBP & already CHL (stored date) is within 45 days..Grab all the 3 dates as all are within 45 days from anchor date (SBP date).
SO the o/p will be
1001274 SBP 11/05/2009
1001274 CHL 08/05/2009
1001274 DBP 10/05/2009
Code which I wrote :I know some where I am missing the loop
declare
V_ID1 VARCHAR2(200) := '';
V_TEST1 VARCHAR2(200) := '';
V_DATE1 DATE := NULL;
[code]...
I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.
The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:
select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL))
from dwt_dvt_work_time where dwt_create_date > sysdate - 30
and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id
Here's the function:
CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE)
RETURN NUMBER
IS total_days NUMBER(11,2);
holiday_days NUMBER(11,2);
[code]....
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
View 7 Replies View Relatedwant to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
I got all the month_numbers when i did this
[/b]select distinct t.f_month_number
from time_dim t
where
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)[b]
but when i add
select distinct t.f_month_number,p.start_date,round(replace(p.total_sal,',','')/12,2) as Monthly_sal
from time_dim t, employee p
where
t.f_date = p.start_date and
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)
i got only one month value.
I need query to fetch last six months dyanamically based on the mon-yyyy passed by user
Input to query-JUN-2010
Result-
JAN-2010
FEB-2010
MAR-2010
APR-2010
MAY-2010
JUN-2010
I want the months between two date. I want the months like this :
My parameter for the date from and to means i will enter start date and end date
Suppose Date From is 01-apr-11 and end date 31-mar-12
I want the output like this :
April
May
June
July
August
September
October
November
December
January
February
March
How to do this
I want to display all months (JAN till DEC) in 1st column and their counts in 2nd column but as there are no records in JAN, FEB and march, so they are not coming up.
Get JAN, FEB etc with counts as 0?I know it can be done with NVL function but I don't know where to put it. I'm using oracle 10g on Windows XP. [code]SELECT '',
CASE WHEN b.mon= '01' THEN 'JAN' WHEN b.mon= '02' THEN 'FEB' WHEN b.mon= '03' THEN 'MAR' WHEN b.mon= '04' THEN 'APR' WHEN b.mon= '05' THEN 'MAY' WHEN b.mon= '06' THEN 'JUN' WHEN b.mon= '07' THEN 'JUL' WHEN b.mon= '08' THEN 'AUG' WHEN b.mon= '09' THEN 'SEP' WHEN b.mon= '10' THEN 'OCT' WHEN b.mon= '11' THEN 'NOV' WHEN b.mon= '12' THEN 'DEC' END Months, count(*) cnt FROM (SELECT con.fst_name first_name, con.last_name, usr.login USER_ID, app.appl_src_cd Registration_Source,to_date(usr.created,'DD-MON-YY') Created_Date, TO_CHAR(usr.created,'MM') mon from siebel.s_user usr, siebel.s_contact con, siebel.S_PER_PRTNRAPPL app where con.par_row_id = usr.row_id and app.row_id = con.row_id and app.appl_src_cd = 'Siebel eService' AND TO_CHAR(usr.created,'YYYY') = :P415_YEAR ) bgroup by b.monorder by 3 desc[/code]
Right now getting output as....MONTHSCNTAPR4818JUL4543JUN4295MAY4190AUG541MAR20 What Jan, Feb, March etc in it too with count as 0.
I have table data in which we are entering Visitor's information.We need a monthly report with the count .There are some months which dont have data .So Names of month are not coming .Can i Print Month Name with 0 visitor.
Sample Data
Quote:ID Name Visit_date
1 ABC 01/02/2011
2 DEF 03/04/2011
im using query
Quote:SELECT count(ID) Nos ,TO_CHAR(visit_date,'MONTH') Month FROM DELEGATE_DETAILS WHERE visit_date BETWEEN '01/02/2011' AND '01/04/2011'
GROUP BY TO_CHAR(ARR_DATE,'MONTH')
ORDER BY TO_CHAR(ARR_DATE,'MONTH');
Output
Quote:Nos Month
1 February
1 April
Desired Output:-
Quote:Nos Month
1 February
0 March
1 April
I have this same problem and still i am getting one error message
ORA-00933: SQL command not properly ended
and the code in highlighted in 'by'
'from test_case partition by'
I need to calculate total number of months within a year that account existed for each SSN.
SSN CODE RECORD_DATE PAYMENT
--- ---- ----------- ----------------------
AAA 00 01-FEB-89 50
AAA 01 01-AUG-89 50
BBB 00 01-FEB-89 0
BBB 01 01-AUG-89 50
CCC 00 01-FEB-89 50
CCC 01 01-AUG-89 0
A non-zero payment indicates that the account was open on that date. A zero payment indicates that the account is closed and assumes that it was open since Jan-01.
AAA: code 00 was open in February, so it was open for 11 months (Feb-Dec)
code 01 was open in August, so it was open for 5 months (Aug-Dec)
So the result should be 11
BBB: 00 - closed in February, existed for 1 month
01 - open in August, existed for 5 months
Result should be 6.
CCC: 00 - 11 months(Feb to Dec)
01 - 7 months (Jan to Aug)
Result: 12 months
Need to get:
AAA 11
BBB 6
CCC 12
Here is the source table:
SELECT 'AAA' SSN, '00' CODE, '01-FEB-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'AAA' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'BBB' SSN, '00' CODE, '01-FEB-89' RECORD_DATE, 0 Payment from dual union all
SELECT 'BBB' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'CCC' SSN, '00' CODE, '01-FEB-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'CCC' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 0 Payment from dual union all
SELECT 'DDD' SSN, '00' CODE, '01-OCT-89' RECORD_DATE, 0 Payment from dual union all
SELECT 'DDD' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 50 Payment from dual
How can I fetch a date less than 3 months, if date is '31-Mar-2011' ?
View 3 Replies View RelatedI have a table called transaction_dw and I need to select all records that have an account balance that has been below 0 in the past 6 months. initial query I tried was:
select account_balance, timestamp
from transaction_dw
where account_balance < 0
and timestamp between sysdate and sysdate - 6;
but this is only taking 6 days off the sysdate rather than months, how I can get it to take off 6 months?
I have data like this.
Process_date SEQ_No
------------- ---------
16-MAR-13 733
09-MAR-13 732
02-MAR-13 731
24-FEB-13 730
16-FEB-13 728
09-FEB-13 727
02-FEB-13 726
26-JAN-13 725
21-JAN-13 724
12-JAN-13 723
05-JAN-13 722
29-DEC-12 721
24-DEC-12 720
15-DEC-12 719
08-DEC-12 718
03-DEC-12 717
22-NOV-12 716
17-NOV-12 715
10-NOV-12 714
03-NOV-12 713
29-OCT-12 712
23-OCT-12 711
13-OCT-12 710
05-OCT-12 709
28-SEP-12 708
22-SEP-12 707
15-SEP-12 706
08-SEP-12 705
01-SEP-12 704
every month admin will refresh actual data table and automatically this above table will update with unique seq_no and process_date.
I need to extract min date of every month(First refresh of last 6 months - excluding current month) and also seq_no related to that month so using joins(using seq_no - that is available in main table) i can combine actual data.
I need result like:
02-MAR-13 731 ( I don't need MAR as it should not take current month data)
so i need final result like below:
02-FEB-13 726
05-JAN-13 722
08-DEC-12 718
03-NOV-12 713
05-OCT-12 709
01-SEP-12 704
I need to display the month as below, in a sql statements.
MONTH
JAN-1-15
JAN-16-31
FEB-1-15
FEB-15-28
MAR-1-15
MAR-15-31
i tired with this, but it dint come
select trunc(sysdate, 'year') one, trunc(sysdate, 'year') + floor((last_day(trunc(sysdate, 'year')) + 1 - trunc(sysdate, 'year'))/2) - 1 two,
trunc(sysdate, 'year') + floor((last_day(trunc(sysdate, 'year')) + 1 - trunc(sysdate, 'year'))/2) three, last_day(trunc(sysdate, 'year')) four from dual
SQL> select * from query;
CUSTO SWITCH DATE_X METRIC COUNT_X SEQUENCE_NO FILE
------- ------- --------- ------- ---------- ----------- ----
JCI S1 28-JUN-10 PORT1 10 4 TNB
JCI S1 28-JUN-10 PORT2 4 4 TNB
JCI S1 28-JUN-10 PORT3 8 4 TNB
JCI S2 28-JUN-10 PORT1 1 2 TNB
JCI S2 28-JUN-10 PORT2 5 2 TNB
JCI S3 28-JUN-10 PORT1 6 8 TNB
JCI S5 28-JUN-10 PORT2 2 4 TNB
------->s5 only in the current month-it was not in the previous month data collection
-----------------------------------------------------------------------------
JCI S1 28-MAY-10 PORT1 10 3 TNB
JCI S1 28-MAY-10 PORT3 5 3 TNB
JCI S2 28-MAY-10 PORT1 4 1 TNB
JCI S2 28-MAY-10 PORT2 2 1 TNB
JCI S2 28-MAY-10 PORT3 8 1 TNB
JCI S3 28-MAY-10 PORT2 7 7 TNB
JCI S3 28-MAY-10 PORT3 5 7 TNB
JCI S4 28-MAY-10 PORT1 2 10 TNB
------->s4 in the previous month data
15 rows selected.
1 SELECT A.CUSTO,A.SWITCH,
2 A.PORT1-B.PORT1,
3 A.PORT2-B.PORT2,
4 A.PORT3-B.PORT3
5 FROM (SELECT
6 A.CUSTO
[Code] ......
CUSTO SWITCH A.PORT1-B.PORT1 A.PORT2-B.PORT2 A.PORT3-B.PORT3
------- ------- --------------- --------------- ---------------
JCI S1 0 4 3
JCI S2 -3 3 -8
JCI S3 6 -7 -5
How to include the Switch S4 and S5 in the output. how implemented FULL OUTER JOIN
I need the following totals for each student based on the schools that they are enrolled for each month July through June.
Total Days Suspended from each school
Attendance Table Columns - Absent Date, Absent Code, Pupil_Number, School (Absent Codes for suspended = 3)
Total Days Present at each school - Days Enrolled at each school minus Days Suspended minus Absences
Totals Takes the first day that a student is enrolled (counts the days that the school is in session and the student is not marked absent) Student must be enrolled during the time frame for that month.
Total Days Absent - Total days absent minus suspensions
Examples
Student enrolls in school 11111 on 7/15/2011
Student withdraws from School 11111 on 11/15/2011
Student enrolls in school 22222 on 11/20/2011
Total Days Present should be totaled for each student for each month that they are in a school.
I need 1 row of data for the above student for each month that contains total days suspended, total days present and total days absent.
Pupil Number School Month Totals Days Suspended Total Days Absent Total Days Present
1234 11111 07 0 0 0
1234 11111 08 0 0 4 (school days 4)
1234 11111 09 3 1 16 (schools days 20 - 3-1)
1234 11111 10 0 1 18 (school days 19 - 1)
1234 11111 11 1 1 7 (student enrolled at school A 9 days -1-1)
1234 22222 11 0 1 10 (student enrolled at school B 11 days -1)
1234 22222 12 1 2 17 (school B 20-1-2)
1234 22222 01 0 0 20
I have a contract that has several categories with payments in each one. If there is a payment=0, then a category is considered closed. The contract is considered closed when all categories are closed.
Date Category Payments
01/01/07 1 5
01/01/07 2 7.5
01/01/07 3 6
05/01/07 2 0
09/01/07 1 0
11/01/07 3 0
(date here is in mm/dd/yy)
I need a SQL that will return the number of months within the year that contract was open. In the example above, the last category closed on 11/01, so the result should be 10. If the last line was not there, the contract would still be open in 2007 and the result should be 12.
i have written an sql to look as sales orders but i want it to only return the last 12 months worth of sales for the date its run, the date file [sdtrdj] is julian date so i used to_char to conver it to dd-mm-yyyy how can i get it to only return the last 12 months from the date its run
select
sdshan As "Location", sddcto As "Order Type", sddoco As "Order Number",sdlitm As "Product Code", sddsc1 As "Product Description",
to_char(to_date(sdtrdj + 1900000, 'yyyyddd'),'DD-MM-YY')As "Order Date", sduorg As "Order Qty", sdaexp As "Extended Amount", sdsoqs As "Quantity Shipped",
ibsrp4 As "Srp4", ibsrp6 As "Srp6", ibsrp7 As "srp7", ibsrp9 As "Srp9", ibsrp0 As "srp10", sdsrp2 As "Franchise"
From proddta.f4211, proddta.f4102
Where sdmcu = ' UKC001'
and sddcto = 'KO'
and sdlitm = iblitm and sdmcu = ibmcu
and sdsrp2 In ('504','973','322','236','232','856','233','566','590','470','343','266','279')
I would like to convert a number to years & months.
e.g. 119 = 9 years and 11 months
This would be displayed as 9.11
Is there an oracle function or sql that can calculate this value,
am trying to write a simple sql which would delete data from last n months but it will keep the data for the first of each of those month from current sysdate
e.g
Jan 1 - 30 deletes 2 - 30 keeps data for 1st
Feb 1 - 28 deletes 2 - 28 keeps data for 1st
Mar
Apr Current sysdate
May
I need to get the past 12 months from the current month
for example
input:
march2010
output:
apr2009
may2009
june2009
july2009
augest2009
september2009
october2009
november2009
december2009
january2010
february2010
how to query a list to see if a person had events in consectutive months within the past year. We call a person a LongTermResident if they had a review in any two consectutive months within a reporting period. I wrote a function isResidentLongTerm, passing in FacilityID, ResidentID, ReportPeriodStart, and ReportPeriodStop and returning a 'Y' or 'N'. It works, but the performance is slow.
So if I have a list of reviewers, facilities, reviewees I want to select only those SNF/NF residents who have had routine reviews in any two consectutive months at the same facility.
This is my query:
select ConsultantID, ResidentID
from (
select distinct ConsultantID, FacilityID, ResidentID
from Reviews
where BedType = 17820 -- SNF/NF bed
and ReviewType = 17474 -- routine review
)
where isResidentLongTerm( FacilityID, ResidentID, :startDate, :stopDate ) = 'Y'
getting the yearly qty distributed evenly across 12 months. I can do this in PL/SQL but want to know is it possible in SQL.
Database version 10g
create table test_tbl( qty number(22),
yr number,
key_val varchar(10)
);
insert into test_tbl values( 500000, 2013, '1');
insert into test_tbl values (56789, 2014, '2');
commit;
This is the output I need to get from a SQL select query
Key Month Year qty
--------------------------------------------------------------
1 1 2013 41667
1 2 2013 41667
1 3 2013 41667
1 4 2013 41667
1 5 2013 41667
1 6 2013 41667
1 7 2013 41667
[code]....
