PL/SQL :: Convert A Number To Years And Months

Jul 30, 2012

I would like to convert a number to years & months.

e.g. 119 = 9 years and 11 months

This would be displayed as 9.11

Is there an oracle function or sql that can calculate this value,

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SQL & PL/SQL :: Convert Days To Months

Nov 21, 2011

I have the following in my select statement and I am getting the days like 1130, 50, 60 etc

round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS

Now I want this to convert these days into months like
1.10 this denotes (one month 10 days)
1.25 this denotes (one month 25 days)
2.05 this denotes (two months 5 days)

I know I am using old Oracle but what to do my company is not spending to upgrade.

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SQL & PL/SQL :: Number Of Years Calculation

Mar 16, 2012

for making the query for following data,when we give start and end date then query need to calculate number of years.

if less than one year then return 0
if exact one year then return 1
if exact 1.5 years (18 months) then return 2
if exact 2 years (24 months) then also return 2
if exact 2.5 years (30 months) then return 3
if exact 3 years (36 months) then also return 3
if exact 3.5 years (42 months) then return 4
if exact 4 years (48 months) then also return 4
and so.

also we need to add leap year 1 day if exist in start and end date.

YearSalary
11
1.52
22
2.53
33
3.54
44
4.55
55
[code]....

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SQL & PL/SQL :: Merge Number Of Months?

Sep 4, 2012

I need to calculate total number of months within a year that account existed for each SSN.

SSN CODE RECORD_DATE PAYMENT
--- ---- ----------- ----------------------
AAA 00 01-FEB-89 50
AAA 01 01-AUG-89 50
BBB 00 01-FEB-89 0
BBB 01 01-AUG-89 50
CCC 00 01-FEB-89 50
CCC 01 01-AUG-89 0

A non-zero payment indicates that the account was open on that date. A zero payment indicates that the account is closed and assumes that it was open since Jan-01.

AAA: code 00 was open in February, so it was open for 11 months (Feb-Dec)
code 01 was open in August, so it was open for 5 months (Aug-Dec)
So the result should be 11

BBB: 00 - closed in February, existed for 1 month
01 - open in August, existed for 5 months
Result should be 6.

CCC: 00 - 11 months(Feb to Dec)
01 - 7 months (Jan to Aug)
Result: 12 months

Need to get:
AAA 11
BBB 6
CCC 12

Here is the source table:

SELECT 'AAA' SSN, '00' CODE, '01-FEB-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'AAA' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'BBB' SSN, '00' CODE, '01-FEB-89' RECORD_DATE, 0 Payment from dual union all
SELECT 'BBB' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'CCC' SSN, '00' CODE, '01-FEB-89' RECORD_DATE, 50 Payment from dual union all
SELECT 'CCC' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 0 Payment from dual union all
SELECT 'DDD' SSN, '00' CODE, '01-OCT-89' RECORD_DATE, 0 Payment from dual union all
SELECT 'DDD' SSN, '01' CODE, '01-AUG-89' RECORD_DATE, 50 Payment from dual

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SQL & PL/SQL :: Number Of Months The Contract Was Open

Aug 21, 2012

I have a contract that has several categories with payments in each one. If there is a payment=0, then a category is considered closed. The contract is considered closed when all categories are closed.

Date Category Payments
01/01/07 1 5
01/01/07 2 7.5
01/01/07 3 6
05/01/07 2 0
09/01/07 1 0
11/01/07 3 0

(date here is in mm/dd/yy)

I need a SQL that will return the number of months within the year that contract was open. In the example above, the last category closed on 11/01, so the result should be 10. If the last line was not there, the contract would still be open in 2007 and the result should be 12.

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SQL & PL/SQL :: Procedure To Compute Ratios Across Variable Number Of Months

Nov 19, 2011

the problem below:

I have a table AlertData below:

DeptIDMONTHCount
192010-041392
192010-051134
192010-061094
192010-071333
292010-042217

[Code]...

Within each DeptID group I need to calculate absolute change of 'Count' column between previous and current months and compare change value with threshold.

If ratio >= threshold N number of times I need to make a note of that event. Threshold = 0.1 N = 2 - alert needs to exceed threshold two consequtive times

Here is data processing algorithm:

1. Calculate change between month 2010-04 and 2010-05: abs((1134/1392 - 1))= 0.18;
2. check change value against threshold: 0.18 > 0.1
3. Threshold was exceeded, set alert_fired_cnt counter to = 1
4. Once alert fired it creates a baseline for comparison - I need to use Count from month 2010-04: We're now in month 2010-06: abs(1094 / 1392 - 1)=0.21
5. check change value against threshold: 0.21 > 0.1
6. Threshold was exceeded, increment alert_fired_cnt counter by 1 = 2
7. At this point alert exceede threshold two times, I need to set a alert_triggered flag = 1 and reset alert_fired_cnt = 0 for further calculations
8. We're in montn 2010-07: abs(1333/1294-1)=0.03
8. check change value against threshold: 0.03 < 0.1
9. Since threshold was not exceeded, keep alert_fired_cnt counter to = 0

Above algorithm needs to be run for all DeptID groups.

I load above data into an associative array and loop through elements. I am having trouble keeping computations within each DeptID group.

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Aug 27, 2010

wanna to make matrix report retrieve months year and the number of weeks from dual table it supposes to the weeks number is 52 or 53 week months and weeks on the rows please find attach pic it show what i need to do for exmple

month name: January February March April May June July August September Nov October December
no of week : 1-2-3-4-5-6-7-8-9-10-11-12-13-14-15-16-17-18-20-21-22....... TO 52 week

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SQL & PL/SQL :: How To Convert RAW To Number

Sep 27, 2013

can we convert RAW to number in sql.because i have to bitand of one raw and number variable.

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PL/SQL :: Convert Number?

Jun 14, 2013

would need to convert a number in this way:10.1 ---> 10101.90 ----> 190  How can i?

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SQL & PL/SQL :: Convert Char To Number

Mar 16, 2011

I've got a table with varchar records and I need to separate numerical value and convert into the number datatype.

create table tmp_mape

(remark varchar2(100) )

insert into tmp_mape values ('Dobitie zdarma 3,32EUR 0910105067 02/02')
insert into tmp_mape values ( 'Dobitie pravidelné 9,00EUR' )

I just need to get values 3.32 and 9 from that example into the new column.

The select below returns ORA-01722: invalid number

how to solve it?

select remark,
to_number( to_number(REGEXP_SUBSTR (remark, '[[:digit:]]+', 1) ) ||','|| to_number(substr(REGEXP_SUBSTR (remark, ',[^EUR]+', 1) ,2) ) )
from tmp_mape

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Jan 15, 2013

How to convert varchar2 to number data?

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SQL & PL/SQL :: How To Convert Number To Date

Oct 28, 2011

how can convert this number 00001021992 to this format

1-02-1992

i used thie query but no result

select substr(to_date('00001021992','dd-mm-yyyy'),(6,6)) from dual;

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SQL & PL/SQL :: Convert Character Into Number

Jul 30, 2010

the basic salary has data type character.when i write

select basic_salary from table_name

it shows output.but when i need annul for that basic salary(basic_salary*12) it shows error. invalid number.

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Jan 1, 2013

I want to convert below MS-SQL query in oracle 10g.

for eg:

Select numasdate,
Cast(numasdate / 60 as Varchar) + ' hours ' +
Cast(numasdate % 60 as Varchar) + ' minutes'
as [TotalHoursAndMinutes]
From
#SampleTable

Output:

9436 157 hours 16 minutes
537 8 hours 57 minutes
9323 155 hours 23 minutes
12525 208 hours 45 minutes

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Mar 8, 2013

I need a query that convert number into time.

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Sep 10, 2012

I have a value that I need in the number format, but without decimals. Is this possible?

TO_NUMBER(SY_KEY1,'9999999') AS SY_KEY1The result I get back is:

1114225.0So, I need a result of 1114225 and in the number format.

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Aug 14, 2013

I want to convert decimal number 44 to character(" ' " i.e single quotation);

I have already tried to_char function but it's not working.

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SQL & PL/SQL :: Convert Varchar2 To Date Or Number

Jun 18, 2011

I created table Contains then following columns

cheq varchar2(50)
date_due varchar2(50)

and data entry in this columns

cheq 500,1500,5000 all values numbers in this columns

date_due 1-1-2012 , 15-9-2010 all values in this columns date

i want sum the column "cheq"

when used this code but it's not working

select sum(to_number(cheq))
from table_name but the code not working

second column "date_due"

i want search between to date i used this code but also not working

select cloumn1,cloum2
from table_name
where to_char(date_due,'dd-mm-yyyy')
between to_char(date_due,'dd-mm-yyyy') and
(date_due,'dd-mm-yyyy')

but not work

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Jun 23, 2013

One table ACCOUNT_T.CREATED_T is number (38). It is mapped to /ACCOUNT's PIN_FLD_CREATED_T, which is timestamp. ACCOUNT_T table has one record, CREATED_T = 1362063600. This field is displayed at the GUI (Customer Center) as Feb 28, 2013 So my question, how to convert the number value (1362063600) to a date value (Feb 28, 2013)?

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Forms :: How To Convert Exponent Into Pure Number

Nov 22, 2006

I have to convert the following

3.3767E+14
4.40453E+15
4.40453E+15

into

337670137917014.00
4404530588226230.00
4404530588226230.00

Any function or formula for this one?

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Apr 14, 2011

I want to convert a number to this format using below query but i'm getting error. how to correct the below query.

SELECT TO_CHAR(12345678, '99G9999D99') FROM dual;

error:-###########

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Oct 5, 2010

I have year/quarter number field (200903 3-rd quarters of 2009) and I need to convert to data format.

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May 16, 2013

How to convert exponential number into pure number while writing on excel using report builder.Excel only takes 15 digit as pure number and remaining number it converts into zero or you can say in exponential form.

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Aug 5, 2011

how can convert number from Arabic to English in oracle report builder

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SQL & PL/SQL :: Days To Years Converter

May 11, 2012

Our "client" is delivering data that contains an "age" field. However, they've put the AGE in DAYS instead of years, while our system can only work with years. So I needed to convert the age to years.

We are getting 2 parameters: LOWAGE and HIGHAGE (both in days). However, for the same "test" (laboratory test), we are also getting some other records

eg:

TEST 1 lowage = 0 upperage = 5 OTHER values = xxx
TEST 1 lowage = 6 upperage = 100 OTHER values = yyy

So if the person would be 5 years or less, the values xxx would apply. If they are 6 years and older, the yyy values apply. Now, the problem is that we are not getting this data in years, but in days. And whichever function I try, the upperage from the first test also seems to be equal to the lowerage from the second test. And this gives an error, because both would apply to this person....

I've tried stuff like:

age/365
age/365.25 (leap years)
trunc(months_between(sysdate+ranges.lowerage,sysdate)/12)

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PL/SQL :: Query To Get List Of Years?

Feb 15, 2013

I am trying to generate a list of years, starting with 2010 and counting up through 5 years from the current date. For example, if it is currently 2013, the list would include 2010 through 2018. 2 years from now, I want the list to go from 2010 through 2020.

I am currently using

SELECT to_char(add_months(to_date('2010','YYYY'),12 * (rownum-1)),'YYYY')
FROM dual
CONNECT BY level <= 10to get a list with 10 entries.

How can I make this dynamic enough to return a variable number of records depending on the current year?

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SQL & PL/SQL :: Find Years Between Any Given Date Range

Apr 5, 2011

I require to find the years between any given date range. For example what are the years between the dates '01/12/2010' and '01/02/2012'? Answer must be '2010,2011,2012'. how to code the query for this result?

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SQL & PL/SQL :: Chinese Zodiac Associated With Birth Years

Aug 8, 2010

I have a question to write a pl/sql for Chinese zodiac but i cant do it, even i Google it i cant find any solution..the question is as below:

The Chinese zodiac associates birth years with the following; animals:

Birth Year Animal
1924,1936.1948,1960,1972,1984,1996 Rat
1925,1937,1949,1961,1973,1985,1997 Cow
1926,1938,1950,1962,1974,1986,1998 Tiger
1927,1939,1951,1963,1975,1987,1999 Rabbit
1928,1940,1952.1964,1976,1988,2000 Dragon
1929,1941,1953,1965,1977,1989,2001 Snake
1930,1942,1954,1966.1978,1990,2002 Horse
1931,1943,1955.1967,1979,1991,2003 Sheep
1932,1944,1956,1968,1980,1992,2004 Monkey
1933,1945,1957,1969,1981,1993,2005 Chicken
1934.1946,1958,1970,1982,1994,2006 Dog
1935,1947,1959,1971,1983,1995,2007 Pig

Write a command to declare a date variable named birth_date, and assign to it your birth date. Use an IF/ELS1F structure to test every year and determine the animal associated with your birth year. Then display your birth year and the associated animal name. For example, the program would display the following output for someone born in 1984:

I was born in 1984, which is the year of the Rat. Declare and use additional variables as needed.

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Mar 26, 2011

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SQL & PL/SQL :: Query To Find User Who Did Not Login From Past 3 Years?

Nov 2, 2012

I have two table APPLICATION_1 and APPLICATION_2, where user's login date is captured.There will be multiple records for each user.Same user may or may not be present in both tables.

The requirement is to find those users who have not logged-in in the last 3 years.

-- Test Case

DROP TABLE application_1;
DROP TABLE application_2;
CREATE TABLE application_1
(
seq NUMBER ,
user_id VARCHAR2(30),

[code].....

Using the below query I'm able to get the desired output.

SELECT user_id, MAX(login_date) last_login_date FROM (
SELECT user_id, MAX(login_date) login_date FROM application_1 GROUP BY user_id
UNION ALL
SELECT user_id, MAX(login_date) login_date FROM application_2 GROUP BY user_id
) GROUP BY user_id

[code].....

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