In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
I have a problem with a query. I have a table employee with data as
emp_id date day working_ind 1 01-Jan-2011 Mon Y 1 02-Jan-2011 Tue Y 1 03-Jan-2011 Wed Y 1 04-Jan-2011 Thu Y 1 05-Jan-2011 Fri Y 1 06-Jan-2011 Sat N 1 07-Jan-2011 Sun N 1 09-Jan-2011 Tue Y
Sundays/ Monday/ any public holiday the working_ind will be N. If the emp is absent on one day then there will be no record entered in the table (e.g. 8th jan there is no record). Each table has only one year data.
I need to retrieve for all employees when they worked for 30 consecutive days without being absent which does not include sat/ Sunday / holidays.
Its like: -- i need to order by emp_id and date -- get oly the data with working_ind as Y -- make sure that i get 30 consecutive days (from what ever i get above) where no days data is missing
I tried using lag and inner join but it does not seem to be working.
The code should identify that the 'Bonus' project missed updates on 02/08/2013 and 06/08/2013. Should be a simple enough piece of code for an experienced developer i'm sure
I have a need to query a real time production database to return a set of results that spans a three day period. When the three days are consecutive it's easy but sometimes there is a 1 or two day gap between the days. For example I'm querying results from a group of people that work between Tuesday and Saturday. On a Wednesday I need t produce a set of results that spans Tuesday of the current week, and Saturday and Friday of the previous week; on Thursday I need to produce a set of results that that spans Wednesday and Tuesday of the current week and Saturday of the previous week.I'm using SQL Developer to execute the code.
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
I want to do group ranking in desired col3 in such a way that it checks for different values across consecutive rows under col2 and assigns a number to each group. Just when two consecutive rows in col2 have same value then the group ends and the next group starts.
So my desired output is:
Col1 Col2 Col3 1 A 1 2 B 1 3 C 1 4 D 1 5 D 2 6 A 2
[code]...
Here you can see that the first four rows under col2 are unique i.e A,B,C,D so col3 assigns this as group number 1. It ends at row 4 becuase row 5 also has value D under column 2. So in other words, each group must have all unique values and there should not be any repetition. For example, see group 3 (under col3) in above desired output; it starts from row 9 and ends at row 11 because row 12 also has value 'C' and the value 'C' has already occurred in group 3 in row 9.
I want to achieve this SQL. I tried using Dense rank but couldn't go through. I want the shortest possible query to acheive this.
i want to restrict the user if he/she enters any 3 consecutive sequence of numbers,characters,alphanumerics and special characters for example aaa, aAa, @@@, ---- , 111, 123 are not valid.
valid sequences are a1w,?1A,aa1,WW2,78a,-#a
i want to show the invalid sequence in a single query using regular expression function. suppose for example if user enters aaa,$$$,123 then the query output is aaa,$$$,123.
i have written two different queries for that but i want a single query
SELECT REGEXP_SUBSTR('EEE','([a-z])\1\1',1,1,'i') FROM DUAL; SELECT REGEXP_SUBSTR('111','([0-9])\1\1',1,1,'i') FROM DUAL; SELECT REGEXP_SUBSTR('@@@','([^-$])\1\1',1,1,'i') FROM DUAL; -it is not checking for -(hypen) characters
$x being a range of non-consecutive values like so: 1,3,5-9,13,18,21 and so on...
I realize I can query using an array of operands and such, but these ranges will be in upwards of 100 or more items. I want to minimize the number of queries I have to do and the length of them. Is there any resource you can point me to that can optimize something like this?
SELECT DISTINCT a.emp_id, a.cal_id, TO_CHAR(a.ts_date, 'DD/MM/YYYY') tsdate, a.ts_date, 1 as days FROM tmsh_timesheet a INNER JOIN project b ON TO_CHAR(b.proj_id) = a.proj_id INNER JOIN tmsh_ts_calendar c ON c.cal_id = a.cal_id INNER JOIN (SELECT a.cal_id, a.emp_id, MAX(a.status) as status, a.create_dt, a.create_by FROM tmsh_stat_hist a
I want update col1 whis is null to max(col1) ++ in a row, order by cr_date like 1,1,20110102 2,2,20110101 3,null,20110105 => 3,5,20110105 because this row is after 20110103 4,3,20110104 5,null,20110103 => 5,4,20110103 because this row is before 20110105
update test_table set col1 = (select max(col1) from test_table) + rownum where col1 is null;
version : Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
i want to ,remove consecutive occurance from string
Example I/P: 'POWELL POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL' to O/P : 'POWELL BRIAN K AND BONNIE POWELL JARRELL'I tried the below code is Working fine , But i wanted to do this using Regexp or Some other Better Method WITH T
how to query a list to see if a person had events in consectutive months within the past year. We call a person a LongTermResident if they had a review in any two consectutive months within a reporting period. I wrote a function isResidentLongTerm, passing in FacilityID, ResidentID, ReportPeriodStart, and ReportPeriodStop and returning a 'Y' or 'N'. It works, but the performance is slow.
So if I have a list of reviewers, facilities, reviewees I want to select only those SNF/NF residents who have had routine reviews in any two consectutive months at the same facility.
This is my query:
select ConsultantID, ResidentID from ( select distinct ConsultantID, FacilityID, ResidentID from Reviews where BedType = 17820 -- SNF/NF bed and ReviewType = 17474 -- routine review ) where isResidentLongTerm( FacilityID, ResidentID, :startDate, :stopDate ) = 'Y'
I want to find out consecutive non-increasing sequences of value (2nd column) order by sr. no (first column) in ascending order.
For example, in the 2nd column, 17 is followed by 0 and 0 and then 38 so it means 3 consecutive values (i.e starting from 17 are 0 and 0) are non-increasing and they are ranked by '1' in my desired in third column as shown below. similarly, the 2nd non-increasing sequence starts with 38,32,24 and 12 and this is ranked as '2' in the third column. same is the case with rank '3' for the third non increasing sequence. so bascially i want the third column with "ranks" starting and ending as per above logic. i tried using LEAD function but doesn't get what I want. I need the shortest possible query to get that third column since i have other columns in the original table in a multiple group by query.
create table T (student_id number, class_id number, quiz_id number, marks number)
some sample rows like
INSERT INTO T VALUES (1,1, 1, 50); INSERT INTO T VALUES (2,2, 2, 40); INSERT INTO T VALUES (3,1, 3, 34); INSERT INTO T VALUES (1,1, 4, 10); INSERT INTO T VALUES (1,1, 5, 30); INSERT INTO T VALUES (1,1, 6, 29); INSERT INTO T VALUES (3,2, 7, 34); INSERT INTO T VALUES (3,2, 8, 33); INSERT INTO T VALUES (3,2, 9, 56); INSERT INTO T VALUES (1,1, 7, 90); INSERT INTO T VALUES (2,2, 8, 0,); INSERT INTO T VALUES (1,1, 8, 80); INSERT INTO T VALUES (2,2, 8, 65); INSERT INTO T VALUES (1,1, 9, 34); INSERT INTO T VALUES (2,2, 9, 11);
each student belongs to one class_id. each student participates in many quizes. each quiz has its unique id. each student can appear once in a quiz_id
I am doing the below analysis and query:
1. with below query I am finding which student_id had most marks in any 3 successive quizes (see the 3-1 part below) in the query..
With above query, I can play around and find for any 'n' number of consecutive quizes, like marks in 2 consecutives quizes, 3, 4 and so on but for each 'n' value I've to run a seperate query mentioning (2-1) or (3-1) or (4-1) and so on..
since my table is big and there are about 400 quizes so what I want to find out is for each 'n' consecutive quiz (from 1 to 400) which student had most marks for each consecutie 'n' quiz. Like in 1 (consecutive) quiz which student had the highest marks and then 2 conseuctive quiz who had most marks and then in 3 consecutive quiz who had most marks and so on till 400 consecutive quiz who had most marks... rather than running query for each 'n' value seperately i want a single query that can give me a summary of most marks in each n consecutive quizes...
Is this possible to get the above output from one single query? If there are two or more students with equal most marks for any 'n' conseutive quizes then both should come in the summary.
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
How to select last 10 days rows only (from sysdate)
Error
1) SQL> select * from Test where to_date(start_ts, 'DD-MON-YYYY HH24:MI:SS') > to_date(sysdate, 'DD-MON-YYYY HH24:MI:SS')-10 ; (or)
2) SQL> select * from Test where to_date(start_ts, 'MM/DD/YYYY HH24:MI:SS') > to_date(sysdate, 'MM/DD/YYYY HH24:MI:SS')-10 ; ORA-01858: a non-numeric character was found where a numeric was expected
Our "client" is delivering data that contains an "age" field. However, they've put the AGE in DAYS instead of years, while our system can only work with years. So I needed to convert the age to years.
We are getting 2 parameters: LOWAGE and HIGHAGE (both in days). However, for the same "test" (laboratory test), we are also getting some other records
eg:
TEST 1 lowage = 0 upperage = 5 OTHER values = xxx TEST 1 lowage = 6 upperage = 100 OTHER values = yyy
So if the person would be 5 years or less, the values xxx would apply. If they are 6 years and older, the yyy values apply. Now, the problem is that we are not getting this data in years, but in days. And whichever function I try, the upperage from the first test also seems to be equal to the lowerage from the second test. And this gives an error, because both would apply to this person....
i have an employee table where there is a column called join date. Now i have to select the employee according to the days. Means how many employee joined on Monday/Tuesday etc.
I have the following in my select statement and I am getting the days like 1130, 50, 60 etc
round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS
Now I want this to convert these days into months like 1.10 this denotes (one month 10 days) 1.25 this denotes (one month 25 days) 2.05 this denotes (two months 5 days)
I know I am using old Oracle but what to do my company is not spending to upgrade.
I want to find the months and days between 2 dates. For Eg. Date-1 : 25-Aug-2013Date-2 : 23-Oct-2013 If we consider every month as 30 days it should give 25-Aug-2013 to 30-Aug-2013 = 6 days 01-Sep-2013 to 30-Sep-2013 = 1 Month 23-Oct-2013 to 30-Oct-2013 = 8 days Total = 1 month and 14 days
1. Make the jobname distinct, because it keeps giving me multiple entries for each jobname 2. Add the the start_time of SOD_start_data9_UAT1 to end_time fodba_MUAT1 to get the combined duration 3. CONCAT jobnames SOD_start_data9_UAT1 and end_time fodba_MUAT1 4. Generate the last seven days batch run times 5. Generate a report into .csv format and email out 6. I have access to sqlplus and plsql developer
