SQL & PL/SQL :: Find Two Or More Consecutive Dates?
Feb 23, 2010
I am pulling information from a view to get the current results and placing them into a cursor which then inserts the results into a temp table.
Current Results:
JOB_NAMESCHEDULED_TIME STATUS
JOB_1 02/23/2010 13:25:00Failed
JOB_1 02/22/2010 13:25:00Failed
JOB_1 02/21/2010 13:25:00Failed
JOB_1 02/19/2010 13:25:00Failed
JOB_2 02/21/2010 13:25:00Failed
JOB_2 02/18/2010 13:25:00Failed
JOB_2 02/17/2010 13:25:00Error
JOB_2 02/15/2010 13:25:00Error
Needed Results:
JOB_NAMESCHEDULED_TIME STATUS
JOB_1 02/23/2010 13:25:00Failed
JOB_1 02/22/2010 13:25:00Failed
JOB_1 02/21/2010 13:25:00Failed
JOB_2 02/18/2010 13:25:00Failed
JOB_2 02/17/2010 13:25:00Error
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Mar 23, 2010
SELECT DISTINCT a.emp_id, a.cal_id, TO_CHAR(a.ts_date, 'DD/MM/YYYY') tsdate, a.ts_date, 1 as days
FROM tmsh_timesheet a
INNER JOIN project b ON TO_CHAR(b.proj_id) = a.proj_id
INNER JOIN tmsh_ts_calendar c ON c.cal_id = a.cal_id
INNER JOIN (SELECT a.cal_id, a.emp_id, MAX(a.status) as status, a.create_dt, a.create_by FROM tmsh_stat_hist a
[Code]...
this query results
EMP_IDCAL_IDTSDATE
048283404/10/2010
048283502/11/2010
048283503/11/2010
048283504/11/2010
048283508/11/2010
i need the ts date to be in like this
04/10/2010
02/11/2010 - 04/11/2010
08/11/2010
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Sep 26, 2012
I need query to find the missing dates between two columns in given month.
CREATE TABLE emp_shift (
empno NUMBER(4),
fr_date DATE,
TO_DATE DATE,
shift VARCHAR2(1));
CREATE TABLE emp (
empno NUMBER(4)
);
[code].....
Required output is
MISSING_DATES EMPNO
---------------------- ----------
09-SEP-12 TO 11-SEP-12 7499
23-SEP-12 TO 26-SEP-12 7499
01-sep-12 TO 30-SEP-12 7521
01-sep-12 TO 30-SEP-12 7788
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Mar 17, 2011
I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.
The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:
select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL))
from dwt_dvt_work_time where dwt_create_date > sysdate - 30
and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id
Here's the function:
CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE)
RETURN NUMBER
IS total_days NUMBER(11,2);
holiday_days NUMBER(11,2);
[code]....
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Jan 26, 2011
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
1220.01.10
1321.01.10
1423.01.10
1526.01.10
1627.01.10
1729.01.10
1831.01.10
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
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Mar 10, 2011
Split a date into new dates according to black out dates!
Here is my tables:
CREATE TABLE travel
(
start_date,
end_date
)
AS
SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;
[code]....
I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.
Note: Travel Date can be between 0000-01-01 - 9999 12 31
Sample:
Travel Date:
Travel | START DATE | END DATE
T | 2011 01 04 | 2011 12 11
Black Out Dates:
BO | START DATE | END DATE
A | 2010 11 01 | 2011 02 11
B | 2011 01 20 | 2011 02 15
C | 2011 03 13 | 2011 04 10
D | 2011 03 20 | 2011 06 29
Excepted Result:
New Travel | START DATE | END DATE
X1 | 2011 02 16 | 2011 03 12
X2 | 2011 06 30 | 2011 12 11
Visually:
Travel Date : -----[--------------------------]--
A : --[------]-------------------------
B : ------[---]------------------------
C : --------------[---]----------------
D : ----------------[------]-----------
Result :
X1 : -----------[--]--------------------
X2 : -----------------------[--------]--
Sample 2:
Travel Date : -[--------------------------------]--
BO Date A : ----[------]-------------------------
BO Date B : -------------------------[---]-------
BO Date C : ----------------[---]----------------
BO Date D : ------------------[------]-----------
Result X1 : -[-]-------------------------------
Result X2 : -----------[--]--------------------
Result X3 : -----------------------------[--]--
How can I do it using PL SQL ?
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Oct 18, 2010
I need to know if a customer appears at least 4 consecutive days. Here's an example of data
CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
123 , 2010/10/10
456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
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May 11, 2012
I have a table with three columns: terminal, place and batch. How can I check for missing batches?
select * from transactions;
terminal place batch
84812
84813
84814
84816
84821
84823
84824
84825
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Aug 23, 2012
I have a table T with columns
Col1 Col2
1 A
2 B
3 C
4 D
[code]..
I want to do group ranking in desired col3 in such a way that it checks for different values across consecutive rows under col2 and assigns a number to each group. Just when two consecutive rows in col2 have same value then the group ends and the next group starts.
So my desired output is:
Col1 Col2 Col3
1 A 1
2 B 1
3 C 1
4 D 1
5 D 2
6 A 2
[code]...
Here you can see that the first four rows under col2 are unique i.e A,B,C,D so col3 assigns this as group number 1. It ends at row 4 becuase row 5 also has value D under column 2. So in other words, each group must have all unique values and there should not be any repetition. For example, see group 3 (under col3) in above desired output; it starts from row 9 and ends at row 11 because row 12 also has value 'C' and the value 'C' has already occurred in group 3 in row 9.
I want to achieve this SQL. I tried using Dense rank but couldn't go through. I want the shortest possible query to acheive this.
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Nov 14, 2010
i want to restrict the user if he/she enters any 3 consecutive sequence of numbers,characters,alphanumerics and special characters for example aaa, aAa, @@@, ---- , 111, 123 are not valid.
valid sequences are a1w,?1A,aa1,WW2,78a,-#a
i want to show the invalid sequence in a single query using regular expression function. suppose for example if user enters aaa,$$$,123 then the query output is aaa,$$$,123.
i have written two different queries for that but i want a single query
SELECT REGEXP_SUBSTR('EEE','([a-z])\1\1',1,1,'i') FROM DUAL;
SELECT REGEXP_SUBSTR('111','([0-9])\1\1',1,1,'i') FROM DUAL;
SELECT REGEXP_SUBSTR('@@@','([^-$])\1\1',1,1,'i') FROM DUAL; -it is not checking for -(hypen) characters
any 3 consecutive characters from key board.
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Aug 23, 2007
SELECT * FROM table WHERE id = $x
$x being a range of non-consecutive values like so:
1,3,5-9,13,18,21 and so on...
I realize I can query using an array of operands and such, but these ranges will be in upwards of 100 or more items. I want to minimize the number of queries I have to do and the length of them. Is there any resource you can point me to that can optimize something like this?
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Apr 14, 2011
create table test_table(
rn varchar2(10),
col1 varchar2(10),
col2 varchar2(10),
[code]...
I want update col1 whis is null to max(col1) ++ in a row, order by cr_date like
1,1,20110102
2,2,20110101
3,null,20110105 => 3,5,20110105 because this row is after 20110103
4,3,20110104
5,null,20110103 => 5,4,20110103 because this row is before 20110105
update test_table
set col1 = (select max(col1) from test_table) + rownum
where col1 is null;
this gives ora-00933
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Jun 4, 2013
version : Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
i want to ,remove consecutive occurance from string
Example I/P: 'POWELL POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL'
to O/P : 'POWELL BRIAN K AND BONNIE POWELL JARRELL'I tried the below code is Working fine , But i wanted to do this using Regexp or Some other Better Method
WITH T
[Code]....
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Oct 23, 2011
provide SQL query (not PL/SQL block) for the following. I have data in table as shown below
Serial No value
========= ========
123
2-99
3-99
4-99
534
656
77
88
990
1065
1167
12-99
13-99
14-99
15-99
16-99
17-99
182
1945
206
The output of the SQL will be the largest consecutive series of the value -99 is 6 and total count of the value -99 is 9
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Jul 15, 2011
I have a problem with a query. I have a table employee with data as
emp_id date day working_ind
1 01-Jan-2011 Mon Y
1 02-Jan-2011 Tue Y
1 03-Jan-2011 Wed Y
1 04-Jan-2011 Thu Y
1 05-Jan-2011 Fri Y
1 06-Jan-2011 Sat N
1 07-Jan-2011 Sun N
1 09-Jan-2011 Tue Y
Sundays/ Monday/ any public holiday the working_ind will be N. If the emp is absent on one day then there will be no record entered in the table (e.g. 8th jan there is no record). Each table has only one year data.
I need to retrieve for all employees when they worked for 30 consecutive days without being absent which does not include sat/ Sunday / holidays.
Its like:
-- i need to order by emp_id and date
-- get oly the data with working_ind as Y
-- make sure that i get 30 consecutive days (from what ever i get above) where no days data is missing
I tried using lag and inner join but it does not seem to be working.
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Apr 7, 2011
how to query a list to see if a person had events in consectutive months within the past year. We call a person a LongTermResident if they had a review in any two consectutive months within a reporting period. I wrote a function isResidentLongTerm, passing in FacilityID, ResidentID, ReportPeriodStart, and ReportPeriodStop and returning a 'Y' or 'N'. It works, but the performance is slow.
So if I have a list of reviewers, facilities, reviewees I want to select only those SNF/NF residents who have had routine reviews in any two consectutive months at the same facility.
This is my query:
select ConsultantID, ResidentID
from (
select distinct ConsultantID, FacilityID, ResidentID
from Reviews
where BedType = 17820 -- SNF/NF bed
and ReviewType = 17474 -- routine review
)
where isResidentLongTerm( FacilityID, ResidentID, :startDate, :stopDate ) = 'Y'
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Apr 14, 2012
I have a table with numbers like this in a column
sr no. value
1 17
2 0
3 0
4 38
5 32
6 24
7 12
8 51
9 42
10 1
11 1
12 0
13 0
14 1
15 1
.
.
.
so on....
I want to find out consecutive non-increasing sequences of value (2nd column) order by sr. no (first column) in ascending order.
For example, in the 2nd column, 17 is followed by 0 and 0 and then 38 so it means 3 consecutive values (i.e starting from 17 are 0 and 0) are non-increasing and they are ranked by '1' in my desired in third column as shown below. similarly, the 2nd non-increasing sequence starts with 38,32,24 and 12 and this is ranked as '2' in the third column. same is the case with rank '3' for the third non increasing sequence. so bascially i want the third column with "ranks" starting and ending as per above logic. i tried using LEAD function but doesn't get what I want. I need the shortest possible query to get that third column since i have other columns in the original table in a multiple group by query.
my desired output is:
sr no. value Rank
1 17 1
2 0 1
3 0 1
4 38 2
5 32 2
6 24 2
7 12 2
8 51 3
9 42 3
10 1 3
11 1 3
12 0 3
13 0 3
14 1 4
15 1 4
.
.
.
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Nov 11, 2011
I have table T with 50,000 rows
create table T
(student_id number,
class_id number,
quiz_id number,
marks number)
some sample rows like
INSERT INTO T VALUES (1,1, 1, 50);
INSERT INTO T VALUES (2,2, 2, 40);
INSERT INTO T VALUES (3,1, 3, 34);
INSERT INTO T VALUES (1,1, 4, 10);
INSERT INTO T VALUES (1,1, 5, 30);
INSERT INTO T VALUES (1,1, 6, 29);
INSERT INTO T VALUES (3,2, 7, 34);
INSERT INTO T VALUES (3,2, 8, 33);
INSERT INTO T VALUES (3,2, 9, 56);
INSERT INTO T VALUES (1,1, 7, 90);
INSERT INTO T VALUES (2,2, 8, 0,);
INSERT INTO T VALUES (1,1, 8, 80);
INSERT INTO T VALUES (2,2, 8, 65);
INSERT INTO T VALUES (1,1, 9, 34);
INSERT INTO T VALUES (2,2, 9, 11);
each student belongs to one class_id. each student participates in many quizes. each quiz has its unique id. each student can appear once in a quiz_id
I am doing the below analysis and query:
1. with below query I am finding which student_id had most marks in any 3 successive quizes (see the 3-1 part below) in the query..
SELECT QUIZ_ID,
STUDENT_ID,
SUM (MARKS)
[Code]....
SQL> /
QUIZ_ID STUDENT_ID CONSECMARKS
---------- ---------- -----------
7 1 170
6 1 166
8 1 129
5 1 106
8 3 89
8 2 76
3 3 68
7 3 67
8 2 65
1 1 60
9 3 56
9 1 49
2 2 40
4 1 40
9 2 11
15 rows selected.
With above query, I can play around and find for any 'n' number of consecutive quizes, like marks in 2 consecutives quizes, 3, 4 and so on but for each 'n' value I've to run a seperate query mentioning (2-1) or (3-1) or (4-1) and so on..
since my table is big and there are about 400 quizes so what I want to find out is for each 'n' consecutive quiz (from 1 to 400) which student had most marks for each consecutie 'n' quiz. Like in 1 (consecutive) quiz which student had the highest marks and then 2 conseuctive quiz who had most marks and then in 3 consecutive quiz who had most marks and so on till 400 consecutive quiz who had most marks... rather than running query for each 'n' value seperately i want a single query that can give me a summary of most marks in each n consecutive quizes...
my sample output is:
Nth consecutive quiz student_id sum(marks)
1 1 90
2 1 170
3 1 246
4
.
.
.
100
.
.
200
.
.
300
.
400 ? ?
Is this possible to get the above output from one single query? If there are two or more students with equal most marks for any 'n' conseutive quizes then both should come in the summary.
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Aug 7, 2013
I have a table (tblProject) with the following fields:
Project_ID, Project_Name, Update_Date
I need to look back over the last week to find out which of the projects stored in the above tables haven't been updated on consecutive days day.
For example i would expect to see:
14, Streamline, 01/08/2013
14, Streamline, 02/08/2013
14, Streamline, 03/08/2013
14, Streamline, 04/08/2013
14, Streamline, 05/08/2013
14, Streamline, 06/08/2013
14, Streamline, 07/08/2013
15, Bonus, 01/08/2013
15, Bonus, 03/08/2013
15, Bonus, 04/08/2013
15, Bonus, 05/08/2013
15, Bonus, 07/08/2013
The code should identify that the 'Bonus' project missed updates on 02/08/2013 and 06/08/2013. Should be a simple enough piece of code for an experienced developer i'm sure
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Dec 10, 2011
I have a need to query a real time production database to return a set of results that spans a three day period. When the three days are consecutive it's easy but sometimes there is a 1 or two day gap between the days. For example I'm querying results from a group of people that work between Tuesday and Saturday. On a Wednesday I need t produce a set of results that spans Tuesday of the current week, and Saturday and Friday of the previous week; on Thursday I need to produce a set of results that that spans Wednesday and Tuesday of the current week and Saturday of the previous week.I'm using SQL Developer to execute the code.
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Jul 6, 2012
oracle version 11gr2.
In the below sample data column a,b if there is Two (2) consecutive numbers are transposed in column B from A it should return string 'true'.
with t as
(
select '123456789' a ,'123476581' b from dual
union all
select '123456789' ,'123465789' from dual
union all
[Code]....
i need a output as below.
a b val
123456789 123476581 FALSE
123456789 123465789 TRUE
332211 332121 TRUE
54321 54312 TRUE
78901 79801 TRUE
65432 63452 FALSE
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Aug 16, 2011
How to Check for party names contains standalone four length keywords of consecutive letters(both upper and lower case)
For.e.g. "VMWARE ABCD"
"Jack XWyz jon"
output shoud be: abcd
ABCD,
XWYZ,
like this i want to remove the consecutive characters.
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Oct 22, 2003
How can I select all of the dates between two dates? For example, given the start date 12/2/2003 and the end date 12/5/2003 I want to return:
12/2/2003
12/3/2003
12/4/2003
12/5/2003
Is there a built in function for this? Is there a way for a function to return multiple rows? It has to be a function because I need to use it within other SQL statements.
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Aug 5, 2010
I am newbie to oracle and using oracle 10g as database. I want to get dates between two dates .... let me give an example
suppose a user enters 1-Aug-2010 - 31-Aug-2010 , so i should get all dates in between from date and to date.
something like "select date..or whatever from dual where date between 1-Aug-2010 and 31-Aug-2010 " like this type or other.
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Nov 9, 2010
I want the dates between 2 dates. Suppose i give the dates 01-jan-2010 and 31-jan-2010 and i need the following output.
01-jan-2010
02-jan-2010
03-jan-2010
.
.
.
.
31-jan-2010
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Sep 17, 2008
I got all the month_numbers when i did this
[/b]select distinct t.f_month_number
from time_dim t
where
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)[b]
but when i add
select distinct t.f_month_number,p.start_date,round(replace(p.total_sal,',','')/12,2) as Monthly_sal
from time_dim t, employee p
where
t.f_date = p.start_date and
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)
i got only one month value.
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Jan 23, 2013
I am looking to subtract two columns and get the difference.
select to_char('06-NOV-2012 20:00','DD-MON-YYYY HH24:MI') - to_char(systimestamp,'DD-MON-YY HH24:MI') from dual;
select to_char('06-NOV-2012 20:00','DD-MON-YYYY HH24:MI') - to_char(systimestamp,'DD-MON-YY HH24:MI') from dual
*
ERROR at line 1:
ORA-01722: invalid number
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Mar 14, 2012
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
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Dec 7, 2012
I am looking for a query to find out minimun and maximum rates of an item with corresponding dates. findout a query to get the required result.
Here is sample data
CREATE TABLE scott.item_rate
(
code VARCHAR2(3),
rate NUMBER(10,4),
vdate DATE
);
[Code]..
COD RATE VDATE
--- ---------- ---------
001 108.97 25-MAY-12
001 108.97 07-APR-12
001 105 05-DEC-12
001 105 11-OCT-12
001 91 02-JUL-10
001 1 05-JUL-10
001 1 31-AUG-10
7 rows selected.
The required result is
CODE MIN_RATE MIN_DATE MAX_RATE MAX_DATE
001 1 05-JUL-10 108.97 25-MAY-12
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Jul 13, 2010
I need to aggregate the data based the two dates criteria.
I have two tables
1. Table1
Number Date1 Date2
1 10-Jun-2010 30-Jun-2010
2 10-Feb-2010 30-Feb-2010
----------------------------------
2. Table2
Number Date Revenue
1 11-Jun-2010 100
1 09-Jun-2010 100
1 12-Jun-2010 100
2 11-Feb-2010 100
2 12-Feb-2010 100
2 13-Feb-2010 100
......................
......................
So on
Output:
Number Revenue Date2
1 200 30-Jun-2010
2 300 30-Feb-2010
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