SELECT DISTINCT a.emp_id, a.cal_id, TO_CHAR(a.ts_date, 'DD/MM/YYYY') tsdate, a.ts_date, 1 as days
FROM tmsh_timesheet a
INNER JOIN project b ON TO_CHAR(b.proj_id) = a.proj_id
INNER JOIN tmsh_ts_calendar c ON c.cal_id = a.cal_id
INNER JOIN (SELECT a.cal_id, a.emp_id, MAX(a.status) as status, a.create_dt, a.create_by FROM tmsh_stat_hist a
I've read so many different pages on this topic but I can't seem to get my query the way it needs to be. Here's the query:
select admitnbr, lastname||', '||firstname||' '||finitial, hphone, mobile, wphone, med_rec, dob from patients join schedule using (key_patien) join adtmirro using (key_patien) where appt_state = 'ON HOLD'
Because patients in my database can have multiple appointments "on hold" there are duplicates in the results. I only need 1 record per patient in order to forward this information into an automated dialer to contact that patient. I do NOT want to call the patient over and over again. Once will suffice. I'm trying to make a distinction on the column 'med_rec'. One row per 'med_rec' will be awesome but I can't find a way to create a distinct on that column.
I have a select statement that selects all columns from the join of 3 oracle views. I would like to change it to select only the distinct rows, not sure how to code this. Here is my sql statement:
select * from myschema.view_1 acct Left JOIN myschema.view_2 freq
How can I select all of the dates between two dates? For example, given the start date 12/2/2003 and the end date 12/5/2003 I want to return:
12/2/2003 12/3/2003 12/4/2003 12/5/2003
Is there a built in function for this? Is there a way for a function to return multiple rows? It has to be a function because I need to use it within other SQL statements.
Having production system: 11.2.0.1 on Windows Server x64 Test system: 9.2.0.1 on Windows XP
Problem preface: to get all unique CASEID which should be checked up by biometric system.What i should check - all CASEs for different PERSONs having same PHONEs at least among one phone type (1..4).Real table contains little bit more than 10 million records.I made test scripts.
Below the DDL for test table creation: ------------------------------------------ -- Create CASEINFO test table ------------------------------------------ DROP TABLE CASEINFO; CREATE TABLE CASEINFO
[code]...
Below i've put SQL/DLL to make test data.number of records inserted 2 millions. PERSON_COUNT := #/8; ------------------------------------------ -- fill CASEINFO with sample data ------------------------------------------ DECLARE I INTEGER;
[code]...
Below SQL select to check the data in created table. ------------------------------------------ -- Check test data counters ------------------------------------------ SELECT 'TOTAL',count(*) from CASEINFO UNION ALL SELECT 'LEGAL',count(*) from CASEINFO where
[code]...
The PROBLEM is that i am experiencing HUGE perfomance problems on both test and production systems with that query:
select distinct b.caseid from CASEINFO a, CASEINFO b where (a.person<>b.person) and (a.sex=b.sex) and ( (a.phone1=b.phone1) or (a.phone1=b.phone2) or (a.phone1=b.phone3) or
[code]...
This query takes almost 90 minutes to execute.And i do not know how to avoid this.Full SQL file to make test attached.
I am only able to extract only 4000 characters from the clob column "DESCRIPTION".how to get more characters or max for that column with the same query concept?
I need to write a query in plsql to select records for first 3 distinct values of a single column (below example, ID )and all the rows for next 3 distinct values of the column and so on till the end of count of distinct values of a column.
eg: ID name age 1 abc 10 1 def 20 2 ghi 10 2 jkl 20 2 mno 60 3 pqr 10 4 rst 10 4 tuv 10 5 vwx 10 6 xyz 10 6 hij 10 7 lmn 10 . . . so on... (till some count) Result should be Query 1 should result ---> ID name age 1 abc 10 1 def 20 2 ghi 10 2 jkl 20 2 mno 60 3 pqr 10
query 2 should result --> 4 rst 10 4 tuv 10 5 vwx 10 6 xyz 10 6 hij 10
query 3 should result --> 7 lmn 10 . . 9 .. .. so on..
I have an PL/SQL query which gives the data between the date interval submitted by the user.The problem is that i want all the date irrespective of it has data or not for eg: Let say date parameter is from 1-Jan-2012 to 5-Jan-2012
Now, in the database the available dates are:
1-Jan-2012 2-Jan-2012 5-Jan-2012
So as you can see here that dates 3-Jan-2012 and 4-Jan-2012 is not resulted out by the query. I want all the dates.
I have an athletics participation table that only has the relevant emplid and effective date field. There is no term field on the table. I'm trying to only select those emplid's where the max( effdt) for the emplid is between the begin and end date of the current term. I only want to select current athletes. I would much rather it be for the current academic year but it seems impossible. Why can't I use max(effdt) here?
sql Code
AND h.emplid IN(SELECT b.emplid FROM PS_ATHL_PART_STAT b where max(b.effdt) between (SELECT term_begin_date AND term_end_date from PS_TERM_TBL
In a table I have a column update_date and its type is DATE. Sample values from this column are as follows. I am using the following query to select all update_date lie between sysdate and sysdate-90.
select update_date from table1 where update_date between sysdate and sysdate-90
The above query retrun no data even data is there in the table for this range.
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
Split a date into new dates according to black out dates!
Here is my tables:
CREATE TABLE travel ( start_date, end_date ) AS SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;
[code]....
I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.
Note: Travel Date can be between 0000-01-01 - 9999 12 31
Sample:
Travel Date:
Travel | START DATE | END DATE T | 2011 01 04 | 2011 12 11
Black Out Dates:
BO | START DATE | END DATE A | 2010 11 01 | 2011 02 11 B | 2011 01 20 | 2011 02 15 C | 2011 03 13 | 2011 04 10 D | 2011 03 20 | 2011 06 29
Excepted Result:
New Travel | START DATE | END DATE X1 | 2011 02 16 | 2011 03 12 X2 | 2011 06 30 | 2011 12 11
Visually:
Travel Date : -----[--------------------------]--
A : --[------]------------------------- B : ------[---]------------------------ C : --------------[---]---------------- D : ----------------[------]-----------
Travel Date : -[--------------------------------]--
BO Date A : ----[------]------------------------- BO Date B : -------------------------[---]------- BO Date C : ----------------[---]---------------- BO Date D : ------------------[------]-----------
Result X1 : -[-]------------------------------- Result X2 : -----------[--]-------------------- Result X3 : -----------------------------[--]--
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
I want to do group ranking in desired col3 in such a way that it checks for different values across consecutive rows under col2 and assigns a number to each group. Just when two consecutive rows in col2 have same value then the group ends and the next group starts.
So my desired output is:
Col1 Col2 Col3 1 A 1 2 B 1 3 C 1 4 D 1 5 D 2 6 A 2
[code]...
Here you can see that the first four rows under col2 are unique i.e A,B,C,D so col3 assigns this as group number 1. It ends at row 4 becuase row 5 also has value D under column 2. So in other words, each group must have all unique values and there should not be any repetition. For example, see group 3 (under col3) in above desired output; it starts from row 9 and ends at row 11 because row 12 also has value 'C' and the value 'C' has already occurred in group 3 in row 9.
I want to achieve this SQL. I tried using Dense rank but couldn't go through. I want the shortest possible query to acheive this.
i want to restrict the user if he/she enters any 3 consecutive sequence of numbers,characters,alphanumerics and special characters for example aaa, aAa, @@@, ---- , 111, 123 are not valid.
valid sequences are a1w,?1A,aa1,WW2,78a,-#a
i want to show the invalid sequence in a single query using regular expression function. suppose for example if user enters aaa,$$$,123 then the query output is aaa,$$$,123.
i have written two different queries for that but i want a single query
SELECT REGEXP_SUBSTR('EEE','([a-z])\1\1',1,1,'i') FROM DUAL; SELECT REGEXP_SUBSTR('111','([0-9])\1\1',1,1,'i') FROM DUAL; SELECT REGEXP_SUBSTR('@@@','([^-$])\1\1',1,1,'i') FROM DUAL; -it is not checking for -(hypen) characters
$x being a range of non-consecutive values like so: 1,3,5-9,13,18,21 and so on...
I realize I can query using an array of operands and such, but these ranges will be in upwards of 100 or more items. I want to minimize the number of queries I have to do and the length of them. Is there any resource you can point me to that can optimize something like this?
I want update col1 whis is null to max(col1) ++ in a row, order by cr_date like 1,1,20110102 2,2,20110101 3,null,20110105 => 3,5,20110105 because this row is after 20110103 4,3,20110104 5,null,20110103 => 5,4,20110103 because this row is before 20110105
update test_table set col1 = (select max(col1) from test_table) + rownum where col1 is null;
version : Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
i want to ,remove consecutive occurance from string
Example I/P: 'POWELL POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL' to O/P : 'POWELL BRIAN K AND BONNIE POWELL JARRELL'I tried the below code is Working fine , But i wanted to do this using Regexp or Some other Better Method WITH T
I have a problem with a query. I have a table employee with data as
emp_id date day working_ind 1 01-Jan-2011 Mon Y 1 02-Jan-2011 Tue Y 1 03-Jan-2011 Wed Y 1 04-Jan-2011 Thu Y 1 05-Jan-2011 Fri Y 1 06-Jan-2011 Sat N 1 07-Jan-2011 Sun N 1 09-Jan-2011 Tue Y
Sundays/ Monday/ any public holiday the working_ind will be N. If the emp is absent on one day then there will be no record entered in the table (e.g. 8th jan there is no record). Each table has only one year data.
I need to retrieve for all employees when they worked for 30 consecutive days without being absent which does not include sat/ Sunday / holidays.
Its like: -- i need to order by emp_id and date -- get oly the data with working_ind as Y -- make sure that i get 30 consecutive days (from what ever i get above) where no days data is missing
I tried using lag and inner join but it does not seem to be working.
how to query a list to see if a person had events in consectutive months within the past year. We call a person a LongTermResident if they had a review in any two consectutive months within a reporting period. I wrote a function isResidentLongTerm, passing in FacilityID, ResidentID, ReportPeriodStart, and ReportPeriodStop and returning a 'Y' or 'N'. It works, but the performance is slow.
So if I have a list of reviewers, facilities, reviewees I want to select only those SNF/NF residents who have had routine reviews in any two consectutive months at the same facility.
This is my query:
select ConsultantID, ResidentID from ( select distinct ConsultantID, FacilityID, ResidentID from Reviews where BedType = 17820 -- SNF/NF bed and ReviewType = 17474 -- routine review ) where isResidentLongTerm( FacilityID, ResidentID, :startDate, :stopDate ) = 'Y'
I want to find out consecutive non-increasing sequences of value (2nd column) order by sr. no (first column) in ascending order.
For example, in the 2nd column, 17 is followed by 0 and 0 and then 38 so it means 3 consecutive values (i.e starting from 17 are 0 and 0) are non-increasing and they are ranked by '1' in my desired in third column as shown below. similarly, the 2nd non-increasing sequence starts with 38,32,24 and 12 and this is ranked as '2' in the third column. same is the case with rank '3' for the third non increasing sequence. so bascially i want the third column with "ranks" starting and ending as per above logic. i tried using LEAD function but doesn't get what I want. I need the shortest possible query to get that third column since i have other columns in the original table in a multiple group by query.
create table T (student_id number, class_id number, quiz_id number, marks number)
some sample rows like
INSERT INTO T VALUES (1,1, 1, 50); INSERT INTO T VALUES (2,2, 2, 40); INSERT INTO T VALUES (3,1, 3, 34); INSERT INTO T VALUES (1,1, 4, 10); INSERT INTO T VALUES (1,1, 5, 30); INSERT INTO T VALUES (1,1, 6, 29); INSERT INTO T VALUES (3,2, 7, 34); INSERT INTO T VALUES (3,2, 8, 33); INSERT INTO T VALUES (3,2, 9, 56); INSERT INTO T VALUES (1,1, 7, 90); INSERT INTO T VALUES (2,2, 8, 0,); INSERT INTO T VALUES (1,1, 8, 80); INSERT INTO T VALUES (2,2, 8, 65); INSERT INTO T VALUES (1,1, 9, 34); INSERT INTO T VALUES (2,2, 9, 11);
each student belongs to one class_id. each student participates in many quizes. each quiz has its unique id. each student can appear once in a quiz_id
I am doing the below analysis and query:
1. with below query I am finding which student_id had most marks in any 3 successive quizes (see the 3-1 part below) in the query..
With above query, I can play around and find for any 'n' number of consecutive quizes, like marks in 2 consecutives quizes, 3, 4 and so on but for each 'n' value I've to run a seperate query mentioning (2-1) or (3-1) or (4-1) and so on..
since my table is big and there are about 400 quizes so what I want to find out is for each 'n' consecutive quiz (from 1 to 400) which student had most marks for each consecutie 'n' quiz. Like in 1 (consecutive) quiz which student had the highest marks and then 2 conseuctive quiz who had most marks and then in 3 consecutive quiz who had most marks and so on till 400 consecutive quiz who had most marks... rather than running query for each 'n' value seperately i want a single query that can give me a summary of most marks in each n consecutive quizes...
Is this possible to get the above output from one single query? If there are two or more students with equal most marks for any 'n' conseutive quizes then both should come in the summary.
The code should identify that the 'Bonus' project missed updates on 02/08/2013 and 06/08/2013. Should be a simple enough piece of code for an experienced developer i'm sure
