SQL & PL/SQL :: Split A Date Into New Dates According To Black Out Dates?
Mar 10, 2011
Split a date into new dates according to black out dates!
Here is my tables:
CREATE TABLE travel
(
start_date,
end_date
)
AS
SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;
[code]....
I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.
Note: Travel Date can be between 0000-01-01 - 9999 12 31
Sample:
Travel Date:
Travel | START DATE | END DATE
T | 2011 01 04 | 2011 12 11
Black Out Dates:
BO | START DATE | END DATE
A | 2010 11 01 | 2011 02 11
B | 2011 01 20 | 2011 02 15
C | 2011 03 13 | 2011 04 10
D | 2011 03 20 | 2011 06 29
Excepted Result:
New Travel | START DATE | END DATE
X1 | 2011 02 16 | 2011 03 12
X2 | 2011 06 30 | 2011 12 11
Visually:
Travel Date : -----[--------------------------]--
A : --[------]-------------------------
B : ------[---]------------------------
C : --------------[---]----------------
D : ----------------[------]-----------
Result :
X1 : -----------[--]--------------------
X2 : -----------------------[--------]--
Sample 2:
Travel Date : -[--------------------------------]--
BO Date A : ----[------]-------------------------
BO Date B : -------------------------[---]-------
BO Date C : ----------------[---]----------------
BO Date D : ------------------[------]-----------
Result X1 : -[-]-------------------------------
Result X2 : -----------[--]--------------------
Result X3 : -----------------------------[--]--
How can I do it using PL SQL ?
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Jan 26, 2011
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
1220.01.10
1321.01.10
1423.01.10
1526.01.10
1627.01.10
1729.01.10
1831.01.10
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
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Dec 19, 2012
I need to find the closest Date that matches a Particular Date. The Closest Date from the Group may be less than or greater than the Date I am trying to find.
I have two columns: VISIT_DATE and ACTUAL_DATE. The VISIT_DATE columns has many records with different dates while the ACTUAL_DATE column would only have one record per Student ID.
Here is an example of dates:
Visit Date Actual Date
==========================
01-APR-09 19-MAR-10
16-NOV-09 19-MAR-10
17-MAR-10 19-MAR-10
21-MAR-10 19-MAR-10
04-APR-11 19-MAR-10
15-JUN-11 19-MAR-10
19-SEP-11 19-MAR-10
24-FEB-12 19-MAR-10
The closest date to 19-MAR-10 are in fact 17-MAR-10 and 21-MAR-10. I would in that case need to pick up both records.
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Sep 8, 2012
Is there a way I can generate a list of date using a simple SELECT statement to generate all dates between to date points? For example between SYSDATE AND SYSDATE-7?
One way I know is have a table and run PL/SQL script to put all dates in it and query that but was wondering if it can be achieve via SQL SELECT query at all without creating a table (querying DUAL).
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Sep 11, 2010
In my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
what if i select y? it will override three files
what if i select n? default option
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Jan 26, 2011
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
[Code]...
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
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Feb 16, 2010
Oracle 10g
In a table I have a column update_date and its type is DATE. Sample values from this column are as follows. I am using the following query to select all update_date lie between sysdate and sysdate-90.
select update_date from table1
where update_date between sysdate and sysdate-90
The above query retrun no data even data is there in the table for this range.
Update_date
11-FEB-10
08-FEB-10
08-FEB-10
08-FEB-10
08-FEB-10
[code]...
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Oct 22, 2003
How can I select all of the dates between two dates? For example, given the start date 12/2/2003 and the end date 12/5/2003 I want to return:
12/2/2003
12/3/2003
12/4/2003
12/5/2003
Is there a built in function for this? Is there a way for a function to return multiple rows? It has to be a function because I need to use it within other SQL statements.
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Aug 5, 2010
I am newbie to oracle and using oracle 10g as database. I want to get dates between two dates .... let me give an example
suppose a user enters 1-Aug-2010 - 31-Aug-2010 , so i should get all dates in between from date and to date.
something like "select date..or whatever from dual where date between 1-Aug-2010 and 31-Aug-2010 " like this type or other.
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Nov 9, 2010
I want the dates between 2 dates. Suppose i give the dates 01-jan-2010 and 31-jan-2010 and i need the following output.
01-jan-2010
02-jan-2010
03-jan-2010
.
.
.
.
31-jan-2010
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Sep 17, 2008
I got all the month_numbers when i did this
[/b]select distinct t.f_month_number
from time_dim t
where
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)[b]
but when i add
select distinct t.f_month_number,p.start_date,round(replace(p.total_sal,',','')/12,2) as Monthly_sal
from time_dim t, employee p
where
t.f_date = p.start_date and
f_date between (select start_date from employee where emp_id = 111 ) and
(select add_months(start_Date,12) from employee where emp_id = 111)
i got only one month value.
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Jan 23, 2013
I am looking to subtract two columns and get the difference.
select to_char('06-NOV-2012 20:00','DD-MON-YYYY HH24:MI') - to_char(systimestamp,'DD-MON-YY HH24:MI') from dual;
select to_char('06-NOV-2012 20:00','DD-MON-YYYY HH24:MI') - to_char(systimestamp,'DD-MON-YY HH24:MI') from dual
*
ERROR at line 1:
ORA-01722: invalid number
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Mar 14, 2012
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
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Dec 7, 2012
I am looking for a query to find out minimun and maximum rates of an item with corresponding dates. findout a query to get the required result.
Here is sample data
CREATE TABLE scott.item_rate
(
code VARCHAR2(3),
rate NUMBER(10,4),
vdate DATE
);
[Code]..
COD RATE VDATE
--- ---------- ---------
001 108.97 25-MAY-12
001 108.97 07-APR-12
001 105 05-DEC-12
001 105 11-OCT-12
001 91 02-JUL-10
001 1 05-JUL-10
001 1 31-AUG-10
7 rows selected.
The required result is
CODE MIN_RATE MIN_DATE MAX_RATE MAX_DATE
001 1 05-JUL-10 108.97 25-MAY-12
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Jul 13, 2010
I need to aggregate the data based the two dates criteria.
I have two tables
1. Table1
Number Date1 Date2
1 10-Jun-2010 30-Jun-2010
2 10-Feb-2010 30-Feb-2010
----------------------------------
2. Table2
Number Date Revenue
1 11-Jun-2010 100
1 09-Jun-2010 100
1 12-Jun-2010 100
2 11-Feb-2010 100
2 12-Feb-2010 100
2 13-Feb-2010 100
......................
......................
So on
Output:
Number Revenue Date2
1 200 30-Jun-2010
2 300 30-Feb-2010
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Dec 21, 2011
below is the table and data
create table bday (name varchar2(30),bdate varchar2(10));
insert into bday values('jeffery','0110');
insert into bday values('boss','1231');
insert into bday values('raj','1225');
[Code]...
the BDATE column is in the form "mmdd".
I just want to select the name between 2 dates ( not including years). lets say between sysdate and sysdate+20, i.e
select to_char(sysdate,'dd-mon'),to_char(sysdate+25,'dd-mon') from dual;
TO_CHAR(SYSDATE,'DD-MON') TO_CHAR(SYSDATE+25,'DD-MON')
21-dec 15-jan
but when I run the below query, it is not showing me 'january' data
select name from bday
where to_date(bdate,'mm/dd') between sysdate and sysdate+25;
o/p comes as:
NAME BDATE
boss 1231
raj 1225
but the actual o/p should be:
NAME BDATE
boss 1231
raj 1225
jeffery 0110
it seems to me that because of year change the rows are not displayed.how to handle this in single SQL
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Sep 24, 2012
for the below table
create table RM_TR_INVESTMENT
(
AS_ON_DT DATE not null,
EXP_ID NUMBER(10) not null,
BO_REF_ID VARCHAR2(30),
FO_REF_ID VARCHAR2(30),
BK_PRODUCT_ID VARCHAR2(20),
BK_INV_TYPE_ID VARCHAR2(20),
[code]....
I want to find the sum of NP_AMT_CCY where difference between Start_Dt and Maturity_Dt >= 14 days and <=28 days.How can I build the query for the above statement ?
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Jan 28, 2013
I'm trying to use a PIVOT on the following data set:
ID STATUS_DESC PAY_STATUS PAID_DATE TRANSACTION_TYPE TRANSACTION_DESC DEBIT TOTAL
--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
9876 In Progress 2nd Payment Made 11-DEC-12 19.38.57 Card Payment Payment 2 349 349
9876 In Progress 2nd Payment Made 06-DEC-12 14.33.57 Card Payment Payment 1 100 100
However I'm still getting two rows as per the below. Ideally all data should be on a single row.
ID STATUS_DESC PAY_STATUS PAYMENT_1_DATE PAYMENT_1_AMT PAYMENT_2_DATE PAYMENT_2_AMT TOTAL
--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
9876 In Progress 2nd Payment Made 06-DEC-12 14.33.57 100 100
9876 In Progress 2nd Payment Made 11-DEC-12 19.38.57 349 349
I have constructed my pivot using the following on the outer select:
PIVOT (MAX (insert_timestamp) AS paid_date
,SUM (debit) AS amt
FOR transaction_desc IN ('Payment 1' AS payment_1,
'Payment 2' AS payment_2)) ;
I've used MAX to pivot the date and also tried using NVL on the insert_timestamp but still no luck.
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Jun 25, 2012
I'm trying to run a report that has a moving date and I need to find data that's within 12 months of that certain date.
So for example... customers come in everyday all year long. I wanted to find the number of unique customers in a year. But the year is moving... So 1 year from 1/15/2011 is 1/14/2012. And 1 year from 1/16/2011 is 1/15/12. So I had something like this but doesn't quite work..
SELECT ...
NVL(COUNT(DISTINCT CASE WHEN TX.DATE_OF_FIRST_VISIT BETWEEN TO_DATE(TX.DATE_OF_FIRST_VISIT,'MM-YYYY') AND ADD_MONTHS(TO_DATE(TX.DATE_OF_FIRST_VISIT,'MM-YYYY'),12) THEN (TX.CLINIC_ID||TX.PATIENT_UNIQUE_ID)END),0) AS "YEAR_1"
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Mar 10, 2012
My homework requires me to create a booking table for a hotel and I have created the table but I'm having trouble inserting the dates.
This is my table:
DROP TABLE BookingDM CASCADE CONSTRAINTS PURGE;
CREATE TABLE BookingDM (
hNo NUMBER(3),
gNo NUMBER(5),
dFrom DATE NOT NULL,
[code]......
This is the first set I'm attempting to insert
hNo = 148
gNo = 11169
dFrom = 09/03/2009
dTo = 09/10/2009
rNo = 202
This is my attempt to insert the set:
SQL> INSERT INTO BookingDM VALUES('148', '11169', '09/03/2009', '09/10/2009', '202');
INSERT INTO BookingDM VALUES('148', '11169', '09/03/2009', '09/10/2009', '202')
*
ERROR at line 1:
ORA-01843: not a valid month
I need my dates to be in the format "MM/DD/YYYY".
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Mar 9, 2013
ii have written a query like thi:
select to_char(order_date,'mon-yyyy') "months", sum(nob) "number of bags"
from p_in where order_date between '1-apr-11 and '31-mar-12'
group by to_char(order_date,'mon-yyyy')
the above query returns me a resultset which gives me number of bags sold in every month, but it does not sort the month in their chronological order. i want to sort my resultset in ascending order of month s.,means jan-feb-march-apr-may ams so on...QUOTE
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Jan 14, 2008
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
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Apr 26, 2012
I need to store a date that will always be x years before the current date. Is doing something like
select sysdate -x from dual
Going to result in any weird issues down the road? Also, because I haven't explicitly specified the date, when queried, will the value always be sysdate - x (What I want to happen) as opposed to dateRowWasCreated - x?
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Sep 21, 2004
I am wondering how can I select data between two dates (ie from 08/12/2004 to today?)
Name DateS
Bob 08/11/2004
Tom 08/12/2004
Bill 09/21/2004 <-- today
return
Tom 08/12/2004
Bill 09/21/2004
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Jun 25, 2011
i have two dates like
30-may-2011 11:50:34 and 27-may-2011 13:59:37
how i can calculate proper hrs between these dates? My condition is time calculate from 8.30AM to 5.30PM
it does not considered 24 hrs
if i calculate hrs
30-may-2011 11:50:34 - 27-may-2011 13:59:37
then it shows 69.85 hrs . but it considered full 24 hrs.
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Jul 6, 2010
I want to substract two dates to get the age of a person. One of the date is sysdate and the other is date of birth. Assuming we remove the time part of the date.
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Oct 8, 2012
How to print data between two dates... startdate and enddate inclusive
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Apr 3, 2012
I have the following table with some sample data. I just need to transform (unknown no of) rows into (unknown no of) columns. like a matrix report.
Test case
---create table
create table attendance
(
REG_NO NUMBER(7),
COURSE_SEQ_NO NUMBER(4),
SECTION VARCHAR2(1),
SEMESTER_CODE NUMBER(1),
[code]....
--insert data
Insert into attendance (REG_NO,COURSE_SEQ_NO,SECTION,SEMESTER_CODE,SEMESTER_YEAR,ATT_DATE,ATT_FLAG) values
(2014035,149,'A',1,2012,to_timestamp('12-MAR-12','DD-MON-RR HH.MI.SSXFF AM'),0);
Insert into attendance (REG_NO,COURSE_SEQ_NO,SECTION,SEMESTER_CODE,SEMESTER_YEAR,ATT_DATE,ATT_FLAG) values
(2014048,149,'A',1,2012,to_timestamp('12-MAR-12','DD-MON-RR HH.MI.SSXFF AM'),1);
Insert into attendance (REG_NO,COURSE_SEQ_NO,SECTION,SEMESTER_CODE,SEMESTER_YEAR,ATT_DATE,ATT_FLAG) values
[code]....
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Aug 15, 2012
I have a table with 4 records with start_date and end_date fields
start_date end_date
1/1/2003 1/4/2005
1/1/2004 5/3/2006
1/1/2007 1/4/2008
1/1/2008 6/3/2009
as you see records 1,2 and records 3,4 have overlapping dates. I need to combine them to get continuous intervals. The result should be:
start_date end_date
1/1/2003 5/3/2006
1/1/2007 6/3/2009
Is it possible to do by SQL query?
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Jul 31, 2013
I have a table with emploees hire dates.get the query that gives me a list of people with their anniversary dates falling between two specific dates like 12/12/2013 and 01/13/2014?
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