SQL & PL/SQL :: Days Between Dates
Mar 14, 2012
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
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Jan 26, 2011
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
1220.01.10
1321.01.10
1423.01.10
1526.01.10
1627.01.10
1729.01.10
1831.01.10
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
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Jan 14, 2008
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
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Apr 28, 2010
I have a table with starting date and ending date.
I want to fetch monthwise days for given two dates
IE starting 25/12/2009 ending 25/03/2010
Result should like below.
Dec-09 7
Jan-10 31
Feb-10 28
Mar-10 25
I have tried this but it is not giving me the result which want..
select to_char(thedate,'mon-yy') mnth,count(to_char(thedate,'mon-yy')) days from
(SELECT TRUNC(to_date('25/12/2009','dd/mm/yyyy'),'Y')+ROWNUM-1 THEDATE
FROM ( SELECT 1 just_a_column
FROM dual
CONNECT BY LEVEL <= 366
[code].....
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Nov 13, 2011
I want function return me how many days Thursday and Friday between two dates.
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Apr 18, 2013
i want to create function to show number of days between to days such as number of Friday days between to dates
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Sep 5, 2012
Is there an Oracle date function that ignores public bank holidays and calculates working days only?
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Sep 11, 2010
In my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
what if i select y? it will override three files
what if i select n? default option
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Jan 26, 2011
I want to find the dates which have a date plus with in 2 days after this date. I mean group by 3 days each even the date i missing between two days. Actualy I want to find the start date where the employ was missing on job.
Basic concept is employes have allowed to use 10 personal leaves of a year. Each leave can be use for maximum 3 days.
If employ did not come on the job for one day or two days or three days, it shoul be count as ONE personal leave. And If employ is missing at job for four or five days, it should be count as 2 personal leaves.
seq date
------------------------------
101.01.10
205.01.10
306.01.10
410.01.10
512.01.10
613.01.10
714.01.10
815.01.10
916.01.10
1018.01.10
1119.01.10
[Code]...
The result should be (Don't use Pl/Sql)
seq date
------------------------------
101.01.10
205.01.10
310.01.10
413.01.10
516.01.10
619.01.10
723.01.10
826.01.10
929.01.10
After finding these days I want to select the starting date of 5th personal leave. (which is 16.01.10).
I am not a expert of using SQL, but I think it could be possible with using partitioning a table on the givin reslult and further partition the reslut on rownum() as rn and the using case statement where rn = 5.
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Sep 25, 2012
how to caluclate days between two dates of single timestamp filed and with this
query
Select * from m_activity_transaction where actn_opp_id in (
Select actn_opp_id from m_activity_transaction where ACTN_ACTV_ID = 218
Group by actn_opp_id
[code]...
and i nedd to caluclate no.of days between two dates like 27-JAN-12 11.06.20.000000 AM and 08-FEB-12 05.32.54.000000 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
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Mar 17, 2011
I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.
The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:
select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL))
from dwt_dvt_work_time where dwt_create_date > sysdate - 30
and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id
Here's the function:
CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE)
RETURN NUMBER
IS total_days NUMBER(11,2);
holiday_days NUMBER(11,2);
[code]....
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May 22, 2010
The data in one of the temporary table has been compiled as below. Number of Days elapsed between two transaction dates is required to be computed and multiplied with the balance. There can be multiple number of same transaction dates. When previous date and the current transaction dates are same the resulting number of day difference should be 0. But when they are different the difference between them is to be computed. On the last day of the Financial Year i.e. '31/03' of any year the difference day should be shown as 1 so as to make 365 or 366 days in a year. Simply deducting d1 from d2 on 31st will not be suffice as the difference is one day less.
----------------------------------------------------------------------------------------- -------
Transaction Narration DebitCreditBalanceNo of DaysProduct
DateDifference
----------------------------------------------------------------------------------------- --------
01/04/2009Opening Balance 45020450277346654
17/06/2009ByAmt5044521253424
29/06/2009By Amt1004352156678912
02/12/2009By Amt424310119476000
[code]....
improve the above code and get the desired output result.
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Feb 17, 2010
I want Oracle stored function/procedure to calculate number of working days between two dates. We need to exclude Firdays and Saturdays as there are weekend holidays and also exclude official holidasy that lie between two dates.
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Sep 2, 2011
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
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Apr 5, 2011
want to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
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Mar 10, 2011
Split a date into new dates according to black out dates!
Here is my tables:
CREATE TABLE travel
(
start_date,
end_date
)
AS
SELECT DATE '0000-01-01', DATE '9999-12-31' FROM DUAL;
[code]....
I have lets say a "travel date" and black out dates. I will split the travel date into pieces according to the black out dates.
Note: Travel Date can be between 0000-01-01 - 9999 12 31
Sample:
Travel Date:
Travel | START DATE | END DATE
T | 2011 01 04 | 2011 12 11
Black Out Dates:
BO | START DATE | END DATE
A | 2010 11 01 | 2011 02 11
B | 2011 01 20 | 2011 02 15
C | 2011 03 13 | 2011 04 10
D | 2011 03 20 | 2011 06 29
Excepted Result:
New Travel | START DATE | END DATE
X1 | 2011 02 16 | 2011 03 12
X2 | 2011 06 30 | 2011 12 11
Visually:
Travel Date : -----[--------------------------]--
A : --[------]-------------------------
B : ------[---]------------------------
C : --------------[---]----------------
D : ----------------[------]-----------
Result :
X1 : -----------[--]--------------------
X2 : -----------------------[--------]--
Sample 2:
Travel Date : -[--------------------------------]--
BO Date A : ----[------]-------------------------
BO Date B : -------------------------[---]-------
BO Date C : ----------------[---]----------------
BO Date D : ------------------[------]-----------
Result X1 : -[-]-------------------------------
Result X2 : -----------[--]--------------------
Result X3 : -----------------------------[--]--
How can I do it using PL SQL ?
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Oct 22, 2003
How can I select all of the dates between two dates? For example, given the start date 12/2/2003 and the end date 12/5/2003 I want to return:
12/2/2003
12/3/2003
12/4/2003
12/5/2003
Is there a built in function for this? Is there a way for a function to return multiple rows? It has to be a function because I need to use it within other SQL statements.
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Oct 18, 2010
I need to know if a customer appears at least 4 consecutive days. Here's an example of data
CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
123 , 2010/10/10
456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
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Aug 2, 2012
My Table structure is
SL# Start_ts
1 7/31/2012 3:53:42.864070 AM
2 7/26/2012 2:13:58.280928 PM
3 7/25/2012 2:13:41.692569 PM
4 7/21/2012 2:13:26.821070 PM
5 7/18/2012 2:13:07.827278 PM
6 7/13/2012 2:05:35.023520 PM
Question
How to select last 10 days rows only (from sysdate)
Error
1) SQL> select * from Test where to_date(start_ts, 'DD-MON-YYYY HH24:MI:SS') > to_date(sysdate, 'DD-MON-YYYY HH24:MI:SS')-10 ; (or)
2) SQL> select * from Test where to_date(start_ts, 'MM/DD/YYYY HH24:MI:SS') > to_date(sysdate, 'MM/DD/YYYY HH24:MI:SS')-10 ;
ORA-01858: a non-numeric character was found where a numeric was expected
[Code]...
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May 11, 2012
Our "client" is delivering data that contains an "age" field. However, they've put the AGE in DAYS instead of years, while our system can only work with years. So I needed to convert the age to years.
We are getting 2 parameters: LOWAGE and HIGHAGE (both in days). However, for the same "test" (laboratory test), we are also getting some other records
eg:
TEST 1 lowage = 0 upperage = 5 OTHER values = xxx
TEST 1 lowage = 6 upperage = 100 OTHER values = yyy
So if the person would be 5 years or less, the values xxx would apply. If they are 6 years and older, the yyy values apply. Now, the problem is that we are not getting this data in years, but in days. And whichever function I try, the upperage from the first test also seems to be equal to the lowerage from the second test. And this gives an error, because both would apply to this person....
I've tried stuff like:
age/365
age/365.25 (leap years)
trunc(months_between(sysdate+ranges.lowerage,sysdate)/12)
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Jun 8, 2010
i have an employee table where there is a column called join date. Now i have to select the employee according to the days. Means how many employee joined on Monday/Tuesday etc.
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Nov 21, 2011
I have the following in my select statement and I am getting the days like 1130, 50, 60 etc
round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS
Now I want this to convert these days into months like
1.10 this denotes (one month 10 days)
1.25 this denotes (one month 25 days)
2.05 this denotes (two months 5 days)
I know I am using old Oracle but what to do my company is not spending to upgrade.
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Nov 2, 2010
i want create a report like this
location sysdate refdate No_of_days SL1(0-90) SL2(91-180) SL3(>180)
So when no. of days between (0-90) data put in SL1
And when no. of days between (91-180) data put in sl2
I want to achieve this only in single query.
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Oct 9, 2013
I want to find the months and days between 2 dates. For Eg. Date-1 : 25-Aug-2013Date-2 : 23-Oct-2013 If we consider every month as 30 days it should give 25-Aug-2013 to 30-Aug-2013 = 6 days 01-Sep-2013 to 30-Sep-2013 = 1 Month 23-Oct-2013 to 30-Oct-2013 = 8 days Total = 1 month and 14 days
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Jan 8, 2013
I would the query to do the following:
1. Make the jobname distinct, because it keeps giving me multiple entries for each jobname
2. Add the the start_time of SOD_start_data9_UAT1 to end_time fodba_MUAT1 to get the combined duration
3. CONCAT jobnames SOD_start_data9_UAT1 and end_time fodba_MUAT1
4. Generate the last seven days batch run times
5. Generate a report into .csv format and email out
6. I have access to sqlplus and plsql developer
select distinct JOBNAME, schedtab
, to_char(to_timestamp(trim(timestmp)
, 'YYYYMMDDHH24MISS') - numtodsinterval(elaptime / 100
, 'SECOND'), 'YYYY-MM-DD HH24:MI:SS') as start_time
[code]...
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Aug 5, 2010
I want to pull out the output only when Day is 1 and 2 and 3. I don't want if either Day is 1 or Day is 2 or Day is 3 is present.
Test Case
--Creat Table
create table dummy_name
(name varchar2(5) not null,
day number(3) not null);
--Insert Values
insert into dummy_name values ('A', 1);
insert into dummy_name values ('B', 2);
insert into dummy_name values ('C', 3);
insert into dummy_name values ('B', 1);
insert into dummy_name values ('B', 2);
insert into dummy_name values ('C', 1);
[code]...
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Jul 7, 2012
Tables
--------
ROWID START_DATEEND_DATE
101/26/2012 00:00:0001/31/2012 00:00:00
201/26/2012 00:00:0002/02/2012 00:00:00
302/03/2012 00:00:0003/31/2012 00:00:00
How to find out the days difference in sql query, start date of next records and end date of previous records as highlighted on blue color
query out put should give as below
start_date + next record ,end_date - Previous records should give the difference of
6
1
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Jan 18, 2012
I have a table like this below one.
CCCID MCODECNODDEADLINEDATEDDEADLINETIME
IN00100213201201219/01/20121050
IN00100213201201118/01/20121050
IN00100213201201320/01/20121050
IN00100213111219821/01/20121050
I need a query which will fetch only 3 rows for a day. For eg if today is 18-jan-2012, then i have to show rows whose deadline date is 18-jan-2011, 19-jan-2011 and 20-jan-2011. And on 18-Jan-2011, after 10.50 a.m it should not consider deadline date 18-jan-2011, instead it show deadline date is 21-jan-2011.
This deadlinedate will not have all dates, only exchange working dates, so at one time we should show only the probable 3 deadline dates..
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Dec 29, 2012
i need to find the number of days employee was absent for the month, we are maintaining a table of attendance , where the daily data of hours is captured, what i need now is to capture total number of days he was absent or not present.How can i get the sum of absent days per employee based on given month, as the difficulty is i have to consider 30 days as standard working days for the month , regardless of months having either 30 days (April,June,September,November),or 31(January,March,May,July,August,December) or 28(Consider leap year also february) days.For eg ,If he is absent for 31 days in december then it should consider only 30 days as absent or if he is absent for 28 days in february still it should consider 30 Days as absent.
create table ot_job_det (jt_txn varchar2(12),jt_no number,jt_dt date ,jt_emp_code varchar2(6),jt_duration number )
delete from ot_job_det
[Code].....
I managed to do this with the given query , but this will check only for 31 days and 30 how to consider the february month or any leap year.
SELECT JT_EMP_CODE,DECODE(SIGN(30-COUNT(JT_DT)),-1,30,30-COUNT(JT_DT)) a FROM
OT_JOB_DET WHERE
TO_CHAR(JT_DT,'YYYYMM')='201212'
GROUP BY JT_EMP_CODE;
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Oct 21, 2010
I intend to get for every client the start date and end of a contiguous range of days. Example for the same client have two records, in the first goes from day 1 to day 5 and the second from day 3 to day 9, i intend to get a record for this client where indicated that the start date is on day 1 and ending on Day 9.
SELECT 123 as CLI_ID, TO_DATE('20100101', 'YYYYMMDD') as DT_START, TO_DATE('20100105', 'YYYYMMDD') as DT_END FROM DUAL UNION
SELECT 123 as CLI_ID, TO_DATE('20100208', 'YYYYMMDD') as DT_START, TO_DATE('20100321', 'YYYYMMDD') as DT_END FROM DUAL UNION
SELECT 123 as CLI_ID, TO_DATE('20100219', 'YYYYMMDD') as DT_START, TO_DATE('20100228', 'YYYYMMDD') as DT_END FROM DUAL UNION
SELECT 123 as CLI_ID, TO_DATE('20100227', 'YYYYMMDD') as DT_START, TO_DATE('20100405', 'YYYYMMDD') as DT_END FROM DUAL UNION
SELECT 123 as CLI_ID, TO_DATE('20100901', 'YYYYMMDD') as DT_START, TO_DATE('20101013', 'YYYYMMDD') as DT_END FROM DUAL
Expected :
CLI_ID,DT_START,DT_END
123,01/01/2010,05/01/2010
123,08/02/2010,05/04/2010
123,01/09/2010,13/10/2010
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