PL/SQL :: Two Consecutive Number Transformed Return True Or False

Jul 6, 2012

oracle version 11gr2.

In the below sample data column a,b if there is Two (2) consecutive numbers are transposed in column B from A it should return string 'true'.

with t as
(
select '123456789' a ,'123476581' b from dual
union all
select '123456789' ,'123465789' from dual
union all

[Code]....

i need a output as below.

a b val

123456789 123476581 FALSE
123456789 123465789 TRUE
332211 332121 TRUE
54321 54312 TRUE
78901 79801 TRUE
65432 63452 FALSE

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On the menu properties, I have done:
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functional -> visible in Menu: No
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On the form where this menu is attached, I have written trigger new form instance:

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create table test_table(
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[code]...

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update test_table
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this gives ora-00933

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PL/SQL :: Two Consecutive  Numbers Are Transposed Function Returns True

Jul 6, 2012

oracle version 11gr2.In the below sample data column a,b if there is Two (2) consecutive numbers are transposed in column B from A it should return string 'true'.

with t as
(
select '123456789' a ,'123476581' b from dual
union all
select '123456789' ,'123465789' from dual
union all
select '332211' ,'332121' from dual
union all
[code]....

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Sep 8, 2011

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Oct 18, 2010

I need to know if a customer appears at least 4 consecutive days. Here's an example of data

CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
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456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11

In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.

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May 11, 2012

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select * from transactions;

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84812
84813
84814
84816
84821
84823
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Aug 23, 2012

I have a table T with columns

Col1 Col2
1 A
2 B
3 C
4 D

[code]..

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So my desired output is:

Col1 Col2 Col3
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2 B 1
3 C 1
4 D 1
5 D 2
6 A 2

[code]...

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Feb 23, 2010

I am pulling information from a view to get the current results and placing them into a cursor which then inserts the results into a temp table.

Current Results:
JOB_NAMESCHEDULED_TIME STATUS
JOB_1 02/23/2010 13:25:00Failed
JOB_1 02/22/2010 13:25:00Failed
JOB_1 02/21/2010 13:25:00Failed
JOB_1 02/19/2010 13:25:00Failed
JOB_2 02/21/2010 13:25:00Failed
JOB_2 02/18/2010 13:25:00Failed
JOB_2 02/17/2010 13:25:00Error
JOB_2 02/15/2010 13:25:00Error

Needed Results:
JOB_NAMESCHEDULED_TIME STATUS
JOB_1 02/23/2010 13:25:00Failed
JOB_1 02/22/2010 13:25:00Failed
JOB_1 02/21/2010 13:25:00Failed
JOB_2 02/18/2010 13:25:00Failed
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Nov 14, 2010

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any 3 consecutive characters from key board.

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Mar 23, 2010

SELECT DISTINCT a.emp_id, a.cal_id, TO_CHAR(a.ts_date, 'DD/MM/YYYY') tsdate, a.ts_date, 1 as days
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INNER JOIN project b ON TO_CHAR(b.proj_id) = a.proj_id
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[Code]...

this query results

EMP_IDCAL_IDTSDATE

048283404/10/2010
048283502/11/2010
048283503/11/2010
048283504/11/2010
048283508/11/2010

i need the ts date to be in like this

04/10/2010
02/11/2010 - 04/11/2010
08/11/2010

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Jun 4, 2013

version : Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production

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WITH T

[Code]....

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Oct 23, 2011

provide SQL query (not PL/SQL block) for the following. I have data in table as shown below

Serial No value
========= ========
123
2-99
3-99
4-99
534
656
77
88
990
1065
1167
12-99
13-99
14-99
15-99
16-99
17-99
182
1945
206

The output of the SQL will be the largest consecutive series of the value -99 is 6 and total count of the value -99 is 9

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Jul 15, 2011

I have a problem with a query. I have a table employee with data as

emp_id date day working_ind
1 01-Jan-2011 Mon Y
1 02-Jan-2011 Tue Y
1 03-Jan-2011 Wed Y
1 04-Jan-2011 Thu Y
1 05-Jan-2011 Fri Y
1 06-Jan-2011 Sat N
1 07-Jan-2011 Sun N
1 09-Jan-2011 Tue Y

Sundays/ Monday/ any public holiday the working_ind will be N. If the emp is absent on one day then there will be no record entered in the table (e.g. 8th jan there is no record). Each table has only one year data.

I need to retrieve for all employees when they worked for 30 consecutive days without being absent which does not include sat/ Sunday / holidays.

Its like:
-- i need to order by emp_id and date
-- get oly the data with working_ind as Y
-- make sure that i get 30 consecutive days (from what ever i get above) where no days data is missing

I tried using lag and inner join but it does not seem to be working.

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Apr 7, 2011

how to query a list to see if a person had events in consectutive months within the past year. We call a person a LongTermResident if they had a review in any two consectutive months within a reporting period. I wrote a function isResidentLongTerm, passing in FacilityID, ResidentID, ReportPeriodStart, and ReportPeriodStop and returning a 'Y' or 'N'. It works, but the performance is slow.

So if I have a list of reviewers, facilities, reviewees I want to select only those SNF/NF residents who have had routine reviews in any two consectutive months at the same facility.

This is my query:

select ConsultantID, ResidentID
from (
select distinct ConsultantID, FacilityID, ResidentID
from Reviews
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and ReviewType = 17474 -- routine review
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Apr 14, 2012

I have a table with numbers like this in a column

sr no. value
1 17
2 0
3 0
4 38
5 32
6 24
7 12
8 51
9 42
10 1
11 1
12 0
13 0
14 1
15 1
.
.
.
so on....

I want to find out consecutive non-increasing sequences of value (2nd column) order by sr. no (first column) in ascending order.

For example, in the 2nd column, 17 is followed by 0 and 0 and then 38 so it means 3 consecutive values (i.e starting from 17 are 0 and 0) are non-increasing and they are ranked by '1' in my desired in third column as shown below. similarly, the 2nd non-increasing sequence starts with 38,32,24 and 12 and this is ranked as '2' in the third column. same is the case with rank '3' for the third non increasing sequence. so bascially i want the third column with "ranks" starting and ending as per above logic. i tried using LEAD function but doesn't get what I want. I need the shortest possible query to get that third column since i have other columns in the original table in a multiple group by query.

my desired output is:

sr no. value Rank
1 17 1
2 0 1
3 0 1
4 38 2
5 32 2
6 24 2
7 12 2
8 51 3
9 42 3
10 1 3
11 1 3
12 0 3
13 0 3
14 1 4
15 1 4
.
.
.

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Nov 11, 2011

I have table T with 50,000 rows

create table T
(student_id number,
class_id number,
quiz_id number,
marks number)

some sample rows like

INSERT INTO T VALUES (1,1, 1, 50);
INSERT INTO T VALUES (2,2, 2, 40);
INSERT INTO T VALUES (3,1, 3, 34);
INSERT INTO T VALUES (1,1, 4, 10);
INSERT INTO T VALUES (1,1, 5, 30);
INSERT INTO T VALUES (1,1, 6, ‘29);
INSERT INTO T VALUES (3,2, 7, 34);
INSERT INTO T VALUES (3,2, 8, 33);
INSERT INTO T VALUES (3,2, 9, 56);
INSERT INTO T VALUES (1,1, 7, 90);
INSERT INTO T VALUES (2,2, 8, 0,);
INSERT INTO T VALUES (1,1, 8, 80);
INSERT INTO T VALUES (2,2, 8, 65);
INSERT INTO T VALUES (1,1, 9, ‘34);
INSERT INTO T VALUES (2,2, 9, 11);

each student belongs to one class_id. each student participates in many quizes. each quiz has its unique id. each student can appear once in a quiz_id

I am doing the below analysis and query:

1. with below query I am finding which student_id had most marks in any 3 successive quizes (see the 3-1 part below) in the query..

SELECT QUIZ_ID,
STUDENT_ID,
SUM (MARKS)

[Code]....

SQL> /

QUIZ_ID STUDENT_ID CONSECMARKS
---------- ---------- -----------
7 1 170
6 1 166
8 1 129
5 1 106
8 3 89
8 2 76
3 3 68
7 3 67
8 2 65
1 1 60
9 3 56
9 1 49
2 2 40
4 1 40
9 2 11

15 rows selected.

With above query, I can play around and find for any 'n' number of consecutive quizes, like marks in 2 consecutives quizes, 3, 4 and so on but for each 'n' value I've to run a seperate query mentioning (2-1) or (3-1) or (4-1) and so on..

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my sample output is:

Nth consecutive quiz student_id sum(marks)
1 1 90
2 1 170
3 1 246
4
.
.
.
100
.
.
200
.
.
300
.
400 ? ?

Is this possible to get the above output from one single query? If there are two or more students with equal most marks for any 'n' conseutive quizes then both should come in the summary.

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Aug 7, 2013

I have a table (tblProject) with the following fields:

Project_ID, Project_Name, Update_Date

I need to look back over the last week to find out which of the projects stored in the above tables haven't been updated on consecutive days day.

For example i would expect to see:

14, Streamline, 01/08/2013
14, Streamline, 02/08/2013
14, Streamline, 03/08/2013
14, Streamline, 04/08/2013
14, Streamline, 05/08/2013
14, Streamline, 06/08/2013
14, Streamline, 07/08/2013
15, Bonus, 01/08/2013
15, Bonus, 03/08/2013
15, Bonus, 04/08/2013
15, Bonus, 05/08/2013
15, Bonus, 07/08/2013

The code should identify that the 'Bonus' project missed updates on 02/08/2013 and 06/08/2013. Should be a simple enough piece of code for an experienced developer i'm sure

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Aug 16, 2011

How to Check for party names contains standalone four length keywords of consecutive letters(both upper and lower case)

For.e.g. "VMWARE ABCD"

"Jack XWyz jon"

output shoud be: abcd
ABCD,
XWYZ,

like this i want to remove the consecutive characters.

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