I am working in development environment which has only 150 gb db size but suddenly it is raised to 250gb within 10 days i want to see which user did what in my database.How we can see what task made what in past 10 days.
View 3 RepliesI have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
View 7 Replies View RelatedI just want to know the user login / log out information for the past 31days. how can i get that?
View 11 Replies View RelatedI killed some 70 sessions which where inactive couple of days ago using alter system kill session(sid,serial#) immediate;
But even after killing them it still exists in the v$session view when I query select sid,serial# from v$session where username is not null; It has the same sid and serial#....I tried killing them every now and then but it still shows those exists
My problem is only on Some Saturday's my Oracle server's Load average goes high (more than 300 ).
-- oracle version 11.2.0.1.0
-- runs on Sun solaris 10
-- Sun fire V 440
-- Sun storEdge 3315 connected to the server.
Same setup is working find with higher volumes without any problem but only on saturday's, that too not on all saturdays, some specific saturdays the load average goes high.
At the time nothing will be processed from the application side and the cpu utilisation goes high upto 95 %.
I am sending necessary information as follows.
vmstat 6 10
kthr memory page disk faults cpu
r b w swap free re mf pi po fr de sr s0 s1 s3 s4 in sy cs us sy id
3 0 0 28660024 6513408 285 212 2044 2 2 0 0 0 17 0 42 830 3469 1380 22 5 74
125 0 0 29027480 6156256 2 6 34 0 0 0 0 0 5 0 10 791 53770 30278 83 17 0
125 0 0 29027680 6157496 29 140 21 1 1 0 0 0 5 0 9 786 52756 30309 83 17 0
116 0 0 29031600 6159896 24 125 0 0 0 0 0 7 3 0 5 819 54081 31069 83 17 0
[code]....
Is there any way I could find the number of inserts happened every day to a particular table.
View 10 Replies View Relatedwant to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
Past 13 MonthEnds from a input date
(i.e.: 6/13/2010 is supplied, then query should be able to retrieve 5/31/2010, 4/30/2010, 3/31/2010, 2/26/2010, 1/29/2010, 12/31/2009?.....5/29/2009)
If the month end date falls on a weekend (Sat or Sun), then it should have the prior Friday's date.
I want to get a past 13 weekdays (Exclude weekends) from the supplied date
Like if 20100613 is the supplied date, then it should give me following dates
DatesSr No
11-Jun1
10-Jun2
9-Jun3
8-Jun4
7-Jun5
4-Jun6
3-Jun7
2-Jun8
1-Jun9
31-May10
28-May11
27-May12
26-May13
I am trying following way but giving me same date 11 june
SELECT
dt from
(
select
CASE when to_char(To_Date(To_Char('20100613'),'YYYYMMDD'),'fmDy') in ('Sat','Sun')
then next_day(To_Date(To_Char('20100613'),'YYYYMMDD')-7,'Friday')
else To_Date(To_Char('20100613'),'YYYYMMDD')end as dt
[Code]...
i have an application for a medical laboratory, i insert patients every day , what i want is toget the number of patients for the past month ?2- for the past week ?3- the past day , and so on.
View 11 Replies View RelatedI need to get the past 12 months from the current month
for example
input:
march2010
output:
apr2009
may2009
june2009
july2009
augest2009
september2009
october2009
november2009
december2009
january2010
february2010
I have two table APPLICATION_1 and APPLICATION_2, where user's login date is captured.There will be multiple records for each user.Same user may or may not be present in both tables.
The requirement is to find those users who have not logged-in in the last 3 years.
-- Test Case
DROP TABLE application_1;
DROP TABLE application_2;
CREATE TABLE application_1
(
seq NUMBER ,
user_id VARCHAR2(30),
[code].....
Using the below query I'm able to get the desired output.
SELECT user_id, MAX(login_date) last_login_date FROM (
SELECT user_id, MAX(login_date) login_date FROM application_1 GROUP BY user_id
UNION ALL
SELECT user_id, MAX(login_date) login_date FROM application_2 GROUP BY user_id
) GROUP BY user_id
[code].....
I have an requirement to load past and future data from different source table to one tgt table.Say now we are in July
Past Data
Apr May Jun
Future Data
Aug Sep Oct
I HAVE actual sales for past month and present month which is in Table A & expected sales in table B.for every month i have to load 7 months data TARGRT TABLE..
In future the requirement may change to 6 months also. in that case the procedure has to load past 6 month + current month + 6month future so totally 13 month should be loaded.
How can I find out the particular oracle session which was consuming high memory in the past?
I can't get the data in v$sessstat
Unable to get the information in AWR
dba_hist_active_session_history do not have field which indicate memory related information
Shall I concetrate on EVENT in dba_hist_active_session_history which continuosly had sort, direct path read
Or
Locate sql_id from dba_hist_sqlstat with high SORTS_DELTA for snapshots belonging to problematic time period and then using the sql_id query dba_hist_active_session_history
which approach I shall take to find out the session which consumed most memory in the past?
resolve issue while modified the user function code for returns the values as timestamps
---function code
create or replace
function fun_test_timestamp(P_HOUR varchar2) return varchar2
is
sql_stmt varchar2(1000);
begin
[Code].....
Input:-
select fun_test_timestamp('5') from dual;
Output:-
SELECT CURRENT_TIMESTAMP - INTERVAL '5' HOUR FROM DUAL;
Modified Fun Code:
create or replace
function fun_test_timestamp(P_HOUR varchar2) return timestamp
is
sql_stmt varchar2(1000);
[Code]...
Input:-
select fun_test_timestamp('5') from dual;
Output:-
ORA-00911: invalid character
ORA-06512: at "NETVERTEXTRUNK.FUN_TEST_TIMESTAMP", line 8
00911. 00000 - "invalid character"
*Cause: identifiers may not start with any ASCII character other than letters and numbers. $#_ are also allowed after the first character. Identifiers enclosed by doublequotes may contain
any character other than a doublequote. Alternative quotes (q'#...#') cannot use spaces, tabs, or carriage returns as delimiters. For all other contexts, consult the SQL Language Reference Manual.
*Action:
I want to ask if I restore a control file from backup of say day2 and I recover till day1 using RMAN script, then what will be the state of my database? I mean day2 control file may be having SCN-Day2, and I am instructing RMAN to recover till past point in time that is SCN-Day1.
View 3 Replies View Relatedi'm a student currently learning database administration security.
I need to create a tablespace for administration of database but i don't know what datafile settings are best suited for admin usage.
I have attached the schema that was given to me for this assignment.
I need to know if a customer appears at least 4 consecutive days. Here's an example of data
CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
123 , 2010/10/10
456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
My manager is asking to create a SQL scrip, which will provide following information.
Our database is 9.2.0.7.0 on Windows 2000 Server
-How many records Insert / Update or Delete daily in my Oracle database?
- Check Archive log / Redo Log switching information?
-Check database growth ?
i am trying to install Oracle 10.10.2.0 on Windows Server 2003 standard x64 Edition Service Pack, but when i try to run the installer or open DVD it gives me below error.
"The image file D: is Valid, but is for a machine type other than the current machine."
I was trying to delete the database in the test server. When i was deleting listener was already stopped, i continued deleting using dbca, it shown me some alert that datafiles cant be deleted because system could't find database, since listner was stopped so only service was deleted(the one showing in the windows administrator toolsservicesOracleServiceTEST).
All the datafile parameter files are still there. How can i delete the datafiles and parameter files belongs to that database or how to create the deleted service, so that i will start the listener and do the complete deleting of the database.
I have to migrate production database version 10gR2 on windows 2003 server to oracle 11gR2 on windows 2008 server . So far i have just installed the oracle software on 64bit windows 2008 server. How to move the data or migrate from old server to new server .
View 22 Replies View Relatedafter a long time,(i never remember when was the last time i installed 9i)i was asked to install 9i.So, whether i install server or cilent i get this error <attachment>
after i ignore it and finished the installation,The server installation gets abruptly ended for the client i get TNS errors.
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
View 1 Replies View RelatedMy Table structure is
SL# Start_ts
1 7/31/2012 3:53:42.864070 AM
2 7/26/2012 2:13:58.280928 PM
3 7/25/2012 2:13:41.692569 PM
4 7/21/2012 2:13:26.821070 PM
5 7/18/2012 2:13:07.827278 PM
6 7/13/2012 2:05:35.023520 PM
Question
How to select last 10 days rows only (from sysdate)
Error
1) SQL> select * from Test where to_date(start_ts, 'DD-MON-YYYY HH24:MI:SS') > to_date(sysdate, 'DD-MON-YYYY HH24:MI:SS')-10 ; (or)
2) SQL> select * from Test where to_date(start_ts, 'MM/DD/YYYY HH24:MI:SS') > to_date(sysdate, 'MM/DD/YYYY HH24:MI:SS')-10 ;
ORA-01858: a non-numeric character was found where a numeric was expected
[Code]...
Our "client" is delivering data that contains an "age" field. However, they've put the AGE in DAYS instead of years, while our system can only work with years. So I needed to convert the age to years.
We are getting 2 parameters: LOWAGE and HIGHAGE (both in days). However, for the same "test" (laboratory test), we are also getting some other records
eg:
TEST 1 lowage = 0 upperage = 5 OTHER values = xxx
TEST 1 lowage = 6 upperage = 100 OTHER values = yyy
So if the person would be 5 years or less, the values xxx would apply. If they are 6 years and older, the yyy values apply. Now, the problem is that we are not getting this data in years, but in days. And whichever function I try, the upperage from the first test also seems to be equal to the lowerage from the second test. And this gives an error, because both would apply to this person....
I've tried stuff like:
age/365
age/365.25 (leap years)
trunc(months_between(sysdate+ranges.lowerage,sysdate)/12)
i have an employee table where there is a column called join date. Now i have to select the employee according to the days. Means how many employee joined on Monday/Tuesday etc.
View 17 Replies View RelatedI have the following in my select statement and I am getting the days like 1130, 50, 60 etc
round(MAX (TO_DATE ('31-OCT-2011 23:59:59','dd-mon-yyyy hh24:mi:ss') - a.tx_dtime),0) DAYS
Now I want this to convert these days into months like
1.10 this denotes (one month 10 days)
1.25 this denotes (one month 25 days)
2.05 this denotes (two months 5 days)
I know I am using old Oracle but what to do my company is not spending to upgrade.
i want create a report like this
location sysdate refdate No_of_days SL1(0-90) SL2(91-180) SL3(>180)
So when no. of days between (0-90) data put in SL1
And when no. of days between (91-180) data put in sl2
I want to achieve this only in single query.