Syntax To Calculate Number Of Days Difference
Sep 27, 2010
setting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.
CODESELECT
To_Date(need_date, 'YYYYMMDD') Need_Dt,
To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Biggest_Date,
To_Date(need_date, 'YYYYMMDD') - To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Date_Diff
FROM tableT
WHERE
need_date <= (Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END)
ORDER BY Date_Diff ASC
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Feb 17, 2010
I want Oracle stored function/procedure to calculate number of working days between two dates. We need to exclude Firdays and Saturdays as there are weekend holidays and also exclude official holidasy that lie between two dates.
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Apr 9, 2013
I need the query to calculate minutes from difference of to number fields. Test case is as below.
DROP TABLE tmp;
CREATE TABLE tmp
(
code NUMBER(4),
stime NUMBER(4,2),
otime NUMBER(4,2)
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
NOMONITORING;
[code]......
CODE STIME OTIME
---------- ---------- ----------
1065 20 19.49
1082 20 18.57
1279 19.3 18.59
2075 19.3 15.32
Required output is
CODE STIME OTIME HR_MIN MINUTES
---------- ---------- ---------- ------------- --------
1065 20 19.49 00 HR 21 MIN 21
1082 20 18.57 01 HR 03 MIN 63
1279 19.3 18.59 00 HR 31 MIN 31
2075 19.3 15.32 03 HR 58 MIN 238
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May 20, 2013
i have table name order table . in that i have column name install date,order date.
the difference bet ween order date and install date should be greate than or equal to 3 working days.
fri and sat are holidays.
i need one query to find the difference betwwen orderdate and install date is greate than 3 working days
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Mar 13, 2009
how do i can make oracle function for the following vb6 function.
This function is used for calculating working days between two date.
****************************************
Public Function Work_Days(BegDate As Variant, EndDate As Variant) As Integer
' Note that this function does not account for holidays.
Dim WholeWeeks As Variant
Dim DateCnt As Variant
Dim EndDays As Integer
On Error GoTo Err_Work_Days
BegDate = DateValue(BegDate)
EndDate = DateValue(EndDate)
WholeWeeks = DateDiff("w", BegDate, EndDate)
DateCnt = DateAdd("ww", WholeWeeks, BegDate)
[code]......
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Sep 25, 2012
how to caluclate days between two dates of single timestamp filed and with this
query
Select * from m_activity_transaction where actn_opp_id in (
Select actn_opp_id from m_activity_transaction where ACTN_ACTV_ID = 218
Group by actn_opp_id
[code]...
and i nedd to caluclate no.of days between two dates like 27-JAN-12 11.06.20.000000 AM and 08-FEB-12 05.32.54.000000 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
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Oct 17, 2012
Detail table will look like below:
Product_id issue_date action_date Force_date
1 10/10/2012 10/10/2012 10/10/2012
2 10/10/2012 10/10/2012 10/10/2012
3 10/10/2012 13/10/2012 15/10/2012
[code]....
Need the data like
Issue_date count_action_date count_Force_date (diff(action_date,force_date) 1 2 3 4 5 6(days since over)
10/10/2012 3 4 1 4 2 1 0 0
How to get the data like this? automatically how to get 123.... and how to calculate the difference by which day the count of difference is going?
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Aug 10, 2003
I want to calculate time difference b/w two time clocks, just like we calculate the date difference and answer is in days, In the same way i like to have answer in hrs,min and ss.
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Jul 7, 2012
Tables
--------
ROWID START_DATEEND_DATE
101/26/2012 00:00:0001/31/2012 00:00:00
201/26/2012 00:00:0002/02/2012 00:00:00
302/03/2012 00:00:0003/31/2012 00:00:00
How to find out the days difference in sql query, start date of next records and end date of previous records as highlighted on blue color
query out put should give as below
start_date + next record ,end_date - Previous records should give the difference of
6
1
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Sep 19, 2010
format of dtActivityStartDate/dtActivityFinishDate: 2010-09-17 14:50:51.150 Note: Both dtActivityStartDate/dtActivityFinishDate
vcActivityName = Process Request
usdFuncTimeCalc (vcActivityName,dtActivityStartDate, dtActivityFinishDate)
i need to calculate time elasped for that type of activity following are the rules:
(If Process Request is the activity)
Working Days: Monday through Saturday
Hours of Operation: 9AM 5PM
only working hours of day need to the counted like for example if it is sep 15 11 Am is dtActivityStartDate & Sep 17 is dtActivityFinishDate is 10 Am. then time elapsed is 11am to 5pm on sep 15 , 9 to 5 on sep 16 & 9 to 10 on sep 17 so total should be
6+ 8 + 1 = 15 hours + minutes.
format of date time: 2010-09-17 14:50:51.150
vcActivityName = Process Request
Don't worry about process request..
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Feb 28, 2013
I need to subtract multiple numbers to get the difference between each numbers, the amount of numbers to subtract between each others can vary between 2 and 10.
create table table_1 (
col1 varchar2(5),
col2 number(6,0),
col3 number(12,0)
)
insert into table_1 values ('AAA', 34379, 11111);
insert into table_1 values ('AAA', 39032, 11111);
insert into table_1 values ('AAA', 54337, 11111);
insert into table_1 values ('AAA', 78005, 11111);
insert into table_1 values ('AAA', 66793, 22222);
insert into table_1 values ('AAA', 74323, 22222);
insert into table_1 values ('AAA', 81426, 22222);
Expected Output:
col1 col2 col3
AAA -4653 11111
AAA -15305 11111
AAA -23668 11111
AAA -7530 22222
AAA -7103 22222
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Nov 29, 2011
during application migration, i got one table from MS Access, and have situation where two events are splited into 4 columns (start: date1 time1 and stop: dat2 and time2). How to properly calculate duration between these two events, and show it in format: hh:mi ?
CREATE TABLE ACCBTP_DCZASTOJ
(ID NUMBER(11,0),
NASTANAK_KVARA DATE,
VRIJ_NASTKVARA DATE,
VRIJEME_OPRAVKE DATE,
DATUM_OPRAVKE DATE);
[Code]....
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Sep 11, 2010
In my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
what if i select y? it will override three files
what if i select n? default option
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Apr 25, 2011
1) First Problem:
Difference in hours is supposed to be 35 but it comes as 34.When i manually find the difference in days and multiply by 24 it comes as 34.999999999 and floor converts it as 34.. But when i execute the difference between dates alone and convert to 24 it shows as 35. So when i apply floor to this, it should be 35 instead of 34 right?
SQL> select (to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
2 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss'))
3 from dual
4 ;
[code].....
1) Second Problem:
For the following query, difference of the dates in minutes is 2100.. so mod(2100,60) should give 0 but it's giving 60.. Separately if if put mod(2100,60) it is giving as 0 only.
SQL> SELECT MOD(((to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
2 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss')) * 1440),
3 60) AS duration,
4 (to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
5 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss')) * 1440 as diffinmin
[code]....
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Mar 24, 2011
I have two different date in my payroll software,
1-Shift_date shift date *used to contain shift timings
2-Attendace_datedate *used to contain employee IN timings
As you all know that shift is a setup form, where user input data once in the starting of software so the shift_date can be "01/jan/2011 16:00 pm" but attendance loads daily and attendance field data can be in this form "24/mar/2011 16:15 pm"..Now I want to calculate difference time between these two fields therefore I used this statement
SQL> Select to_char(attendance_date,'HH24:MI') to_char(shift_date,'HH24:MI') from dual;
but it is showing error: ORA-01722: invalid number...I used hours/minutes format mask in my query because you can see there is a difference of dates between these fields and it will be increase in the coming future and I need late hours and minutes.
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Jan 10, 2012
how to calculate the difference between multiple dates at the same time..
Select to_date('10/10/2011','mm/dd/yyyy')
- to_date('09/10/2011','mm/dd/yyyy')
- to_date('08/10/2011','mm/dd/yyyy') from dual;
Giving me an error...
ORA 00932 : inconsisten data types:expected DATE Julkian got DATE..
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Sep 22, 2011
create or replace function getDate(p_joing_date Date,p_sysdate)
Return Date;
IS
v_compltd_mnths;
BEGIN
SELECT into v_compltd_mnths MONTHS_BETWEEN(TO_DATE('sysdate','MM-DD-YYYY'), TO_DATE('joing_date','MM-DD-YYYY') ) "Months"FROM DUAL;
return v_compltd_mnths;
END;
that i have worte..
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Jan 14, 2008
What I need to do is take 2 dates from a table named 'projects' and insert the number of days between them into a table named 'time_record'.How do I go about this?
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Apr 18, 2013
i want to create function to show number of days between to days such as number of Friday days between to dates
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Dec 15, 2011
I have to procedure that computes number of project, and average working hours of employees where employee id is passed as a parameter to the procedure. If the average working hours is less than 10 then employee's salary remain the same, otherwise check if number of project is less than 4 then 5% of salary, else 10% of salary is added to the salary.
my tables are:
CREATE TABLE employee(
empid number(5),
empname varchar(20),
address varchar(20),
no_of_dependents number(5),
deptno number(5),
CONSTRAINT EMPLOYEE_PKEY PRIMARY KEY(empid),
CONSTRAINT EMPLOYEE_FKEY FOREIGN KEY(deptno) REFERENCES department(deptno));
[code]...
the problem is i have to use only 2 cursors - 1 for select and 1 for update.
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Oct 20, 2011
Is there any Oracle query I can run to determine the "number of days since the last backup"? SQL Server provides this data but I cant seem to find the equivalent for Oracle. Looks like there may be some information like this via RMAN tables and if so I want to create the simplest query possible to obtain that information.
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Oct 1, 2012
We have a requirement where we need to pay allowance for the employees based on their number of working days. Say for example if an employee worked from 03/Mar/2012 to 05/Apr/2012.
We have a fixed value for per month 300 Dirhams. But the Number of Days on March s 31 and Number of days in April is 30. So per day allowance for March day would be 300/31 and April would be 300/30.
We are looking for logic opr query which calculates first eh number of days in each month ( across months) and then calculate as below
Number of Working days in March is 31 - 3 + 1 = 29
Allowance A1 = (300 * 29 )/31
Number of Working days in April is 5 ( this also needs to find logical I am guess )
Allowance A2 = (300 * 5 )/30
Then A1 + A2.
The A(n) would be the total allowance where provided the number of month across.
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Jun 12, 2012
There is a attendance table having structure(empid number,signtime datetime)It has data of attendance of employees:
What is the right sql to show employees detail attendance according to the no of days attendance . i.e.(According to the maximum no of attendance first and so on)
suppose: 3 employees abc,bbc,cca abc has 20 days of attendance ,bbc has 21 days,cca has 19 days..The report like this:
bbc 1/5/12 10:30
abc .....
then
cca
according to the no of attendannce
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Mar 31, 2011
I was reading the documentation for oracle 11gr2, with reference to URL>.....
The following examples show how to correctly choose the cluster key and set the HASH IS, SIZE, and HASHKEYS parameters. For all examples, assume that the data block size is 2K and that on average, 1950 bytes of each block is available data space (block size minus overhead).Note that 34 hash keys are assigned for each data block
how they arrive at 34 hash keys because another portion of the document states
This space determines the maximum number of cluster or hash values stored in a data block. If SIZE is not a divisor of the data block size, then Oracle Database uses the next largest divisor.
if that is the case, then number of hash keys should be 1900/55 = 34.55 which should have rounded up to 35.
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Apr 19, 2009
I have been trying to construct a query in Oracle that allows me to do the following:
For example if I have the data below:
EmpNo DOB SickDays
Alex 445 15/06/1985 7
Tom 778 22/08/1981 4
James 992 07/10/1978 5
I need to write and a query to lists the employee number and the amount of days sick that they have had and also add a column that compares the number of sick days to the average number of suck days by ALL employees.
I can calculate the average sick days etc, but It wont see to allow me to find the difference between that and the amount of sick days that each person has had. I have tried this many ways and have not been able to come up with a solution.
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May 22, 2010
The data in one of the temporary table has been compiled as below. Number of Days elapsed between two transaction dates is required to be computed and multiplied with the balance. There can be multiple number of same transaction dates. When previous date and the current transaction dates are same the resulting number of day difference should be 0. But when they are different the difference between them is to be computed. On the last day of the Financial Year i.e. '31/03' of any year the difference day should be shown as 1 so as to make 365 or 366 days in a year. Simply deducting d1 from d2 on 31st will not be suffice as the difference is one day less.
----------------------------------------------------------------------------------------- -------
Transaction Narration DebitCreditBalanceNo of DaysProduct
DateDifference
----------------------------------------------------------------------------------------- --------
01/04/2009Opening Balance 45020450277346654
17/06/2009ByAmt5044521253424
29/06/2009By Amt1004352156678912
02/12/2009By Amt424310119476000
[code]....
improve the above code and get the desired output result.
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Oct 25, 2013
I used this query:
SELECT to_char(return_date_time,'dd/mon/yyyy hh24:mi:ss') Test,DECODE ('I', 'I', DECODE (1, NULL, NULL, 0, NULL, SYSDATE + 1)) Days,DECODE ('I', 'I', SYSDATE + 1) Day1FROM fm_curr_locnWHERE patient_id = 'DU00002765' output: TestDays Day126/oct/2013 00:00:00 26-OCT-13 10/26/2013 3:06:59 PM
I want to know the difference between Days column and Day1 column and why the days column didn't show the time .
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Sep 2, 2011
I have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
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Oct 20, 2012
I can't understand >>
1. Number 2 is less than number 100,
2. string '2' is greater than string '100'.
>> Numbers are ordered by numerical value; strings are ordered by alphabetical value. >>
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Apr 5, 2011
want to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
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