I can't understand >>
1. Number 2 is less than number 100,
2. string '2' is greater than string '100'.
>> Numbers are ordered by numerical value; strings are ordered by alphabetical value. >>
I am confused with third one.
CODE1. >> Comparing two strings >>
SQL> select greatest('99' ,'100') from dual;
GR
99
2. >> comparing both numbers >>
SQL> select greatest( 99 ,100) from dual;
GR
100
3.>> Comparing string and number >>
SQL> select greatest('99' ,100) from dual;
GR
99
whats the logic behind 99 being returned for thirdone.
i want to replace 4 digit number in a given string with the same number incremented by 10000.
That mean in the given sting 1201 should be replace by 11201 (Icremented BY 10000).
Input String:
<query><matchAll>true</matchAll><row><columnId>1201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>1224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>
Required output :
<query><matchAll>true</matchAll><row><columnId>11201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>11224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>
setting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.
CODESELECT
To_Date(need_date, 'YYYYMMDD') Need_Dt,
To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Biggest_Date,
To_Date(need_date, 'YYYYMMDD') - To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Date_Diff
FROM tableT
WHERE
need_date <= (Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END)
ORDER BY Date_Diff ASC
I need the query to calculate minutes from difference of to number fields. Test case is as below.
DROP TABLE tmp;
CREATE TABLE tmp
(
code NUMBER(4),
stime NUMBER(4,2),
otime NUMBER(4,2)
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
NOMONITORING;
[code]......
CODE STIME OTIME
---------- ---------- ----------
1065 20 19.49
1082 20 18.57
1279 19.3 18.59
2075 19.3 15.32
Required output is
CODE STIME OTIME HR_MIN MINUTES
---------- ---------- ---------- ------------- --------
1065 20 19.49 00 HR 21 MIN 21
1082 20 18.57 01 HR 03 MIN 63
1279 19.3 18.59 00 HR 31 MIN 31
2075 19.3 15.32 03 HR 58 MIN 238
If I run the following query I got 997 records by using GROUP BY.
SELECT c.ins_no, b.pd_date,a.project_id,
a.tech_no
FROM mis.tranche_balance a,
FMSRPT.fund_reporting_period b,
ods.proj_info_lookup c,
ods.institution d
WHERE a.su_date = b.pd_date
AND a.project_id = c.project_id
AND c.ins_no = d.ins_no
AND d.sif_code LIKE 'P%'
AND d.sif_code <> 'P-DA'
AND a.date_stamp >='01-JAN-2011'
AND pd_date='31-MAR-2011'
GROUP BY c.ins_no,
b.pd_date,
a.project_id,
a.tech_no;
I want to show the extra columns a.date_stamp and a.su_date in the out put so that I have used PARTITION BY in the second query but I got 1079 records.
SELECT c.ins_no, b.pd_date,a.date_stamp,a.su_date, a.project_id,
a.tech_no,
COUNT(*) OVER(PARTITION BY c.ins_no,
b.pd_date,
a.project_id,
a.tech_no)c
[code]....
why I got 1079 records.how to show the two extra columns in the out put whcich are not used in GROUP BY clause.
If I have a "smart" key in a database, say one for which each byte of the key is meaningful, is it generally a good idea to string together a number of LIKEs with ORs? For example, if I want to select people where the last two bytes of that smart code are in a certain list and write:
where smart_key LIKE '%02'
or smart_key LIKE '%03'
or smart_key LIKE '%07'
or smart_key LIKE '%19'
or smart_key LIKE '%23'
or smart_key LIKE '%30'
or smart_key LIKE '%33'
or smart_key LIKE '%34'
or smart_key LIKE '%41'
etc.
Say I string a lot of those together, with 40 or 50 ORs. Right off the bat is it fair to say that's a bad query for Oracle, or do substrings of this sort generally perform well?
I found this query in my sub version repository and really wondering how this working
select to_char(to_date(1000000,'J') ,'JSP') string_value from dual;
I am using this Regexp to extract numbers from a string, and I doubt that there is a more efficient way to get this done:
SELECT regexp_replace (regexp_replace ( REGEXp_REPLACE (' !@#$%^&*()_+= '' + 00 SDFKA 324 000 8702 234 | " ' , '[[:punct:]]',''), '[[:space:]]',''), '[[:alpha:]]','') FROM dual
{code}
Is there a more efficient way to get this done ?
Im trying to generate this link on my result [URL].....
materialId and materialFolderId are the results of my query.. Im not sure how to combine my results and string on my query..
I am currently working on a Data Dictionary project where we need to run a few rules against the give data sources to see if they all comply together.
One of the rule is to check if the no. is negative or not. So for that what I tried to do was to check if first the field is number or not and then check on if it is negative or not.
This is the code I am currently trying on and is not looking good.
SELECT 1 FROM DUAL
WHERE decode(DECODE( TRANSLATE('-123.45','-0.123456789',''), NULL, 1,0), 1,substr('-123.45',1,1) ,' ' ) = '-'
I wanna convert the amount of money from number to string such as 144.5 to be one hundred forty four point five is there any function or i have to write my function? How could i put new line in the string?
for example if i have 'SAB Bank' || 'Riyadh'
but i want SAB bank to be displayed in line and Riyadh in line.
The code which I am working on consists of an incoming dynamic string which be in the form of binary digits. The max size of the string will be 12 digits. For example, the string can be '111011000001', '000000000000', '111111011111', etc.
I need to find the number of occurences of '111' in the incoming string. Say in the 1st example, result will be 1, in the 2nd example result will be 0, and in the third example, the result will be 3.
I have been trying to capture the string length and replacing the variables '111' to find the number of occurences, but it isn't giving me the result that I want. This is what I have tried
SQL> conn hr/hr
Connected.
SQL> show user
USER is "HR"
[Code]....
I searched the forum and found a similar topic, and following that guideline, I even tried dividing the string with the length of the pattern. It works in some scenarios (the first and second examples mentioned below), while it fails in some scenarios (third example mentioned below)
SQL> select (length('11101110111') - length(replace('11101110111','111','')))/length('111') as occurences from dual;
OCCURENCES
----------
3
SQL> select (length('110111110111') - length(replace('110111110111','111','')))/length('111') as occurences from dual;
OCCURENCES
----------
2
SQL> select (length('111111111111') - length(replace('111111111111','111','')))/length('111') as occurences from dual;
OCCURENCES
----------
SQL>
I have a string like this:
s_list varchar2(234) :=
'asdasd
asfsdf
dsfsdfs
dfsdfs';
How can I find the number of lines in this string? I tried using
INSTR('s_list', '
', 1, 1)
but it gives 0.
Is there any inbuilt function/proc SQL or PL/SQL which can do this?
I have created a function that is used for splitting a comma separated string & give the output in tabular form.here is the function
Here I have used CLOB as my input string will be huge(greater than max limit of varchar2)
CREATE OR REPLACE TYPE SPLIT_TBL_CLOB AS TABLE OF CLOB;
CREATE OR REPLACE FUNCTION CSVTOSTRING_CLOB
(
P_LIST CLOB,
P_DEL VARCHAR2 := ','
) RETURN SPLIT_TBL_CLOB PIPELINED
[code]....
But here I am facing 2 problems.
1. The function is not accepting a large string & I am getting the error
ORA-01704: string literal too long
2. The function is going for an infinite loop.
I have a table(PSUSEROBJTYPE) with a long field(PTCUSTFORMAT) containing a row value value in the form:
#1|0|0|0|0|#2|1|0|0|1|#3|1|0|0|0|#4|0|0|0|0
Here, I want to update the above field value to a value in the form:
#2|0|0|0|0|#3|1|0|0|1|#4|1|0|0|0|#5|0|0|0|0
This is nothing but finding each occurrence of (#n) in the above string and replacing it by (#n+1). (i.e #1 is replaced by #2,#2 is replaced by #3).
I need to concatenate string to the number field in an update statement like this:
update test1 set model_pin = seq_no || '_' || model
where eoc_code like 'AEW%'
When I run this command in sql , I get ERROR at line 1:
ORA-01722: invalid number
I need writing sql which can return the Count of Comma's in a string. Here is my table and data
CREATE TABLE TEST1(SNO NUMBER,STR1 VARCHAR2(30));
INSERT INTO TEST1 VALUES(1234,'ABCD,LL LT,MP');
INSERT INTO TEST1 VALUES(1456,'PP MR');
INSERT INTO TEST1 VALUES(1589,NULL);
INSERT INTO TEST1 VALUES(1897,'PP MR,FTR CLR ON');
Here is the output I am expecting
SNO STR1 STR1_COUNT
1234 ABCD,LL LT,MP 3
1456 PP MR 1
1589 0
1897 PP MR,FTR CLR ON 2
Basically I need to the count of Words separated by comma
Detail table will look like below:
Product_id issue_date action_date Force_date
1 10/10/2012 10/10/2012 10/10/2012
2 10/10/2012 10/10/2012 10/10/2012
3 10/10/2012 13/10/2012 15/10/2012
[code]....
Need the data like
Issue_date count_action_date count_Force_date (diff(action_date,force_date) 1 2 3 4 5 6(days since over)
10/10/2012 3 4 1 4 2 1 0 0
How to get the data like this? automatically how to get 123.... and how to calculate the difference by which day the count of difference is going?
I have this error (and solution):
ORA-02085: database link string connects to string
Cause: a database link connected to a database with a different name. The connection is rejected.
Action: create a database link with the same name as the database it connects to, or set global_names=false.
Where should I set global_names=false ?
I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.
For ex:
The first value fetched from the select query first is ABCDEFG which gets appended to a variable
The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.
writing that piece of code to append the value fetched which doesn't exactly match with the existing string
show an ex to use string buffer for select statemnt
View 1 Replies View Relatedi am using oracle developer 6i report builder i required this type of query
example
if (:page number LIKE '1')
then
srw.set_text_color('darkred');
end if;
return (TRUE);
end;
but page number is not my table database item how can i use builtan page &<pagenumber> use for conditional format.
I have a text field and if the text field has 5 consecutive numbers then I have to extract the number and the previous character from where the 5digit number starting
For example i/p asdfasfsdS251432dasdasd o/p should be S251432
I gone through many forums and found that the number of voting disks should be always in odd number. Then why the maximum number of voting disk is 32?
View 1 Replies View Relatedhow do I count a list of number value eg 1,1,1,1,3,3,6,4 and find the one with maximum number which is 1
View 5 Replies View RelatedI have the following select query that works perfectly fine. Returns 25 rows based on the descending order of the price.But, I want add one more expression to this list of columns in this query (apart from customer_id).
the expression should look like Cust-01 for the first customer from the below query all the way to Cust-25 for the last customer.But how can I can generate 01 to 25 in oracle?
select customer_id from
(select customer_id from capitalPLAN
where member_status = 'MEMBER' AND customer_id NOT in ('156','201','1385','2125','3906','165')
order by price desc
)
where rownum <= 25
my column type is NUMBER(10,0) ,it accept the input value from text field I using TO_NUMBER(?) to insert value into table, is the a way to handle if the input is 'aaaaaaaaaa' not digit?
View 6 Replies View RelatedHere is script of tables
Quote:drop table p;
create table p (qty number(3), beg_no number(5));
insert into p values(5, 110);
insert into p values(8, 786);
drop table s;
create table s (used_no number(5));
insert into s values(111);
insert into s values(113);
insert into s values(791);
Table p: it has ticket quantity and ticket begining number. Thus according to first record ticket number will begin at 110 and will end at 110+5 (Beg_no +qty). According to second record ticket number will begin at 786 and will end at 786+8 (Beg_no +qty). This table can have many records.
Table s: it has ticket numbers which are sold. The ticket will always be any number from table and will lay in any record in this format between beg_no and beg_no+qty
Required: I want "p MINUS s" information. i.e.
Quote:
110
112
114
786
787
788
789
790
792
793
I am not expert in level by command.
Oracle version: 9
OS: Windows XP
I have a report created in Reports6i. I have two fields at the bottom
1.Page Total
2.Voucher Total
I do not want to print the Page Total if the total number of pages = 1.
How can I achieve this?