Select Greatest - Difference Between Number And String?

Oct 21, 2012

I am confused with third one.

CODE1. >> Comparing two strings >>
SQL> select greatest('99' ,'100') from dual;
GR
99

2. >> comparing both numbers >>
SQL> select greatest( 99 ,100) from dual;
GR
100

3.>> Comparing string and number >>
SQL> select greatest('99' ,100) from dual;
GR
99

whats the logic behind 99 being returned for thirdone.

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SQL & PL/SQL :: Select Greatest Number From Row

Sep 18, 2012

I've a table where I've to select the greatest value from each row.

create table find_max ( colA number, colB number, colC number );
insert all
into find_max values (8,12,13)
into find_max values (-1,-22,3)
into find_max values (1,null,13)
into find_max values (-1,-2,-3)
into find_max values (-1,0,-10)
select * from dual;
the desired format of output is:
three fields for colA, colB, colC and max_value
max_value for 1st row is 13, 2nd is 3, 3rd is 13, 4th is -1,5th is 0.

how can I find the max_value without using any built in functions??

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Difference Between Number And String?

Oct 20, 2012

I can't understand >>

1. Number 2 is less than number 100,

2. string '2' is greater than string '100'.

>> Numbers are ordered by numerical value; strings are ordered by alphabetical value. >>

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SQL & PL/SQL :: How To Find Greatest Values In A String

Jul 22, 2011

I am trying to update the greatest value in a column from a string of other column.

Ex: f the value is shown 10M+16M+25M-DG, then populate 25 only

so for that I had written query as follows:

update ANCHOR set IEL_STRAND_SIZE= greatest(
substr
(REPLACE(REPLACE(REGEXP_REPLACE( F_TYP, '[A-Z]', '' ),'+',','),'-',','),
0,
length(REPLACE(REPLACE(REGEXP_REPLACE( F_TYP, '[A-Z]', '' ),'+',','),'-',','))-1))

The output is given as 10,16,25,but not as 25.so how could i write it?Do I need to implement procedure or arrays for it.

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Aug 4, 2010

SQL> select greatest ( 1000,null) from dual;

GREATEST(1000,NULL)
-------------------
SQL> with t as
2 ( select 1 a from dual union all
3 select null from dual)
4 select max(a) from t;

MAX(A)
----------
1

Why greatest returns null ( as the greatest value among the list of values) as the greatest value while max returns 1 in the above case?

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Jun 17, 2010

i want to replace 4 digit number in a given string with the same number incremented by 10000.

That mean in the given sting 1201 should be replace by 11201 (Icremented BY 10000).

Input String:

<query><matchAll>true</matchAll><row><columnId>1201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>1224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>

Required output :

<query><matchAll>true</matchAll><row><columnId>11201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>11224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>

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Aug 29, 2012

just i want add diiferece column in my select statement.For Example:-

select
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date_first_payment,
date_last_payment,
(date_first_payment-date_last_payment) Datediff
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then its working

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its not working..

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Sep 27, 2010

setting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.

CODESELECT
To_Date(need_date, 'YYYYMMDD') Need_Dt,
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WHERE
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Apr 9, 2013

I need the query to calculate minutes from difference of to number fields. Test case is as below.

DROP TABLE tmp;

CREATE TABLE tmp
(
code NUMBER(4),
stime NUMBER(4,2),
otime NUMBER(4,2)
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
NOMONITORING;
[code]......

CODE STIME OTIME
---------- ---------- ----------
1065 20 19.49
1082 20 18.57
1279 19.3 18.59
2075 19.3 15.32

Required output is

CODE STIME OTIME HR_MIN MINUTES
---------- ---------- ---------- ------------- --------
1065 20 19.49 00 HR 21 MIN 21
1082 20 18.57 01 HR 03 MIN 63
1279 19.3 18.59 00 HR 31 MIN 31
2075 19.3 15.32 03 HR 58 MIN 238

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Feb 17, 2012

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a.tech_no
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FMSRPT.fund_reporting_period b,
ods.proj_info_lookup c,
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AND c.ins_no = d.ins_no
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I want to show the extra columns a.date_stamp and a.su_date in the out put so that I have used PARTITION BY in the second query but I got 1079 records.

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a.tech_no,
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b.pd_date,
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a.tech_no)c
[code]....

why I got 1079 records.how to show the two extra columns in the out put whcich are not used in GROUP BY clause.

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Jun 28, 2010

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{code}

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Feb 4, 2012

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SQL> conn hr/hr
Connected.
SQL> show user
USER is "HR"

[Code]....

I searched the forum and found a similar topic, and following that guideline, I even tried dividing the string with the length of the pattern. It works in some scenarios (the first and second examples mentioned below), while it fails in some scenarios (third example mentioned below)

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OCCURENCES
----------
3

SQL> select (length('110111110111') - length(replace('110111110111','111','')))/length('111') as occurences from dual;

OCCURENCES
----------
2

SQL> select (length('111111111111') - length(replace('111111111111','111','')))/length('111') as occurences from dual;

OCCURENCES
----------

SQL>

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[URL]...

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Aug 31, 2011

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