PL/SQL :: Extract Number From String

Oct 21, 2012

I am using this Regexp to extract numbers from a string, and I doubt that there is a more efficient way to get this done:

SELECT  regexp_replace (regexp_replace ( REGEXp_REPLACE ('  !@#$%^&*()_+= '' + 00 SDFKA 324 000 8702 234 |  " ' , '[[:punct:]]',''), '[[:space:]]',''), '[[:alpha:]]','')  FROM dual
{code}

Is there a more efficient way to get this done ?

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SQL & PL/SQL :: Extract Number And Previous Character From Where 5 Digit Number Starting

Oct 21, 2011

I have a text field and if the text field has 5 consecutive numbers then I have to extract the number and the previous character from where the 5digit number starting

For example i/p asdfasfsdS251432dasdasd o/p should be S251432

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SQL & PL/SQL :: Extract Date From String

Jan 8, 2013

I need to extract the First portion of date entered in remarks column , i have prepared a test as below.

CREATE TABLE LEAVE_DYS (LV_EMP_CODE VARCHAR2(12), LV_DESC VARCHAR2(2000));
INSERT INTO LEAVE_DYS VALUES ('R0754','LEAVE SALARY FOR APRIL 16, 2010 - APRIL 15, 2012 (33 ABSENTS)');
INSERT INTO LEAVE_DYS VALUES ('R0667','LEAVE SALARY FOR JULY 14, 2009 - JULY 13, 2011 (44 ABSENTS)');
INSERT INTO LEAVE_DYS VALUES ('R0841','LEAVE SALARY FOR MAY 29, 2010 - MAY 28, 2012 (NO ABSENT)');
INSERT INTO LEAVE_DYS VALUES ('R0854','LEAVE SALARY FOR MAY 29, 2010 - MAY- 28, 2012 (1 ABSENT)');
[code].....

--Required output is

LV_EMP_CODE LV_DESC
R0754 16/04/2012
R0667 14/07/2012
R0841 29/05/2012
R0854 29/05/2012
R0313 09/09/2012

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SQL & PL/SQL :: Extract String Between The Braces?

Sep 13, 2011

I have following column data

NZ(abc_mode)/ (NZ(bch_mode) + NZ(cdh_mode)

Now i need query to extract the string inside the braces NZ() with or without using regular expressions in SQL

the output should be

abc_mode
bch_mode
cdh_mode

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SQL & PL/SQL :: Extract Part Of String And Replace

Feb 13, 2012

I have written one program that inserts one field in table item_master based on existing field,for eg, its like old field is 'HEB240x240x10x17x13000mm, S 275 JR' - and i want to replace the 5 digits before mm i.e 13000 needs to be replaced by 6000 or 4000 based on generated values and the new item will be like 'HEB240x240x10x17x6000mm, S 275 JR' or 'HEB240x240x10x17x4000mm, S 275 JR'.

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PL/SQL :: Extract Values From String To Variables?

Jul 16, 2013

I need to extract values from string to variables as below.

declare
str varchar2(100):='Acknowledgment=1234,Order Requester=5678,Site Contact=9999,Other Contact=1456,Pre=1234,23445,56767';
l_a varchar2(100);
l_or  varchar2(100);
l_s  varchar2(100);
l_ot  varchar2(100);
l_pre  varchar2(100);
Begin
l_a:='1234';
l_or:='5678';
l_s:='9999';
l_ot:='1456';
l_pre:='1234,23445,56767';
end;
/

But here challenge is order of alignment change dynamically. ex as below. 

str varchar2(100):='Order Requester=5678,Acknowledgment=1234,Site Contact=9999,Other Contact=1456,Pre=1234,23445,56767';
str varchar2(100):='Pre=1234,23445,56767,Order Requester=5678,Acknowledgment=1234,Site Contact=9999,Other Contact=1456';

 So how to extract Acknowledgement to l_a,Order requester to l_or ...

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SQL & PL/SQL :: String Function - Extract Domain From Email Address

Oct 12, 2011

I'm trying to extract the domain from email addresses like from clay500@msn.com I want to pull msn

I figured I would use the POSITION function, but it fails, even when I cut and pasted the example from the syntax guide

SELECT POSITION ('CAT' IN 'CATCH') FROM DUAL;

the guide says you get the answer 1

but I get ORA-00907: missing right parenthesis

What gives?

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SQL & PL/SQL :: How To Extract First 3 Characters From Each Word In A String / Sentence And Separate With Underscore

Oct 22, 2013

I have some strings like

'Net Amount Payable by an Individual',
'Net Amount Payable by an Individual+Tax',
'Total Amount Payable towards Service',
'Total Amount Payable towards Service.+Tax'

I need to extract the first three letters from each word and separate them using an underscore. The output should be as follows for the above strings -

Net_Amo_Pay_by_an_Ind
Net_Amo_Pay_by_an_Ind_Tax
Tot_Amo_Pay_tow_Ser
Tot_Amo_Pay_tow_Ser_Tax

I request to let me know the way to get the ouput as mentioned.

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SQL & PL/SQL :: Extract Email ID From A String / Text Using Oracle Regular Expressions

Oct 14, 2013

code to extract email id (full email id) from a string/text using Oracle Regular Expressions.

Example -

"This is my String with email abc.efg@hij.com to test" O/p - abc.efg@hij.com

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SQL & PL/SQL :: Replacing 4 Digit Number In A Given String With The Same Number Incremented By 10000?

Jun 17, 2010

i want to replace 4 digit number in a given string with the same number incremented by 10000.

That mean in the given sting 1201 should be replace by 11201 (Icremented BY 10000).

Input String:

<query><matchAll>true</matchAll><row><columnId>1201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>1224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>

Required output :

<query><matchAll>true</matchAll><row><columnId>11201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>11224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>

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SQL & PL/SQL :: Extract Only Number Part Of Column?

Mar 25, 2010

In a table, I have a column in a table with the following values:

targetcol

30 WD
180 WD
70%
0
80%
180 CD
70%
0
7 WD
2 WD
0

-
-
-
-
-
-
-
-
-

where WD is working days and CD Calendar days.

I just need to extract number from above.

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Difference Between Number And String?

Oct 20, 2012

I can't understand >>

1. Number 2 is less than number 100,

2. string '2' is greater than string '100'.

>> Numbers are ordered by numerical value; strings are ordered by alphabetical value. >>

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SQL & PL/SQL :: String Together Number Of LIKEs With ORs

Jun 28, 2010

If I have a "smart" key in a database, say one for which each byte of the key is meaningful, is it generally a good idea to string together a number of LIKEs with ORs? For example, if I want to select people where the last two bytes of that smart code are in a certain list and write:

where smart_key LIKE '%02'
or smart_key LIKE '%03'
or smart_key LIKE '%07'
or smart_key LIKE '%19'
or smart_key LIKE '%23'
or smart_key LIKE '%30'
or smart_key LIKE '%33'
or smart_key LIKE '%34'
or smart_key LIKE '%41'
etc.

Say I string a lot of those together, with 40 or 50 ORs. Right off the bat is it fair to say that's a bad query for Oracle, or do substrings of this sort generally perform well?

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SQL & PL/SQL :: Converting Number To String?

Apr 27, 2012

I found this query in my sub version repository and really wondering how this working

select to_char(to_date(1000000,'J') ,'JSP') string_value from dual;

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PL/SQL :: String And Result Number

Jul 9, 2012

Im trying to generate this link on my result [URL].....

materialId and materialFolderId are the results of my query.. Im not sure how to combine my results and string on my query..

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SQL & PL/SQL :: Find A Negative Number In String?

Apr 24, 2012

I am currently working on a Data Dictionary project where we need to run a few rules against the give data sources to see if they all comply together.

One of the rule is to check if the no. is negative or not. So for that what I tried to do was to check if first the field is number or not and then check on if it is negative or not.

This is the code I am currently trying on and is not looking good.

SELECT 1 FROM DUAL
WHERE decode(DECODE( TRANSLATE('-123.45','-0.123456789',''), NULL, 1,0), 1,substr('-123.45',1,1) ,' ' ) = '-'

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Reports & Discoverer :: Converting The Number To String

Dec 6, 2010

I wanna convert the amount of money from number to string such as 144.5 to be one hundred forty four point five is there any function or i have to write my function? How could i put new line in the string?

for example if i have 'SAB Bank' || 'Riyadh'

but i want SAB bank to be displayed in line and Riyadh in line.

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Select Greatest - Difference Between Number And String?

Oct 21, 2012

I am confused with third one.

CODE1. >> Comparing two strings >>
SQL> select greatest('99' ,'100') from dual;
GR
99

2. >> comparing both numbers >>
SQL> select greatest( 99 ,100) from dual;
GR
100

3.>> Comparing string and number >>
SQL> select greatest('99' ,100) from dual;
GR
99

whats the logic behind 99 being returned for thirdone.

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SQL & PL/SQL :: Finding Number Of Pattern Occurrences In String?

Feb 4, 2012

The code which I am working on consists of an incoming dynamic string which be in the form of binary digits. The max size of the string will be 12 digits. For example, the string can be '111011000001', '000000000000', '111111011111', etc.

I need to find the number of occurences of '111' in the incoming string. Say in the 1st example, result will be 1, in the 2nd example result will be 0, and in the third example, the result will be 3.

I have been trying to capture the string length and replacing the variables '111' to find the number of occurences, but it isn't giving me the result that I want. This is what I have tried

SQL> conn hr/hr
Connected.
SQL> show user
USER is "HR"

[Code]....

I searched the forum and found a similar topic, and following that guideline, I even tried dividing the string with the length of the pattern. It works in some scenarios (the first and second examples mentioned below), while it fails in some scenarios (third example mentioned below)

SQL> select (length('11101110111') - length(replace('11101110111','111','')))/length('111') as occurences from dual;

OCCURENCES
----------
3

SQL> select (length('110111110111') - length(replace('110111110111','111','')))/length('111') as occurences from dual;

OCCURENCES
----------
2

SQL> select (length('111111111111') - length(replace('111111111111','111','')))/length('111') as occurences from dual;

OCCURENCES
----------

SQL>

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Count Number Of Lines In Multi Line String

Aug 2, 2007

I have a string like this:

s_list varchar2(234) :=
'asdasd
asfsdf
dsfsdfs
dfsdfs';

How can I find the number of lines in this string? I tried using

INSTR('s_list', '
', 1, 1)

but it gives 0.

Is there any inbuilt function/proc SQL or PL/SQL which can do this?

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SQL & PL/SQL :: Split String Function For Large Number Of Records?

Aug 6, 2010

I have created a function that is used for splitting a comma separated string & give the output in tabular form.here is the function

Here I have used CLOB as my input string will be huge(greater than max limit of varchar2)

CREATE OR REPLACE TYPE SPLIT_TBL_CLOB AS TABLE OF CLOB;
CREATE OR REPLACE FUNCTION CSVTOSTRING_CLOB
(
P_LIST CLOB,
P_DEL VARCHAR2 := ','
) RETURN SPLIT_TBL_CLOB PIPELINED

[code]....

But here I am facing 2 problems.

1. The function is not accepting a large string & I am getting the error

ORA-01704: string literal too long

2. The function is going for an infinite loop.

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SQL & PL/SQL :: Pattern Matching And Updating Of Number Values In String?

Nov 5, 2011

I have a table(PSUSEROBJTYPE) with a long field(PTCUSTFORMAT) containing a row value value in the form:

#1|0|0|0|0|#2|1|0|0|1|#3|1|0|0|0|#4|0|0|0|0

Here, I want to update the above field value to a value in the form:

#2|0|0|0|0|#3|1|0|0|1|#4|1|0|0|0|#5|0|0|0|0

This is nothing but finding each occurrence of (#n) in the above string and replacing it by (#n+1). (i.e #1 is replaced by #2,#2 is replaced by #3).

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SQL & PL/SQL :: Concatenate String To Number Field In Update Statement

Oct 4, 2011

I need to concatenate string to the number field in an update statement like this:

update test1 set model_pin = seq_no || '_' || model
where eoc_code like 'AEW%'

When I run this command in sql , I get ERROR at line 1:

ORA-01722: invalid number

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SQL & PL/SQL :: Count Number Of Words In A String Separated By Comma

Aug 31, 2011

I need writing sql which can return the Count of Comma's in a string. Here is my table and data

CREATE TABLE TEST1(SNO NUMBER,STR1 VARCHAR2(30));

INSERT INTO TEST1 VALUES(1234,'ABCD,LL LT,MP');
INSERT INTO TEST1 VALUES(1456,'PP MR');
INSERT INTO TEST1 VALUES(1589,NULL);
INSERT INTO TEST1 VALUES(1897,'PP MR,FTR CLR ON');

Here is the output I am expecting

SNO STR1 STR1_COUNT
1234 ABCD,LL LT,MP 3
1456 PP MR 1
1589 0
1897 PP MR,FTR CLR ON 2

Basically I need to the count of Words separated by comma

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Jun 19, 2012

I have this error (and solution):

ORA-02085: database link string connects to string

Cause: a database link connected to a database with a different name. The connection is rejected.

Action: create a database link with the same name as the database it connects to, or set global_names=false.
Where should I set global_names=false ?

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SQL & PL/SQL :: How To Find Whether Exact String Is Present / Not In Given String

Mar 14, 2013

I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.

For ex:

The first value fetched from the select query first is ABCDEFG which gets appended to a variable
The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.

writing that piece of code to append the value fetched which doesn't exactly match with the existing string

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May 9, 2008

show an ex to use string buffer for select statemnt

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Jan 26, 2010

i am using oracle developer 6i report builder i required this type of query

example

if (:page number LIKE '1')
then
srw.set_text_color('darkred');
end if;

return (TRUE);
end;

but page number is not my table database item how can i use builtan page &<pagenumber> use for conditional format.

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SQL & PL/SQL :: How To Extract Data Between [ ]

Jun 8, 2012

I have a requirement where the data between [] or ][ has to be extracted from a string.

Here is my situation :

INPUT:
[abc] [def]-[ghi][jlk]

OUTPUT:
row_num field_name
1 abc
2 <blank_space>
3 def
4 -
5 ghi
6 null
7 jkl

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SQL & PL/SQL :: Extract One Schema's DDL

Apr 22, 2011

Is there any option available in DBMS_METADATA.GET_DDL in such a way that I can extract the script (user creation+grants)only for that particular schema?

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