SQL & PL/SQL :: Find A Negative Number In String?
Apr 24, 2012
I am currently working on a Data Dictionary project where we need to run a few rules against the give data sources to see if they all comply together.
One of the rule is to check if the no. is negative or not. So for that what I tried to do was to check if first the field is number or not and then check on if it is negative or not.
This is the code I am currently trying on and is not looking good.
SELECT 1 FROM DUAL
WHERE decode(DECODE( TRANSLATE('-123.45','-0.123456789',''), NULL, 1,0), 1,substr('-123.45',1,1) ,' ' ) = '-'
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Mar 14, 2013
I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.
For ex:
The first value fetched from the select query first is ABCDEFG which gets appended to a variable
The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.
writing that piece of code to append the value fetched which doesn't exactly match with the existing string
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Jun 17, 2010
i want to replace 4 digit number in a given string with the same number incremented by 10000.
That mean in the given sting 1201 should be replace by 11201 (Icremented BY 10000).
Input String:
<query><matchAll>true</matchAll><row><columnId>1201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>1224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>
Required output :
<query><matchAll>true</matchAll><row><columnId>11201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>11224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>
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Jan 26, 2010
i am using oracle developer 6i report builder i required this type of query
example
if (:page number LIKE '1')
then
srw.set_text_color('darkred');
end if;
return (TRUE);
end;
but page number is not my table database item how can i use builtan page &<pagenumber> use for conditional format.
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May 21, 2010
how do I count a list of number value eg 1,1,1,1,3,3,6,4 and find the one with maximum number which is 1
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Aug 2, 2012
Below is a column 'ADDR' with the data (single column)
ADDR
--------
/shared/Folder_1 :^BIAdministrator:^BIAuthor:^BIConsumer:BISystemUser:OracleSystemUser:System:weblogic: :F
[Code]....
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Jun 29, 2012
I am required to manipulate a string in this way.For example ABCDEF)* to $ABCDEF). So I should find * and delete it and instead put $ in the beginning of string.
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Jul 22, 2011
I am trying to update the greatest value in a column from a string of other column.
Ex: f the value is shown 10M+16M+25M-DG, then populate 25 only
so for that I had written query as follows:
update ANCHOR set IEL_STRAND_SIZE= greatest(
substr
(REPLACE(REPLACE(REGEXP_REPLACE( F_TYP, '[A-Z]', '' ),'+',','),'-',','),
0,
length(REPLACE(REPLACE(REGEXP_REPLACE( F_TYP, '[A-Z]', '' ),'+',','),'-',','))-1))
The output is given as 10,16,25,but not as 25.so how could i write it?Do I need to implement procedure or arrays for it.
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Jul 11, 2012
How can i identify all the occurences of raise_application_error(-20XXX, '<the message>'); within all database objects, and replace them with other text?
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Dec 5, 2012
Is there a way to find out the ending digits in a string?
Examples of input and outputs:
'ABC123' -> 123
'ABC' -> NULL
'123ABC' -> NULL
'123ABC456' -> 456
'123ABC456QP98' -> 98
I have figured a way to do it by doing Reverse and re-reversing using: reverse(regexp_substr(reverse(p_string), '[ [:digit:]]*'))
But I'm sure there is a way to do it backwards without using reverse function, which I am not able to properly put in the syntax.
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May 16, 2008
How to find out lowercase char in a String in a SQL query
for example
"ORAclE" here c and l are lowercase so how can i find out this condition... is there any build in function in oracle?
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Sep 8, 2011
How to find whether any character in a string is repeating or not
Eg: '123LH563' should return 'YES' , as 3 is repating there
'1234567' sould return 'NO' as there is no character which is repeating
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Sep 4, 2013
I have a requirement, where i need to find and replace values in delimited string. For example, the string is
"GL~1001~157747~FEB-13~ CREDIT~ A~N~ USD~ NULL~".
The 4th column gives month and year. I need to replace it with previous month name. For example:
"GL~1001~ 157747~ JAN-13~ CREDIT~ A~N~USD~NULL~".
I need to do same for last 12 months. I thought of first devide the values and store it in variable and then after replacing it with required value, join it back. I just wanted to know if there is any better way to do it?
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Nov 7, 2011
I want to search for some specific string in packaged procedures source code, and want to list the name of those procedures along with package names.
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Sep 19, 2013
I have a table like mentioned below
create table test1( test_no number, test_description varchar2(100));
insert into test1 values (1,'ABC£¥');
insert into test1 values (2,'BCD£¥');
Now I am selecting from the above table and the expected rest it should have shown is as shown below
TEST1
-----------------------
TEST_NO TEST_DESCRIPTION
1 ABC£¥
2 BCD£¥
But instead of showing the extended ascii characters, it is showing some different characters as shown below
select * from test1;
TEST1
-----------------------
TEST_NO TEST_DESCRIPTION
1 ABCLY
2 BCDLY
I have an requirement where i need to fetch the exact ascii characters for £ and ¥ instead of L and Y respectively.
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Oct 20, 2012
I can't understand >>
1. Number 2 is less than number 100,
2. string '2' is greater than string '100'.
>> Numbers are ordered by numerical value; strings are ordered by alphabetical value. >>
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Jun 28, 2010
If I have a "smart" key in a database, say one for which each byte of the key is meaningful, is it generally a good idea to string together a number of LIKEs with ORs? For example, if I want to select people where the last two bytes of that smart code are in a certain list and write:
where smart_key LIKE '%02'
or smart_key LIKE '%03'
or smart_key LIKE '%07'
or smart_key LIKE '%19'
or smart_key LIKE '%23'
or smart_key LIKE '%30'
or smart_key LIKE '%33'
or smart_key LIKE '%34'
or smart_key LIKE '%41'
etc.
Say I string a lot of those together, with 40 or 50 ORs. Right off the bat is it fair to say that's a bad query for Oracle, or do substrings of this sort generally perform well?
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Apr 27, 2012
I found this query in my sub version repository and really wondering how this working
select to_char(to_date(1000000,'J') ,'JSP') string_value from dual;
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Oct 21, 2012
I am using this Regexp to extract numbers from a string, and I doubt that there is a more efficient way to get this done:
SELECT regexp_replace (regexp_replace ( REGEXp_REPLACE (' !@#$%^&*()_+= '' + 00 SDFKA 324 000 8702 234 | " ' , '[[:punct:]]',''), '[[:space:]]',''), '[[:alpha:]]','') FROM dual
{code}
Is there a more efficient way to get this done ?
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Jul 9, 2012
Im trying to generate this link on my result [URL].....
materialId and materialFolderId are the results of my query.. Im not sure how to combine my results and string on my query..
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Jun 1, 2011
Quote: I have a table(table name is names) with column as name(varchar) . I have the following data for name column.
Miss
Mississ
Mississipp
I would like to find a nearest match for Mississippi, that means sql should return row that contains Mississipp( Row #3)
If I try to find nearest match for Mississirr then sql should return row that has column value Mississ (Row#2)
Is this possible ? Here is the code for table creation and data.
create table names (name varchar2(20));
insert into names values('Miss');
insert into names values('Mississ');
insert into names values('Mississipp');
commit;
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Jan 9, 2012
I am doing a Gross Profit percentage. I want to display zero if the GP% is have negative value.
for example
If GP% shows -75 I want to display as 0.
trunc((sum(total)-(sum(DECODE(po_pur,'',0,PO_PUR))+sum(DECODE(pl_pur,'',0,PL_PUR))+SUM(parts))) / SUM(DECODE(TOTAL,0,1,TOTAL))*100,2) "GP%"
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Dec 6, 2010
I wanna convert the amount of money from number to string such as 144.5 to be one hundred forty four point five is there any function or i have to write my function? How could i put new line in the string?
for example if i have 'SAB Bank' || 'Riyadh'
but i want SAB bank to be displayed in line and Riyadh in line.
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Oct 21, 2012
I am confused with third one.
CODE1. >> Comparing two strings >>
SQL> select greatest('99' ,'100') from dual;
GR
99
2. >> comparing both numbers >>
SQL> select greatest( 99 ,100) from dual;
GR
100
3.>> Comparing string and number >>
SQL> select greatest('99' ,100) from dual;
GR
99
whats the logic behind 99 being returned for thirdone.
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Feb 4, 2012
The code which I am working on consists of an incoming dynamic string which be in the form of binary digits. The max size of the string will be 12 digits. For example, the string can be '111011000001', '000000000000', '111111011111', etc.
I need to find the number of occurences of '111' in the incoming string. Say in the 1st example, result will be 1, in the 2nd example result will be 0, and in the third example, the result will be 3.
I have been trying to capture the string length and replacing the variables '111' to find the number of occurences, but it isn't giving me the result that I want. This is what I have tried
SQL> conn hr/hr
Connected.
SQL> show user
USER is "HR"
[Code]....
I searched the forum and found a similar topic, and following that guideline, I even tried dividing the string with the length of the pattern. It works in some scenarios (the first and second examples mentioned below), while it fails in some scenarios (third example mentioned below)
SQL> select (length('11101110111') - length(replace('11101110111','111','')))/length('111') as occurences from dual;
OCCURENCES
----------
3
SQL> select (length('110111110111') - length(replace('110111110111','111','')))/length('111') as occurences from dual;
OCCURENCES
----------
2
SQL> select (length('111111111111') - length(replace('111111111111','111','')))/length('111') as occurences from dual;
OCCURENCES
----------
SQL>
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Sep 4, 2013
Insert into PROFILE
(INSTANCE, PROFILENAME, USER_DATA, UPDATE_DATE)
Values
(138, 'Test A', 'SRC!-1,ARCHIVE_OPT!-1,DATE_FIELD!155,DATE_RULE!1,DISTINCT!1', TO_DATE('01/20/2005 13:35:33', 'MM/DD/YYYY HH24:MI:SS'));
/
Insert into RULES
(ID, NAME)
Values
(155, 'DATE_TEST');
I want a code something of this sort:
select profilename from PROFILE where user_data like '%DATE_RULE!115%';
Output will be "Test A".Now, this is just a single value from RULES table used to find the data of PROFILE table.I will have to run the query on multiple values of RULES tables to find records containing a string format of sort "DATE_RULE!<rule_no>". How to search on WILD CARDs like these?
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Aug 2, 2007
I have a string like this:
s_list varchar2(234) :=
'asdasd
asfsdf
dsfsdfs
dfsdfs';
How can I find the number of lines in this string? I tried using
INSTR('s_list', '
', 1, 1)
but it gives 0.
Is there any inbuilt function/proc SQL or PL/SQL which can do this?
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Aug 6, 2010
I have created a function that is used for splitting a comma separated string & give the output in tabular form.here is the function
Here I have used CLOB as my input string will be huge(greater than max limit of varchar2)
CREATE OR REPLACE TYPE SPLIT_TBL_CLOB AS TABLE OF CLOB;
CREATE OR REPLACE FUNCTION CSVTOSTRING_CLOB
(
P_LIST CLOB,
P_DEL VARCHAR2 := ','
) RETURN SPLIT_TBL_CLOB PIPELINED
[code]....
But here I am facing 2 problems.
1. The function is not accepting a large string & I am getting the error
ORA-01704: string literal too long
2. The function is going for an infinite loop.
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Nov 5, 2011
I have a table(PSUSEROBJTYPE) with a long field(PTCUSTFORMAT) containing a row value value in the form:
#1|0|0|0|0|#2|1|0|0|1|#3|1|0|0|0|#4|0|0|0|0
Here, I want to update the above field value to a value in the form:
#2|0|0|0|0|#3|1|0|0|1|#4|1|0|0|0|#5|0|0|0|0
This is nothing but finding each occurrence of (#n) in the above string and replacing it by (#n+1). (i.e #1 is replaced by #2,#2 is replaced by #3).
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Oct 4, 2011
I need to concatenate string to the number field in an update statement like this:
update test1 set model_pin = seq_no || '_' || model
where eoc_code like 'AEW%'
When I run this command in sql , I get ERROR at line 1:
ORA-01722: invalid number
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