I'm trying to insert a character from the extended ascii character set. Specifically, there's a company that has an accented e (�) in the name. Right now, the company name doesn't have the e at all, accent or no accent. So I'm trying to do an update, something like
update table1 set company_name='blah�" where company='blah'
It runs, but doesn't do the update. Even when I try to forcefully do an insert (instead of an update) I get nowhere; the accented is simply dropped. So the basic question is, how do you insert extended ascii characters into oracle?
I can't think of a clue how to get the desired results.
I have table column with varchar2 type. I need to convert the strings in this column to ascii values. Now I know Oracle function ascii() converts a character to ascii values. But it just converts the first character of the string and ignore the others. I need to convert the whole string to ascii values. For example, if I need to convert the string "USA", the result should be '858365' (as in U decimal value is 85, S decimal value is 83 and A decimal is 65).
I think I need to use instr() function and also PL/SQL to pass all these strings through a cursor and then use a loop but I'm still confused about it.
I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.
For ex:
The first value fetched from the select query first is ABCDEFG which gets appended to a variable The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG. The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG. The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.
writing that piece of code to append the value fetched which doesn't exactly match with the existing string
I believe we need to use Translate function to get rid of special characters, But I would not be knowing what sort of special charecters which appear in the string, In that case how do I use Translate?
I need to remove the alpha characters from a string, leaving only numbers, but I am getting unexpected results:
SQL> SELECT TRANSLATE('3N', 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', NULL) a FROM DUAL; A -
I thought this would leave the 3 from the 3N, but it is returning an empty string. For my application, the string '3N' could be any length, will only contain letters and numbers, and the letters will always come at the end, but there could be more than one letter
'Net Amount Payable by an Individual', 'Net Amount Payable by an Individual+Tax', 'Total Amount Payable towards Service', 'Total Amount Payable towards Service.+Tax'
I need to extract the first three letters from each word and separate them using an underscore. The output should be as follows for the above strings -
I have a table test with column containing dates, characters and numbers. I have to extract the number part and the three characters before the number . My data looks like :
TEST ID DATA 1 3/12/2007 2 0 3 3/8/2010 ABC 217 4 NONE 5 COLM XYZ 469 6/8/2011 6 LMN 209
I am required to manipulate a string in this way.For example ABCDEF)* to $ABCDEF). So I should find * and delete it and instead put $ in the beginning of string.
How can i identify all the occurences of raise_application_error(-20XXX, '<the message>'); within all database objects, and replace them with other text?
I am currently working on a Data Dictionary project where we need to run a few rules against the give data sources to see if they all comply together.
One of the rule is to check if the no. is negative or not. So for that what I tried to do was to check if first the field is number or not and then check on if it is negative or not.
This is the code I am currently trying on and is not looking good.
SELECT 1 FROM DUAL WHERE decode(DECODE( TRANSLATE('-123.45','-0.123456789',''), NULL, 1,0), 1,substr('-123.45',1,1) ,' ' ) = '-'
I have a requirement, where i need to find and replace values in delimited string. For example, the string is
"GL~1001~157747~FEB-13~ CREDIT~ A~N~ USD~ NULL~".
The 4th column gives month and year. I need to replace it with previous month name. For example:
"GL~1001~ 157747~ JAN-13~ CREDIT~ A~N~USD~NULL~".
I need to do same for last 12 months. I thought of first devide the values and store it in variable and then after replacing it with required value, join it back. I just wanted to know if there is any better way to do it?
Quote: I have a table(table name is names) with column as name(varchar) . I have the following data for name column.
Miss Mississ Mississipp
I would like to find a nearest match for Mississippi, that means sql should return row that contains Mississipp( Row #3)
If I try to find nearest match for Mississirr then sql should return row that has column value Mississ (Row#2) Is this possible ? Here is the code for table creation and data.
create table names (name varchar2(20));
insert into names values('Miss'); insert into names values('Mississ'); insert into names values('Mississipp'); commit;
