replace the first 5 commas with the character '|' in the below string:
'Red, White, Blue, Purple, Pink, Green, Yellow, Gold and many others, like Black and Silver'
I tried:
SELECT regexp_replace('Red, White, Blue, Purple, Pink, Green, Yellow, Gold and many others, like Black and Silver',
',','|',1,5) from dual
but it only replaces the 5th comma.
i have a database column holding first name and last name. I want to find out the special characters and convert it to empty space.
Eg : kishore's 001 ==> kishores 001
: jerryKumar* ==> jerryKumar
I have a function that will replace the contents of the input parameter and replace any non-numeric characters.� I just want to know if there is a more efficient way to code this (oracle 8i or higher).
function strip_non_numeric(p_string in varchar2) return varchar2 is
Result varchar2(100) := '' ;
x_length number;
begin
SELECT LENGTH(p_string) INTO X_LENGTH FROM DUAL;
FOR i in 1..X_LENGTH LOOP
[Code]....
i am working on the oracle 10g.currently i want to build one procedure,where i get a variable which contain character as well as number.my aim in the procedure is to replace all the character like ( a,b..z) in this variable with the number field.
example
suppose i have one variable say
var := 'MALT011000012345MTLCAST001SMT84'
now i want to replace each character say
A with value 23
B with value 56
L with value 99
9 i will get these value form another table).
i will have handle thousands of variable and they can start with any character and they contain character anywhere.
I want to replace numeric values of a specific format with 'X' , find the below example and note that the string in the example only for sample values and the strings may be different.
Eg.
Input String :
Ticket no 12343 , 1234567891234567 , origin-dxb , dest-lhr , 1234 5678 9012 2345 , address - rose wood
bldg 2444 , downtown ,london-33 .
Output string :
Ticket no 12343 , XXXXXXXXXXXXXXXX , origin-dxb , dest-lhr , XXXX XXXX XXXX XXXX , address - rose wood
bldg 2444 , downtown
I have a string. For example "I have too many files. There are 1000 files. I have to delete them." Sometimes the string can be "I have too many files. There are 115003 files. I have to delete them." Whatever the srting is, I need to change the string to "I have too many files. There are 10 files. I have to delete them." replace the "1000" or "115003" to "10". This portion of the string is always an integer. I use Oracle 11G2.
View 6 Replies View RelatedI am using regexp_replace function to replace the string between the double quotes with the first occurance but i am able to replace first occurance but I am not getting remaining string.
For example:
select REGEXP_replace('Parent.addChildByName("DS-Id of OAL(BROBA)")||parent.add("DS-Id of OAL(BROBA)")','["]:print:+:punct::print:*["]','XXXX') from DUAL
O/P: Parent.addChildByName(XXXX)
Expected O/P : Parent.addChildByName(XXXX)||parent.add("DS-Id of OAL(BROBA)")
I am using the oracle 10g, I am trying to write the a sql query by which in a below mention patterns I can replace the digits after a string 'CVV' with X. The no of X will be equal to the no of digits after CVV
1. BTA CVV 8810
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVV498
3. C***CVV VI 569***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV 063/dffddf:dfdfdfd
5. (T) CVV 4671
6. MS-ACEEML/CVV
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES
AFTER a change above data should look like as mentioned below
1. BTA CVV XXXX
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVVXXX
3. C***CVV VI XXX***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV XXX/dffddf:dfdfdfd
5. (T) CVV XXX
6. MS-ACEEML/CVV -- no change for this
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES --- -- no change for this
Initially I tried to find the position of CVV in any string and then from that position take the digit and replace them with X. I tried the below code which is not complete
select REGEXP_INSTR('BTA CVV XXXX','CVV',1,1) from dual;
Years ago, someone created a database in Oracle that was carried over and now sits in Oracle 10g. I am developing an application that queries this database and returns the result as XML.
Many (thousands) of rows have an item description that contains an ampersand. I want each of these pieces of data to have it written as & amp; (had to add a space so it would show up here, but you know what I mean) instead of &, but I don't feel like doing thousands of UPDATEs to change this.
Does Oracle have any global find/replace functions that I can call? I'd rather do one update statement that replaces all occurances of & with & amp; but I can't seem to find a function that will do this.
I'm thinking something that would work like:
UPDATE table SET column1=REPLACE(column1,oldstr,newstr);
I am required to manipulate a string in this way.For example ABCDEF)* to $ABCDEF). So I should find * and delete it and instead put $ in the beginning of string.
View 9 Replies View RelatedI have written one program that inserts one field in table item_master based on existing field,for eg, its like old field is 'HEB240x240x10x17x13000mm, S 275 JR' - and i want to replace the 5 digits before mm i.e 13000 needs to be replaced by 6000 or 4000 based on generated values and the new item will be like 'HEB240x240x10x17x6000mm, S 275 JR' or 'HEB240x240x10x17x4000mm, S 275 JR'.
View 3 Replies View RelatedI want to search for a pattern and replace with a string. I can easily achieve the same in oracle 10g with REGEXP_REPLACE , I want to get the similar solution in 9i.
Eg.
I have to search for a string pattern 1234 5678 9012 6736 , I want to replace the same with XXXX XXXX XXXX XXXX.
I have a requirement, where i need to find and replace values in delimited string. For example, the string is
"GL~1001~157747~FEB-13~ CREDIT~ A~N~ USD~ NULL~".
The 4th column gives month and year. I need to replace it with previous month name. For example:
"GL~1001~ 157747~ JAN-13~ CREDIT~ A~N~USD~NULL~".
I need to do same for last 12 months. I thought of first devide the values and store it in variable and then after replacing it with required value, join it back. I just wanted to know if there is any better way to do it?
how to get last 4 characters in a string. But i don't know the length , for example the string is
abcdefghij
i want only ghij.
notes column having 2000 characters max, i want my string output based on 35 characters, ya i need to replace tag after 30 characters in the string.. I need out put as "hi hello how are you doing out there, similar i need to calculate the sting length and have to split it 35+35+35..
This i tried
select substr(note,1,(instr(note, ' ',35)))||'
'||substr(note,instr(note, ' ',35),(instr(note, ' ',35)))notes from test
I want to replace double space with single space and also remove junk characters from the data. How can I do that?
CREATE TABLE test07013
(
NAME VARCHAR2(50)
);
INSERT INTO VALUES ('WARREN,'); -- REMOVE ","
INSERT INTO VALUES ('CLARK H'); -- REPLACE "DOUBLE SPACE" WITH "SINGLE SPACE"
INSERT INTO VALUES ('BRYAN A.'); -- REMOVE "."
INSERT INTO VALUES ('CARTER JR. ROBERT'); -- REMOVE "."," AND REPLACE "DOUBLE SPACE" WITH "SINGLE SPACE"
how to count different characters from a string ....
View 7 Replies View RelatedI am looking for a SQL query which checks for special character(s) in a string and remove them if any.
for e.g: input string : 'ABCD $ & * # 123 Test'
expected output should be in upper case : 'ABCD123TEST'
we do not know the position of special characters and also what kind of special characters will come as input.
Is there any function to count number of specific character inside string. For example :
my string is 'ABCEF AYZA'
I want to calculate how many 'A' exist in my string. result should be = 3
I have a following table,
create table test1(col1 varchar2(20));
insert into test1 values('4711-3/01');
I believe we need to use Translate function to get rid of special characters, But I would not be knowing what sort of special charecters which appear in the string, In that case how do I use Translate?
I have a table like mentioned below
create table test1( test_no number, test_description varchar2(100));
insert into test1 values (1,'ABC£¥');
insert into test1 values (2,'BCD£¥');
Now I am selecting from the above table and the expected rest it should have shown is as shown below
TEST1
-----------------------
TEST_NO TEST_DESCRIPTION
1 ABC£¥
2 BCD£¥
But instead of showing the extended ascii characters, it is showing some different characters as shown below
select * from test1;
TEST1
-----------------------
TEST_NO TEST_DESCRIPTION
1 ABCLY
2 BCDLY
I have an requirement where i need to fetch the exact ascii characters for £ and ¥ instead of L and Y respectively.
A sample query to check whether a string contains 2 upper characters and numbers are present in that character using regular_exp .
View 12 Replies View RelatedI am on 11g.
I need to remove the alpha characters from a string, leaving only numbers, but I am getting unexpected results:
SQL> SELECT TRANSLATE('3N', 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', NULL) a FROM DUAL;
A
-
I thought this would leave the 3 from the 3N, but it is returning an empty string. For my application, the string '3N' could be any length, will only contain letters and numbers, and the letters will always come at the end, but there could be more than one letter
VALID INPUT samples:
4
25
11F
361NG
8ABC
I have some strings like
'Net Amount Payable by an Individual',
'Net Amount Payable by an Individual+Tax',
'Total Amount Payable towards Service',
'Total Amount Payable towards Service.+Tax'
I need to extract the first three letters from each word and separate them using an underscore. The output should be as follows for the above strings -
Net_Amo_Pay_by_an_Ind
Net_Amo_Pay_by_an_Ind_Tax
Tot_Amo_Pay_tow_Ser
Tot_Amo_Pay_tow_Ser_Tax
I request to let me know the way to get the ouput as mentioned.
I have a table test with column containing dates, characters and numbers. I have to extract the number part and the three characters before the number . My data looks like :
TEST
ID DATA
1 3/12/2007
2 0
3 3/8/2010 ABC 217
4 NONE
5 COLM XYZ 469 6/8/2011
6 LMN 209
My expected results should look like :
ID DATA
1
2
3 ABC 217
4
5 XYZ 469
6 LMN 209
create table test
(
name varchar2(50),
descd varchar2(50)
)
insert into test values ('kethlin','da,dad!tyerx');
insert into test values ('tauwatson','#$dfegr');
insert into test values ('jennybrown','fsa!!trtw$ fda');
insert into test values ('tauwatson','#$dfegr ,try');
how do I get the first three characters and last three characters from name field and remove all the junk characters from descd field?
so my o/p be like;
Quote:('ketlin','dadadtyerx')
('tauson','dfegr')
('jenown','fsatrtw fda')
('tauson','dfegr try')
I have 70 materialized views where I need to replace the FROM SCHEMA1 TO FROM SCHEMA2...To quickly to do the fix for all the 70 views..
SELECT REPLACE (QUERY, 'schema1', 'schema2' )FROM USER_MVIEWS ;
But It throws me an error that Number cannot be replace.
I have this error (and solution):
ORA-02085: database link string connects to string
Cause: a database link connected to a database with a different name. The connection is rejected.
Action: create a database link with the same name as the database it connects to, or set global_names=false.
Where should I set global_names=false ?
I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.
For ex:
The first value fetched from the select query first is ABCDEFG which gets appended to a variable
The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.
writing that piece of code to append the value fetched which doesn't exactly match with the existing string
show an ex to use string buffer for select statemnt
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