SQL & PL/SQL :: String Split / Replace Based On Character Length
Jun 19, 2013
notes column having 2000 characters max, i want my string output based on 35 characters, ya i need to replace tag after 30 characters in the string.. I need out put as "hi hello how are you doing out there, similar i need to calculate the sting length and have to split it 35+35+35..
This i tried
select substr(note,1,(instr(note, ' ',35)))||'
'||substr(note,instr(note, ' ',35),(instr(note, ' ',35)))notes from test
Where I am copying the data from one database to another I am getting this error.
ORA-01458: invalid length inside variable character string
This is applicable for only character string.
The source Database is Oracle9i Release 9.2.0.8.0 - 64bit Production PL/SQL Release 9.2.0.8.0 - Production CORE 9.2.0.8.0 Production TNS for HPUX: Version 9.2.0.8.0 - Production NLSRTL Version 9.2.0.8.0 - Production
The destination database is Oracle9i Enterprise Edition Release 9.0.1.1.1 - Production PL/SQL Release 9.0.1.1.1 - Production CORE 9.0.1.1.1 Production TNS for 32-bit Windows: Version 9.0.1.1.0 - Production NLSRTL Version 9.0.1.1.1 - Production
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I want to replace numeric values of a specific format with 'X' , find the below example and note that the string in the example only for sample values and the strings may be different.
I have a string. For example "I have too many files. There are 1000 files. I have to delete them." Sometimes the string can be "I have too many files. There are 115003 files. I have to delete them." Whatever the srting is, I need to change the string to "I have too many files. There are 10 files. I have to delete them." replace the "1000" or "115003" to "10". This portion of the string is always an integer. I use Oracle 11G2.
If i try to find length of the string with more than 4000 char in SQL Developer it throws error "ORA-01704: string literal too long". if anything i need to SET in preference.
select length('string with more than 4000 char) from dual;
I have created a VIEW with a column containing user-defined aggregated values(stores the output in varchar2 data type). Some of the records exceed the maximum limit, for example varchar2(4000). I was suggested a PL/SQL function to check the length and build a string if necessary..
CREATE OR REPLACE FUNCTION SUBURL(col1 IN VARCHAR2, col2 IN varchar2) RETURN varchar2
[Code].....
Here, I got the following error,
Error(4,25): PLS-00103: Encountered the symbol "," when expecting one of the following: := . ( @ % ; not null range default character
How do i split a string based on a space. And then create a view with three columns of that split string.
For example if i have a table with Full name as a column how do i split that string and create a view with firstname, middlename, lastname as column names with the split string as data.
I am trying to split comma separated string. My table has more than 5 lacks data. I have tried the following SQL but its taking more than 5 minutes. Any Alternative solution to return data quickly ?
SELECT REGEXP_SUBSTR(order_id, '[^,]+', 1, LEVEL) order_id FROM order_detail CONNECT BY REGEXP_SUBSTR(order_id,'[^,]+',1,LEVEL) IS NOT NULL
SELECT REGEXP_SUBSTR(order_id, '[^,]+', 1, LEVEL) order_id FROM order_detail CONNECT BY LEVEL <= LENGTH(order_id) - LENGTH(REPLACE(order_id, ',')) + 1
I am having data in this format in my column 1234~2345~3456~4567.
I need a query to split the data in the column based on the identifier '~',so that i can pick out the value after the second occurrence of the identifier.
I want to read content from blob column and write into file using dbms_output.put_line. See below code. i am getting PLS-00215: String length constraints must be in range (1 .. 32767) error.
set serveroutput on DECLARE l_file UTL_FILE.FILE_TYPE;
[Code]....
the length of the blob column is 1081656. so i have changed in raw(1081656) in above code. after the execution, i am getting the below error PLS-00215: String length constraints must be in range (1 .. 32767).
I am using regexp_replace function to replace the string between the double quotes with the first occurance but i am able to replace first occurance but I am not getting remaining string.
For example:
select REGEXP_replace('Parent.addChildByName("DS-Id of OAL(BROBA)")||parent.add("DS-Id of OAL(BROBA)")','["]:print:+:punct::print:*["]','XXXX') from DUAL
O/P: Parent.addChildByName(XXXX)
Expected O/P : Parent.addChildByName(XXXX)||parent.add("DS-Id of OAL(BROBA)")
I am using the oracle 10g, I am trying to write the a sql query by which in a below mention patterns I can replace the digits after a string 'CVV' with X. The no of X will be equal to the no of digits after CVV
AFTER a change above data should look like as mentioned below
1. BTA CVV XXXX 2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVVXXX 3. C***CVV VI XXX*** 4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV XXX/dffddf:dfdfdfd 5. (T) CVV XXX 6. MS-ACEEML/CVV -- no change for this 7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES --- -- no change for this
Initially I tried to find the position of CVV in any string and then from that position take the digit and replace them with X. I tried the below code which is not complete
select REGEXP_INSTR('BTA CVV XXXX','CVV',1,1) from dual;
