PL/SQL :: Replace The Digits After A String CVV With X?
Jul 13, 2012
I am using the oracle 10g, I am trying to write the a sql query by which in a below mention patterns I can replace the digits after a string 'CVV' with X. The no of X will be equal to the no of digits after CVV
1. BTA CVV 8810
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVV498
3. C***CVV VI 569***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV 063/dffddf:dfdfdfd
5. (T) CVV 4671
6. MS-ACEEML/CVV
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES
AFTER a change above data should look like as mentioned below
1. BTA CVV XXXX
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVVXXX
3. C***CVV VI XXX***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV XXX/dffddf:dfdfdfd
5. (T) CVV XXX
6. MS-ACEEML/CVV -- no change for this
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES --- -- no change for this
Initially I tried to find the position of CVV in any string and then from that position take the digit and replace them with X. I tried the below code which is not complete
select REGEXP_INSTR('BTA CVV XXXX','CVV',1,1) from dual;
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Dec 5, 2012
Is there a way to find out the ending digits in a string?
Examples of input and outputs:
'ABC123' -> 123
'ABC' -> NULL
'123ABC' -> NULL
'123ABC456' -> 456
'123ABC456QP98' -> 98
I have figured a way to do it by doing Reverse and re-reversing using: reverse(regexp_substr(reverse(p_string), '[ [:digit:]]*'))
But I'm sure there is a way to do it backwards without using reverse function, which I am not able to properly put in the syntax.
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Jun 26, 2012
I want to replace numeric values of a specific format with 'X' , find the below example and note that the string in the example only for sample values and the strings may be different.
Eg.
Input String :
Ticket no 12343 , 1234567891234567 , origin-dxb , dest-lhr , 1234 5678 9012 2345 , address - rose wood
bldg 2444 , downtown ,london-33 .
Output string :
Ticket no 12343 , XXXXXXXXXXXXXXXX , origin-dxb , dest-lhr , XXXX XXXX XXXX XXXX , address - rose wood
bldg 2444 , downtown
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Sep 26, 2013
I have a string. For example "I have too many files. There are 1000 files. I have to delete them." Sometimes the string can be "I have too many files. There are 115003 files. I have to delete them." Whatever the srting is, I need to change the string to "I have too many files. There are 10 files. I have to delete them." replace the "1000" or "115003" to "10". This portion of the string is always an integer. I use Oracle 11G2.
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Apr 7, 2011
replace the first 5 commas with the character '|' in the below string:
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I tried:
SELECT regexp_replace('Red, White, Blue, Purple, Pink, Green, Yellow, Gold and many others, like Black and Silver',
',','|',1,5) from dual
but it only replaces the 5th comma.
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Nov 12, 2012
I am using regexp_replace function to replace the string between the double quotes with the first occurance but i am able to replace first occurance but I am not getting remaining string.
For example:
select REGEXP_replace('Parent.addChildByName("DS-Id of OAL(BROBA)")||parent.add("DS-Id of OAL(BROBA)")','["]:print:+:punct::print:*["]','XXXX') from DUAL
O/P: Parent.addChildByName(XXXX)
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Jan 9, 2007
Years ago, someone created a database in Oracle that was carried over and now sits in Oracle 10g. I am developing an application that queries this database and returns the result as XML.
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Does Oracle have any global find/replace functions that I can call? I'd rather do one update statement that replaces all occurances of & with & amp; but I can't seem to find a function that will do this.
I'm thinking something that would work like:
UPDATE table SET column1=REPLACE(column1,oldstr,newstr);
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Jun 29, 2012
I am required to manipulate a string in this way.For example ABCDEF)* to $ABCDEF). So I should find * and delete it and instead put $ in the beginning of string.
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Feb 13, 2012
I have written one program that inserts one field in table item_master based on existing field,for eg, its like old field is 'HEB240x240x10x17x13000mm, S 275 JR' - and i want to replace the 5 digits before mm i.e 13000 needs to be replaced by 6000 or 4000 based on generated values and the new item will be like 'HEB240x240x10x17x6000mm, S 275 JR' or 'HEB240x240x10x17x4000mm, S 275 JR'.
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Jun 20, 2012
I want to search for a pattern and replace with a string. I can easily achieve the same in oracle 10g with REGEXP_REPLACE , I want to get the similar solution in 9i.
Eg.
I have to search for a string pattern 1234 5678 9012 6736 , I want to replace the same with XXXX XXXX XXXX XXXX.
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Sep 4, 2013
I have a requirement, where i need to find and replace values in delimited string. For example, the string is
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I need to do same for last 12 months. I thought of first devide the values and store it in variable and then after replacing it with required value, join it back. I just wanted to know if there is any better way to do it?
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Jun 19, 2013
notes column having 2000 characters max, i want my string output based on 35 characters, ya i need to replace tag after 30 characters in the string.. I need out put as "hi hello how are you doing out there, similar i need to calculate the sting length and have to split it 35+35+35..
This i tried
select substr(note,1,(instr(note, ' ',35)))||'
'||substr(note,instr(note, ' ',35),(instr(note, ' ',35)))notes from test
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Mar 4, 2010
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eg: - 23115645
after masking should be - xxxx5645,
create table test1(x varchar2(12))
insert into test1 values('34567745')
/
insert into test1 values('438765311')
/
insert into test1 values('1112345')
/
commit
[Code].....
y should store value of x in such a way that no matter what the size of x is (7 characters or 9), we should see only the last 4, but the remaining should be masked with xxxx
I tried the above update, but using substr, i am able to get this if x has 9 characters
not sure how to achieve this if x has 7, or 4 characters
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Jul 16, 2010
I have 70 materialized views where I need to replace the FROM SCHEMA1 TO FROM SCHEMA2...To quickly to do the fix for all the 70 views..
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But It throws me an error that Number cannot be replace.
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Dec 6, 2008
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This is input data in hex value:-
STARTTIME : 080b1317021a
This is decimal value after convert from hex to decimal:-
STARTTIME : 081119230226
My problem is how could i convert hex to decimal in oracle? Below are my coding:-
case
when substr(LOAD_NGNSM.STARTTIME, 1, 2) not between '00' and '99'
or substr(LOAD_NGNSM.STARTTIME, 3, 2) not between '01' and '12'
or substr(LOAD_NGNSM.STARTTIME, 5, 2) not between '01' and '31'
or substr(LOAD_NGNSM.STARTTIME, 7, 2) not between '00' and '59'
or substr(LOAD_NGNSM.STARTTIME, 9, 2) not between '00' and '59'
[code]....
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Aug 11, 2008
How Do I Create An Interactive Program That Will Add Numbers Between Two Given Digits Using Sql. For Example:
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Enter End Num: 15
Then It Does 1+2+3+...........+14
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Apr 10, 2013
I have a table like:
0035987850 P
0035987851 P
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35987850 P
35987851 P
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Mar 10, 2011
How to write SQL query for selecting all the values (numbers) in the table which has 3 digit after decimal point.
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123.22
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From this I need only
300.456
1234.344
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Oct 9, 2012
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Mar 28, 2011
There is a text item on my form with NUMBER data type. I want to force the user to enter exactly 3 digits in to that text item. My current FORMAT MASK is set to 990. But this allows user to enter even a single digit where as my requirement is user should enter exactly 3 digits. Can we achieve this by changing the FORMAT MASK property?
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Jun 19, 2012
I have this error (and solution):
ORA-02085: database link string connects to string
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Action: create a database link with the same name as the database it connects to, or set global_names=false.
Where should I set global_names=false ?
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Mar 14, 2013
I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.
For ex:
The first value fetched from the select query first is ABCDEFG which gets appended to a variable
The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.
writing that piece of code to append the value fetched which doesn't exactly match with the existing string
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May 9, 2008
show an ex to use string buffer for select statemnt
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Sep 14, 2010
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ex.
col1
y
y
n
n
output:
col1
n
n
y
y
How can i do that ?
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Jan 4, 2011
I have a table MOM i.e. Minutes of meeting where important points in a meeting are captured. Now these points may include words like, "don't" or "can't" which will be recorded first in a text file and later copied to the table MOM. Rest of the details are unimportant. All I want to know is how do I enter these words without getting the ORA-01756 error? Do I need to always correct them before entering or is there perhaps another way?
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Jan 23, 2012
TestCase
DROP TABLE test ;
CREATE TABLE test (id NUMBER, cnt_str VARCHAR2(200));
INSERT INTO test (id, cnt_str) VALUES
(1,'AKRN000002,1451-1473,00000A,74,AKRN000002,1475-14791000000A,8010AKRN000002,1481-1492,00000A,9310AKRN000002,1494-1500')
[code]...
The requirement is in each of the string where there is comma after the number and the number is prefixed by "-" character,
the comma after the number should be replaced by '10'.
For example in the second record where ID = 2,
CNT_STR is '00000B,1-251000000D,26-32,ADTW000301,2858-2875'.
In this string -32, should become -3210 and resulting string should be '00000B,1-251000000D,26-3210ADTW000301,2858-2875'
Expected Result.
ID CNT_STR
-------- -------------------------------------
1 AKRN000002,1451-14731000000A,7410AKRN000002,1475-14791000000A,8010AKRN000002,1481-14921000000A,9310AKRN000002,1494-1500
2 00000B,1-251000000D,26-3210ADTW000301,2858-2875
3 AKRN000001,1126-12001000000B,501-525
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Sep 19, 2010
For example i've a select query as below.
1.select store_name, store_id from stores
2.select store_name, (select store_id from inventory where store_id=<somevalue>) from stores
3. select store_name, store_id from stores
where store_id in(select store_id from stores1)
based on above examples i need to replace all the columns(oly the column names not the column names in the subquery) in a sql query .
is there is any oracle function to achieve this?
and the result shud be as follows if i replace with STORE_DET.
1.select STORE_DET from stores
2.select STORE_DET from stores
3. select STORE_DET from stores
where store_id in(select store_id from stores1)
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Jan 18, 2013
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Jan 16, 2011
So many of the queries in our database query by an account but an account is allowed to vary by prefix and so queries are written similar to account like '%suffix'
Our DBA has rejected the use of context indexes and friends to deal with this.
as an aside and I'm probably going to regret going into this much detail but our model is
A->>B->>C
typically the queries want to fetch C's for a customer defined by A.account
A, B, C are all partitioned with partition key created_date
however, only C is typically queried with created_date as a qualifier. A and B are related by joins from A->>B and B->>C
when queries are written to use '%' leading wildcards often it results in a full table scan across multiple partitions. on any given day all we care about are the most recent C's for the customer where customer is defined by A.account.
I recently had an idea whereby fields such as A.Account could also be kept(denormalized) in the C table
the idea is if the queries were written to use C.account like '%bla' instead of A.account like '%bla' then because C is always qualified with the partition key ie. C.created_date that would at worst result in a full partition scan only. this is considerably less expensive than doing a full table scan of A. The IO cost of doing that is huge.
populating the C.account is a simple before insert or update trigger. when you insert a C you have a foreign key to a B and B has a foreign key to A. A and B are always created before any C is seen for any given C. When a C is seen A and B already exist in the database.
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Dec 19, 2012
I am looking for oracle query to replace repeating description with -DO-. Sample Data is:
CREATE TABLE SCOTT.ITAX
(
VDATE DATE,
[Code].....
VDATE DESCRIPTION ITAX AMOUNT
--------- -------------------------------------------------- ---------- ----------
14-NOV-12 CANOLA OIL 3 3500
25-NOV-12 CANOLA OIL 3 2500
10-DEC-12 CANOLA OIL 3 3300
01-NOV-12 CANOLA SEES 3 5600
10-NOV-12 CANOLA SEES 3 5500
01-DEC-12 CANOLA SEES 3 5400
6 rows selected.
Required Output is:
VDATE DESCRIPTION ITAX AMOUNT
--------- -------------------------------------------------- ---------- ----------
14-NOV-12 CANOLA OIL 3 3500
25-NOV-12 -DO- 3 2500
10-DEC-12 -DO- 3 3300
01-NOV-12 CANOLA SEES 3 5600
10-NOV-12 -DO- 3 5500
01-DEC-12 -DO- 3 5400
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