How Do I Create An Interactive Program That Will Add Numbers Between Two Given Digits Using Sql. For Example:
Enter Start Num: 0
Enter End Num: 15
Then It Does 1+2+3+...........+14
How to write SQL query for selecting all the values (numbers) in the table which has 3 digit after decimal point.
For example say A is the table it has following values
200.24
300.456
123.22
1234.344
From this I need only
300.456
1234.344
I have a table test with column containing dates, characters and numbers. I have to extract the number part and the three characters before the number . My data looks like :
TEST
ID DATA
1 3/12/2007
2 0
3 3/8/2010 ABC 217
4 NONE
5 COLM XYZ 469 6/8/2011
6 LMN 209
My expected results should look like :
ID DATA
1
2
3 ABC 217
4
5 XYZ 469
6 LMN 209
Is there any difference between include program header before CREATE OR REPLACE PACKAGE statement and program header after CREATE OR REPLACE PACKAGE statement
View 4 Replies View Relatedi just want to know how can i create a procedure in the program unit and assign the output to a field in the report.
View 7 Replies View RelatedI have a Cobol program that call C program above
#include stdlib
EXEC SQL INCLUDE SQLCA;
EXEC SQL BEGIN DECLARE SECTION;
char *uid = "puntos/puntos@cmrdesar";
[code]....
Are something wrong in C programm ? Pro*C code from vouters.dyndns.org/tima/OpenVMS-Cobol-C-Cobol_ passing_ variable_ number_ of_ arguments_to_C.html
I have a requirement where I have a value stored in varchar2(12), and no matter what the size of data, I should mask all the characters except the last 4
eg: - 23115645
after masking should be - xxxx5645,
create table test1(x varchar2(12))
insert into test1 values('34567745')
/
insert into test1 values('438765311')
/
insert into test1 values('1112345')
/
commit
[Code].....
y should store value of x in such a way that no matter what the size of x is (7 characters or 9), we should see only the last 4, but the remaining should be masked with xxxx
I tried the above update, but using substr, i am able to get this if x has 9 characters
not sure how to achieve this if x has 7, or 4 characters
Actually I got a data in hex values and i want to convert it to datetime format. But before i convert the hex value into datetime format, i must convert the hex values into decimal val first for each 2 digits of hex values. This is an example of the input data:-
This is input data in hex value:-
STARTTIME : 080b1317021a
This is decimal value after convert from hex to decimal:-
STARTTIME : 081119230226
My problem is how could i convert hex to decimal in oracle? Below are my coding:-
case
when substr(LOAD_NGNSM.STARTTIME, 1, 2) not between '00' and '99'
or substr(LOAD_NGNSM.STARTTIME, 3, 2) not between '01' and '12'
or substr(LOAD_NGNSM.STARTTIME, 5, 2) not between '01' and '31'
or substr(LOAD_NGNSM.STARTTIME, 7, 2) not between '00' and '59'
or substr(LOAD_NGNSM.STARTTIME, 9, 2) not between '00' and '59'
[code]....
I am using the oracle 10g, I am trying to write the a sql query by which in a below mention patterns I can replace the digits after a string 'CVV' with X. The no of X will be equal to the no of digits after CVV
1. BTA CVV 8810
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVV498
3. C***CVV VI 569***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV 063/dffddf:dfdfdfd
5. (T) CVV 4671
6. MS-ACEEML/CVV
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES
AFTER a change above data should look like as mentioned below
1. BTA CVV XXXX
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVVXXX
3. C***CVV VI XXX***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV XXX/dffddf:dfdfdfd
5. (T) CVV XXX
6. MS-ACEEML/CVV -- no change for this
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES --- -- no change for this
Initially I tried to find the position of CVV in any string and then from that position take the digit and replace them with X. I tried the below code which is not complete
select REGEXP_INSTR('BTA CVV XXXX','CVV',1,1) from dual;
Is there a way to find out the ending digits in a string?
Examples of input and outputs:
'ABC123' -> 123
'ABC' -> NULL
'123ABC' -> NULL
'123ABC456' -> 456
'123ABC456QP98' -> 98
I have figured a way to do it by doing Reverse and re-reversing using: reverse(regexp_substr(reverse(p_string), '[ [:digit:]]*'))
But I'm sure there is a way to do it backwards without using reverse function, which I am not able to properly put in the syntax.
I have a table like:
0035987850 P
0035987851 P
0035987852 P
I would like to update removing 00 in the first column. So after update to have:
35987850 P
35987851 P
35987852 P
I am facing an issue here at my workplace, there is a report developed in report builder , the user wants to see the digits in arabic.
View 4 Replies View RelatedThere is a text item on my form with NUMBER data type. I want to force the user to enter exactly 3 digits in to that text item. My current FORMAT MASK is set to 990. But this allows user to enter even a single digit where as my requirement is user should enter exactly 3 digits. Can we achieve this by changing the FORMAT MASK property?
View 6 Replies View RelatedI have the following set of numbers that i am passing in as one input into a stored procedure.
234,456,234,456,567
Now i want to take this list of numbers and use it in an IN statement:
select * from table where column_a in (P_INPUT);
however, when i try this, it give me an invalid error. I have tried inserting single quote around each value and get the same invalid error. I tried a To_char around my column, which solved the error, but it never finds a match!
I want to get 10 random numbers from existing 100 numbers. How can we get/generate random numbers ?
for example I have a table with customer ID, customer Name, having 100 record. We want 10 customers ID randomly from that 100 record not repeated any number. Have any command or procedure for that ?
I have a column of datatype varchar2
this column may contain char or may contain number or may contain both
some values in this column are only number is there any function or any other way to get those column that are only number
Earlier, we had a discussion how to generate the permutations. generating the code for combinations
For eg: if I have input as [1,2,3,4,5] then 5c2 = 20 combinations should be generated as pairs
1,2
1,3
1,4
1,5
2,3
2,4
2,5
3,4
3,5
4,5
Total of 10 combinations
I am creating a function to sum five numbers (less 1). Is it possible to have an array of numbers in an SQL function, and how would this be implemented?
Here is the screenshot of my output (I cannot embed links until 5 posts!): flic.kr/p/eaSHBP
CREATE OR REPLACE FUNCTION sumfivenumbers ( n1 NUMBER, n2 NUMBER, n3 NUMBER, n4 NUMBER, n5 NUMBER)
RETURN NUMBER
IS
Sumnums NUMBER;
BEGIN
SELECT SUM(n1+n2+n3+n4+n5-1) INTO Sumnums FROM DUAL;
DBMS_OUTPUT.PUT_LINE(Sumnums);
RETURN 1;
END sumfivenumbers;
/
SELECT sumfivenumbers(5,5,5,5,5) AS "Five Numbers less 1" FROM DUAL;
I need to find the top two values value for each ID Number:
CREATE TABLE TABLE_1
(ID number (8),
NUMBER_1 number (2),
NUMBER_2 number (2),
NUMBER_3 number (2),
NUMBER_4 number (2));
INSERT INTO TABLE_1
VALUES
('12345679','30','25','30','05');
INSERT INTO TABLE_1
VALUES
('99999999','30','25','15','05');
Desired Result:
ID Number 1st 2nd
12345679 30 30
99999999 30 25
I have a requirement to display numbers as equivalent alphabets , like if the stored value is 1 then it should display as 'A' ,2 means 'B' ,is there a way to find out.
CREATE TABLE APS ( ITEM_NO NUMBER, ITEM_NAME VARCHAR2(12))
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (1,'TEST1');
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (2,'TEST2');
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (3,'TEST3');
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (4,'TEST4');
-- The output to be is.
item_no , item_name
A TEST1
B TEST2
C TEST3
D TEST4
I tried to convert numbers to words, it shows the below error.
SQL*Plus: Release 10.2.0.1.0 - Production on Fri Jul 6 11:00:29 2012
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Connected to: Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - Production With the Partitioning, OLAP, Data Mining and Real Application Testing options
SQL> SELECT TO_CHAR (TO_DATE (2447834, 'j'), 'jsp') FROM DUAL;
TO_CHAR(TO_DATE(2447834,'J'),'JSP')
---------------------------------------------------------------------------
two million four hundred forty-seven thousand eight hundred thirty-four
SQL> SELECT TO_CHAR (TO_DATE (244783400, 'j'), 'jsp') FROM DUAL;
SELECT TO_CHAR (TO_DATE (244783400, 'j'), 'jsp') FROM DUAL
*
ERROR at line 1: ORA-01830: date format picture ends before converting entire input string
SQL>
Here i face probelm that he numbers must be follw by DOT "." , this is not correct if the statment only conatines numbers without DOT that not extract. As the
SELECT REGEXP_SUBSTR ( 'hello to 8898989898989 jkjk nnnm mnj'
, '([0-9]+.[0-9]*)' || -- Starts with digit(s) (may or may not have digits after .)
'|' || -- or
'(.[0-9]+)' -- starts with decimal point
) AS result
FROM dual
;
but mean i have to add . after numbers . as follow
SELECT REGEXP_SUBSTR ( 'hello to 8898989898989 jkjk nnnm mnj'
, '([0-9]+.[0-9]*)' || -- Starts with digit(s) (may or may not have digits after .)
'|' || -- or
'(.[0-9]+)' -- starts with decimal point
) AS result
FROM dual
;
but this is not right
i want to extract numbers without DOT also.
How to print even numbers 1 to 10.without using the MOD Function
View 17 Replies View RelatedI am trying to run this script:
Update ACT.CUSTOMER_CLIENT_REFERENCE
Set ORIGINAL_SOURCE_FG = 'N',
CANADIAN_ULTIMATE_REFERENCE_FG = 'N',
LUDT = SYSDATE,
CLT_NO = (Select clt_no from client.client where clt_no between 701885 and 705287)
Where Exists (Select 1 from client.client where clt_ofc_no = 19 and clt_no between 701885 and 705287)
But the CLT_NO = .... line is giving me this error: ORA-01427: single-row subquery returns more than one row
what i am trying to do is insert all the client numbers between 701885 and 705287 into ACT.CUSTOMER_CLIENT_REFERENCE
I have a table with three columns: terminal, place and batch. How can I check for missing batches?
select * from transactions;
terminal place batch
84812
84813
84814
84816
84821
84823
84824
84825
I found a message which explain how to spell out numbers to words. I'm french and the purpose of my question is how to convert numbers to word (to print cheque) but in french the function found in the newsgroup was :
select decode( sign( &num ), -1, 'Negative ', 0, 'Zero', NULL ) ||
decode( sign( abs(&num) ), +1, to_char( to_date( abs(&num),'J'),'Jsp') )
from dual
/
I'm afraid but i don't undaunted how pass my number to this function (&num ???)
create table t (
number_from number,
number_to number);
insert into t values(1,3);
insert into t values(5,9);
insert into t values(10,15);
commit;
I need to create a stored function that could find/return missing numbers between number_from and number_to for each record in table t.
For example:
Number_fromNumber_to missing
13
594 from previous record, this record is supposed to start from 4
I am developing a form where I need to add Numbers.In fact we have a bag of Cones that contain 24 cones.In normal calculation when I add numbers for example
5.24 Plus 5.24 it will give the result 10.48
I Need the appropriate method to calculate if I add these two numbers it should give the result 5.24 Plus 5.24 the result should be 12
I have a table A with 10000 records with values as 1 to 10000. Table B has columns as range,number1,number2. Totally there are three rows as
ROW1=range1,1,100 & ROW2=range2,300,500 & ROW3=range3,800,900
I need to select all records from table A when it is between any one of the three rows from table B.
acheive the below result.
Select * from result;
res
===
3
3
3
3
3
0
3
3
3
0
3
0
output:
I would like to get res1 using SQL query.
resres1
31
32
33
34
35
00
31
32
00
31
32
33
34
00
.. ....