SQL & PL/SQL :: Assigning Numbers To The List?
Apr 10, 2012
acheive the below result.
Select * from result;
res
===
3
3
3
3
3
0
3
3
3
0
3
0
output:
I would like to get res1 using SQL query.
resres1
31
32
33
34
35
00
31
32
00
31
32
33
34
00
.. ....
View 9 Replies
ADVERTISEMENT
Jan 3, 2013
I am trying to set the intial value of "Select List" to APP_USER the only first time when the page loads and use it to filter the report, any other time once the page is loaded the user should select another value from the Select List then click the submit button to display the details in the report, i tried to achieve this by setting "select List" creating LOV for Select List then set default=APP_USER but now the problem any time you click the submit button it reset the "Select List" from selected value back to default so how can you achieve this to set the value of Select List only the first time the page loads?
View 1 Replies
View Related
Jul 13, 2011
I have a table test with column containing dates, characters and numbers. I have to extract the number part and the three characters before the number . My data looks like :
TEST
ID DATA
1 3/12/2007
2 0
3 3/8/2010 ABC 217
4 NONE
5 COLM XYZ 469 6/8/2011
6 LMN 209
My expected results should look like :
ID DATA
1
2
3 ABC 217
4
5 XYZ 469
6 LMN 209
View 7 Replies
View Related
Jun 14, 2011
Can I assign the outcome of a select query to a defined variable
like
var=select emp id from emp where empname='ddf'
View 5 Replies
View Related
Feb 4, 2013
I have a table with 200k entries, which has ~12k unique combination of columns that I wish to assign an ID to. My real world problem is with addresses and street components (of which nulls are allowed); but this should be a reasonable example.
DROP TABLE tt;
CREATE TABLE tt AS
SELECT ROWNUM id,
CASE
WHEN MOD(ROWNUM, 107) = 0 THEN NULL
ELSE MOD(ROWNUM, 101)
END
c1,
CASE
[Code]...
Now I have 3 ways to assigned an ID (fill the SID column).
The first is congruent with the method most commonly used, but seems especially slow in this case. I think this is due to the COALESCE/TO_CHAR usage. Can this be optimized?
DECLARE
CURSOR c1 IS
SELECT a.*, sid_seq.NEXTVAL sid
FROM (SELECT DISTINCT c1, c2 FROM tt) a;
BEGIN
FOR s IN c1 LOOP
UPDATE tt d
[Code]...
The second I've made relies on the usage of a temp table, which I really don't like, but it is faster; so that is something at least.
CREATE TABLE ttt AS
SELECT a.*, sid_seq.NEXTVAL sid
FROM (SELECT DISTINCT c1, c2 FROM tt) a;
[Code]...
The third discards the sequence, and uses dense_rank. This allows us to use the ID (which might have an index, whereas c1 and c2 will not).
MERGE INTO tt d
USING (SELECT id, (SELECT COALESCE(MAX(sid), 317) FROM tt) + DENSE_RANK() OVER (ORDER BY c1, c2) sid FROM tt) s
ON (d.id = s.id)
WHEN MATCHED THEN
UPDATE SET d.sid = s.sid
The ideal solution would use the SEQUENCE, not use a temporary table and match/merge/update based on ID, and be 'fast'; but I cannot conceive of such a solution; does one exist? What would you do?
View 2 Replies
View Related
Dec 14, 2012
if it is possible to assign a varchar2(14) index to a pl/sql table while fetching bulk data with bulk collect.my requirement is to assign varchar2(14) index to a pl/sql table so that i can directly reach to my record by index and process the record further.
further i need to run a loo on this ( for processing each record)my database version is 11.2.01.0.
View 4 Replies
View Related
Jan 23, 2013
in my procedure i am creating a sequence on the fly, i am preparing the name with some passed parameters like below
v_seq_name := 'seq_'||loadid||v_table_name;
execute immediate 'CREATE SEQUENCE '||v_seq_name||' MINVALUE 1 MAXVALUE 999999999999999999999999999 START WITH 1 increment by 1 cache 20';
and now after doing some operations i need to assign the current value of sequence to a number variable i tried following but not working
1) v_curr_value : = v_seq_name.currval ;
2) select v_seq_name||'.nextval' into v_curr_value from dual;
how i can get the value in plsql block.
View 4 Replies
View Related
Sep 23, 2008
I am writing a code in Proc as
<code>
#define SMSDUN_LANGID_LEN 10
-- other statements
EXEC SQL BEGIN DECLARE SECTION
char dbLanguageId[SMSDUN_LANGID_LEN + 1];
EXEC SQL END DECLARE SECTION
-- other statements
EXEC SQL EXECUTE
BEGIN
SELECT LANGUAGE_ID -- Length of this column is 10
INTO :dbLanguageId
FROM CUSTOMERATTRIBUTES
[code]...
While executing the above command, it is giving error as "ORA-01480: trailing null missing from STR bind value". Its working in some oracle versions but not in other. where exactly the problem is.
View 1 Replies
View Related
Sep 27, 2011
I am creating the Dynamic list but when i am compiling the form it gives the compilation error "No list elements defined for the list item".
I can eliminate it by entering the dummy list element but this dummy value will be displayed at form run time.
View 1 Replies
View Related
Dec 14, 2011
Im trying to list the products list of a client grouped by type of the product. Ex:
product type
prod.A acid
prod.B flavour
prod.C acid
prod.D cleaner
prod.E flavour
I want to list something as:
Acid
Prod.A
Prod.C
Cleaner
prod.D
Flavour
prod.B
prod.E
View 1 Replies
View Related
Oct 30, 2011
DECLARE
CURSOR GRP IS
SELECT RowNum rn, Letter_Group_ID||'-'||A_Desc AName,Letter_Group_ID
FROM Hrs_Group;
BEGIN
Clear_list('Letter_Group_ID');
FOR I IN GRP LOOP
Add_List_Element('Letter_Group_ID',I.rn,I.AName,I.Letter_Group_ID);
end loop;
END;
FRM-30351: No list elements defined for list item.
List LETTER_GROUP_ID
View 4 Replies
View Related
Apr 22, 2013
I just want to list and group all my tables that are linked together by constraints. I just want my tables to be able to be listed together as one particular database. my tables are , CUSTOMER, ORDER_INFO, ORDER_LINE, PRODUCT. They're all linked together by way of constraint and I want to list and print them all together as one DB. HOW DO I put them all in one schema and then also list them all together and print/illustrate them as one. also, I tried to import them into their own scheme but i ran into a series of probs regaurding the .dmp file being read.
View 2 Replies
View Related
Oct 12, 2007
I have the following set of numbers that i am passing in as one input into a stored procedure.
234,456,234,456,567
Now i want to take this list of numbers and use it in an IN statement:
select * from table where column_a in (P_INPUT);
however, when i try this, it give me an invalid error. I have tried inserting single quote around each value and get the same invalid error. I tried a To_char around my column, which solved the error, but it never finds a match!
View 6 Replies
View Related
Jul 1, 2010
I want to get 10 random numbers from existing 100 numbers. How can we get/generate random numbers ?
for example I have a table with customer ID, customer Name, having 100 record. We want 10 customers ID randomly from that 100 record not repeated any number. Have any command or procedure for that ?
View 3 Replies
View Related
Jul 25, 2010
I have a column of datatype varchar2
this column may contain char or may contain number or may contain both
some values in this column are only number is there any function or any other way to get those column that are only number
View 3 Replies
View Related
Nov 1, 2010
Earlier, we had a discussion how to generate the permutations. generating the code for combinations
For eg: if I have input as [1,2,3,4,5] then 5c2 = 20 combinations should be generated as pairs
1,2
1,3
1,4
1,5
2,3
2,4
2,5
3,4
3,5
4,5
Total of 10 combinations
View 8 Replies
View Related
Apr 13, 2013
I am creating a function to sum five numbers (less 1). Is it possible to have an array of numbers in an SQL function, and how would this be implemented?
Here is the screenshot of my output (I cannot embed links until 5 posts!): flic.kr/p/eaSHBP
CREATE OR REPLACE FUNCTION sumfivenumbers ( n1 NUMBER, n2 NUMBER, n3 NUMBER, n4 NUMBER, n5 NUMBER)
RETURN NUMBER
IS
Sumnums NUMBER;
BEGIN
SELECT SUM(n1+n2+n3+n4+n5-1) INTO Sumnums FROM DUAL;
DBMS_OUTPUT.PUT_LINE(Sumnums);
RETURN 1;
END sumfivenumbers;
/
SELECT sumfivenumbers(5,5,5,5,5) AS "Five Numbers less 1" FROM DUAL;
View 7 Replies
View Related
Jul 6, 2012
I need to find the top two values value for each ID Number:
CREATE TABLE TABLE_1
(ID number (8),
NUMBER_1 number (2),
NUMBER_2 number (2),
NUMBER_3 number (2),
NUMBER_4 number (2));
INSERT INTO TABLE_1
VALUES
('12345679','30','25','30','05');
INSERT INTO TABLE_1
VALUES
('99999999','30','25','15','05');
Desired Result:
ID Number 1st 2nd
12345679 30 30
99999999 30 25
View 7 Replies
View Related
Jul 6, 2013
I have a requirement to display numbers as equivalent alphabets , like if the stored value is 1 then it should display as 'A' ,2 means 'B' ,is there a way to find out.
CREATE TABLE APS ( ITEM_NO NUMBER, ITEM_NAME VARCHAR2(12))
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (1,'TEST1');
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (2,'TEST2');
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (3,'TEST3');
INSERT INTO APS (ITEM_NO,ITEM_NAME) VALUES (4,'TEST4');
-- The output to be is.
item_no , item_name
A TEST1
B TEST2
C TEST3
D TEST4
View 23 Replies
View Related
Jul 6, 2012
I tried to convert numbers to words, it shows the below error.
SQL*Plus: Release 10.2.0.1.0 - Production on Fri Jul 6 11:00:29 2012
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Connected to: Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - Production With the Partitioning, OLAP, Data Mining and Real Application Testing options
SQL> SELECT TO_CHAR (TO_DATE (2447834, 'j'), 'jsp') FROM DUAL;
TO_CHAR(TO_DATE(2447834,'J'),'JSP')
---------------------------------------------------------------------------
two million four hundred forty-seven thousand eight hundred thirty-four
SQL> SELECT TO_CHAR (TO_DATE (244783400, 'j'), 'jsp') FROM DUAL;
SELECT TO_CHAR (TO_DATE (244783400, 'j'), 'jsp') FROM DUAL
*
ERROR at line 1: ORA-01830: date format picture ends before converting entire input string
SQL>
View 4 Replies
View Related
Sep 18, 2012
Here i face probelm that he numbers must be follw by DOT "." , this is not correct if the statment only conatines numbers without DOT that not extract. As the
SELECT REGEXP_SUBSTR ( 'hello to 8898989898989 jkjk nnnm mnj'
, '([0-9]+.[0-9]*)' || -- Starts with digit(s) (may or may not have digits after .)
'|' || -- or
'(.[0-9]+)' -- starts with decimal point
) AS result
FROM dual
;
but mean i have to add . after numbers . as follow
SELECT REGEXP_SUBSTR ( 'hello to 8898989898989 jkjk nnnm mnj'
, '([0-9]+.[0-9]*)' || -- Starts with digit(s) (may or may not have digits after .)
'|' || -- or
'(.[0-9]+)' -- starts with decimal point
) AS result
FROM dual
;
but this is not right
i want to extract numbers without DOT also.
View 6 Replies
View Related
Mar 1, 2012
How to print even numbers 1 to 10.without using the MOD Function
View 17 Replies
View Related
May 12, 2010
I am trying to run this script:
Update ACT.CUSTOMER_CLIENT_REFERENCE
Set ORIGINAL_SOURCE_FG = 'N',
CANADIAN_ULTIMATE_REFERENCE_FG = 'N',
LUDT = SYSDATE,
CLT_NO = (Select clt_no from client.client where clt_no between 701885 and 705287)
Where Exists (Select 1 from client.client where clt_ofc_no = 19 and clt_no between 701885 and 705287)
But the CLT_NO = .... line is giving me this error: ORA-01427: single-row subquery returns more than one row
what i am trying to do is insert all the client numbers between 701885 and 705287 into ACT.CUSTOMER_CLIENT_REFERENCE
View 6 Replies
View Related
May 11, 2012
I have a table with three columns: terminal, place and batch. How can I check for missing batches?
select * from transactions;
terminal place batch
84812
84813
84814
84816
84821
84823
84824
84825
View 5 Replies
View Related
Mar 14, 2002
I found a message which explain how to spell out numbers to words. I'm french and the purpose of my question is how to convert numbers to word (to print cheque) but in french the function found in the newsgroup was :
select decode( sign( &num ), -1, 'Negative ', 0, 'Zero', NULL ) ||
decode( sign( abs(&num) ), +1, to_char( to_date( abs(&num),'J'),'Jsp') )
from dual
/
I'm afraid but i don't undaunted how pass my number to this function (&num ???)
View 12 Replies
View Related
Feb 16, 2010
create table t (
number_from number,
number_to number);
insert into t values(1,3);
insert into t values(5,9);
insert into t values(10,15);
commit;
I need to create a stored function that could find/return missing numbers between number_from and number_to for each record in table t.
For example:
Number_fromNumber_to missing
13
594 from previous record, this record is supposed to start from 4
View 24 Replies
View Related
Feb 5, 2011
I am developing a form where I need to add Numbers.In fact we have a bag of Cones that contain 24 cones.In normal calculation when I add numbers for example
5.24 Plus 5.24 it will give the result 10.48
I Need the appropriate method to calculate if I add these two numbers it should give the result 5.24 Plus 5.24 the result should be 12
View 7 Replies
View Related
Sep 21, 2011
I have a table A with 10000 records with values as 1 to 10000. Table B has columns as range,number1,number2. Totally there are three rows as
ROW1=range1,1,100 & ROW2=range2,300,500 & ROW3=range3,800,900
I need to select all records from table A when it is between any one of the three rows from table B.
View 13 Replies
View Related
Aug 5, 2011
how can show this query in this picture
select round(15.555,2) from dual appear final result 15.55 only
and this query don't be this result 15.56
because i have filed and always Decimal numbers be (15.555,2)
i want only result appear after two numbers and no rounded the numbers
View 2 Replies
View Related
Jan 30, 2013
Using DB 10.2.0.5, I've encountered a strange behavior today while trying to compare ORA_ROWSCN with a previous SCN stored in a column.
SELECT
h.id HID,
h.ora_rowscn HSCN,
o.id OID,
o.scn OSCN,
[code]......
1157 rows While casting o.scn to a number gives me another resultset (this one is correct):
SELECT
h.id HID,
h.ora_rowscn HSCN,
o.id OID,
o.scn OSCN,
h.ora_rowscn-o.scn DIFF
[code]......
2114 rows I got the same result if I use NVL(o.scn,0) rather than TO_NUMBER(o.scn). I can't find out why this happens. Obviously, the ">" condition doesn't match when the difference is too small.
AFAIK, ora_rowscn is a NUMBER while my "scn" column is a NUMBER(12) (which should be sufficient to store my DB or remote DB's SCN).
View 9 Replies
View Related