How to write SQL query for selecting all the values (numbers) in the table which has 3 digit after decimal point.
For example say A is the table it has following values
200.24
300.456
123.22
1234.344
From this I need only
300.456
1234.344
Actually I got a data in hex values and i want to convert it to datetime format. But before i convert the hex value into datetime format, i must convert the hex values into decimal val first for each 2 digits of hex values. This is an example of the input data:-
This is input data in hex value:-
STARTTIME : 080b1317021a
This is decimal value after convert from hex to decimal:-
STARTTIME : 081119230226
My problem is how could i convert hex to decimal in oracle? Below are my coding:-
case
when substr(LOAD_NGNSM.STARTTIME, 1, 2) not between '00' and '99'
or substr(LOAD_NGNSM.STARTTIME, 3, 2) not between '01' and '12'
or substr(LOAD_NGNSM.STARTTIME, 5, 2) not between '01' and '31'
or substr(LOAD_NGNSM.STARTTIME, 7, 2) not between '00' and '59'
or substr(LOAD_NGNSM.STARTTIME, 9, 2) not between '00' and '59'
[code]....
How Do I Create An Interactive Program That Will Add Numbers Between Two Given Digits Using Sql. For Example:
Enter Start Num: 0
Enter End Num: 15
Then It Does 1+2+3+...........+14
I have a small prob. I want an amount to be always 2 decimal places. I've used the Round function - Round(amount,2). the problem is that if the amount is only to 1 dp like 1.4. the above function will return 1.4. I want it to appear like 1.40
View 2 Replies View Related how to create a function that will multiply the number when the number has more than 3 decimal point.
Example.
123.012 - multiply by 10
123.0123 - multiply by 100
123.01234 - miltiply by 1000
Column A is the result of the number being multiplied according to decimal point.
Column B contains the multiplier used in column A.
I would like to use the REGEX_LIKE to check a number with up to two digits and at least one decimal point: Ex.10.11.1112 This is what I have so far.
if regexp_like(v_expr, '^(d{0,2})+(.[0-9]{1})?$') t
I have a question on Round Function
Round(###.###,1)
Will the round function output depend on 2nd digit after decimal point also or not?
how can show this query in this picture
select round(15.555,2) from dual appear final result 15.55 only
and this query don't be this result 15.56
because i have filed and always Decimal numbers be (15.555,2)
i want only result appear after two numbers and no rounded the numbers
I need to find the top two values value for each ID Number:
CREATE TABLE TABLE_1
(ID number (8),
NUMBER_1 number (2),
NUMBER_2 number (2),
NUMBER_3 number (2),
NUMBER_4 number (2));
INSERT INTO TABLE_1
VALUES
('12345679','30','25','30','05');
INSERT INTO TABLE_1
VALUES
('99999999','30','25','15','05');
Desired Result:
ID Number 1st 2nd
12345679 30 30
99999999 30 25
I have a table test with column containing dates, characters and numbers. I have to extract the number part and the three characters before the number . My data looks like :
TEST
ID DATA
1 3/12/2007
2 0
3 3/8/2010 ABC 217
4 NONE
5 COLM XYZ 469 6/8/2011
6 LMN 209
My expected results should look like :
ID DATA
1
2
3 ABC 217
4
5 XYZ 469
6 LMN 209
I have a requirement where I have a value stored in varchar2(12), and no matter what the size of data, I should mask all the characters except the last 4
eg: - 23115645
after masking should be - xxxx5645,
create table test1(x varchar2(12))
insert into test1 values('34567745')
/
insert into test1 values('438765311')
/
insert into test1 values('1112345')
/
commit
[Code].....
y should store value of x in such a way that no matter what the size of x is (7 characters or 9), we should see only the last 4, but the remaining should be masked with xxxx
I tried the above update, but using substr, i am able to get this if x has 9 characters
not sure how to achieve this if x has 7, or 4 characters
I am using the oracle 10g, I am trying to write the a sql query by which in a below mention patterns I can replace the digits after a string 'CVV' with X. The no of X will be equal to the no of digits after CVV
1. BTA CVV 8810
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVV498
3. C***CVV VI 569***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV 063/dffddf:dfdfdfd
5. (T) CVV 4671
6. MS-ACEEML/CVV
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES
AFTER a change above data should look like as mentioned below
1. BTA CVV XXXX
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVVXXX
3. C***CVV VI XXX***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV XXX/dffddf:dfdfdfd
5. (T) CVV XXX
6. MS-ACEEML/CVV -- no change for this
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES --- -- no change for this
Initially I tried to find the position of CVV in any string and then from that position take the digit and replace them with X. I tried the below code which is not complete
select REGEXP_INSTR('BTA CVV XXXX','CVV',1,1) from dual;
Is there a way to find out the ending digits in a string?
Examples of input and outputs:
'ABC123' -> 123
'ABC' -> NULL
'123ABC' -> NULL
'123ABC456' -> 456
'123ABC456QP98' -> 98
I have figured a way to do it by doing Reverse and re-reversing using: reverse(regexp_substr(reverse(p_string), '[ [:digit:]]*'))
But I'm sure there is a way to do it backwards without using reverse function, which I am not able to properly put in the syntax.
I have a table like:
0035987850 P
0035987851 P
0035987852 P
I would like to update removing 00 in the first column. So after update to have:
35987850 P
35987851 P
35987852 P
I am facing an issue here at my workplace, there is a report developed in report builder , the user wants to see the digits in arabic.
View 4 Replies View RelatedThere is a text item on my form with NUMBER data type. I want to force the user to enter exactly 3 digits in to that text item. My current FORMAT MASK is set to 990. But this allows user to enter even a single digit where as my requirement is user should enter exactly 3 digits. Can we achieve this by changing the FORMAT MASK property?
View 6 Replies View RelatedI have a field in a table that is declared in the CREATE statement as an INT datatype. However, when I query that table using vb.net, the value comes back as a decimal.
How do you declare a field in Oracle as a true integer data type?
I have a table with column amount as decimal(11,2). I want to store the values as shown below
15.30
but it stores as
15.3
Is it possible to store the value in 15.30?
What would be the syntax if I want to use use '999G999G990D00' to show only two decimal points for outstanding_receipt_value in the following
((declared_quantity - delivered_qty) * po_unit_price) outstanding_receipt_value
I am using Oracle Forms 6i. In my program unit i write into a .CSV and .TXT File. Here if the amount is 100.00 then it prints as 100 only. That is if the 2nd decimal digit is 0 it doesnt print it.
For example
10.00 -->10
10.01--> 10.01
10.10-->10.1
10.12-->10.12
I used to_char(nvl(&amount,0),'9999999.99') so if query select to_char(nvl(10.10,0),'9999999.99') from dual, then i get the output as 10.10.
Do you think this is a problem with Oracle forms or SQL or the formatting of .TXT & .CSV.
I have an amount field and I want the o/p in the format of $9,999,999.99
like for 1500 it should display $1,500.00
for 25000 it should display $25,000.00
for 25000000 it should display $25,000,000.00
Test case
add comma from last 3rd position ,and append a $ in the start with two decimal places
Recently i have started working on PLSQL coding. I have a requirement. Either error or un-processed record count is 90% of to be processed records then the script has to fail. Currently I am having a situation where error count is 1 and total to be processed is also 1.
in the below
V_ERR is error count
V_UPS is un processed count
V_PROCESSED_COUNT is total to be processed.
I am expecting PASS result but it is giving FAIL.
DECLARE
V_ERR NUMBER:=0;
V_UPS NUMBER:=0;
V_PROCESSED_COUNT NUMBER:=0;
NIN NUMBER;
BEGIN
V_PROCESSED_COUNT:=1;
[Code] .......
If I perform a Query as below
SELECT SUM(total_amt) FROM Amont_dtls WHERE id=10;
It's giving me the value as
2.08166817117217E-19
The values in total_amount column for ID=10 is 0.01 and -0.01..Actually it should return 0.If I use the query like
SELECT SUM(0.01-0.01) FROm Amont_dtls WHERE id=10;
Then I am getting 0.Why it's a variation.And also the data type of the column is NUMBER.If I use
SELECT TRUNC(SUM(total_amt)) FROm Amont_dtls WHERE id=10;
Then I am getting 0.But some other ID's decimal values are truncating.
Ex: If i Use TRUNC
Instead of 28781947.48 it's showing 28781947
Instead of 590874.5 it's showing 590874
In oracle 9i, I have a table and i inserted the more then 3 records and while inserting each records i have created the save point. But, now i rollback to that particular save point, the whole transaction get roll backed.
Here the similar example what i have tried using SQL Developer Eg:
insert into dept (deptid,dept_name) values (3,'Purchase');
savepoint aa;
insert into dept (deptid,dept_name) values (4,'IT');
savepoint bb;
insert into dept (deptid,dept_name) values (5,'System');
savepoint cc;
rollback to bb;
Using Oracle SQL Developer 2.1.1.64 to run the queries & Oracle 11g.
I have two numbers in two colomns of an oracle table(colomn a & colomn b). I am trying to divide colomn a/colomn b and putting the results in colomn c & also in colomn d (all in the same table) using update commands
Eg: UPDATE MTOTABLE_PWELD pw SET pw.WELDO=(pw.pipe_length/12000);
But here is the real issue. In colomn d I only need the integer portion of the division value.
For example , when I divide colomn a/colomn b , let us assume that we are getting a value of 2.56. Then I want the value of 2 to go to colomn d.
I tried round((colomn a/colomn b),0). But it rounds off 2.56 to 3. I dont want that. I need the exact integer portion of the value to be seperated.
i have a column
NUMBER(13,4)
when i insert 234.000
in show only 234
where as when i insert 234.12
i shows 234.12
is there any setting by which i can show 234.0000
CREATE TABLE TEST ( CREDIT_BALANCE VARCHAR2(11 BYTE), AWARDS_BALANCE VARCHAR2(11 BYTE) )
Insert into TEST(CREDIT_BALANCE, AWARDS_BALANCE)
Values ('1678.09', '1678.9');
Insert into TEST(CREDIT_BALANCE, AWARDS_BALANCE)
[Code]....
From valid records from test table those two columns,need to be insert into test1 table. We should validate the decimal values while selecting from test table.
using regexp.
In a control file, the code is as follows:
load data
infile 'C:\Documents and Settings\xxxxx\Desktop\abc.txt'
APPEND
PRESERVE BLANKS
INTO TABLE table1
[code]...
When I run the above control file in sqlldr, I'm getting the error as
Record 1: Rejected - Error on table table1, column column3.
ORA-01481: invalid number format model
In the table the column3 data type is NUMBER(6,2).: The column size in table is 6 and position of column3 in control file is only 4. Also if possible let me know how the same data (send me 2 dummy records) which exactly works for the above control file especially for column3 where decimal number comes in the flat file.
For generating the flat file, for column3, i'm using LPAD(:value,4,0) in the select query column list.
IF I have Salary Table,In that Salary Table,How to retrieve 6 decimal place of data .
View 16 Replies View RelatedI want to convert decimal number 44 to character(" ' " i.e single quotation);
I have already tried to_char function but it's not working.