i have table name order table . in that i have column name install date,order date.
the difference bet ween order date and install date should be greate than or equal to 3 working days.
fri and sat are holidays.
i need one query to find the difference betwwen orderdate and install date is greate than 3 working days
I have a query that uses a function to find the business days between two dates.It sums the total number of days between two dates per employee to find the total days for the past 30, 90, or 365 days.
The problem is that the query takes 21 second to return the last 30 days.Over 70 second to return the last 90 days and over 140 second to return the last 365 days.Do you know how I could tune the query to return faster? Below is the query for the last 30 days:
select dwt_emp_id, SUM((SELECT GET_BDAYS(DWT_DATE,DWT_CREATE_DATE) FROM DUAL))
from dwt_dvt_work_time where dwt_create_date > sysdate - 30
and dwt_hours > 4 and dwt_usr_uid_created_by <> -1 group by dwt_emp_id order by dwt_emp_id
Here's the function:
CREATE FUNCTION get_bdays (d1 IN DATE, d2 IN DATE)
RETURN NUMBER
IS total_days NUMBER(11,2);
holiday_days NUMBER(11,2);
[code]....
format of dtActivityStartDate/dtActivityFinishDate: 2010-09-17 14:50:51.150 Note: Both dtActivityStartDate/dtActivityFinishDate
vcActivityName = Process Request
usdFuncTimeCalc (vcActivityName,dtActivityStartDate, dtActivityFinishDate)
i need to calculate time elasped for that type of activity following are the rules:
(If Process Request is the activity)
Working Days: Monday through Saturday
Hours of Operation: 9AM 5PM
only working hours of day need to the counted like for example if it is sep 15 11 Am is dtActivityStartDate & Sep 17 is dtActivityFinishDate is 10 Am. then time elapsed is 11am to 5pm on sep 15 , 9 to 5 on sep 16 & 9 to 10 on sep 17 so total should be
6+ 8 + 1 = 15 hours + minutes.
format of date time: 2010-09-17 14:50:51.150
vcActivityName = Process Request
Don't worry about process request..
I need a similar function to determinate difference between two dates, but i need other business hours; Monday - Friday: 9:00 - 21:00 (this is OK)Saturday: 09:00 - 14:00 (and this is my problem, how to add this condition in this function)
View 4 Replies View Relatedsetting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.
CODESELECT
To_Date(need_date, 'YYYYMMDD') Need_Dt,
To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Biggest_Date,
To_Date(need_date, 'YYYYMMDD') - To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Date_Diff
FROM tableT
WHERE
need_date <= (Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END)
ORDER BY Date_Diff ASC
how do i can make oracle function for the following vb6 function.
This function is used for calculating working days between two date.
****************************************
Public Function Work_Days(BegDate As Variant, EndDate As Variant) As Integer
' Note that this function does not account for holidays.
Dim WholeWeeks As Variant
Dim DateCnt As Variant
Dim EndDays As Integer
On Error GoTo Err_Work_Days
BegDate = DateValue(BegDate)
EndDate = DateValue(EndDate)
WholeWeeks = DateDiff("w", BegDate, EndDate)
DateCnt = DateAdd("ww", WholeWeeks, BegDate)
[code]......
how to caluclate days between two dates of single timestamp filed and with this
query
Select * from m_activity_transaction where actn_opp_id in (
Select actn_opp_id from m_activity_transaction where ACTN_ACTV_ID = 218
Group by actn_opp_id
[code]...
and i nedd to caluclate no.of days between two dates like 27-JAN-12 11.06.20.000000 AM and 08-FEB-12 05.32.54.000000 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
I want Oracle stored function/procedure to calculate number of working days between two dates. We need to exclude Firdays and Saturdays as there are weekend holidays and also exclude official holidasy that lie between two dates.
View 7 Replies View RelatedI want to pull out the output only when Day is 1 and 2 and 3. I don't want if either Day is 1 or Day is 2 or Day is 3 is present.
Test Case
--Creat Table
create table dummy_name
(name varchar2(5) not null,
day number(3) not null);
--Insert Values
insert into dummy_name values ('A', 1);
insert into dummy_name values ('B', 2);
insert into dummy_name values ('C', 3);
insert into dummy_name values ('B', 1);
insert into dummy_name values ('B', 2);
insert into dummy_name values ('C', 1);
[code]...
I want to write a query that lists last 11 days. I tried the following query using CONNECT BY...
SQL> SELECT MIN_DT + LEVEL - 1 DAYS FROM
(
SELECT TRUNC(SYSDATE -10) MIN_DT, TRUNC(SYSDATE) MAX_DT FROM DUAL
)
CONNECT BY LEVEL <= MAX_DT - MIN_DT + 1;
DAYS
--------------
20100514000000
For some reason it gives only the first day.. But this one works -
SQL> SELECT MIN_DT + LEVEL - 1 DAYS FROM
(
WITH MYDUAL AS (
SELECT 1 FROM DUAL
)
SELECT TRUNC(SYSDATE -10) MIN_DT, TRUNC(SYSDATE) MAX_DT FROM MYDUAL
)
CONNECT BY LEVEL <= MAX_DT - MIN_DT + 1;
DAYS
--------------
20100514000000
20100515000000
20100516000000
20100517000000
20100518000000
20100519000000
20100520000000
20100521000000
20100522000000
20100523000000
20100524000000
11 rows selected. I am not able to understand what is the difference between the two queries! Why is the second query able to do what the first query cannot?
I have a table which contains two columns containing the range of some products. These range are alphanumeric and i want to calculate the count of this range by a query. .
test case:
CREATE TABLE MARRIAGE_FILE_NAME
(
START_SERIAL_NO VARCHAR2(10 BYTE) NOT NULL,
END_SERIAL_NO VARCHAR2(10 BYTE) NOT NULL,
CATCODE VARCHAR2(10 BYTE) NOT NULL,
[code]....
Is there any Oracle query I can run to determine the "number of days since the last backup"? SQL Server provides this data but I cant seem to find the equivalent for Oracle. Looks like there may be some information like this via RMAN tables and if so I want to create the simplest query possible to obtain that information.
View 3 Replies View RelatedI am trying to get the last 7 days of record from today date, this query runs every night and I always want the last 7 days. Example - today is 3/13/2013 so I want record from 3/7/2013 to 3/13/2013 and tomorrow it would be 3/8/2013 to 3/14/2013
Here is my query, dont mind the ****,$$$ or ####
SELECT INFORMENT.PRODUCT_OFFER_PURCHASE.*******_#######, INFORMENT.INVOLVED_PARTY.INVOLVED_PARTY_ID, To_Char(INFORMENT.PRODUCT_OFFER_PURCHASE.DATE_ADDED, 'YYYYMMDD'), INFORMENT.DEPOSIT_$$$$$$$.BAL_LEDGER_CURRENT, INFORMENT.PRODUCT_OFFER_PURCHASE.INTEREST_RATE, To_Char(INFORMENT.PRODUCT_OFFER_PURCHASE.DATE_OPEN, 'YYYYMMDD'), To_Char(INFORMENT.PRODUCT_OFFER_PURCHASE.DATE_CLOSE, 'YYYYMMDD'), INFORMENT.PRODUCT_OFFER_PURCHASE.*******_STATUS_CODE, [code]..........
I have a problem with a query. I have a table employee with data as
emp_id date day working_ind
1 01-Jan-2011 Mon Y
1 02-Jan-2011 Tue Y
1 03-Jan-2011 Wed Y
1 04-Jan-2011 Thu Y
1 05-Jan-2011 Fri Y
1 06-Jan-2011 Sat N
1 07-Jan-2011 Sun N
1 09-Jan-2011 Tue Y
Sundays/ Monday/ any public holiday the working_ind will be N. If the emp is absent on one day then there will be no record entered in the table (e.g. 8th jan there is no record). Each table has only one year data.
I need to retrieve for all employees when they worked for 30 consecutive days without being absent which does not include sat/ Sunday / holidays.
Its like:
-- i need to order by emp_id and date
-- get oly the data with working_ind as Y
-- make sure that i get 30 consecutive days (from what ever i get above) where no days data is missing
I tried using lag and inner join but it does not seem to be working.
I have a following requirement in SQL -
Requirement -
I need to list the purchase Ordrers which are not closed.
my sql query should pull if the PO is not closed in 30,90 and 150 days.
It should be shown only on 3oth,90th and 150th day only even the Purchase order is not closed on 33rd day.
We have a requirement where we need to pay allowance for the employees based on their number of working days. Say for example if an employee worked from 03/Mar/2012 to 05/Apr/2012.
We have a fixed value for per month 300 Dirhams. But the Number of Days on March s 31 and Number of days in April is 30. So per day allowance for March day would be 300/31 and April would be 300/30.
We are looking for logic opr query which calculates first eh number of days in each month ( across months) and then calculate as below
Number of Working days in March is 31 - 3 + 1 = 29
Allowance A1 = (300 * 29 )/31
Number of Working days in April is 5 ( this also needs to find logical I am guess )
Allowance A2 = (300 * 5 )/30
Then A1 + A2.
The A(n) would be the total allowance where provided the number of month across.
I've below tables.
create table tst_link (parent_pid number(5),
child_pid number(5)
);
insert into tst_link (1, 2);
[Code]....
For each parent pid i need to calculate total miles (including the child_pid also).
Required Output
PARENT_PID TOTAL_MILES
----------- ------------
1 48
4 100
8 125
I have a need to query a real time production database to return a set of results that spans a three day period. When the three days are consecutive it's easy but sometimes there is a 1 or two day gap between the days. For example I'm querying results from a group of people that work between Tuesday and Saturday. On a Wednesday I need t produce a set of results that spans Tuesday of the current week, and Saturday and Friday of the previous week; on Thursday I need to produce a set of results that that spans Wednesday and Tuesday of the current week and Saturday of the previous week.I'm using SQL Developer to execute the code.
View 7 Replies View RelatedI have installed Oracle Database 11g.2 by database configuration assistant on windows XP as and adminstrator on my laptop(no connection to network),but when I want to create database I face this warning: error securing database control ,Datatbase control has been brought up in non-secure mode . to secure the database conntrol execute following command....(error is attached).
View 7 Replies View RelatedI have been trying to construct a query in Oracle that allows me to do the following:
For example if I have the data below:
EmpNo DOB SickDays
Alex 445 15/06/1985 7
Tom 778 22/08/1981 4
James 992 07/10/1978 5
I need to write and a query to lists the employee number and the amount of days sick that they have had and also add a column that compares the number of sick days to the average number of suck days by ALL employees.
I can calculate the average sick days etc, but It wont see to allow me to find the difference between that and the amount of sick days that each person has had. I have tried this many ways and have not been able to come up with a solution.
Using Oracle 11gR2 on windows 7 client. I have a question on calculating sum() on multiple columns on different columns and store the results in a view. Unfortunately I could not post the problem here as it keeps on giving error "Sorry, this content is not allowed", without telling where or what it is! So I had to post it in the stack-overflow forum, here is the link: [URL] .........
View 6 Replies View Relatedwant to write Procedure to return weeks and days from given set of days.
let suppose we have 72 days to return weeks and days then return should be 7 weeks and 2 days.Can i use date function Or ?
I need to calculate first business day of a given month . Below is complete explanation
Business day=sould not include weekends and holidays.
In a table say ACTIVITY_XX I have all the month begin dates say 01-JAN-2010,01-FEB-2010,01-MAR-2010,01-APR-2010 and so on..and I have a HOLIDAY table where all the holidays are stored.
So using the above info I need to calculate the first business day for a given month. I guess this cannot be done by using a simple SQL query? I was wondering how could it be written using a PL/SQL function.
I'll be passing the month begin date as parameter..so the function should return the first business day for that month.
I have a field in Customers table called shipeddate....
I wnat to check the number of hours an item which has a shipeddate is in the store room to the current datetime...
But the business hrs of the store room are from 8am-5pm..
So when a shipped date is 4pm on MOnday
and i am checking on 9 am Tuesday the number of hrs shud be 1(4-5 of Monday)+1(8-9 of tuesday) =2hrss..
How can i achieve this...
i have business units for which i have multiple department ids so just wanted to have dept ids order by business units
View 12 Replies View RelatedWe need some transformation rules on Source employee table which comes from SAP and want to load in Target table.Basic idea is we need to calculate time when position was not held by sub owner so . . . Etc
Source looks like:
POSITION_TCD START_DT END_DT SUBTYPE POSI_HOLDER
Example 1:
10005822 10/16/2003 11/20/2008 A008 105404
10005822 10/16/2003 3/31/2009 A999 105404
10005822 6/23/2008 7/5/2009 A008 124530
10005822 11/21/2008 8/31/2009 A008 105404
10005822 8/31/2009 4/16/2010 A008 105323
10005822 4/19/2010 12/31/9999 A999 131995
10005822 7/5/2010 12/31/9999 A008 131995
Example 2:
10084408 5/3/2010 12/31/9999 A008 130591
10084408 3/21/2011 5/17/2011 A008 132725
10084408 5/3/2010 1/2/2011 A999 130591
After business rules data should look like:
Target
Example 1:
POSITION_TCD POSI_HOLDER SUBS_OWNER EMP_ASSI_TYPE START_DT END_DT
10005822 105404 105404 Hold=Subs 10/16/2003 11/20/2008
10005822 124530 105404 Hold<>Subs 6/23/2008 3/31/2009
10005822 124530 No Substantive No Substan 4/1/2009 7/5/2009
10005822 105404 No Substantive No Substan 11/21/2008 8/31/2009
10005822 105323 No Substantive No Substan 8/31/2009 4/16/2010
10005822 No Holder 131995 No Holder 4/19/2010 7/4/2010
10005822 131995 131995 Hold=Subs 7/5/2010 12/31/9999
Example 2:
10084408 130591 130591 Hold=Subs 5/3/2010 1/2/2011
10084408 130591 No Substantive No Substan 1/3/2011 12/31/9999
10084408 132725 No Substantive No Substan 3/21/2011 5/17/2011
I want to try installing Oracle E-business suite on Mandriva But when I try e.g. domainame I get blank.
A) How can I check my domainname ?How can I set it?Here is the hosts file
[Select all] [Show/ hide]
127.0.0.1 localdomain
192.168.0.2 david.domain.com david
I have been asked to see why a sister company cannot access multiple business areas through a single responsibility. At present, if they log in through a GL responsibility they can see all GL folders, items and the returned data. If they then go to the AP business area, they can see the folders and items, but when they run a report they get an error message 'Query returned no data' - but if they run the same query using an AP responsibility they get the correct results. I have looked at their user set up, and it seems fine i.e. has access to all business areas and required priveledges.
View 4 Replies View RelatedI need to know if a customer appears at least 4 consecutive days. Here's an example of data
CLI_ID , DATE
-------------------------
123 , 2010/10/01
123 , 2010/10/04
123 , 2010/10/05
123 , 2010/10/06
123 , 2010/10/07
123 , 2010/10/08
123 , 2010/10/10
456 , 2010/10/01
456 , 2010/10/02
456 , 2010/10/03
456 , 2010/10/06
456 , 2010/10/07
456 , 2010/10/08
456 , 2010/10/11
In the example the client 123 appears from 2010/10/04 to 2010/10//08 (5 consecutive days), so this client must appear in the output. In the example customer 456 does not appear at least 4 consecutive days, so should not appear in the output.
I have not defined the table ( I only have privileges to query data).
I am unable to copy and paste my real code here, and the actual results from the run, as my company will fire me if I do so... so here is how things approximately look like (tried to keep it as real as possible).
Let's say that the table CYCLE has client numbers (clientid), cycle number (cycleno), date of visit (visdt).
I am trying to create a query to calculate how many days there are between each two consecutive visits/cycles for a single client(let's say 1200004)
clientid / cycleno / visdt
---------------------------
1200004 / 1 / 10OCT2011
1200004 / 2 / 31OCT2011
1200004 / 3 / 21NOV2011
1200004 / 4 / 05DEC2011
1200004 / 5 / 03JAN2012
...
1000005 / 1 / 04NOV2011
1000005 / 2 / 03DEC2011
1200004 / 1 / 10JAN2012
1200004 / 2 / 15FEB2012
.
.
.
The code below is the only one that kind of seemed to work, but it is definitely not giving me the right results.
SELECT cycleno1, visdt1, cycleno2, visdt2, to_date(visdt1) - to_date(visdt2) days
FROM (SELECT clientid, cycleno cycleno1, visdt visdt1,
LEAD (visdt, 1) OVER (ORDER BY cycleno) visdt2
FROM CYCLE) a
[Code]....
I am getting a mess of a result of the kind:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 1/ 18OCT2011 / -8
1 / 10OCT2011 / 2/ 18OCT2011 / -8
1 / 10OCT2011 / 3/ 18OCT2011 / -8
1 / 10OCT2011 / 4/ 18OCT2011 / -8
1 / 10OCT2011 / 5/ 18OCT2011 / -8
I need my result to look like:
cycleno1 / visdt1 / cycleno2 / visdt2 / days
--------------------------------------------
1 / 10OCT2011 / 2/ 31OCT2011 / 21
2 / 31OCT2011 / 3/ 21NOV2011 / 22
3 / 21NOV2011 / 4/ 05DEC2011 / 15
4 / 05DEC2011 / 5/ 03JAN2012 / 30
5 / 03JAN2012 / / /
.
.
.
