SQL & PL/SQL :: Hierarchy Query - Calculate Total Miles
Jul 30, 2013
I've below tables.
create table tst_link (parent_pid number(5),
child_pid number(5)
);
insert into tst_link (1, 2);
[Code]....
For each parent pid i need to calculate total miles (including the child_pid also).
Required Output
PARENT_PID TOTAL_MILES
----------- ------------
1 48
4 100
8 125
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Oct 18, 2013
If we want to know the number of instances, number of RAC databases and whole total disk space used by oracle (not file system size),1. Any script can be ran from OEM grid control against all instances/databases? or2. we have a repository unix server which has all tnsnames of whole databases, any script we can run from there?
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May 27, 2013
I am trying to calculating the total column based on two columns, Total=unitprice*no.of items
I wrote this Javascript in page properties>javascrpt>Execute when Page Loads
"$('input[name=f05],input[name=f06]').change( function(){
parent_row = $(this).parents('tr:first');
sal = ( parent_row.find('input[name=f05]').val() == ' ') ? 0 : parseFloat(parent_row.find('input[name=f05]').val() );
comm = ( parent_row.find('input[name=f06]').val() == ' ') ? 0 : parseFloat(parent_row.find('input[name=f06]').val() );
total = sal * comm;
parent_row.find('input[name=f07]').val(total);
});
But its not Giving any result in total column?
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Jun 10, 2013
Is it possible to sort records based on hierarchy in such a way that records sorts in sequence and records of same level comes in the last (in sorting order)
Eg: Default hierarchy level order: 0,1,2,2,3,3,3,4,5
Above given is the default sorting order of an query for an parent 'NODE_A1' having multiple same level i.e 2 and 3
Expected Hierarchy level order: 0,1,2,3,4,5,2,3,3
Please check attached file for an example.
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Jun 4, 2013
How to get only the last level in Oracle SQL Hierarchy Query?
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Jun 26, 2012
How to create one complex query. here what I have in my table.
DELIVERABLESPRECURSORS
------------ -----------
4 15
15 332
15 26
26 332
29 4
29 15
224 26
224 274
224 259
259 29
274 15
288 259
288 26
288 274
916 27
917 27
918 27
I need a query which run against this table and bring me the following result.
4 > 15 > 332
15 > 332
15 > 26 > 332
26 > 332
29 > 4 > 15 > 332
..... and so on
In theory, I need query which will track DELIVERABLES'S PRECURSOR and PRECURSOR's of there PRECURSOR'S.
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Mar 5, 2013
To use dynatree (URL] I want the result to be in the xml form.but the result is not what I want.
SELECT
XMLELEMENT("div",xmlattributes('tree' AS "id"),
(SELECT DBMS_XMLGEN.getXMLType(
DBMS_XMLGEN.newContextFromHierarchy('
SELECT LEVEL,
case
when CONNECT_BY_ISLEAF = 0 then
[code]....
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Nov 9, 2011
We are on oracle 10.2.0.4 on solaris 10. My question is on a sql query. Is it possible to rewrite a query to avoid the connect by and prior constructs and use joins? For example i have the following query:
SELECT empno,
ename,
job,
mgr,
hiredate
FROM emp
START WITH empno in (7566,7698)
CONNECT BY PRIOR empno = mgr
How can it be rewritten using a two table join (self join)? I am not sure if it can be done and whether it is possible.
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Apr 29, 2013
I am using Oracle database 10g R2.
suppose I have this structure
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
What I want is when I query for any EMP_ID, I want to get all his manager first, and the last record is the employee in leaf of the hierarchy in the query.
For example, when I query for EMP_ID=2 ,I want to get this result
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
and when I query for EMP_ID=3 ,I want to get this result:
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
How to write this query?
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Jun 30, 2010
I have a table which contains two columns containing the range of some products. These range are alphanumeric and i want to calculate the count of this range by a query. .
test case:
CREATE TABLE MARRIAGE_FILE_NAME
(
START_SERIAL_NO VARCHAR2(10 BYTE) NOT NULL,
END_SERIAL_NO VARCHAR2(10 BYTE) NOT NULL,
CATCODE VARCHAR2(10 BYTE) NOT NULL,
[code]....
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May 20, 2013
i have table name order table . in that i have column name install date,order date.
the difference bet ween order date and install date should be greate than or equal to 3 working days.
fri and sat are holidays.
i need one query to find the difference betwwen orderdate and install date is greate than 3 working days
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May 31, 2013
I need to modify my query so that it can give me a total(duration) and total(stlmntcharge) per day in april 2013 starting from the 1st till the 30th. At the moment my query looks like below:
SELECT sum(duration),sum(stlmntcharge)
FROM voipcdr
WHERE (calldate >= TO_DATE('20130401','YYYYMMDD') AND calldate <= TO_DATE('20130430','YYMMDD'))
AND (remtrunkid IN (SELECT UNIQUE trunkid FROM trunks WHERE description LIKE '%Telkom%' AND gw_range_id = '61' AND trunkid like '9%'))
or remip in(SELECT UNIQUE startip FROM gateways WHERE rangename LIKE 'vo-za%' OR rangename LIKE 'PC-IS-VOIS%')
AND direction = 'I'
ORDER BY calldate, calltime;
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Apr 29, 2010
i need the total of the count query I am executing.My query is
SELECT COUNT(*) FROM po_headers WHERE
CREATION_DATE BETWEEN '01-MAR-2010' and '31-MAR-2010' GROUP BY VENDOR_ID
this gives output as
6
1
3
4
My objective is to find the total of distinct vendors for a given date range.how should I modify this query.
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Oct 29, 2013
I want to get any employee name of deptno 10 but total count of number of employees under dept 10.
DECLARE
l_deptno NUMBER:=10;
l_count NUMBER;
l_ename varchar2(20);
BEGIN
SELECT count(*) OVER(order by empno) ,ename INTO l_count,l_ename FROM emp WHERE ROWNUM=1 and deptno=l_deptno;
dbms_output.put_line(l_count||' '||l_ename);
end;
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Oct 20, 2011
I am trying to calculate the total points of each customer
create table Customers(Customer_no number,revenue varchar2(30),Regularity varchar 2(30)
);
insert into Customers values(1,'25','2');
insert into Customers values(2,'50','3');
Table customers:
Customer_no, revenue, regularity
1,25,2
2,50,3
create table Points(ponts ID number,Factor varchar2(30),Weight number);
insert into Points values(1,revenue,2);
insert into Points values(1,Regularity,4);
Table points
Points ID,Factor,Weight
1,revenue,2
1,regularity,4
So for customer_no: 1
revenue is 25 * 2(weight for revenue ) =50
regularity is 2*4(weight for regularity) =8
Total =58
So for customer_no: 2
revenue is 50 * 2(weight for revenue ) =100
regularity is 3*4(weight for regularity) =12
Total =104
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Jul 21, 2012
I need the following totals for each student based on the schools that they are enrolled for each month July through June.
Total Days Suspended from each school
Attendance Table Columns - Absent Date, Absent Code, Pupil_Number, School (Absent Codes for suspended = 3)
Total Days Present at each school - Days Enrolled at each school minus Days Suspended minus Absences
Totals Takes the first day that a student is enrolled (counts the days that the school is in session and the student is not marked absent) Student must be enrolled during the time frame for that month.
Total Days Absent - Total days absent minus suspensions
Examples
Student enrolls in school 11111 on 7/15/2011
Student withdraws from School 11111 on 11/15/2011
Student enrolls in school 22222 on 11/20/2011
Total Days Present should be totaled for each student for each month that they are in a school.
I need 1 row of data for the above student for each month that contains total days suspended, total days present and total days absent.
Pupil Number School Month Totals Days Suspended Total Days Absent Total Days Present
1234 11111 07 0 0 0
1234 11111 08 0 0 4 (school days 4)
1234 11111 09 3 1 16 (schools days 20 - 3-1)
1234 11111 10 0 1 18 (school days 19 - 1)
1234 11111 11 1 1 7 (student enrolled at school A 9 days -1-1)
1234 22222 11 0 1 10 (student enrolled at school B 11 days -1)
1234 22222 12 1 2 17 (school B 20-1-2)
1234 22222 01 0 0 20
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May 13, 2013
Using Oracle 11gR2 on windows 7 client. I have a question on calculating sum() on multiple columns on different columns and store the results in a view. Unfortunately I could not post the problem here as it keeps on giving error "Sorry, this content is not allowed", without telling where or what it is! So I had to post it in the stack-overflow forum, here is the link: [URL] .........
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Sep 17, 2010
DECLARE
l_query VARCHAR2(4000);
TYPE cursor_type IS REF CURSOR;
[Code].....
How can I get the total number of rows returned by the query?
I want to be able to check omething like c1.ROWS = 0
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Jun 13, 2011
I want to know that whether we can write a query to add total number of count of each table.
for example:
select count(*) from emp;
count(*)
14
select count(*) from emp_1;
count(*)
15
select count(*) from emp_2;
count(*)
16
My question is that is it possible to add this all the three results and get the value as 45.
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Aug 22, 2012
How can I create a query to display the total no of employees and, of that total, the number of employees hired in 1995,1996,1997,1998.
I am using Oracle® Database Express Edition 10g Release 2 (10.2)
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Mar 26, 2013
I'm running a query like the below but now i would like to make the last line actually say Grand Total. Instead of just total.
SELECT decode (grouping (farinva_invh_Code),0,null,'Total') farinva_invh_Code,
--decode ( grouping (amt),0,null,'GrantTotal')Grant_Total,
farinva_invh_Code,
spriden_id,
--spriden_last_name "last Name"
[Code]....
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Oct 1, 2009
query in order to display a hierarchy list. Example:
Database has three tables
Heading --> id, status, order, title
Sub-heading --> id, status, order, title, heading_id
Item --> id, status, order, title, heading_id, sub-heading_id, actual_content
order = the sequence in which they are to be displayed a sub-heading's heading_id refers to the parent heading, likewise an item's sub-heading_id refers to the parent sub-heading.
I assumed there was no need to track child content.
Now, the output format should be something like this, where the sub-headings are not repeated, nor are the items. Sort of like chapters in a book, things in a catalogue, or even topics in a forum.
Heading 1
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Heading 2
Sub-heading 1
Item 1
Item 2
Item 3
Heading 3
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Sub-heading 3
Item 1
Item 2
Item 3
Where I'm getting hung up is how to query the data so it's quick, efficient, clean and easy to read and maintain. I've only gotten to listing the sub-headings and already the query looks convoluted. So, how should I approach this? Should it be done all in one query, and always checking against the results to know when to print a new heading or sub heading. Or should I run multiple queries and save the results to a variable, and then run sub-queries off that? Is there a better way to do this, am I going about it the hard way or am I in the right direction and just haven't gone far enough with it yet?
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Dec 20, 2012
way to achieve the below logic.
SQL to pick up parent child relationship within same table with a certain logic.
Example:
mod_product_numberProduct_Hierarchy
H555888 PH05678
H888987 H555888
H8889 H555888
[code]...
Example: I expect the rows with H8889,H9955 & P6666 & P5555 to be sub-category values value for product hierarchy H555888.
If there are rows with H8888987 as Product_hierarchy, we will pull up those rows too for product hierarchy H555888. The extra condition is we drill down only on 7 character mod_prod_number not on 5 character mod_prod_number. We pull out all sub category mod_prod_number for all distinct Product hierarchy.
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Jun 13, 2011
Ihave the following result set based on a hiearchy query
SELECT LEVEL ,
BM.ITEM item
BM.Part part
connect_by_isleaf leaf
FROM item_part_tab bm
START WITH bm.item_id='002PH'
CONNECT BY BM.ITEM_ID = prior BM.PART_id
LEVEL ITEM PART LEAF
-----------------------------------------------------------------
1 002IT XPART1 0
2 XPART1 SUBPART1 1
In the above resultset PART='SUBPART1' does'nt have any child as evident from the connect_by_isleaf (LEAF=1) .Is there any way to create a pseudo record if such values are returned by the query, i.e., if a part has no tree under it a dummy record should be created i.e. in this case an additional record should be returned by this query. i.e., as below. the LEVEL=3 record should be created.
LEVEL ITEM PART LEAF
---------------------------------------------------------
1 002IT XPART1 0
2 XPART1SUBPART1 1
3 SUBPART1 1
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Feb 1, 2012
Is it possible to find the locked objects in hierarchical order. Consider the below example
--Connect to scott schema
create table block_session(a NUMBER, b VARCHAR2(100))
/
insert into block_session select rownum,rownum*10 from dual connect by level<=10
/
COMMIT
/
GRANT ALL ON block_session to HR
/
update scott.block_session
SET a=10
where b=10
[code]......
Is it possible to get all locked table details in hierarchical order?
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Jul 18, 2013
I have requirement to suppress the duplicate nodes on same level in hierarchy query.
Below given is the script for it.
CREATE TABLE NODE_LVL (PARENT_NODE VARCHAR2(100), CHILD_NODE VARCHAR2(100));
INSERT INTO NODE_LVL VALUES('TBL_APL','TBL_AFL');
INSERT INTO NODE_LVL VALUES('TBL_APP','TBL_ACS');
INSERT INTO NODE_LVL VALUES('TBL_ADD','TBL_ADW');
INSERT INTO NODE_LVL VALUES('TBL_ADP','TBL_ADV');
INSERT INTO NODE_LVL VALUES('TBL_AOP','TBL_AOV');
[code]......
Table 'TBL_APP' is having 2 parent nodes i.e 'TBL_AOV' and 'TBL_ADV'
SELECT * FROM node_lvl WHERE child_node = 'TBL_APP';
At level 5 there is duplicate nodes i.e 'TBL_APP' and 'TBL_ACS' as parent_node and child_node respectively.
SELECT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
I want to suppress such duplicates. So I added DISTINCT
SELECT DISTINCT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
BUT requirement is to maintain the same order (of hierarchy) as it was before adding DISTINCT.
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Oct 3, 2013
I want to create a materialized view for the with same logic as below view
CREATE OR REPLACE FORCE VIEW GFL_MCP_CORE.VW_CLIENT_HIERARCHY
(KEY_INDENTED, CLIENT_LEVEL, ID, NAME, CLIENT_TYPE_CODE,
L2_CLIENT_ID, L2_CLIENT_NAME, TOP_CLIENT_ID, TOP_CLIENT_NAME, CLIENT_MCP_FLAG,
CLIENT_GROUP_NAME, ORG_REGION_NAME, COUNTRY_NAME, PROCESSOR_CLIENT_CODE)
[code]....
Here is the sample data for the client table and other tables are generic.
Row#IDNAMECOUNTRY_CODECLIENT_TYPE_CODECLIENT_GROUP_IDPARENT_CLIENT_IDSTATUS_FLAG
134801ZhuanshenguangchangCNBR10048232909A
212515229ConsolidatedFCUUSCL54812515A
314821286 Golden Mile BranchCABR53112712A
42050014513Bay CityUSBR56612009A
53864712-44-125 LeicesterGBBR56038630A
63869114736 Freestar BrickyardUSBR10020238686A
731141Walsall StoreGBL254631103A
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Feb 26, 2010
I want to build a hierarchy and output it into a sub-report. Since the data in few hierarchy fields exceeds 4000 characters and therefore m getting the ORA-01489 error and the entire report was failing.
So i have used user aggregate function to print the out put. I have also used row_number() to print sequence in query output.
the query that i am using is
SELECT pr_id,
REPLACE (REPLACE (twadmin.STRAGG2(distinct RPAD (to_number(curr), 2, ' ') || ')' || NVL (DECODE (medical, NULL, clinical, medical), 'UNKNOWN') || '###' ||
RPAD (' Causality as per rport ', 50, ' ') || ': ' || reporter || '###' ||
RPAD (' Causality as per report2 ', 50, ' ') || ': ' || hospital || '###' ||
RPAD (' Dechallenge', 50, ' ') || ': '|| dechallenge || '###' ||
RPAD (' Rechallenge', 50, ' ') || ': '|| rechallenge), ',', CHR(10)), '###', CHR (10)) causality
[code]......
the output of the query is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
2 )Mental status changes (Mental status changes)
[code].......
but the expected out put is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
[code]........
but it should be as
1)
2)
3)
..
..
..
10)
11)
12) for the values in the causality field
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Apr 8, 2009
i have created a tree hierarchy....when the user clicks on any node,that particular form will open....But there is some problem...i click on form A,it opens.,...then i exit that form via a exit button on the toolbar....and then I click on form B on the tree....but first the form A only opens...and then again i exit form A, then form B will open..
i have written the following code in when_tree_node_selected trigger :
if condition then
call_form(path,no_hide,do_replace);
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Aug 3, 2012
I have an requirement to create an function which takes table or hierarchy of tables as input and returns xml output in hierarchy. Below given is the Tables hierarchy.
AAAA
----AAA
----BBB
----CCC
-------CC1
-------CC2
-------CC3
[code]....
Requirement: Initially input was table name and using table as the root node output should generate xml of all the records of child tables.But now requirement is to give the flexibility to user to select what hierarchy he needs i.e he may select AAAA, CCC and in the nodes C1,C2,C3 and C4 if he doesn't want C3 then that node should not be shown in output.
I have created Hierarchy table having 3 columns SI.No, ParentNode and ChildNode and entered the above hierarchy relation.
1. What is the best to way (design)to pass input parameter for the function.
2. How to generate hierarchy in xml using DBMS_XMLGEN
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