PL/SQL :: How To Query A Hierarchy Structure (Manager-Employee)
Apr 29, 2013
I am using Oracle database 10g R2.
suppose I have this structure
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
What I want is when I query for any EMP_ID, I want to get all his manager first, and the last record is the employee in leaf of the hierarchy in the query.
For example, when I query for EMP_ID=2 ,I want to get this result
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
and when I query for EMP_ID=3 ,I want to get this result:
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
How to write this query?
View 3 Replies
ADVERTISEMENT
Jun 26, 2012
How to create one complex query. here what I have in my table.
DELIVERABLESPRECURSORS
------------ -----------
4 15
15 332
15 26
26 332
29 4
29 15
224 26
224 274
224 259
259 29
274 15
288 259
288 26
288 274
916 27
917 27
918 27
I need a query which run against this table and bring me the following result.
4 > 15 > 332
15 > 332
15 > 26 > 332
26 > 332
29 > 4 > 15 > 332
..... and so on
In theory, I need query which will track DELIVERABLES'S PRECURSOR and PRECURSOR's of there PRECURSOR'S.
View 16 Replies
View Related
Feb 26, 2013
Refer the table below and provide me the query to find given employee is manager or not.
Refer the table below, emp#100 is manager, emp#300 is not a manager.
<emp> <emp_name> < manager >
100Smith null
200Ram 500
300Shankar 500
400Madhur 200
500Suman 100
600Sundar 100
View 2 Replies
View Related
Nov 1, 2012
i have 3 tables
table employee
employee_no
employee_name
table manager
manager_id
manager_name
table department
dept_id
dept_name
how can show on the tree all manager with employee with department
example
manager ali
employee Mohamed
department marketing
View 6 Replies
View Related
Jun 10, 2013
Is it possible to sort records based on hierarchy in such a way that records sorts in sequence and records of same level comes in the last (in sorting order)
Eg: Default hierarchy level order: 0,1,2,2,3,3,3,4,5
Above given is the default sorting order of an query for an parent 'NODE_A1' having multiple same level i.e 2 and 3
Expected Hierarchy level order: 0,1,2,3,4,5,2,3,3
Please check attached file for an example.
View 8 Replies
View Related
Jun 4, 2013
How to get only the last level in Oracle SQL Hierarchy Query?
View 2 Replies
View Related
Mar 5, 2013
To use dynatree (URL] I want the result to be in the xml form.but the result is not what I want.
SELECT
XMLELEMENT("div",xmlattributes('tree' AS "id"),
(SELECT DBMS_XMLGEN.getXMLType(
DBMS_XMLGEN.newContextFromHierarchy('
SELECT LEVEL,
case
when CONNECT_BY_ISLEAF = 0 then
[code]....
View 6 Replies
View Related
Nov 9, 2011
We are on oracle 10.2.0.4 on solaris 10. My question is on a sql query. Is it possible to rewrite a query to avoid the connect by and prior constructs and use joins? For example i have the following query:
SELECT empno,
ename,
job,
mgr,
hiredate
FROM emp
START WITH empno in (7566,7698)
CONNECT BY PRIOR empno = mgr
How can it be rewritten using a two table join (self join)? I am not sure if it can be done and whether it is possible.
View 4 Replies
View Related
Jul 30, 2013
I've below tables.
create table tst_link (parent_pid number(5),
child_pid number(5)
);
insert into tst_link (1, 2);
[Code]....
For each parent pid i need to calculate total miles (including the child_pid also).
Required Output
PARENT_PID TOTAL_MILES
----------- ------------
1 48
4 100
8 125
View 4 Replies
View Related
Sep 8, 2012
Explain the following query to me:
in particular Lpad (' ', Level-1)*3.
select lpad(' ' , (level-1)*3) || emp_last_name employee
from emp
connect by supervisor_emp_id = prior emp_id
start with supervisor_emp_id is null;
View 1 Replies
View Related
Aug 11, 2013
/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */
CREATE PROCEDURE p_get_name (
p_empno IN OUT NUMBER,
p_name OUT VARCHAR2,
p_err OUT NUMBER
[code].......
Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.
View 25 Replies
View Related
Feb 9, 2012
based on the following information
grade lowsal highsal
------ ----- ------
1 700 1200
2 1201 1400
3 1401 2000
4 2001 3000
5 3001 9999
for the employee table to assign grade for each employee based on his salary the following plsql procedure is giving error:
-----------------------------------------------------------
CREATE OR REPLACE PROCEDURE GRADE(EID IN NUMBER,BONUS OUT NUMBER) IS
vGRADE NUMBER(8,2);
vSAL NUMBER(8,2);
BEGIN
vGRADE=1
SELECT SAL INTO vSAL FROM EMP WHERE EMPNO=EMPID;
IF vSAL<= 700 THEN
vGRADE:=1;
ELSEIF vSAL<= 1201 THEN
[code]....
View 4 Replies
View Related
Jul 7, 2011
I have four employee types such as 'C' for consultants, 'S' for staffs, 'W' for workers ,, ('E','S','W') for all types of employees. i have write four queries for showing four types of employees. can it is possible in a single query.
I have written this in oracle forms . I have taken a list item for workers i have taken 'W' , for staffs i have taken 'S' , for consultants i have taken 'C' and for all i have taken 'A'. my column name is emp_type in( :block.list_item ) but it is not taking the value from the list item when the value is emp_type in('C') etc etc..
like this for workers ,staffs . when it is 'A' it will take emp_type in ('E','S','W')
View 3 Replies
View Related
Jun 7, 2012
I have three tables as shown in the image. Need to get the details of each employee in a single row..
EMployee_id BaseSalary Bonus Hike shares
View 4 Replies
View Related
Sep 3, 2012
I am struck in a requirement to show the organization structure in a Top Down Organizational structure.
Is there any way we can make the well structured report OR form?
View 4 Replies
View Related
Apr 19, 2009
I have been trying to construct a query in Oracle that allows me to do the following:
For example if I have the data below:
EmpNo DOB SickDays
Alex 445 15/06/1985 7
Tom 778 22/08/1981 4
James 992 07/10/1978 5
I need to write and a query to lists the employee number and the amount of days sick that they have had and also add a column that compares the number of sick days to the average number of suck days by ALL employees.
I can calculate the average sick days etc, but It wont see to allow me to find the difference between that and the amount of sick days that each person has had. I have tried this many ways and have not been able to come up with a solution.
View 3 Replies
View Related
Nov 25, 2011
I have a table like below,I want retrieve each employee age ,from db column
SQL> select * from dob;
ENAME DB
---------- ---------
vishal 12-MAR-90
jeya 30-MAR-73
vasanthi 17-APR-80
mangai 25-NOV-81
poorna 18-AUG-80
vinod 20-AUG-81
nanthini 01-JUN-86
karthick 20-MAR-88
View 4 Replies
View Related
Jun 27, 2011
Query to find out employees who are all joined before Manager.
For Example the Table may look like.
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E106Manager 11-Oct-08
E107Programmer20-Nov-09
E108Coordinator12-Dec-10
E109DB Admin10-Feb-07
E110DB Analyst10-Aug-05
The out put must be..
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E109DB Admin10-Feb-07
View 4 Replies
View Related
Oct 1, 2009
query in order to display a hierarchy list. Example:
Database has three tables
Heading --> id, status, order, title
Sub-heading --> id, status, order, title, heading_id
Item --> id, status, order, title, heading_id, sub-heading_id, actual_content
order = the sequence in which they are to be displayed a sub-heading's heading_id refers to the parent heading, likewise an item's sub-heading_id refers to the parent sub-heading.
I assumed there was no need to track child content.
Now, the output format should be something like this, where the sub-headings are not repeated, nor are the items. Sort of like chapters in a book, things in a catalogue, or even topics in a forum.
Heading 1
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Heading 2
Sub-heading 1
Item 1
Item 2
Item 3
Heading 3
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Sub-heading 3
Item 1
Item 2
Item 3
Where I'm getting hung up is how to query the data so it's quick, efficient, clean and easy to read and maintain. I've only gotten to listing the sub-headings and already the query looks convoluted. So, how should I approach this? Should it be done all in one query, and always checking against the results to know when to print a new heading or sub heading. Or should I run multiple queries and save the results to a variable, and then run sub-queries off that? Is there a better way to do this, am I going about it the hard way or am I in the right direction and just haven't gone far enough with it yet?
View 11 Replies
View Related
Dec 20, 2012
way to achieve the below logic.
SQL to pick up parent child relationship within same table with a certain logic.
Example:
mod_product_numberProduct_Hierarchy
H555888 PH05678
H888987 H555888
H8889 H555888
[code]...
Example: I expect the rows with H8889,H9955 & P6666 & P5555 to be sub-category values value for product hierarchy H555888.
If there are rows with H8888987 as Product_hierarchy, we will pull up those rows too for product hierarchy H555888. The extra condition is we drill down only on 7 character mod_prod_number not on 5 character mod_prod_number. We pull out all sub category mod_prod_number for all distinct Product hierarchy.
View 11 Replies
View Related
Jun 13, 2011
Ihave the following result set based on a hiearchy query
SELECT LEVEL ,
BM.ITEM item
BM.Part part
connect_by_isleaf leaf
FROM item_part_tab bm
START WITH bm.item_id='002PH'
CONNECT BY BM.ITEM_ID = prior BM.PART_id
LEVEL ITEM PART LEAF
-----------------------------------------------------------------
1 002IT XPART1 0
2 XPART1 SUBPART1 1
In the above resultset PART='SUBPART1' does'nt have any child as evident from the connect_by_isleaf (LEAF=1) .Is there any way to create a pseudo record if such values are returned by the query, i.e., if a part has no tree under it a dummy record should be created i.e. in this case an additional record should be returned by this query. i.e., as below. the LEVEL=3 record should be created.
LEVEL ITEM PART LEAF
---------------------------------------------------------
1 002IT XPART1 0
2 XPART1SUBPART1 1
3 SUBPART1 1
View 16 Replies
View Related
Feb 1, 2012
Is it possible to find the locked objects in hierarchical order. Consider the below example
--Connect to scott schema
create table block_session(a NUMBER, b VARCHAR2(100))
/
insert into block_session select rownum,rownum*10 from dual connect by level<=10
/
COMMIT
/
GRANT ALL ON block_session to HR
/
update scott.block_session
SET a=10
where b=10
[code]......
Is it possible to get all locked table details in hierarchical order?
View 4 Replies
View Related
Jul 18, 2013
I have requirement to suppress the duplicate nodes on same level in hierarchy query.
Below given is the script for it.
CREATE TABLE NODE_LVL (PARENT_NODE VARCHAR2(100), CHILD_NODE VARCHAR2(100));
INSERT INTO NODE_LVL VALUES('TBL_APL','TBL_AFL');
INSERT INTO NODE_LVL VALUES('TBL_APP','TBL_ACS');
INSERT INTO NODE_LVL VALUES('TBL_ADD','TBL_ADW');
INSERT INTO NODE_LVL VALUES('TBL_ADP','TBL_ADV');
INSERT INTO NODE_LVL VALUES('TBL_AOP','TBL_AOV');
[code]......
Table 'TBL_APP' is having 2 parent nodes i.e 'TBL_AOV' and 'TBL_ADV'
SELECT * FROM node_lvl WHERE child_node = 'TBL_APP';
At level 5 there is duplicate nodes i.e 'TBL_APP' and 'TBL_ACS' as parent_node and child_node respectively.
SELECT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
I want to suppress such duplicates. So I added DISTINCT
SELECT DISTINCT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
BUT requirement is to maintain the same order (of hierarchy) as it was before adding DISTINCT.
View 11 Replies
View Related
Oct 3, 2013
I want to create a materialized view for the with same logic as below view
CREATE OR REPLACE FORCE VIEW GFL_MCP_CORE.VW_CLIENT_HIERARCHY
(KEY_INDENTED, CLIENT_LEVEL, ID, NAME, CLIENT_TYPE_CODE,
L2_CLIENT_ID, L2_CLIENT_NAME, TOP_CLIENT_ID, TOP_CLIENT_NAME, CLIENT_MCP_FLAG,
CLIENT_GROUP_NAME, ORG_REGION_NAME, COUNTRY_NAME, PROCESSOR_CLIENT_CODE)
[code]....
Here is the sample data for the client table and other tables are generic.
Row#IDNAMECOUNTRY_CODECLIENT_TYPE_CODECLIENT_GROUP_IDPARENT_CLIENT_IDSTATUS_FLAG
134801ZhuanshenguangchangCNBR10048232909A
212515229ConsolidatedFCUUSCL54812515A
314821286 Golden Mile BranchCABR53112712A
42050014513Bay CityUSBR56612009A
53864712-44-125 LeicesterGBBR56038630A
63869114736 Freestar BrickyardUSBR10020238686A
731141Walsall StoreGBL254631103A
View 1 Replies
View Related
Feb 26, 2010
I want to build a hierarchy and output it into a sub-report. Since the data in few hierarchy fields exceeds 4000 characters and therefore m getting the ORA-01489 error and the entire report was failing.
So i have used user aggregate function to print the out put. I have also used row_number() to print sequence in query output.
the query that i am using is
SELECT pr_id,
REPLACE (REPLACE (twadmin.STRAGG2(distinct RPAD (to_number(curr), 2, ' ') || ')' || NVL (DECODE (medical, NULL, clinical, medical), 'UNKNOWN') || '###' ||
RPAD (' Causality as per rport ', 50, ' ') || ': ' || reporter || '###' ||
RPAD (' Causality as per report2 ', 50, ' ') || ': ' || hospital || '###' ||
RPAD (' Dechallenge', 50, ' ') || ': '|| dechallenge || '###' ||
RPAD (' Rechallenge', 50, ' ') || ': '|| rechallenge), ',', CHR(10)), '###', CHR (10)) causality
[code]......
the output of the query is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
2 )Mental status changes (Mental status changes)
[code].......
but the expected out put is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
[code]........
but it should be as
1)
2)
3)
..
..
..
10)
11)
12) for the values in the causality field
View 25 Replies
View Related
Apr 8, 2009
i have created a tree hierarchy....when the user clicks on any node,that particular form will open....But there is some problem...i click on form A,it opens.,...then i exit that form via a exit button on the toolbar....and then I click on form B on the tree....but first the form A only opens...and then again i exit form A, then form B will open..
i have written the following code in when_tree_node_selected trigger :
if condition then
call_form(path,no_hide,do_replace);
View 3 Replies
View Related
Aug 3, 2012
I have an requirement to create an function which takes table or hierarchy of tables as input and returns xml output in hierarchy. Below given is the Tables hierarchy.
AAAA
----AAA
----BBB
----CCC
-------CC1
-------CC2
-------CC3
[code]....
Requirement: Initially input was table name and using table as the root node output should generate xml of all the records of child tables.But now requirement is to give the flexibility to user to select what hierarchy he needs i.e he may select AAAA, CCC and in the nodes C1,C2,C3 and C4 if he doesn't want C3 then that node should not be shown in output.
I have created Hierarchy table having 3 columns SI.No, ParentNode and ChildNode and entered the above hierarchy relation.
1. What is the best to way (design)to pass input parameter for the function.
2. How to generate hierarchy in xml using DBMS_XMLGEN
View 12 Replies
View Related
Jan 21, 2003
I need to find all "report to" supervisors in a hierarchical chain. A binary search won't work, as each level may contain > 2 supervisors. Example:
1
2 3 4
5 6 7 8 9
10
10 reports to 9
9 reports to 4
5 and 6 report to 2
7 and 8 report to 3
2, 3 and 4 report to 1
Result for all reporting to 1 would be a table containing 2, 3, 4, 5, 6, 7, 8, 9, 10 (order is unimportant!).
I think I need to use recursion. I can do this in C; need code for PL/SQL??? (I can't get the "tree" to display well!)
View 4 Replies
View Related
Apr 20, 2013
What is the hierarchy to stop and start oracle RAC instance ?
View 10 Replies
View Related
Aug 22, 2013
Here is the table structure I will be speaking of below:
SELECT lvl_1_id, lvl_1_dsc,
lvl_2_id, lvl_2_dsc,
lvl_3_id, lvl_3_dsc,
lvl_4_id, lvl_4_dsc,
lvl_5_id, lvl_5_dsc,
lvl_6_id, lvl_6_dsc,
lvl_7_id, lvl_7_dsc,
lvl_8_id, lvl_8_dsc
FROM item_hier_tbl;
I have a table that mimics an hierarchy of items (parent-child relationship). The top level (level 1) never has a NULL value, but it is possible for any of the lower values to have a NULL value. For example, levels 1, 2, 5, 7, & 8 may have values, but 3, 4, & 6 may all be NULL.
I need a View that can return the same data, but with out NULL values. The View would move the NOT NULL values up the levels, so there is consecutive data on each level starting at level. So using the example, the View would move value in 5 up to 3, 7 up to 4, and 8 up to 5. Then level 6 to 8 would have NULL.
I have done this already by creating a 2nd table and using a stored proc to copy the data over to the new table they I want it. But I was told a View or Materialized view "may" work, and perform quicker during the queries. I looked at the Oracle functions LAG and LEAD, but by definition they work by rows, I need to work by columns on the same row.
LAG (value_expression [,offset] [,default]) OVER ([query_partition_clause] order_by_clause)
LEAD (value_expression [,offset] [,default]) OVER ([query_partition_clause] order_by_clause)
Is what I am asking possible in a View or Materialized View?
View 2 Replies
View Related
