SQL & PL/SQL :: Find All Data Items In Hierarchy Recursion?
Jan 21, 2003
I need to find all "report to" supervisors in a hierarchical chain. A binary search won't work, as each level may contain > 2 supervisors. Example:
1
2 3 4
5 6 7 8 9
10
10 reports to 9
9 reports to 4
5 and 6 report to 2
7 and 8 report to 3
2, 3 and 4 report to 1
Result for all reporting to 1 would be a table containing 2, 3, 4, 5, 6, 7, 8, 9, 10 (order is unimportant!).
I think I need to use recursion. I can do this in C; need code for PL/SQL??? (I can't get the "tree" to display well!)
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Jan 31, 2012
I have already done a hierarchy tree. Now I'd like to make it bind to text items. When i click a node, it should automatically be bound to text items.
My tree is about sections of students, now when i click a specific section to view its corresponding subjects it would be displayed on text items.
For example:
+Sections
+First Semester
+LM2
+LM3
+Second Semester
+LM4
+LM5
When i would click on LM2 node, its subjects should appear immediately.
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Feb 1, 2012
Is it possible to find the locked objects in hierarchical order. Consider the below example
--Connect to scott schema
create table block_session(a NUMBER, b VARCHAR2(100))
/
insert into block_session select rownum,rownum*10 from dual connect by level<=10
/
COMMIT
/
GRANT ALL ON block_session to HR
/
update scott.block_session
SET a=10
where b=10
[code]......
Is it possible to get all locked table details in hierarchical order?
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Nov 27, 2009
We are using Oracle 11g (11.1.0).I'm not all that prolific when it comes to writing queriesI have a table...
Table1
-----------------------------------------
oid narr parent
-----------------------------------------
1 some narrative null
2 more narrative 1
3 a bit of test narrative 2
Simply put, I need a query that will recurse up through each rows parent and return the concatination of all parents and itself narrative.
Expected output
------------------------------------
some narrative
more narrative some narrative
a bit of test narrative more narrative some narrative
The requirement is that this is one single query as it will be called from a third party application we are using. We need this recursion and concatenation to be done on the database, as while we have control over the database queries that get executed we have no control over the internal source of this third party applications.I have been digging around for a bit, I have tried using a combination of JOINS and UNIONS but keep hitting a brick wall.
The best I could come up with is...
SELECT concat(n1.narr, n2.narr) FROM table1 n1
JOIN table1 n2 ON n1.oid = n2.parent
But this only returns two lines, for oid's 2 and 3, and only concatinates with the immediate parent.
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Aug 31, 2012
we need to use recursion functions in pl/sql?? How can we use them in efficient way?? Also focus on mutual recursion in real world scenario.
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Dec 8, 2010
My form has two list boxes and two buttons add and remove. As and when i click add button, the selected value from left hand side list item should get populated to right hand side list item. And When I click Remove button, it should do vice versa.
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Aug 20, 2011
how to count how many items present in a particular data block in oracle forms 10g.whether it is a text_item or display_item or list_item etc is there any method to do this.
i have written this when-button pressed but the problem is how to get the next item name in the block
DECLARE
V_COUNT NUMBER:=0;
V_FIRSTITEM VARCHAR2(100):='';
BEGIN
GO_BLOCK('BLOCK_ITEMCOUNT');
V_FIRSTITEM := GET_BLOCK_PROPERTY('BLOCK_ITEMCOUNT', FIRST_ITEM);
LOOP
[code]....
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Dec 19, 2012
I'm trying to add edmx file in my project for first time. I want to choose the oracle provider ODP.net but cannot find Oracle in the data source list. I have oracle 11g installed , odp and odt installed and can access it from the solution as well. I saw the Oracle listed under data source when I tried to connect the solution to the database through server explorer. The solution is connected to Oracle database through ODP.
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Oct 1, 2009
query in order to display a hierarchy list. Example:
Database has three tables
Heading --> id, status, order, title
Sub-heading --> id, status, order, title, heading_id
Item --> id, status, order, title, heading_id, sub-heading_id, actual_content
order = the sequence in which they are to be displayed a sub-heading's heading_id refers to the parent heading, likewise an item's sub-heading_id refers to the parent sub-heading.
I assumed there was no need to track child content.
Now, the output format should be something like this, where the sub-headings are not repeated, nor are the items. Sort of like chapters in a book, things in a catalogue, or even topics in a forum.
Heading 1
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Heading 2
Sub-heading 1
Item 1
Item 2
Item 3
Heading 3
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Sub-heading 3
Item 1
Item 2
Item 3
Where I'm getting hung up is how to query the data so it's quick, efficient, clean and easy to read and maintain. I've only gotten to listing the sub-headings and already the query looks convoluted. So, how should I approach this? Should it be done all in one query, and always checking against the results to know when to print a new heading or sub heading. Or should I run multiple queries and save the results to a variable, and then run sub-queries off that? Is there a better way to do this, am I going about it the hard way or am I in the right direction and just haven't gone far enough with it yet?
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Jun 10, 2013
Is it possible to sort records based on hierarchy in such a way that records sorts in sequence and records of same level comes in the last (in sorting order)
Eg: Default hierarchy level order: 0,1,2,2,3,3,3,4,5
Above given is the default sorting order of an query for an parent 'NODE_A1' having multiple same level i.e 2 and 3
Expected Hierarchy level order: 0,1,2,3,4,5,2,3,3
Please check attached file for an example.
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Dec 20, 2012
way to achieve the below logic.
SQL to pick up parent child relationship within same table with a certain logic.
Example:
mod_product_numberProduct_Hierarchy
H555888 PH05678
H888987 H555888
H8889 H555888
[code]...
Example: I expect the rows with H8889,H9955 & P6666 & P5555 to be sub-category values value for product hierarchy H555888.
If there are rows with H8888987 as Product_hierarchy, we will pull up those rows too for product hierarchy H555888. The extra condition is we drill down only on 7 character mod_prod_number not on 5 character mod_prod_number. We pull out all sub category mod_prod_number for all distinct Product hierarchy.
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Jun 13, 2011
Ihave the following result set based on a hiearchy query
SELECT LEVEL ,
BM.ITEM item
BM.Part part
connect_by_isleaf leaf
FROM item_part_tab bm
START WITH bm.item_id='002PH'
CONNECT BY BM.ITEM_ID = prior BM.PART_id
LEVEL ITEM PART LEAF
-----------------------------------------------------------------
1 002IT XPART1 0
2 XPART1 SUBPART1 1
In the above resultset PART='SUBPART1' does'nt have any child as evident from the connect_by_isleaf (LEAF=1) .Is there any way to create a pseudo record if such values are returned by the query, i.e., if a part has no tree under it a dummy record should be created i.e. in this case an additional record should be returned by this query. i.e., as below. the LEVEL=3 record should be created.
LEVEL ITEM PART LEAF
---------------------------------------------------------
1 002IT XPART1 0
2 XPART1SUBPART1 1
3 SUBPART1 1
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Jun 4, 2013
How to get only the last level in Oracle SQL Hierarchy Query?
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Jul 18, 2013
I have requirement to suppress the duplicate nodes on same level in hierarchy query.
Below given is the script for it.
CREATE TABLE NODE_LVL (PARENT_NODE VARCHAR2(100), CHILD_NODE VARCHAR2(100));
INSERT INTO NODE_LVL VALUES('TBL_APL','TBL_AFL');
INSERT INTO NODE_LVL VALUES('TBL_APP','TBL_ACS');
INSERT INTO NODE_LVL VALUES('TBL_ADD','TBL_ADW');
INSERT INTO NODE_LVL VALUES('TBL_ADP','TBL_ADV');
INSERT INTO NODE_LVL VALUES('TBL_AOP','TBL_AOV');
[code]......
Table 'TBL_APP' is having 2 parent nodes i.e 'TBL_AOV' and 'TBL_ADV'
SELECT * FROM node_lvl WHERE child_node = 'TBL_APP';
At level 5 there is duplicate nodes i.e 'TBL_APP' and 'TBL_ACS' as parent_node and child_node respectively.
SELECT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
I want to suppress such duplicates. So I added DISTINCT
SELECT DISTINCT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
BUT requirement is to maintain the same order (of hierarchy) as it was before adding DISTINCT.
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Oct 3, 2013
I want to create a materialized view for the with same logic as below view
CREATE OR REPLACE FORCE VIEW GFL_MCP_CORE.VW_CLIENT_HIERARCHY
(KEY_INDENTED, CLIENT_LEVEL, ID, NAME, CLIENT_TYPE_CODE,
L2_CLIENT_ID, L2_CLIENT_NAME, TOP_CLIENT_ID, TOP_CLIENT_NAME, CLIENT_MCP_FLAG,
CLIENT_GROUP_NAME, ORG_REGION_NAME, COUNTRY_NAME, PROCESSOR_CLIENT_CODE)
[code]....
Here is the sample data for the client table and other tables are generic.
Row#IDNAMECOUNTRY_CODECLIENT_TYPE_CODECLIENT_GROUP_IDPARENT_CLIENT_IDSTATUS_FLAG
134801ZhuanshenguangchangCNBR10048232909A
212515229ConsolidatedFCUUSCL54812515A
314821286 Golden Mile BranchCABR53112712A
42050014513Bay CityUSBR56612009A
53864712-44-125 LeicesterGBBR56038630A
63869114736 Freestar BrickyardUSBR10020238686A
731141Walsall StoreGBL254631103A
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Jun 26, 2012
How to create one complex query. here what I have in my table.
DELIVERABLESPRECURSORS
------------ -----------
4 15
15 332
15 26
26 332
29 4
29 15
224 26
224 274
224 259
259 29
274 15
288 259
288 26
288 274
916 27
917 27
918 27
I need a query which run against this table and bring me the following result.
4 > 15 > 332
15 > 332
15 > 26 > 332
26 > 332
29 > 4 > 15 > 332
..... and so on
In theory, I need query which will track DELIVERABLES'S PRECURSOR and PRECURSOR's of there PRECURSOR'S.
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Feb 26, 2010
I want to build a hierarchy and output it into a sub-report. Since the data in few hierarchy fields exceeds 4000 characters and therefore m getting the ORA-01489 error and the entire report was failing.
So i have used user aggregate function to print the out put. I have also used row_number() to print sequence in query output.
the query that i am using is
SELECT pr_id,
REPLACE (REPLACE (twadmin.STRAGG2(distinct RPAD (to_number(curr), 2, ' ') || ')' || NVL (DECODE (medical, NULL, clinical, medical), 'UNKNOWN') || '###' ||
RPAD (' Causality as per rport ', 50, ' ') || ': ' || reporter || '###' ||
RPAD (' Causality as per report2 ', 50, ' ') || ': ' || hospital || '###' ||
RPAD (' Dechallenge', 50, ' ') || ': '|| dechallenge || '###' ||
RPAD (' Rechallenge', 50, ' ') || ': '|| rechallenge), ',', CHR(10)), '###', CHR (10)) causality
[code]......
the output of the query is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
2 )Mental status changes (Mental status changes)
[code].......
but the expected out put is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
[code]........
but it should be as
1)
2)
3)
..
..
..
10)
11)
12) for the values in the causality field
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Mar 5, 2013
To use dynatree (URL] I want the result to be in the xml form.but the result is not what I want.
SELECT
XMLELEMENT("div",xmlattributes('tree' AS "id"),
(SELECT DBMS_XMLGEN.getXMLType(
DBMS_XMLGEN.newContextFromHierarchy('
SELECT LEVEL,
case
when CONNECT_BY_ISLEAF = 0 then
[code]....
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Apr 8, 2009
i have created a tree hierarchy....when the user clicks on any node,that particular form will open....But there is some problem...i click on form A,it opens.,...then i exit that form via a exit button on the toolbar....and then I click on form B on the tree....but first the form A only opens...and then again i exit form A, then form B will open..
i have written the following code in when_tree_node_selected trigger :
if condition then
call_form(path,no_hide,do_replace);
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Nov 9, 2011
We are on oracle 10.2.0.4 on solaris 10. My question is on a sql query. Is it possible to rewrite a query to avoid the connect by and prior constructs and use joins? For example i have the following query:
SELECT empno,
ename,
job,
mgr,
hiredate
FROM emp
START WITH empno in (7566,7698)
CONNECT BY PRIOR empno = mgr
How can it be rewritten using a two table join (self join)? I am not sure if it can be done and whether it is possible.
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Aug 3, 2012
I have an requirement to create an function which takes table or hierarchy of tables as input and returns xml output in hierarchy. Below given is the Tables hierarchy.
AAAA
----AAA
----BBB
----CCC
-------CC1
-------CC2
-------CC3
[code]....
Requirement: Initially input was table name and using table as the root node output should generate xml of all the records of child tables.But now requirement is to give the flexibility to user to select what hierarchy he needs i.e he may select AAAA, CCC and in the nodes C1,C2,C3 and C4 if he doesn't want C3 then that node should not be shown in output.
I have created Hierarchy table having 3 columns SI.No, ParentNode and ChildNode and entered the above hierarchy relation.
1. What is the best to way (design)to pass input parameter for the function.
2. How to generate hierarchy in xml using DBMS_XMLGEN
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Apr 29, 2013
I am using Oracle database 10g R2.
suppose I have this structure
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
What I want is when I query for any EMP_ID, I want to get all his manager first, and the last record is the employee in leaf of the hierarchy in the query.
For example, when I query for EMP_ID=2 ,I want to get this result
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
and when I query for EMP_ID=3 ,I want to get this result:
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
How to write this query?
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Jul 30, 2013
I've below tables.
create table tst_link (parent_pid number(5),
child_pid number(5)
);
insert into tst_link (1, 2);
[Code]....
For each parent pid i need to calculate total miles (including the child_pid also).
Required Output
PARENT_PID TOTAL_MILES
----------- ------------
1 48
4 100
8 125
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Apr 20, 2013
What is the hierarchy to stop and start oracle RAC instance ?
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Aug 22, 2013
Here is the table structure I will be speaking of below:
SELECT lvl_1_id, lvl_1_dsc,
lvl_2_id, lvl_2_dsc,
lvl_3_id, lvl_3_dsc,
lvl_4_id, lvl_4_dsc,
lvl_5_id, lvl_5_dsc,
lvl_6_id, lvl_6_dsc,
lvl_7_id, lvl_7_dsc,
lvl_8_id, lvl_8_dsc
FROM item_hier_tbl;
I have a table that mimics an hierarchy of items (parent-child relationship). The top level (level 1) never has a NULL value, but it is possible for any of the lower values to have a NULL value. For example, levels 1, 2, 5, 7, & 8 may have values, but 3, 4, & 6 may all be NULL.
I need a View that can return the same data, but with out NULL values. The View would move the NOT NULL values up the levels, so there is consecutive data on each level starting at level. So using the example, the View would move value in 5 up to 3, 7 up to 4, and 8 up to 5. Then level 6 to 8 would have NULL.
I have done this already by creating a 2nd table and using a stored proc to copy the data over to the new table they I want it. But I was told a View or Materialized view "may" work, and perform quicker during the queries. I looked at the Oracle functions LAG and LEAD, but by definition they work by rows, I need to work by columns on the same row.
LAG (value_expression [,offset] [,default]) OVER ([query_partition_clause] order_by_clause)
LEAD (value_expression [,offset] [,default]) OVER ([query_partition_clause] order_by_clause)
Is what I am asking possible in a View or Materialized View?
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Jun 12, 2012
I have a hierarchy tree menu look like this
+GL
Accounts
Inform
+Export
Export Entry Form
+Security
New User Entry
when i click Gl==>Accounts, accounts form opens and i want call my forms and reports through nodes.
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Aug 10, 2012
Database version
Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64bit Production
PL/SQL Release 9.2.0.8.0 - Production
CORE 9.2.0.8.0 Production
TNS for HPUX: Version 9.2.0.8.0 - Production
NLSRTL Version 9.2.0.8.0 - Production
I have this query
select dept_id,qc_subtype_id,equip_code,drive_id
from
(select distinct dept_id,
decode(qc_subtype_id,
[code]...
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Feb 19, 2013
i want to find the duplicate data in my tables i have the below structure
SQL> desc x;
Name Null? Type
----------------------------------------- -------- ----------------------------
FILE_CODE NUMBER(20)
STREAMNUMBER VARCHAR2(50)
SERVICEKEY VARCHAR2(50)
CALLINGPARTYNUMBER VARCHAR2(50)
CALLEDPARTYNUMBER VARCHAR2(50)
CHARGEPARTYINDICATOR VARCHAR2(50)
[Code] ......
i found the below query it's right
SELECT * x
WHERE ROWID NOT IN (SELECT MIN(ROWID) FROM x
GROUP by FILE_CODE,..........................,SEQ_NO ); all the column
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Sep 14, 2011
I wanna to DROP a table called EMPLOYEES, but when I execute the DROP TABLE EMPLOYEES, I get a ERROR saying that I cant do it because this table do reference to another table(s).
I tried to use the DBA_CONS_COLUMNS and DBA_CONSTRAINTS data tables, but its not enough to find it.
How can I find these references?
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Oct 22, 2012
query to find out common data from 2 columns in two different tables??
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