SQL & PL/SQL :: View Of Item Hierarchy By Eliminating NULL Levels
Aug 22, 2013
Here is the table structure I will be speaking of below:
SELECT lvl_1_id, lvl_1_dsc,
lvl_2_id, lvl_2_dsc,
lvl_3_id, lvl_3_dsc,
lvl_4_id, lvl_4_dsc,
lvl_5_id, lvl_5_dsc,
lvl_6_id, lvl_6_dsc,
lvl_7_id, lvl_7_dsc,
lvl_8_id, lvl_8_dsc
FROM item_hier_tbl;
I have a table that mimics an hierarchy of items (parent-child relationship). The top level (level 1) never has a NULL value, but it is possible for any of the lower values to have a NULL value. For example, levels 1, 2, 5, 7, & 8 may have values, but 3, 4, & 6 may all be NULL.
I need a View that can return the same data, but with out NULL values. The View would move the NOT NULL values up the levels, so there is consecutive data on each level starting at level. So using the example, the View would move value in 5 up to 3, 7 up to 4, and 8 up to 5. Then level 6 to 8 would have NULL.
I have done this already by creating a 2nd table and using a stored proc to copy the data over to the new table they I want it. But I was told a View or Materialized view "may" work, and perform quicker during the queries. I looked at the Oracle functions LAG and LEAD, but by definition they work by rows, I need to work by columns on the same row.
LAG (value_expression [,offset] [,default]) OVER ([query_partition_clause] order_by_clause)
LEAD (value_expression [,offset] [,default]) OVER ([query_partition_clause] order_by_clause)
Is what I am asking possible in a View or Materialized View?
View 2 Replies
ADVERTISEMENT
May 3, 2012
As per NULL values concept
One NULL value is not equal to other NULL value.
But how DISTINCT and UNION eliminating NULL values.
Then how UNIQUE key constraint accepting more than one NULL value..
View 1 Replies
View Related
Oct 3, 2013
I want to create a materialized view for the with same logic as below view
CREATE OR REPLACE FORCE VIEW GFL_MCP_CORE.VW_CLIENT_HIERARCHY
(KEY_INDENTED, CLIENT_LEVEL, ID, NAME, CLIENT_TYPE_CODE,
L2_CLIENT_ID, L2_CLIENT_NAME, TOP_CLIENT_ID, TOP_CLIENT_NAME, CLIENT_MCP_FLAG,
CLIENT_GROUP_NAME, ORG_REGION_NAME, COUNTRY_NAME, PROCESSOR_CLIENT_CODE)
[code]....
Here is the sample data for the client table and other tables are generic.
Row#IDNAMECOUNTRY_CODECLIENT_TYPE_CODECLIENT_GROUP_IDPARENT_CLIENT_IDSTATUS_FLAG
134801ZhuanshenguangchangCNBR10048232909A
212515229ConsolidatedFCUUSCL54812515A
314821286 Golden Mile BranchCABR53112712A
42050014513Bay CityUSBR56612009A
53864712-44-125 LeicesterGBBR56038630A
63869114736 Freestar BrickyardUSBR10020238686A
731141Walsall StoreGBL254631103A
View 1 Replies
View Related
Oct 12, 2012
I have a table something as below
Things_t
Things Characteristic Char Value
Item 1 Colour Red
Item 1 Packaging
Item 2 Shape Square
Item 2 Brand Spunk
Now i want to reterive an item with none of its char values as Null. Using the query “ select distinct things from things_t where char value is Null ” will fetch the item 1 also together with item 2. i want to fetch a record from thing for which none of the char values are Null such as Item 2.
View 9 Replies
View Related
Jul 2, 2012
Apex 4.1
Theme 21
I have select list which has null and other values. I have created a blank HTML region with the following text
Report for the year &P2_YEAR. and for geography &P2_GEOG.
Now P2_YEAR works fine because, it is always populated with a year. However, &P2_GEOG has 'All' as null value since we can see the report for all geographies. However, if the all option is selected, the above &P2_GEOG. shows as null. Since its not a PL/SQL proc, I cannot put in a NVL. I am guessing one possible way is to write a PL/SQL code before region and then check if its null and then try to populate a new hidden field and show, something like that. Wondering if there is a way to do it directly in the HTML region?
View 0 Replies
View Related
Aug 1, 2012
I'm having trouble creating a view that has a not null column. Using this script you can see that the resulting table doesn't have a not null constraint for the first column even though both source columns for that row are not null. Is there anyway to force the view to mark that first column as not null? (I need it for ODP.NET otherwise I get an error there)
DROP TABLE MYTABLE;
CREATE table MYTABLE
( COL1 NUMBER(2) NOT NULL,
col2 number(2)) ;
drop table mytable2;
CREATE table MYTABLE2
[code]....
View 7 Replies
View Related
Sep 6, 2012
Attached query is running fine if inline view B (Marked in Comments) returning value. If inline view B returns NULL then it fails to return result. I want if Inline view B is returning NULL then it should pass ZERO to main query.
View 2 Replies
View Related
Apr 24, 2011
I have one scenario in which i want to write the sql,but not able to write correct qry,
tables
1-emp
2-emp_hist
3-dept
4-dept_hist.
i want to retrieve data from the emp and hist able based on some conditions,but if data is not present in emp and dept tables.then fetch data from emp_hist and dept_hist.I have written below qry which is working fine,but my prob is i want to provide my emp_id only one place.
else i have to change my java code.
select * from emp,dept where emp.emp_id=dept.dept_id and emp_id=5
union
select * from emp_hist,dept_hist where emp_hist.emp_id=dept_hist.dept_id and emp_id=5
View 20 Replies
View Related
Sep 13, 2012
I had third party reporting system,in which i could not avoid time selection in the screen. So if a user selets date and time or date alone .i should get only in date foarmat i.e(DD-MM-YYYY)
i had tried from third party tool liket0_char (P_date,'DD-MM-YYYY').But i get error ORA-01841: (full) year must be between -4713 and +9999, and not be 0
View 1 Replies
View Related
Sep 28, 2010
the literature equates dimension hierarchies with fuctional dependencies between the levels. I like to tst the strength of this assumption with the implementation of 'CREATE DIMENSION' which allows you to create roll-up hierarchies.
My question to put it simply is this: Given:
CREATE DIMENSION location_dim
LEVEL location IS (location.loc_id)
LEVEL city IS (location.city)
LEVEL state IS (location.state)
HIERARCHY geog_rollup (
location CHILD OF
city CHILD OF
state CHILD
)
Can I insert the following rows into the dimension:
loc_id, city, state
1, Epping, NSW
2, Epping, VIC
Please note that the two Eppings are different cities.
Given the roll-up hierarchy City -> State, will it require that for every city there can be only one state in which case the FD between City and State cannot hold. Or, is it that the roll-up hierarchy defined here has nothing to do with FD.
The second part of the question is if the answer to the above question is that the roll-up is not the same as FD, then is the ATTRIBUTE clause meant to define the n:1 (functional dependency) instead?
View 4 Replies
View Related
Oct 11, 2012
where to find various logging levels (like 1-10) of audit trail in oracle...if so how to set that logging levels.
View 2 Replies
View Related
May 17, 2010
I would like to display data using the Hierarchical tree up to 3 levels.I need to create all the nodes programatically.
Means Create the parent (Parent1) level nodes , then create the child (Child1) nodes and add them under the parent1.Similarly create child nodes (Child2) and add them under the parent (Child1).
View 1 Replies
View Related
Aug 19, 2010
Ive just tried running a simple
update BASIC set 'column name' = NULL
Which works fine if i specify a where clause that returns a low amount of values, but im trying to run this update for the whole column (1000's or records).
Ive had no experience of this error before and am unsure of where to start, ive had a quick read around but see something of removing triggers?
The full error is :
ORA-00036: maximum number of recursive SQL levels (50) exceeded
ORA-06512: at "new.su_Table", line 61
View 22 Replies
View Related
Aug 29, 2012
I have getting error will insert into table i.e
i have a trigger as below
create or replace trigger INS_ERRORS
before insert on MIG_STG_ERRORS
for each ROW
declare
V VARCHAR2(22);
[code]........
when i insert into MIG_STG_ERRORS getting error message like 00036. 00000 - "maximum number of recursive SQL levels (%s) exceeded"
*Cause: An attempt was made to go more than the specified number of recursive SQL levels.
*Action: Remove the recursive SQL, possibly a recursive trigger.
View 4 Replies
View Related
Jan 26, 2013
Among Hibernate optimistic locking & Database Isolation levels, which one to use? Which gives the better consistency, concurrency and scalability. I read in couple of links that Isolation level will suffer if there is a huge load on the application with multiple users access the appliation at the same time, moreover in islation levels normally we need to look for READ_COMITTED and NON_REPEATABLE_READ to get a better performance? Whether these are true? Whether we can use both Hibernate optimistic locking(version & timestamp) & Database Isolation levels in the same application? What are the implications using these? Which one will be preferred over the other and when?
View 2 Replies
View Related
Aug 10, 2013
From front end the user will enter VACANCY_ID in the label box and once he saves that transaction, in background VACANCY_CD filed(sequence) willautomatically generated
.below is my code:{code}create table tmp1(vac_id number,vac_cd number);create sequence tmp1_seq MINVALUE 1 MAXVALUE 9999999999999999999999999999 INCREMENT BY 1 START WITH 1 CACHE 20 NOORDER NOCYCLE ;select tmp1_seq.nextval from dual; ---initiating seqselect tmp1_seq.currval from dual; --checking the current val--trigger creationCREATE OR REPLACE TRIGGER TRIGGER1 AFTER INSERT ON TMP1 FOR EACH ROW DECLARE seqval
[code]...
Error: ORA-00036: maximum number of recursive SQL levels (50) exceededORA-00036: maximum number of recursive SQL levels (50) exceeded
View 6 Replies
View Related
Aug 29, 2012
I have the following query:
select col_1,col_9 from
book_temp b
where b.col_1 is not null
order by to_number(b.col_16)
;
What I want to add is the following:
COL_9
=====
NULL
A
B
NULL
C
D
E
F
NULL
G
I need to connect the NON-NULL rows to the preceding NULL row.
View 15 Replies
View Related
Jun 21, 2010
I am running a GROUP BY query on a few columns of enumerated data like:
select count(*), Condition, Size
group by Condition, Size;
COUNT(*) CONDITION SIZE
-------- ---------- --------
3 MINT L
2 FAIR L
4 FAIR M
1 MINT S
Well, let's say I also have a timestamp field in the database. I cannot run a group by with that involved because the time is recorded to the milisec and is unique for every record. Instead, I want to include this in my group by function based on whether or not it is NULL.
For example:
COUNT(*) CONDITION SIZE SOLDDATE
-------- ---------- -------- ----------
3 MINT L ISNULL
2 FAIR L NOTNULL
2 FAIR M NOTNULL
2 FAIR M ISNULL
1 MINT S ISNULL
View 9 Replies
View Related
Mar 16, 2011
I have a table which has a not null column. the column is date field. I am trying to change it to Null. But it is giving a error.
I am using below query.
ALTER TABLE T_test
modify (paid_to_date null)
View 9 Replies
View Related
Oct 1, 2009
query in order to display a hierarchy list. Example:
Database has three tables
Heading --> id, status, order, title
Sub-heading --> id, status, order, title, heading_id
Item --> id, status, order, title, heading_id, sub-heading_id, actual_content
order = the sequence in which they are to be displayed a sub-heading's heading_id refers to the parent heading, likewise an item's sub-heading_id refers to the parent sub-heading.
I assumed there was no need to track child content.
Now, the output format should be something like this, where the sub-headings are not repeated, nor are the items. Sort of like chapters in a book, things in a catalogue, or even topics in a forum.
Heading 1
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Heading 2
Sub-heading 1
Item 1
Item 2
Item 3
Heading 3
Sub-heading 1
Item 1
Item 2
Item 3
Sub-heading 2
Item 1
Item 2
Item 3
Sub-heading 3
Item 1
Item 2
Item 3
Where I'm getting hung up is how to query the data so it's quick, efficient, clean and easy to read and maintain. I've only gotten to listing the sub-headings and already the query looks convoluted. So, how should I approach this? Should it be done all in one query, and always checking against the results to know when to print a new heading or sub heading. Or should I run multiple queries and save the results to a variable, and then run sub-queries off that? Is there a better way to do this, am I going about it the hard way or am I in the right direction and just haven't gone far enough with it yet?
View 11 Replies
View Related
Jun 10, 2013
Is it possible to sort records based on hierarchy in such a way that records sorts in sequence and records of same level comes in the last (in sorting order)
Eg: Default hierarchy level order: 0,1,2,2,3,3,3,4,5
Above given is the default sorting order of an query for an parent 'NODE_A1' having multiple same level i.e 2 and 3
Expected Hierarchy level order: 0,1,2,3,4,5,2,3,3
Please check attached file for an example.
View 8 Replies
View Related
Dec 20, 2012
way to achieve the below logic.
SQL to pick up parent child relationship within same table with a certain logic.
Example:
mod_product_numberProduct_Hierarchy
H555888 PH05678
H888987 H555888
H8889 H555888
[code]...
Example: I expect the rows with H8889,H9955 & P6666 & P5555 to be sub-category values value for product hierarchy H555888.
If there are rows with H8888987 as Product_hierarchy, we will pull up those rows too for product hierarchy H555888. The extra condition is we drill down only on 7 character mod_prod_number not on 5 character mod_prod_number. We pull out all sub category mod_prod_number for all distinct Product hierarchy.
View 11 Replies
View Related
Jun 13, 2011
Ihave the following result set based on a hiearchy query
SELECT LEVEL ,
BM.ITEM item
BM.Part part
connect_by_isleaf leaf
FROM item_part_tab bm
START WITH bm.item_id='002PH'
CONNECT BY BM.ITEM_ID = prior BM.PART_id
LEVEL ITEM PART LEAF
-----------------------------------------------------------------
1 002IT XPART1 0
2 XPART1 SUBPART1 1
In the above resultset PART='SUBPART1' does'nt have any child as evident from the connect_by_isleaf (LEAF=1) .Is there any way to create a pseudo record if such values are returned by the query, i.e., if a part has no tree under it a dummy record should be created i.e. in this case an additional record should be returned by this query. i.e., as below. the LEVEL=3 record should be created.
LEVEL ITEM PART LEAF
---------------------------------------------------------
1 002IT XPART1 0
2 XPART1SUBPART1 1
3 SUBPART1 1
View 16 Replies
View Related
Jun 4, 2013
How to get only the last level in Oracle SQL Hierarchy Query?
View 2 Replies
View Related
Oct 24, 2013
create table test
(
id int ,
dat date
)
/
I want to implement a business rule such as we have for each id at most 1 dat null. So, I've created this unique index on test.
create unique index x_only_one_dat_cess_null on test(id, case when dat_cess is null then 'NULL' else to_char(dat_cess, 'dd/mm/yyyy') end);
insert into test values (1, sysdate);
insert into test values (1, sysdate - 1);
insert into test values (1, null);
insert into test values (1, null);
-- -----
insert into test values (2, sysdate);
insert into test values (2, sysdate - 1);
insert into test values (2, null);
The 4th insert will cause an error and this is what I wanted to implement. OK. Now the problem is that for non-null values of dat, we can't have data like this
iddat
------------
124/10/2013
123/10/2013
123/10/2013
1
because of the unique index (the 2nd and the 3rd row are equal). So just for learning purposes, how could we allow at most one null value of dat and allow duplicates for non-null values of dat.
View 2 Replies
View Related
Jan 9, 2012
when i follow this steps mention on this website
[URL].........
to modify column from null to not null i got this error and on this website its show successful
my steps are
first i create a table
SQL> create table Stu_Table(Stu_Id varchar(2), Stu_Name varchar(10),
2 Stu_Class varchar(10));
Table created.
Then insert some rows into Stu_Table
SQL> insert into Stu_Table (Stu_Id, Stu_Name) values(1,'Komal');
1 row created.
SQL> insert into Stu_Table (Stu_Id, Stu_Name) values(2,'Ajay');
1 row created.
SQL> insert into Stu_Table (Stu_Id, Stu_Name) values(3,'Rakesh');
1 row created.
SQL> insert into Stu_Table (Stu_Id, Stu_Name) values(4,'Bhanu');
1 row created.
SQL> insert into Stu_Table (Stu_Id, Stu_Name) values(5,'Santosh');
1 row created.
SQL> select * from Stu_Table;
ST STU_NAME STU_CLASS
-- ---------- ----------
1 Komal
2 Ajay
3 Rakesh
4 Bhanu
5 Santosh
Table Structure is like this
SQL> Describe Stu_Table
Name Null? Type
----------------------------------------- -------- ----------------------------
STU_ID VARCHAR2(2)
STU_NAME VARCHAR2(10)
STU_CLASS VARCHAR2(10)
now when i try to modify this Stu_id column to not null its give me error.
SQL>ALTER TABLE Stu_Table MODIFY Stu_Id int(3)not null;
ALTER TABLE Stu_Table MODIFY Stu_Id int(3)not null
*
ERROR at line 1:
ORA-01735: invalid ALTER TABLE option
and when i try to add new column with not null its also gives me error
SQL> ALTER TABLE Stu_Table add C1_TEMP integer NOT NULL;
ALTER TABLE Stu_Table add C1_TEMP integer NOT NULL
*
ERROR at line 1:
ORA-01758: table must be empty to add mandatory (NOT NULL) column
View 6 Replies
View Related
Feb 1, 2012
Is it possible to find the locked objects in hierarchical order. Consider the below example
--Connect to scott schema
create table block_session(a NUMBER, b VARCHAR2(100))
/
insert into block_session select rownum,rownum*10 from dual connect by level<=10
/
COMMIT
/
GRANT ALL ON block_session to HR
/
update scott.block_session
SET a=10
where b=10
[code]......
Is it possible to get all locked table details in hierarchical order?
View 4 Replies
View Related
Jul 18, 2013
I have requirement to suppress the duplicate nodes on same level in hierarchy query.
Below given is the script for it.
CREATE TABLE NODE_LVL (PARENT_NODE VARCHAR2(100), CHILD_NODE VARCHAR2(100));
INSERT INTO NODE_LVL VALUES('TBL_APL','TBL_AFL');
INSERT INTO NODE_LVL VALUES('TBL_APP','TBL_ACS');
INSERT INTO NODE_LVL VALUES('TBL_ADD','TBL_ADW');
INSERT INTO NODE_LVL VALUES('TBL_ADP','TBL_ADV');
INSERT INTO NODE_LVL VALUES('TBL_AOP','TBL_AOV');
[code]......
Table 'TBL_APP' is having 2 parent nodes i.e 'TBL_AOV' and 'TBL_ADV'
SELECT * FROM node_lvl WHERE child_node = 'TBL_APP';
At level 5 there is duplicate nodes i.e 'TBL_APP' and 'TBL_ACS' as parent_node and child_node respectively.
SELECT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
I want to suppress such duplicates. So I added DISTINCT
SELECT DISTINCT PARENT_NODE, CHILD_NODE, LEVEL FROM NODE_LVL START WITH PARENT_NODE = 'TBL_ACF' CONNECT BY PRIOR CHILD_NODE = PARENT_NODE;
BUT requirement is to maintain the same order (of hierarchy) as it was before adding DISTINCT.
View 11 Replies
View Related
Jun 26, 2012
How to create one complex query. here what I have in my table.
DELIVERABLESPRECURSORS
------------ -----------
4 15
15 332
15 26
26 332
29 4
29 15
224 26
224 274
224 259
259 29
274 15
288 259
288 26
288 274
916 27
917 27
918 27
I need a query which run against this table and bring me the following result.
4 > 15 > 332
15 > 332
15 > 26 > 332
26 > 332
29 > 4 > 15 > 332
..... and so on
In theory, I need query which will track DELIVERABLES'S PRECURSOR and PRECURSOR's of there PRECURSOR'S.
View 16 Replies
View Related
Feb 26, 2010
I want to build a hierarchy and output it into a sub-report. Since the data in few hierarchy fields exceeds 4000 characters and therefore m getting the ORA-01489 error and the entire report was failing.
So i have used user aggregate function to print the out put. I have also used row_number() to print sequence in query output.
the query that i am using is
SELECT pr_id,
REPLACE (REPLACE (twadmin.STRAGG2(distinct RPAD (to_number(curr), 2, ' ') || ')' || NVL (DECODE (medical, NULL, clinical, medical), 'UNKNOWN') || '###' ||
RPAD (' Causality as per rport ', 50, ' ') || ': ' || reporter || '###' ||
RPAD (' Causality as per report2 ', 50, ' ') || ': ' || hospital || '###' ||
RPAD (' Dechallenge', 50, ' ') || ': '|| dechallenge || '###' ||
RPAD (' Rechallenge', 50, ' ') || ': '|| rechallenge), ',', CHR(10)), '###', CHR (10)) causality
[code]......
the output of the query is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
2 )Mental status changes (Mental status changes)
[code].......
but the expected out put is
ID Causality
-- ------
3755101 )Blisters (Blister)
Causality as per report1: Probable
Causality as per report2: Possible
Dechallenge : Not Applicable
Rechallenge : Not Applicable
[code]........
but it should be as
1)
2)
3)
..
..
..
10)
11)
12) for the values in the causality field
View 25 Replies
View Related
