i have 3 tables
table employee
employee_no
employee_name
table manager
manager_id
manager_name
table department
dept_id
dept_name
how can show on the tree all manager with employee with department
example
manager ali
employee Mohamed
department marketing
I would like to create a hierarchical tree with Department number as a node and all the employees (only employee names) under that department as shown below:
[-]Department - 10
KING
JAMES
-----
[-]Department - 20
MARY
|
|
and so on...
I have created a hierarchical tree 'HT_DEPTNO' under block 'BL_EMP'. I also created a Record Group 'RG_HTREE' with query as shown below:
SELECT 1, LEVEL, E.ENAME, D.DEPTNO||' - '||D.DNAME DEPARTMENT, D.DEPTNO
FROM EMP E, DEPT D
WHERE E.DEPTNO = D.DEPTNO
START WITH E.DEPTNO = 10
CONNECT BY PRIOR E.EMPNO=E.MGR
I am attaching the form for your reference.
I have employee interface table something like this.
emp_idemp_name Job_title supervisor_name
1AJ Engineer BJ
2CK Analyst ND
3BJ Manager TR
5TR VP IT JD
6ND S Manager MD
7MD VP Telecom SK
8SK VP Eng JR
I want to idenitfy the VP for each employee. The logic I have to apply is check for hte supervisor of each employee to see if the supervisor has designation starting with 'VP'. If no, I have check the supervisor of the supervisor and so on. I tried using a recursive query using connect_by_root but in the above example for employee ND it lists the VP as both MD and SK. I need it to show on MD who is the lower in the hierarchy.
I am a Java person but since my app uses the Oracle DB I am to do this task.
how to show total number of department with their department name assign to employee table.
View 2 Replies View RelatedI have following tables:
EMPLOYEE (E-Number, Name, Department, age)
ASSIGNMENT (E-Number, P-Number )
PROJECT( P-Number, Project, Manager)
Create a view to show employee names, age and total number of projects they are assigned to
Refer the table below and provide me the query to find given employee is manager or not.
Refer the table below, emp#100 is manager, emp#300 is not a manager.
<emp> <emp_name> < manager >
100Smith null
200Ram 500
300Shankar 500
400Madhur 200
500Suman 100
600Sundar 100
I am using Oracle database 10g R2.
suppose I have this structure
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
What I want is when I query for any EMP_ID, I want to get all his manager first, and the last record is the employee in leaf of the hierarchy in the query.
For example, when I query for EMP_ID=2 ,I want to get this result
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
and when I query for EMP_ID=3 ,I want to get this result:
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
How to write this query?
/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */
CREATE PROCEDURE p_get_name (
p_empno IN OUT NUMBER,
p_name OUT VARCHAR2,
p_err OUT NUMBER
[code].......
Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.
based on the following information
grade lowsal highsal
------ ----- ------
1 700 1200
2 1201 1400
3 1401 2000
4 2001 3000
5 3001 9999
for the employee table to assign grade for each employee based on his salary the following plsql procedure is giving error:
-----------------------------------------------------------
CREATE OR REPLACE PROCEDURE GRADE(EID IN NUMBER,BONUS OUT NUMBER) IS
vGRADE NUMBER(8,2);
vSAL NUMBER(8,2);
BEGIN
vGRADE=1
SELECT SAL INTO vSAL FROM EMP WHERE EMPNO=EMPID;
IF vSAL<= 700 THEN
vGRADE:=1;
ELSEIF vSAL<= 1201 THEN
[code]....
I used Scott schema.I take 2 blocks ,one block having Deptno,Job and also 1st block is a non database block and Another Block Empno,ename,job,sal,deptno, is a database block,my question is when i enter Deptno,Job then Display Employees Details and also Department name
View 1 Replies View RelatedI want to populate only particular employee LOV ,when i am press "Populate LOV"..Button and i attached Form for testing and It is a 10g version..
View 5 Replies View Relatedi want to display employees details when i am passing Deptno and that department employees only display in Oracle Forms
View 16 Replies View RelatedI would like to update the particular employee name by using the cursor ..For that I would like to show the steps which I did . as in the below screen it updated John but it removed the other ename ...I like to update John only and remaining ename should be as it ..
The code which I have written on KEY-COMMIT is below.
I have a requirement that I need to create a report for absent employee, we have "Hand Punch" scanning system for attendance, when a employee scan his hand it put a record with the employee id, date, shift, & time.
Now I need to create a report for absent employees in date range
I am looking to send all employees in the company their payroll slip directly to their email IDs, so I need to built a producer can :
1- Generate their slips and save it into PDF files with each employee number .
2- send an email message to each employee with his slip.
Hierarchical Tree in oracle form 6i .i am trying to build tree in form 6i but it give error
SELECT 1,
level,
job
,
'',
ename
FROM emp
START WITH mgr IS NULL
CONNECT BY PRIOR empno = mgr
order by level
i want to show job wise employees ...
i've got problem when viewing my records from a tree. When i click a data from a tree it displays 2 times. and when i try to click another data my previous data was gone.
my screenshot is attached
this is my
DECLARE
mytree ITEM;
[code].....
I want to know how to create tree structure in forms6i. This should be created as " Control-block". For example when user expand department it shows all department names in college as sub tree. Note: I have no table for department..Just display manually..
View 1 Replies View RelatedI have created the 5 Level Hierarchy Tree using the Tree example
[URL]........
how-to-s/ forms- how- to- create - a- hierarchical - tree-form".
My requirement are
1. I wish to refresh the Hierarchy Tree after DML Operation.
2. I wish to Query the Record when i will select the node.
I have 5 Master Detail Record as:
Master - Detail
Detail Master -- Detail
Detail Master -- Detail
Detail Master -- Detail
Detail Master -- Detail
3. Is there any way to find out which Hierarchy Level currently selected
4. Is there any way to find out which value is for what block.
I need complete source from hartical tree menu using by calling reports and calling forms.
i need related Table ,triggers and Examples.
if i have two reports one of them is that you enter the office name and it will show you list of employee. the second one i want to show the information that is related to that employee by putting beside each employee button that if pressed i will go to other report that show me information about that employee.How i could link the two form and pass the employee name to the next form
View 4 Replies View RelatedI have a table like below,I want retrieve each employee age ,from db column
SQL> select * from dob;
ENAME DB
---------- ---------
vishal 12-MAR-90
jeya 30-MAR-73
vasanthi 17-APR-80
mangai 25-NOV-81
poorna 18-AUG-80
vinod 20-AUG-81
nanthini 01-JUN-86
karthick 20-MAR-88
I am using oracle forms 9i. I have to create a Hierarchical Tree and attach checkbox at its node,so that user can select which tree he want in its further processing.
View 4 Replies View RelatedI have to create a functionality on a button through which all nodes of hierarchical tree will be selected.
I know that this is possible with mouse (one-by-one+Ctrl). But,I have to done this on button.
How to create multi selection tree in oracle forms ?
View 1 Replies View RelatedI created TREE object in my application main menu and I want to use it through MOUSE and KEYBOARD therefore I add WHEN-TREE-NODE-ACTIVATED trigger at my tree object
Trigger text is:
declare
htree item;
node_value VARCHAR2(100);
akt_node ftree.node;
[code]...
Problem:When I am using MOUSE and clicking on + or anyother form/report, it's opened last selected form/report or application closed but it is working fine when I am using KEYBOARD.
i have created a tree hierarchy....when the user clicks on any node,that particular form will open....But there is some problem...i click on form A,it opens.,...then i exit that form via a exit button on the toolbar....and then I click on form B on the tree....but first the form A only opens...and then again i exit form A, then form B will open..
i have written the following code in when_tree_node_selected trigger :
if condition then
call_form(path,no_hide,do_replace);
I have a hierarchical tree with two parent nodes. Each parent node has different number of child nodes. Can i disable or hide a node according to some condition?
View 5 Replies View RelatedI would like to display data using the Hierarchical tree up to 3 levels.I need to create all the nodes programatically.
Means Create the parent (Parent1) level nodes , then create the child (Child1) nodes and add them under the parent1.Similarly create child nodes (Child2) and add them under the parent (Child1).
I have a form in which menu tree is populated with this sql
SELECT 1, Level, MenuLabel, MenuName, MenuId
FROM MenuFile
CONNECT BY PRIOR MenuId = ParentId START WITH menuId = :moduleid||'0000'
The result is attached in the CSV file enclosed in sheet mrnufile1As we can see in row 3 the item LPC has menuid BDME13.
In my view This item should be in ROW 19.How can i change query do get the desired the result.I have also tried another sql query.
select * from menufile where applicationid = 'BD' order by parentid,menuid
Result of this query is in 2nd Half of CSV file
