Refer the table below and provide me the query to find given employee is manager or not.
Refer the table below, emp#100 is manager, emp#300 is not a manager.
<emp> <emp_name> < manager >
100Smith null
200Ram 500
300Shankar 500
400Madhur 200
500Suman 100
600Sundar 100
I am using Oracle database 10g R2.
suppose I have this structure
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
What I want is when I query for any EMP_ID, I want to get all his manager first, and the last record is the employee in leaf of the hierarchy in the query.
For example, when I query for EMP_ID=2 ,I want to get this result
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
and when I query for EMP_ID=3 ,I want to get this result:
EMP_ID EMP_NAME MANAGER_ID
1 KING
2 STEVE 1
3 FRANK 2
How to write this query?
Query to find out employees who are all joined before Manager.
For Example the Table may look like.
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E106Manager 11-Oct-08
E107Programmer20-Nov-09
E108Coordinator12-Dec-10
E109DB Admin10-Feb-07
E110DB Analyst10-Aug-05
The out put must be..
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E109DB Admin10-Feb-07
i have 3 tables
table employee
employee_no
employee_name
table manager
manager_id
manager_name
table department
dept_id
dept_name
how can show on the tree all manager with employee with department
example
manager ali
employee Mohamed
department marketing
I have done it through SUBQUERY AND MIN FUNCTION
SQL> SELECT LAST_NAME ,HIRE_DATE FROM EMPLOYEES
WHERE HIRE_DATE = (SELECT MIN(HIRE_DATE) FROM EMPLOYEES) ;
but i want a smaller, simple code .
In the Employee table i want to display having 4 characters of Emplo_name ,that name's 3rd character must be 'R' How to get it .
View 9 Replies View Related/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */
CREATE PROCEDURE p_get_name (
p_empno IN OUT NUMBER,
p_name OUT VARCHAR2,
p_err OUT NUMBER
[code].......
Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.
based on the following information
grade lowsal highsal
------ ----- ------
1 700 1200
2 1201 1400
3 1401 2000
4 2001 3000
5 3001 9999
for the employee table to assign grade for each employee based on his salary the following plsql procedure is giving error:
-----------------------------------------------------------
CREATE OR REPLACE PROCEDURE GRADE(EID IN NUMBER,BONUS OUT NUMBER) IS
vGRADE NUMBER(8,2);
vSAL NUMBER(8,2);
BEGIN
vGRADE=1
SELECT SAL INTO vSAL FROM EMP WHERE EMPNO=EMPID;
IF vSAL<= 700 THEN
vGRADE:=1;
ELSEIF vSAL<= 1201 THEN
[code]....
I have four employee types such as 'C' for consultants, 'S' for staffs, 'W' for workers ,, ('E','S','W') for all types of employees. i have write four queries for showing four types of employees. can it is possible in a single query.
I have written this in oracle forms . I have taken a list item for workers i have taken 'W' , for staffs i have taken 'S' , for consultants i have taken 'C' and for all i have taken 'A'. my column name is emp_type in( :block.list_item ) but it is not taking the value from the list item when the value is emp_type in('C') etc etc..
like this for workers ,staffs . when it is 'A' it will take emp_type in ('E','S','W')
I have three tables as shown in the image. Need to get the details of each employee in a single row..
EMployee_id BaseSalary Bonus Hike shares
I have been trying to construct a query in Oracle that allows me to do the following:
For example if I have the data below:
EmpNo DOB SickDays
Alex 445 15/06/1985 7
Tom 778 22/08/1981 4
James 992 07/10/1978 5
I need to write and a query to lists the employee number and the amount of days sick that they have had and also add a column that compares the number of sick days to the average number of suck days by ALL employees.
I can calculate the average sick days etc, but It wont see to allow me to find the difference between that and the amount of sick days that each person has had. I have tried this many ways and have not been able to come up with a solution.
I have install oracle 11g database enterprise edition But i cannot find the Oracle Enterprise Manager after the installation. i want the gui based Oracle Enterprise Manager i have access the the web base Oracle Enterprise Manager but not the gui based.how to use and download the GUI Based Oracle Enterprise Manager ....
View 1 Replies View RelatedI have a table like below,I want retrieve each employee age ,from db column
SQL> select * from dob;
ENAME DB
---------- ---------
vishal 12-MAR-90
jeya 30-MAR-73
vasanthi 17-APR-80
mangai 25-NOV-81
poorna 18-AUG-80
vinod 20-AUG-81
nanthini 01-JUN-86
karthick 20-MAR-88
I use Oracle 9i and I created DBMS Job for run Procedure. when job run by scheduled I found Failure notify but I can not find where the detail of it. How do I find path or detail of Failure notify? I use oracle enterprise manager console.
View 1 Replies View RelatedDoes EM have a utility that I can get to scan a set of host machines and their disks and tell me what oracle products are installed? Sort of like that common inventory tool used on windows desktops, but just for Oracle products.
If not EM then any third party tool or some other Oracle tool?
query to get the name and size of all the databases associated to grid..
I need to find this to do capacity planning in our environment.
from the below string i want to find the count of the "<-" using a single query.
string is "aaaa<-bbbb<-ccccc<-ddddd<-eeeeee<-ffffff<-"
If not the query, pointer on using SQL functions.
building SQL query to get the result as shown below.
Create Table Temp
CREATE TABLE TEMP
(
CASEID NUMBER,
SATUS VARCHAR2(1 BYTE),
TRANS_DATE DATE
)
Insert data
[Code]...
I want to build a query which should give output as shown below. Basically i want to select those rows which having minimum trans_date for a given CASEID & Status.
OUTPUT:
CASEIDSATUSTRANS_DATE
100A11/02/2010
100B11/07/2010
100A11/12/2010
200A11/02/2010
200B11/07/2010
the below requirement.
I have 2 tables, first one MAIN_T, which contains, user_id and username.
The second table is a relationship table which contains the referal details.
The requirement is to convert the user_id and frnd_id from RELATION_T to their respctive names using MAIN_T.
-- Test Case
CREATE TABLE main_t (user_id NUMBER, username VARCHAR2(10));
CREATE TABLE relation_t(user_id NUMBER, frnd_id NUMBER);
INSERT INTO main_t VALUES(1, 'u1');
INSERT INTO main_t VALUES(2, 'u2');
INSERT INTO main_t VALUES(3, 'u3');
INSERT INTO main_t VALUES(4, 'u4');
INSERT INTO main_t VALUES(5, 'u5');
[Code]....
I have written this query, which gives me the expected output.
SELECT membr.username member_name , frnd.username friend_name
FROM
main_t membr,
main_t frnd,
relation_t rltn
WHERE
rltn.user_id=membr.user_id
AND rltn.frnd_id=frnd.user_id
/
MEMBER_NAM FRIEND_NAM
---------- ----------
u1 u2
u2 u3
u5 u4
u1 u5
4 rows selected.
a better way for this requirement.
i have a requirement where i have to get the id who are only subscribed to only one course based on the below provided data.
ID Course
103812 CFH
102968 REP
103812 DFH
102968 DFH
103071 DFH
102968 CFH
I have a table with thirty column for attendance like Day_A01,Day_A02......Day_A31.
I need a query that should return the column which is empty but its next and previous column is not empty.
SELECT HISTORY_ID ,SUM(MISSED_SCHOOL) AS MISSED_SCHOOL,SUM(MISSED_SCHOOL_LAST) AS MISSED_SCHOOL_LAST
FROM EMRASTHAMAHISTORYDETAILS
WHERE ------
GROUP BY HISTORY_ID
There is no date column in table using sysdate alone need to retrieve last 6 month records
how to use in where condition
I need to find out that assume i have a table having 2 column
Num Name
1 Adam
2 Akanksha
1 barren
2 bosli
3 Benergee
4 Bhawna
3 anjani
I want a query as if A is there 2 times then there should be 1 then 2 then there is b coming in 4 places then it should be 1 2 3 4 and again there is anjani so 3 should be there as 1 and 2 in first 2 places and the num should be automatically generated number based on the count of the alphabets
i need a SQL query which should return me relevant table names. i.e. if there is table 'EMP' , then query should give table names with below result:
EMP
EMP_1
EMP_2
EMP_3
EMP_4
i.e. All tables which is starting with EMP (No Hardcoding of table, It should be dynamic way).I know we can achieve through SELECT * FROM USER_ OBJECTS WHERE OBJECT_NAME LIKE 'EMP%'. But here object_name i will passing dynamically.
I am working on a form, whose one block is query_find, so on clicking find button it will open another block.the find block contain 4 column and second block contain around 10 column.but the column present in find block are associated to standard tables and the column present in block-2 are from custom tables.there is a query which link those column.
I am not sure where to use that query, so that it will take input from the find block and then populate the result into the block-2.
I want to know how I can find which query is taking more time , for example some query's are run from unix, java and from toad,sqlplus. and one query is taking much more time to execute, so how i can get that query and all the details.
View 2 Replies View RelatedMy table has two date columns EFF_DT which is the start date and TERM_DT is the end date. The EFF_DT of the next record should be the next date of the TERM_DT record.
My table looks like this.
Input Table:
-----------
CK_IDPI_IDEFF_DT TERM_DT
Mem1ABC1-Jan-1331-Mar-13
Mem1ABC1-Apr-1331-May-13
Mem1ABC1-Jun-1330-Sep-13
Mem1ABC15-Oct-1331-Dec-13
Mem1ABC1-Jan-1431-Mar-14
Mem1XYZ1-Apr-1430-Jun-14
Mem1XYZ1-Jul-1431-Dec-14
Expected Output:
----------------
CK_IDPI_IDEFF_DT TERM_DT
Mem1ABC1-Jan-1330-Sep-13
Mem1ABC15-Oct-1331-Mar-14
Mem1XYZ1-Apr-1431-Dec-14
In the fourth record, the effective date should be 1-Oct-13 which is the next date to the last TERM_DT 30-Sep-13.As the is the break in the date, the output should show 15-Oct-13 sa the second start date.
Note: Refer to the PI_ID columns, there is a break in the date for the sale PI_ID 'ABC'.
Here I am trying to generate a pseudo column, so that the table with the pseudo column looks like as shown below. and I can use first_value and LAST_value by partitioning on the pseudo column to get the desired output.
1) CNT_VAL is the pseudo column:
-----------------------------
CK_IDPI_IDEFF_DT TERM_DT CNT_VAL
Mem1ABC1-Jan-1331-Mar-131
Mem1ABC1-Apr-1331-May-131
Mem1ABC1-Jun-1330-Sep-131
[code].....
My Query :
----------
I not getting the desired output here as the value in pseudo column is 3.
select CK_ID, PI_ID,EFF_DT,TERM_DT,
(case
when case_CONT - LAG(case_CONT,1) over (ORDER BY EFF_DT) = 0 then to_char(case_CONT)
when case_CONT - LAG(case_CONT,1) over (ORDER BY EFF_DT) <> 0 then to_char(LAG(case_CONT,1) over (ORDER BY EFF_DT) + 1)
else to_char(nvl(case_CONT,0))
[code].....
Scripts:
--------------------
Create table lead_test(
CK_ID varchar2(10),
PI_IDvarchar2(10),
EFF_DTDate,
TERM_DT date);
[code].....
I need to query a table to get the time difference based on different dates.
SAMPLE DATA:
JOB ID start_time end_time
1 201008190056 19/08/2010 01:23:12
2 201008190123 19/08/2010 01:50:12
2 201008200045 19/08/2010 01:50:12
3 201008070345 7/08/2010 04:50:12
3 201008070345 7/08/2010 04:50:12
1 201008070003 7/08/2010 00:30:12
in the above, for job 1 ,on 19/08/2010 the time difference should be calculated as
01:23:12-00:56:00 and the difference should be in minutes.
for end_time. i can't take the substring as the length of the date varies for 19 and 7. In case of start date, the time has to be in format, hh:mm:ss, to calculate the difference.
find the recent SQL history from Oracle 11. could the following SQL retrieve all SQL history happened in last 5 mins?
SELECT h.user_id,
s2.username,
h.sample_time,
s1.sql_text
FROM v$active_session_history h,
v$sqlarea s1,
[code]....
I have a table as follows:
customers
------------------------------------------------------------------------------------------
custid credit amt month
--------------------------------------------------------------------------------------------
001 C 2000 Jan-2012
001 D 5000 Feb-2012
001 C 3000 Mar-2012
001 C 3000 Apr-2012
001 D 7000 May-2012
I Have to write a single query to calculate the sum of credit and sum of debit value separately.