I have four employee types such as 'C' for consultants, 'S' for staffs, 'W' for workers ,, ('E','S','W') for all types of employees. i have write four queries for showing four types of employees. can it is possible in a single query.
I have written this in oracle forms . I have taken a list item for workers i have taken 'W' , for staffs i have taken 'S' , for consultants i have taken 'C' and for all i have taken 'A'. my column name is emp_type in( :block.list_item ) but it is not taking the value from the list item when the value is emp_type in('C') etc etc..
like this for workers ,staffs . when it is 'A' it will take emp_type in ('E','S','W')
/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */ CREATE PROCEDURE p_get_name ( p_empno IN OUT NUMBER, p_name OUT VARCHAR2, p_err OUT NUMBER [code].......
Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.
EMP_ID EMP_NAME MANAGER_ID 1 KING 2 STEVE 1 3 FRANK 2
What I want is when I query for any EMP_ID, I want to get all his manager first, and the last record is the employee in leaf of the hierarchy in the query.
For example, when I query for EMP_ID=2 ,I want to get this result
EMP_ID EMP_NAME MANAGER_ID 1 KING 2 STEVE 1
and when I query for EMP_ID=3 ,I want to get this result:
EMP_ID EMP_NAME MANAGER_ID 1 KING 2 STEVE 1 3 FRANK 2
I have been trying to construct a query in Oracle that allows me to do the following:
For example if I have the data below:
EmpNo DOB SickDays Alex 445 15/06/1985 7 Tom 778 22/08/1981 4 James 992 07/10/1978 5
I need to write and a query to lists the employee number and the amount of days sick that they have had and also add a column that compares the number of sick days to the average number of suck days by ALL employees.
I can calculate the average sick days etc, but It wont see to allow me to find the difference between that and the amount of sick days that each person has had. I have tried this many ways and have not been able to come up with a solution.
I want to get any employee name of deptno 10 but total count of number of employees under dept 10.
DECLARE l_deptno NUMBER:=10; l_count NUMBER; l_ename varchar2(20); BEGIN SELECT count(*) OVER(order by empno) ,ename INTO l_count,l_ename FROM emp WHERE ROWNUM=1 and deptno=l_deptno; dbms_output.put_line(l_count||' '||l_ename); end;
write a query to get the first row after order by clause using single query alone.Example:I can write following query to select first rowselect * from (selec * from t order by col1) where rownum = 1;But here I should not use inline view to get the result. Because my original requirement needs to use this query in select list and it needs to use a column (of a table from the FROM clause) in the where clause of inline query. Because there is restriction that we can not use the column (of a table from the FROM clause) more than one level of inline query.
I want to replace below multiple call to procedure with a Single query. Currently this proc is getting called multiple times from application.
FUNCTION f_get_shows_info(i_booking_wk_id IN NUMBER, i_screen_id IN NUMBER) RETURN VARCHAR2 IS v_act_shows booking_wk_screen.act_shows%TYPE; v_expected_shows booking_wk_screen.expected_shows%TYPE; v_return VARCHAR2(50); BEGIN SELECT NVL(act_shows, 1), NVL(expected_shows, 1) INTO v_act_shows, v_expected_shows FROM booking_wk_screen WHERE booking_wk_id = i_booking_wk_id [code]...
Is there anyway through which we can achieve this in Oracle 10g.
i have a problem in the following query. i need to fetch the rows such that i want to fetch all the records keeping "segment1" column as distinct and sum all of the corresponding "quantities" column.
i tried to use the partition technique. using partition solved the problem apperently. the sum function worked but redundancy in "segment1" column still persists. i used the sum function only to extract the distinct "segment1" column and summing its corresponding "quantity" column (only quantity column differs in the redundant rows...)
the second query was like:
SELECT prha.segment1, prha.creation_date, SUM(prla.quantity) OVER(PARTITION BY prha.segment1) AS qty, prha.DESCRIPTION,
how does this query execute? what kind of a query is this called?
mysql> select ename,(select dname from dept where deptno=e.deptno ) as dname -> from emp e;
+--------+------------+ | ename | dname | +--------+------------+ | SMITH | RESEARCH | | ALLEN | SALES | | WARD | SALES | | JONES | RESEARCH | | MARTIN | SALES | | BLAKE | SALES | | CLARK | ACCOUNTING | | SCOTT | RESEARCH | | KING | ACCOUNTING | | TURNER | SALES | | ADAMS | RESEARCH | | JAMES | SALES | | FORD | RESEARCH | | MILLER | ACCOUNTING | +--------+------------+ 14 rows in set (0.00 sec)
summer_course_completed | winter_course_completed | user_id | attendance ------------------------------------------------------------------------ y | n | 2 | 20 y | n | 2 | 40 y | y | 2 | 30 n | n | 3 | 20 n | y | 3 | 60
I wish to list each student's name with the number of summer courses he has completed and the number of winter courses he has completed. I am trying this :
select u.name, count(*) from user u, course_user cu where u.id=cu.user_id and cu.summer_course_completed = 'y' group by u.id;
but I can get only the number of summer courses OR the number of winter courses that each student has completed, but never both simultaneously, through a single query. Is there a way to do that ?
select order_number, (select decode(hcp.contact_point_purpose,'ABC',hcp.email_address,'CDE',hcp.email_address,null) from hz_contact_points, hz_parties hz WHERE hz.party_id=hcp.owner_table_id) Email FROM oe_order_headers_all h WHERE h.order_number='102' .................... ..............
Actually the problem i am facing is the inner select query is returning multiple row , so my main query is erroring out, i need to capture the multiple row.
In the above example the inner decode statement returning two mail address, I need to capture that, but while executing the whole query it is erroring out as saying single query returns multiple values. capture multiple values
I have table say Messages. In which there is a column msg_text varchar2(900).My requirement is to fetch the very last character of the msg_text for a single row identified by its msg_code(primary key).
The problem is, whenever msg_text contain second last character as single quote( ' ), it doesn't give me the last character i.e. after the single quote.For example if msg_text is "Congratulations, you opted for 'A'." and if its message_code is 10 then query
SQL> SELECT SUBSTR(msg_text,LENGTH(msg_text),LENGTH(msg_text)) AS LAST_CHAR FROM messages WHERE msg_code = 10;
returns nothing.
Whereas if msg_text is "Are you sure to continue?" and if its message_code is 20 then query
SQL> SELECT SUBSTR(msg_text,LENGTH(msg_text),LENGTH(msg_text)) AS LAST_CHAR FROM messages WHERE msg_code = 20;
The table has single column & the values may differ,that is, they may have 1-2-3-...-n in a single row, but the desired output is to be in the rows as shown above.
I tried concepts of SQL up to my knowledge, but I failed. The query to be done only in SQL.complete this query.
Now I need to start with the employee 1 . As we can see the emp 1 is mapped to dept A and also with multiple dept. Similarly dept id is mapped to multiple emp.
I need the output as below (many to many I.e. cross referencing)
EMPID DEPIDGroup 1A A1 2A A1 2B A1 1B A1 4A A1 5B A1 5A A1 6C B1 -- new group as the emp and dept are not mapped previously 7A A1 8D C1
