PL/SQL :: Query To Find The Sum Of Different Groups Of Same Column
Feb 23, 2013
I have a table as follows:
customers
------------------------------------------------------------------------------------------
custid credit amt month
--------------------------------------------------------------------------------------------
001 C 2000 Jan-2012
001 D 5000 Feb-2012
001 C 3000 Mar-2012
001 C 3000 Apr-2012
001 D 7000 May-2012
I Have to write a single query to calculate the sum of credit and sum of debit value separately.
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Aug 3, 2010
I have a table with thirty column for attendance like Day_A01,Day_A02......Day_A31.
I need a query that should return the column which is empty but its next and previous column is not empty.
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Sep 3, 2013
I google to find the Table Name and Column Name by having a value(Number/String). And my where clauses are
where owner NOT IN ('SYS','SYSTEM') and data_type IN ('CHAR','VARCHAR2','NUMBER')
My query as follows
select a.owner, c.column_name, c.data_type, c.owner, c.table_namefrom dba_objects a, all_tab_cols c where a.owner NOT IN ('SYS','SYSTEM') and where c.owner NOT IN ('SYS','SYSTEM') and where c.data_type IN ('CHAR','VARCHAR2')order by a.owner
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Jun 29, 2010
Need a query to find the count of presence of delimiter "," in column VAL for below mentioned table.
Table:
CREATE TABLE N_B_S_1
(
NUM NUMBER,
VAL VARCHAR2(20)
)
Data:
INSERT INTO N_B_S_1 VALUES(1,'A,B,C');
INSERT INTO N_B_S_1 VALUES(2,'D');
INSERT INTO N_B_S_1 VALUES(3,'ER,NF,G,H,XK');
INSERT INTO N_B_S_1 VALUES(4,'LQW,MBV');
INSERT INTO N_B_S_1 VALUES(5,'KS,YJ,WE,RQ,PM');
COMMIT;
Required output:
num, count of delimiters
===== ===========
1 2
2 1
3 4
4 2
5 4
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Feb 5, 2010
I was looking for application column name corresponding to "Draft Invoice Number" ra_interface_lines_all table.
I tried the below.
/* Get descriptive_flexfield_name for the application table name*/
SELECT *
FROM FND_DESCRIPTIVE_FLEXS_VL
WHERE application_id = 222
AND APPLICATION_TABLE_NAME=upper('ra_interface_lines_all');
/* Get the application column name and end user column name*/
SELECT *
FROM FND_DESCR_FLEX_COLUMN_USAGES
WHERE application_id = 222
AND descriptive_flexfield_name = 'RA_INTERFACE_LINES';
There are many DESCRIPTIVE_FLEX_CONTEXT_CODEs obtained. I could finally trace out that draft invoice number corresponds to INTERFACE_LINE_ATTRIBUTE2. How can I know what DESCRIPTIVE_FLEX_CONTEXT_CODE should I look for?
I want to build a single query to fetch the application column name and flex field name for a specific table .
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Jul 22, 2009
I'm trying to do a pivot query in oracle to get the years from a column and make a separate column for each. I found an example of the code to use on the internet and i changed it for my own tables but i'm getting errors. Namely a "FROM keyword not where expected" error at the beginning of the 'avg(...' statements.
I have copied the code used in
select stud_id, 2006, 2007, 2008, 2009
from (
select stud_id,
avg(case when year=2006 then ((present/poss)*100) else null end) 2006,
avg(case when year=2007 then ((present/poss)*100) else null end) 2007,
avg(case when year=2008 then ((present/poss)*100) else null end) 2008,
avg(case when year=2009 then ((present/poss)*100) else null end) 2009
from attendance.vw_all_attendance_perc
group by stud_id
);
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Feb 11, 2013
We are using Oracle 11g with Apex 3.2 on AIX. We are reporting data from customer satisfaction surveys. I'm using the following sql to create my report
<code>select * from(
select month,'Overall Satisfaction' as q_group, 1 as srt,Overall Satisfaction,site,
case when count(*) < 31 then '*' else
round((sum(ttos)/count(*))*100,0)||'/'|round((sum(bfos)/count(*))*100,0)||'/'||count(*) end ospct
from v_XXX_report a,(select distinct month_dt month from v_XXX_report) b
where Overall_Satisfaction is not null and year_dt = 2012
[Code]....
The problem is that site is not allways present and sometimes I have other variables in addition to site. This creates a situation where the month columns will not allways appear at the same column number. For example, When I run this query as is then the "JAN" column is Col3 (first column is a break, col2 is not shown). When I run this query without site then "JAN" is the second column. I would like to create column links for the "JAN" - "DEC" columns but not for any other columns.
Another issue - in the column link creation screen I can create up to 3 variables that I can pass to the next page. Since my query is a pivot I'm uncertain how to pass the column heading or the row value (for col2)
ie
Overall Satisfaction JAN FEB MAR APR MAY ...
Overall Satisfaction 12/12/200 12/12/210 12/12/220 12/12/230 12/12/240...
Recommend 12/12/200 12/12/210 12/12/220 12/12/230 12/12/240...
etc.
So if I clicked on the values at Recommend:FEB how can I get "Recommend" and "FEB" into variables that I can use on the next page? I've tried #column_name#, #month#, #q_name# and #APEX_APPLICATION.G_F10# but no luck.
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Oct 22, 2010
I am having to pull out all the dependencies for a column as below.
When I select a column in a table, it should list
1. All Views that use this column and table
2. All Stored procs that use this column and table
3. All Functions that use this column and table
4. All Pl/SQL scripts that use this column and table.
Is there a easy way of getting this information from the Oracle dba tables?
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Nov 9, 2011
To find out column in which table it is located.
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May 14, 2013
With Data in a table, is it possible to find out the table name and column name? Means i know the account number (data) of the table and with this data i want to find out column name and table name.
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Feb 25, 2011
We have a new implementation which will be using ASM with RAID. The data area needs to be 3TB, and the recovery area, to be used for archive logs and RMAN backups, needs to be 1TB.
The configuration i'm thinking about now is:
+DATA diskgroup: 5*600G disks, using RAID 1+0 (this will include control files)
+FRA diskgroup: 2*500G disks, using RAID 1
+LOG diskgroup: 2*1G disks, using RAID 1 (this is only for redo logs)
So here are my questions:
1. Am I right in supposing that we would get the best performance on the +FRA and +LOG diskgroups by not using RAID 1+0?
2. It has already been agreed to use RAID 1+0 for the +DATA diskgroup, but I can't see the added benefit of this. ASM will already stripe the data, so surely RAID 0 will just stripe it again (i.e double striping the data). Would it not be the better just to mirror the data at a hardware level?
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Apr 22, 2010
Data at a table with single column unique indexed is like
1,3,5,6,8,10,98,45,23,56,34,12...... there are about 100 million records.
Out of these values we need to create fixed(5 in each) groups, from - to.
example
1-8
10-56
98-..
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Aug 1, 2013
I am able to assign a user to a user group using the User Admin in Apex.I don't know how I would be able to assign a role (that I know how to define that for an individual user).The only thing I can see is a name for User Group and a Description! My requirement is to define a group of people to be assigned to one group/role, so that every change to that role can be automatically be applied to each user in that group
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May 19, 2010
I need the column name and table name which is having the particular value in the whole database.
E.g. :We have 'Scott' value in emp table emp_name column. and we have lot of tables. here we need emp_name and emp as emp table is having scott value in emP_name column.
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Jul 28, 2011
i need an sql query or procedure to find out table name based on the column name..
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Dec 1, 2011
How to find out the required column from user tables using query ?
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Oct 15, 2012
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE 11.2.0.3.0 Production
TNS for Solaris: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production
I have multiple schemas, all which have tons of objects that point to one column of one table. I tried to look at v$sqltext, and v$sqlarea, but it doesn't seem to show as expected.
Is there a view that I can look at that will show me all the objects that relate to one column?
my situation. Had to change the data structure of this one column. Changed the default value from a Y to an L. I have packages, functions, triggers...etc... that deal with this one column. I need to ensure that I go through EACH one and edit them to reflect the change to the table column. And again, this spans multiple schemas that point back to it.
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Apr 16, 2010
from the below string i want to find the count of the "<-" using a single query.
string is "aaaa<-bbbb<-ccccc<-ddddd<-eeeeee<-ffffff<-"
If not the query, pointer on using SQL functions.
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Nov 5, 2010
building SQL query to get the result as shown below.
Create Table Temp
CREATE TABLE TEMP
(
CASEID NUMBER,
SATUS VARCHAR2(1 BYTE),
TRANS_DATE DATE
)
Insert data
[Code]...
I want to build a query which should give output as shown below. Basically i want to select those rows which having minimum trans_date for a given CASEID & Status.
OUTPUT:
CASEIDSATUSTRANS_DATE
100A11/02/2010
100B11/07/2010
100A11/12/2010
200A11/02/2010
200B11/07/2010
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Oct 23, 2012
the below requirement.
I have 2 tables, first one MAIN_T, which contains, user_id and username.
The second table is a relationship table which contains the referal details.
The requirement is to convert the user_id and frnd_id from RELATION_T to their respctive names using MAIN_T.
-- Test Case
CREATE TABLE main_t (user_id NUMBER, username VARCHAR2(10));
CREATE TABLE relation_t(user_id NUMBER, frnd_id NUMBER);
INSERT INTO main_t VALUES(1, 'u1');
INSERT INTO main_t VALUES(2, 'u2');
INSERT INTO main_t VALUES(3, 'u3');
INSERT INTO main_t VALUES(4, 'u4');
INSERT INTO main_t VALUES(5, 'u5');
[Code]....
I have written this query, which gives me the expected output.
SELECT membr.username member_name , frnd.username friend_name
FROM
main_t membr,
main_t frnd,
relation_t rltn
WHERE
rltn.user_id=membr.user_id
AND rltn.frnd_id=frnd.user_id
/
MEMBER_NAM FRIEND_NAM
---------- ----------
u1 u2
u2 u3
u5 u4
u1 u5
4 rows selected.
a better way for this requirement.
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Oct 5, 2012
i have a requirement where i have to get the id who are only subscribed to only one course based on the below provided data.
ID Course
103812 CFH
102968 REP
103812 DFH
102968 DFH
103071 DFH
102968 CFH
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Sep 11, 2013
I have 5 MViews that I want to refresh in two occasions, every Sundays and at the 1st of the month. I created a Refresh Group for the weekly and that work fine. But when I tried to created the second Refresh Group for the monthly I get a "materialized view is already in a refresh group".
You can only have a materialized view in one refresh group? What options to I have to refresh it in different intervals?
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Sep 29, 2010
We recently migrated a database from 9i to 10g (overdue we know!!) and discovered that dbms_mview.refresh default behavior was turned upside down - meaning that 10g didn't first truncate the MV to refresh it. We're trying to unwind a lot of legacy issues, but it also turns out that we also have 100 REFRESH GROUPs and 100 MATERIALIZED VIEWs. That means a 1 to 1 relationship between RGs vs MVs. There is one MV defined to each RG.
These are my questions:
1) Does a 1 to 1 relationship between RGs and MVs make sense to anybody? The original implementors are gone and we can't fathom the reason for this.
2) Is there any reason why I shouldn't convert these 100 groups to plain and simple 100 MVs? I don't want the delete/insert refresh behavior of dbms_refresh.refresh and I do want the truncate behavior of dbms_mview.refresh ATOMIC=FALSE for refreshing a standard MVIEW
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Mar 12, 2008
I have a table of N records with: Name SeqNo ID Col4 ... ColX
where Name and ID are non-unique, and SeqNo is a monotonic non-consecutive sequence 0 .. N that is unique within ID..I'd like to generate the following 'groups': For each record where SeqNo = 0, sorted by Name, create the 'group where ID is the same, ordered by SeqNo irrespective of the
values of any of the other columns. For instance, if the table contained:
NameSeqNoIDCol4 ... ColX
RPL2975...
TLM0444...
AAB2801...
AZZ0801...
ABA3444...
KTT4975...
ABA1801...
YHG0975...
DEF1444...
I'd like to generate:
NameSeqNoIDCol4 ... ColX
AZZ0801...
ABA1801...
AAB2801...
TLM0444...
DEF1444...
ABA3444...
YHG0975...
RPL2975...
KTT4975...
I got my desired results by brute-forcing via four sub-queries:
Sub-query 1 - Generate the sorted Names with SeqNo = 0
Sub-query 2 - Expand above with the additional columns,
maintaining original order
Sub-query 3 - For each of the records from sub-query 2,
generate the 'dependents' having the same ID
and SeqNo != 0
Sub-query 4 - Expand above with the additional columns,
maintaining original order of sub-query 1
Main query - Create UNION of 2 and 4, sorting by original
order and SeqNo
if there were not a simpler approach - after all, this must be a fairly common issue when generating BOMs.
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Mar 14, 2012
i want to create a group xyz and add some users to xyz group and want to grant/revoke permissions to xyz. So that all the users present in that group will have the same permissions as of the xyz group. so that instead of giving the permissions to users individually i can give it at a time.
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Nov 29, 2010
the thread title was a bit confusing, couldn't come up with anything short to describe the question. What I am looking for is a query which will put records into groups based on matching values in one of two columns. So if two records have a matching value in column 1 or column 2 they are in the same group. See the example bellow and expected output for a "better" explanation:
--setup
CREATE TABLE foo
(foo_id NUMBER NOT NULL PRIMARY KEY,
record_number NUMBER,
record_value VARCHAR2(1));
[Code]...
--expected output
group# foo_id record_number record_value
1 1 1 A
1 2 1 B
1 3 2 B
1 4 2 C
2 5 3 D
3 6 4 E
3 7 5 E
My initial thought is that is feels a little bit like the sequential seat problem but not quite close enough. I know it could be done iteratively with PL/SQL but I am thinking there must be a way to do it in SQL I am not seeing yet.
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Jun 11, 2012
I am using 10.2.4.0 of oracle. I am having one requirement, in which i have to divide the set of records into certain groups , so that they can be executed partly but not in one run.
So in the 'SELECT' clause itself i want to assigns particular value (may be 1 )to first 50000 records then another value(may be 2) to next 10000, like wise. And again the total count of records will also varry time to time , if the total count of record set is less than 10000 , then it should only assign '1' to all the records. i will set the group values (1,2,3...) as another column itself.
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Jul 20, 2013
I have two tables tab1 and tab2 with below data Now requirement is to find difference between two table with respect to column "serial_no" which exist only in table tab1 so as per below at serial_no 2 CC4 in tab1 but CC2 in tab2 so this is different how to dump out this data
TAB1
SQL> select * from tab1;
PARENT CHILD ROW_ID SERIAL_NO
-------------------- -------------------- ---------- ----------
P1 CC1 101 1
P1 CC4 104 2
P1 CC5 105 3
P1 CC2 102 4
P1 CC3 103 5
TAB2
SQL> select * from tab2;
PARENT CHILD PREVIOUS_ROWID ROW_ID NEXT_ROWID
-------------------- -------------------- -------------- ---------- ----------
P1 CC1 0 101 102
P1 CC2 101 102 103
P1 CC3 102 103 104
P1 CC4 103 104 105
P1 CC5 104 105 0
create table tab1(parent varchar2(20), child varchar2(20),row_id integer,serial_no integer);
insert into tab1 values('P1','CC1',101,1);
insert into tab1 values('P1','CC4',104,2);
insert into tab1 values('P1','CC5',105,3);
insert into tab1 values('P1','CC2',102,4);
insert into tab1 values('P1','CC3',103,5);
create table tab2(parent varchar2(20), child varchar2(20),previous_rowid integer,row_id integer,next_rowid integer);
insert into tab2 values('P1','CC1',0,101,102);
insert into tab2 values('P1','CC2',101,102,103);
insert into tab2 values('P1','CC3',102,103,104);
insert into tab2 values('P1','CC4',103,104,105);
insert into tab2 values('P1','CC5',104,105,0);
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Jun 20, 2013
How to find date and time of a column in table ?
say for example there is a column called 'date_txn' in a table .When i select that particular column it display output as 'June 2013'.But i want output "with date and time".
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Aug 17, 2012
I'm using Oracle 11g enhanced ADD COLUMN Functionality. Adding new columns with DEFAULT values and NOT NULL constraint no longer requires the default value to be stored in all existing records.
Sometimes we change DB columns from NOT NULL with DEFAULT to NULL with DEFAULT. This operation "materialize" column default. Is there an easy way (Dictionary view) how to find, that COLUMN default value is stored as metadata or is "materialized" ?
Oracle RDBMS version : Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
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