SQL & PL/SQL :: Query To Add Total Number Of Count Of Each Table
Jun 13, 2011
I want to know that whether we can write a query to add total number of count of each table.
for example:
select count(*) from emp;
count(*)
14
select count(*) from emp_1;
count(*)
15
select count(*) from emp_2;
count(*)
16
My question is that is it possible to add this all the three results and get the value as 45.
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May 31, 2013
I need to modify my query so that it can give me a total(duration) and total(stlmntcharge) per day in april 2013 starting from the 1st till the 30th. At the moment my query looks like below:
SELECT sum(duration),sum(stlmntcharge)
FROM voipcdr
WHERE (calldate >= TO_DATE('20130401','YYYYMMDD') AND calldate <= TO_DATE('20130430','YYMMDD'))
AND (remtrunkid IN (SELECT UNIQUE trunkid FROM trunks WHERE description LIKE '%Telkom%' AND gw_range_id = '61' AND trunkid like '9%'))
or remip in(SELECT UNIQUE startip FROM gateways WHERE rangename LIKE 'vo-za%' OR rangename LIKE 'PC-IS-VOIS%')
AND direction = 'I'
ORDER BY calldate, calltime;
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Apr 29, 2010
i need the total of the count query I am executing.My query is
SELECT COUNT(*) FROM po_headers WHERE
CREATION_DATE BETWEEN '01-MAR-2010' and '31-MAR-2010' GROUP BY VENDOR_ID
this gives output as
6
1
3
4
My objective is to find the total of distinct vendors for a given date range.how should I modify this query.
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Sep 17, 2010
DECLARE
l_query VARCHAR2(4000);
TYPE cursor_type IS REF CURSOR;
[Code].....
How can I get the total number of rows returned by the query?
I want to be able to check omething like c1.ROWS = 0
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Apr 27, 2012
display the total number of employee working under president in emp table
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Jan 26, 2010
i am using oracle developer 6i report builder i required this type of query
example
if (:page number LIKE '1')
then
srw.set_text_color('darkred');
end if;
return (TRUE);
end;
but page number is not my table database item how can i use builtan page &<pagenumber> use for conditional format.
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Aug 27, 2010
I would like to give back to the our application user a page of results for a given query along with the total result count, something like: "Showing 1-25 of 650 total results".
Currently I am doing this by submitting a second query:
select count(*) from (<previous query criteria>)
Is there a better performing approach I could be using?
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Feb 24, 2009
I have a table A which has million records, and one of the column is a date. All records prior to 01-FEB-2009 should be deleted.
I cannot run the below code considering the amount of records or rows in the table A.
Begin
Delete from A where trunc(date_column) < '01-FEB-2009';
commit;
End;
where we can delete the rows prior to 01-FEB-2009 and also have a total count of how many were deleted?
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Jan 14, 2013
We have a front end that is polling the database for some set of data.That set of data is returned by opening a ref cursor and passing it back to the calling environment.Now the problem they also want the count of total number of records that will be fetched by my select statement.One option is execute the select statement once ,get the count and pass it.But in that case i will be executuing the query twice once for count other time while openimng for the ref cursor .
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May 21, 2010
how do I count a list of number value eg 1,1,1,1,3,3,6,4 and find the one with maximum number which is 1
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Feb 19, 2013
I have a report created in Reports6i. I have two fields at the bottom
1.Page Total
2.Voucher Total
I do not want to print the Page Total if the total number of pages = 1.
How can I achieve this?
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Mar 23, 2013
I'm using this code, and it performs fine, but I'm wondering if there is a more elegant way to do it--maybe with "ROLLBACK". Basically (as you can see) I need to get a normal count for each group but also for each group take a percentage of the total count (so all groups pct adds up to 100 (oh yeah, don't test for zero below, but just a test... )
select
c.Event,
c.code,
count(1) as calls,
total.total_count,
count(1) / total.total_count * 100 as pct_of_total
from
table1 c
[Code]....
[Edit MC: add code tags, do it yourself next time]
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Apr 19, 2013
how to show total number of department with their department name assign to employee table.
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Apr 20, 2013
I have a query that should return count the number of rows depending on the value of SLOT. The expected result will be like this:
WIPDATAVALUE SLOT N M
1-2 TRALTEST43S1 1 3
1-2 TRALTEST43S1 2 3
3 TRALTEST43S1 3 3
4-6 TRALTEST43S2 1 4
4-6 TRALTEST43S2 2 4
4-6 TRALTEST43S2 3 4
7 TRALTEST43S2 4 4
The M column is used to count the total number of occurrences of a SLOT. Now, as for the N field, this is used to count the occurrence of the SLOT. In my example for the SLOT TRALTEST43S1, it has three occurrences so M will be 3. Why 3, is because of the WIPDATAVALUE. The WIPDATAVALUE of TRALTEST43S1 is 1-2 and 3. 1-2 WIPDATAVALUE signifies two occurrences (one to two) and 3 signifies only one occurrence. As for N, it should just count the number of occurrence. To further explain, see below:
WIPDATAVALUE SLOT N M
1-2 TRALTEST43S1 1 3 -> First occurrence in the total of 3
1-2 TRALTEST43S1 2 3 -> Second occurrence in the total of 3
3 TRALTEST43S1 3 3 -> Third occurrence in the total of 3
4-6 TRALTEST43S2 1 4 -> First occurrence in the total of 4
4-6 TRALTEST43S2 2 4 -> Second occurrence in the total of 4
4-6 TRALTEST43S2 3 4 -> Third occurrence in the total of 4
7 TRALTEST43S12 4 4 -> Fourth occurrence in the total of 4
This is the query that I have so far:
SELECT DISTINCT
WIPDATAVALUE, SLOT
, LEVEL AS n
, m
FROM
(
SELECT
WIPDATAVALUE
, SLOT
, (dulo - una) + 1 AS m
[code]....
I think that my current query is basing its M and N results on WIPDATAVALUE and not the SLOT that is why I get the wrong output. I have also tried to use the WITH Statement and it works well but unfortunately, our system cant accept subquery factoring.
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Apr 3, 2012
Table : Customer
Cust_idNameid
227ABC1
227ABC2
227ABC3
228XYZ1
228XYZ2
228XYZ3
228XYZ4
In one oracle table (Customer) we have multiple cust_id based on that, we want to populate id column as cust_id record count.
I have id column right now null and want result same as above.
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May 20, 2011
how to get total number of record in form
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Apr 20, 2013
here on your forum but has been following several threads ever since.So anyway here is the thing, I have a query that should return count the number of rows depending on the value of SLOT. Something like this:
WIPDATAVALUE SLOT N M
1-2 TRALTEST43S1 1 3
1-2 TRALTEST43S1 2 3
3 TRALTEST43S1 3 3
4-6 TRALTEST43S2 1 4
4-6 TRALTEST43S2 2 4
4-6 TRALTEST43S2 3 4
7 TRALTEST43S2 4 4-----
As you can see above, on the SLOT TRALTEST43S1, there are three occurrences so M (Total number of occurrences) should be three and that column N should count it. Same goes with the SLOT TRALTEST43S2. This is the query that I have so far:
SELECT DISTINCT
WIPDATAVALUE, SLOT
, LEVEL AS n
, m
FROM
(
[code]...
I think that my current query is basing its M and N results on WIPDATAVALUE and not the SLOT that is why I get the wrong output. I have also tried to use the WITH Statement and it works well but unfortunately, our system cant accept subquery factoring.
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Sep 28, 2011
SELECT emp.emp_id, emp.ename, TRUNC (attendancedatetime),
TRUNC ( ( 86400
* (MAX (attendancedatetime) - MIN (attendancedatetime))
)
/ 60
)
- 60
[Code]...
Following is the out put:
EMP_IDENAME Date Min Hrs
10013Javed Iqbal09/20/2011 00:00:0036.007.00
10013Javed Iqbal09/21/2011 00:00:0027.007.00
10013Javed Iqbal09/22/2011 00:00:0049.007.00
10013Javed Iqbal09/23/2011 00:00:000.000.00
10013Javed Iqbal09/24/2011 00:00:000.000.00
i need the TOtal sum of Minutes and Hrs e.g 7+7+7=21 and also minutes but if minutes total increase from 60 minutes then it should add to hrs .how to get sum.
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May 24, 2010
I have the folloiwng two queries:
Query_1: select count(*) yy from table1;
Query_2: select count(*) zz from table2;
I need to compute the following:
var:=(yy/zz)*100
How can I achieve this in a single query?
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Jun 21, 2011
how to store total no of updated rows (number) in a variable after executing an updation query using script
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May 21, 2011
I am working on form which consist of two block, now i need to know total record in detail block, but in form structure i have multiple details entry aginst 1 master entry and after going for next master entry the details of privious master entry are going for posting that's why i am unable to use the currnt_record function. function to retrive the total number of records in details tab.
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Apr 4, 2008
query to know number of columns in a table i.e.
if I want to know how many number of colums are present in a specific table then what would be the query.
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May 4, 2012
is there any view in oracle for getting the total number of processes and currently used process in oracle? i am using oracle 11.2.0.1.0.
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May 3, 2013
I have a multi record field of five rows. And 3 values.
the values are
IT
CSE
ECE
And i have one text item name is COUNT.
how to show the total number of records in Text item .
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Apr 14, 2009
I have following tables:
EMPLOYEE (E-Number, Name, Department, age)
ASSIGNMENT (E-Number, P-Number )
PROJECT( P-Number, Project, Manager)
Create a view to show employee names, age and total number of projects they are assigned to
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May 17, 2011
is there any query to find number of primary keys present in a table.
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Oct 29, 2013
I want to get any employee name of deptno 10 but total count of number of employees under dept 10.
DECLARE
l_deptno NUMBER:=10;
l_count NUMBER;
l_ename varchar2(20);
BEGIN
SELECT count(*) OVER(order by empno) ,ename INTO l_count,l_ename FROM emp WHERE ROWNUM=1 and deptno=l_deptno;
dbms_output.put_line(l_count||' '||l_ename);
end;
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Jan 23, 2013
I have got a procedure that successfully creates an oracle external table and populates it with the contents of a file. This works fine until I have a situation where one of the fields is a VARCHAR2(2) and I try to insert say, a 5 character value. When this happens the record in question does not get populated in the external table (and rightly so), but I could do with working out if there is a discrepancy in the number of records in the file and the number of records that actually make it into the table so I could inform the user that there is a problem.
I have attached the code that creates the external table and populates it.
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Oct 20, 2011
I am trying to calculate the total points of each customer
create table Customers(Customer_no number,revenue varchar2(30),Regularity varchar 2(30)
);
insert into Customers values(1,'25','2');
insert into Customers values(2,'50','3');
Table customers:
Customer_no, revenue, regularity
1,25,2
2,50,3
create table Points(ponts ID number,Factor varchar2(30),Weight number);
insert into Points values(1,revenue,2);
insert into Points values(1,Regularity,4);
Table points
Points ID,Factor,Weight
1,revenue,2
1,regularity,4
So for customer_no: 1
revenue is 25 * 2(weight for revenue ) =50
regularity is 2*4(weight for regularity) =8
Total =58
So for customer_no: 2
revenue is 50 * 2(weight for revenue ) =100
regularity is 3*4(weight for regularity) =12
Total =104
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Jul 21, 2012
I need the following totals for each student based on the schools that they are enrolled for each month July through June.
Total Days Suspended from each school
Attendance Table Columns - Absent Date, Absent Code, Pupil_Number, School (Absent Codes for suspended = 3)
Total Days Present at each school - Days Enrolled at each school minus Days Suspended minus Absences
Totals Takes the first day that a student is enrolled (counts the days that the school is in session and the student is not marked absent) Student must be enrolled during the time frame for that month.
Total Days Absent - Total days absent minus suspensions
Examples
Student enrolls in school 11111 on 7/15/2011
Student withdraws from School 11111 on 11/15/2011
Student enrolls in school 22222 on 11/20/2011
Total Days Present should be totaled for each student for each month that they are in a school.
I need 1 row of data for the above student for each month that contains total days suspended, total days present and total days absent.
Pupil Number School Month Totals Days Suspended Total Days Absent Total Days Present
1234 11111 07 0 0 0
1234 11111 08 0 0 4 (school days 4)
1234 11111 09 3 1 16 (schools days 20 - 3-1)
1234 11111 10 0 1 18 (school days 19 - 1)
1234 11111 11 1 1 7 (student enrolled at school A 9 days -1-1)
1234 22222 11 0 1 10 (student enrolled at school B 11 days -1)
1234 22222 12 1 2 17 (school B 20-1-2)
1234 22222 01 0 0 20
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