SQL & PL/SQL :: Query To Find Number Of Primary Keys Present In A Table?
May 17, 2011is there any query to find number of primary keys present in a table.
View 13 Repliesis there any query to find number of primary keys present in a table.
View 13 RepliesI have table called test script for table is given below
create table TEST
(
col1 Number
);
[Code]...
For these values Query is not returning values(3 and 4). So i want generic query to get this result. I am working on it but not able to generate proper query.
I need to copy the changed and deleted data in an other table. I have searched this site ,asktom and other sites also. I found the following solution from asktom website. But it gives me the changed columns data only and i need the primary key with changed data and deleted rows also.
DROP TABLE emp;
CREATE TABLE emp AS (SELECT * FROM scott.emp);
CREATE TABLE audit_table
[Code].....
In dept table there is deptno=10,20,30,40
in emp table there is deptno=10,20,30
i want to find the deptno which present in dept table but not
present in emp table.
How can find the number of standby databases configured for primary database from os level
View 9 Replies View RelatedInside procedure,I need to validate all the columns (Ex:col1 should not accept more than 40 chars) and update status(containing error or not) of these columns into another column in the same table.For this,I mentioned only 'UPDATE' statements.So 'WHERE' clause of some update statements not using Primary keys.
In that table composite primary key was created.This procedure is successfully complied & executed now.But this procedure took more than 10 mins to execute.I need to reduce the time to less than a min.
How can I create a list of items in a field, for instance lets say I have a table called car and one of the sub categories is parts. How can I make it so that parts can be any number of pre-defined entities? Or even table, for instance if I make a table called parts how can I use that in the car table in place of parts?
My second question is about using foreign keys as primary keys. If I am writing an email sql DB and I decided to use the members usrname as the primary key in the member table but then made another table that lists all the emails and decided to make the foreign key member username the primary key there.
Is that safe to do or should i create a sequence in which to identify a primary key for the email list table? Also what if I extend member to several other tables and use it as a primary key there too, seems like a kind of dangerous way to do things...
I am writing following query
SELECT DISTINCT a.list_type_code, a.list_type_name
FROM jls_list_type a, jls_list_control b
WHERE b.jalsa_srl = :jalsa_srl
AND b.list_no != a.list_type_code
ORDER BY list_type_code
I just want to display only those records from JLS_LIST_TYPE which is not present in other table JLS_LIST_CONTROL ... for this i wrote above query but it is not working.
I have taken database backup using exp command and when I try to import in other pc the foreign keys are not imported. It saying error message that no matching unique key or primary key for this column.
how will i take backup including with primary keys?
I need to find out that assume i have a table having 2 column
Num Name
1 Adam
2 Akanksha
1 barren
2 bosli
3 Benergee
4 Bhawna
3 anjani
I want a query as if A is there 2 times then there should be 1 then 2 then there is b coming in 4 places then it should be 1 2 3 4 and again there is anjani so 3 should be there as 1 and 2 in first 2 places and the num should be automatically generated number based on the count of the alphabets
We have data as below in the table. I need the to display the records in the order based on number of NULL values and position for each record.
provide a simple query using case in ORDER BY clause.
ID CLASS NAME DIST_ID DIST_NAME
0 NULL KIRAN 0 AP
0 C1213 NULL 0 AP
0 NULL NULL 0 AP
NULL C1234 NULL 0 AP
0 NULL NULL 0 AP
NULL NULL NULL NULL NULL
0 C123 RAJESH 0 AP
NULL C123 RAVI NULL AP
We have to give the rank based on NULL values and NULL value column position.Let us assume column positions as
1 2 3 4 5
ID CLASS NAME DIST_ID DIST_NAME
for the following three records number of NULL values are same. but positions are different.
0 NULL NULL 0 AP
NULL C1234 NULL 0 AP
0 NULL NULL 0 AP
NULL C123 RAVI NULL AP
Based on the column positions the ranks as
2*2+3*3=13
1*1+3*3=10
2*2+3*3=13
1*1+4*4=17
Which is having high rank (greatest number) that record should come last . The record which is having all values that should come first. The record which is having all NULL values should come last. The out put I want as
ID CLASS NAME DIST_ID DIST_NAME
0 C123 RAJESH 0 AP
0 NULL KIRAN 0 AP
0 C1213 NULL 0 AP
NULL C1234 NULL 0 AP
0 NULL NULL 0 AP
0 NULL NULL 0 AP
NULL C123 RAVI NULL AP
NULL NULL NULL NULL NULL
We have a requirement where we need to pay allowance for the employees based on their number of working days. Say for example if an employee worked from 03/Mar/2012 to 05/Apr/2012.
We have a fixed value for per month 300 Dirhams. But the Number of Days on March s 31 and Number of days in April is 30. So per day allowance for March day would be 300/31 and April would be 300/30.
We are looking for logic opr query which calculates first eh number of days in each month ( across months) and then calculate as below
Number of Working days in March is 31 - 3 + 1 = 29
Allowance A1 = (300 * 29 )/31
Number of Working days in April is 5 ( this also needs to find logical I am guess )
Allowance A2 = (300 * 5 )/30
Then A1 + A2.
The A(n) would be the total allowance where provided the number of month across.
I need to find all the tables present in DB or Schema.
View 3 Replies View RelatedI was reading the documentation for oracle 11gr2, with reference to URL>.....
The following examples show how to correctly choose the cluster key and set the HASH IS, SIZE, and HASHKEYS parameters. For all examples, assume that the data block size is 2K and that on average, 1950 bytes of each block is available data space (block size minus overhead).Note that 34 hash keys are assigned for each data block
how they arrive at 34 hash keys because another portion of the document states
This space determines the maximum number of cluster or hash values stored in a data block. If SIZE is not a divisor of the data block size, then Oracle Database uses the next largest divisor.
if that is the case, then number of hash keys should be 1900/55 = 34.55 which should have rounded up to 35.
create table call(id number(10) primary key,mobile_no number(10), other_no number(10), call_type varchar2(10),call_date_time date, duration number(10));
insert into call values(1,9818764535,9899875643,'IN','24-APR-13 02:10:43',10);
insert into call values(1,9818764535,9898324234,'IN','24-APR-13 05:06:78',10);
insert into call values(1,9818764535,9215468734,'IN','24-APR-13 15:06:78',10);
insert into call values(1,9818764535,9899875643,'OUT','25-APR-13 01:06:78',10);
insert into call values(1,9899875643,9899875643,,'OUT','25-APR-13 22:06:78',10);
Query : need to find first and last call of '9818764535' mobile number and of call_date between '24-apr-13' and '25-apr-13';
Result :
date ,mobile_no , other_no, call_type, duration
24/apr/13 , 9818764535,9899875643,'IN',10
24/apr/13 ,9818764535,9215468734,'IN',10
[Code]....
how to count how many items present in a particular data block in oracle forms 10g.whether it is a text_item or display_item or list_item etc is there any method to do this.
i have written this when-button pressed but the problem is how to get the next item name in the block
DECLARE
V_COUNT NUMBER:=0;
V_FIRSTITEM VARCHAR2(100):='';
BEGIN
GO_BLOCK('BLOCK_ITEMCOUNT');
V_FIRSTITEM := GET_BLOCK_PROPERTY('BLOCK_ITEMCOUNT', FIRST_ITEM);
LOOP
[code]....
i want a simple query to find out for example the highest age in the table.
View 9 Replies View RelatedIs there any way I could find the number of inserts happened every day to a particular table.
View 10 Replies View Relatedi need a SQL query which should return me relevant table names. i.e. if there is table 'EMP' , then query should give table names with below result:
EMP
EMP_1
EMP_2
EMP_3
EMP_4
i.e. All tables which is starting with EMP (No Hardcoding of table, It should be dynamic way).I know we can achieve through SELECT * FROM USER_ OBJECTS WHERE OBJECT_NAME LIKE 'EMP%'. But here object_name i will passing dynamically.
I google to find the Table Name and Column Name by having a value(Number/String). And my where clauses are
where owner NOT IN ('SYS','SYSTEM') and data_type IN ('CHAR','VARCHAR2','NUMBER')
My query as follows
select a.owner, c.column_name, c.data_type, c.owner, c.table_namefrom dba_objects a, all_tab_cols c where a.owner NOT IN ('SYS','SYSTEM') and where c.owner NOT IN ('SYS','SYSTEM') and where c.data_type IN ('CHAR','VARCHAR2')order by a.owner
I am using Pro*C/C++ Release 10.2.0.2 in HP-UX. But Pro*C/C++ application was written long back during oracle release 8. Now we are facing a problem like EXEC SELECT query is not fetching the records even though record is present in DATABASE.
This is not happening every time. This problem starts happening only after heavy use of the unix process.
For every request, unix process will fetch the record and updates the same at the end and process goes to wait mode to get the request again. Let say after 50 request, process is returned with no rows found error.
It started working fine only after restarting the process and problem starts again after 50th or 60th request. This problem we are facing only after upgrade to 10g.
I want to do an import of a table from my old dump file.The same table is already there in the development box but few more columns are added to that table while testing so in the dump those columns are not available.
TABLE_EXISTS_ACTION=TRUNCATE
The new table
SQL> desc "TESTINVENTORY"."TTRANSACTION"
Name Null? Type
----------------------------------------------------------------------------------- -------- --------------------------------------------------------
TRANSACTIONIDNOT NULL CHAR(26)
BRANCHCODE NOT NULL CHAR(3)
EXTERNALSYSTEM NOT NULL CHAR(3)
EXTRACTSYSTEM NOT NULL CHAR(3)
OWNERBRANCHCODE NOT NULL CHAR(3)
TRADEREFERENCE NOT NULL CHAR(20)
[code]...
It giving error while doing an import.
i am using oracle developer 6i report builder i required this type of query
example
if (:page number LIKE '1')
then
srw.set_text_color('darkred');
end if;
return (TRUE);
end;
but page number is not my table database item how can i use builtan page &<pagenumber> use for conditional format.
the relationship on my script.What I want to do is make it possible to assign many courses to a student.But I have read a few books on foreign keys and primary keys, and I still dont get how to go on doing this....
This is how the table creation with the keys looks right now...
CREATE TABLE CAMPUS (
CAMPUSID NUMBER(4) NOT NULL,
NAME VARCHAR2(80) NOT NULL,
CONSTRAINT CAMPUS_PK PRIMARY KEY (CAMPUSID));
[code]...
query to know number of columns in a table i.e.
if I want to know how many number of colums are present in a specific table then what would be the query.
How do i find a particular SQL or a set of SQL's which are excuted against a table (user identified table) that is either a very frequently executed query against that table or high impact SQL against that table? I am currently looking through the AWR reports to go through all the queries but i was wondering if there are any dictionary views where we can find this info from?
View 2 Replies View RelatedI am having two tables
Table 1 having 16 cror rows .
Table 2 having 1000 rows
I joined both the tables and fetch all inforamtion from big table for those key present in small table.Join query taking more time to fetch the rows .
I'm facing some problem even after using INSTR function in Oracle.The problem is I have written the logic in the PL/SQL block which appends all the values fetched in a loop on the basis of whether the string is present or not.
For ex:
The first value fetched from the select query first is ABCDEFG which gets appended to a variable
The next value fetched is AB even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The next value fetched is BCDEF even this has to be appended to the variable since this exactly doesn't match with ABCDEFG.
The third Value fetched is ABCDEFG this will not get appended presently according to the logic which is correct.
writing that piece of code to append the value fetched which doesn't exactly match with the existing string
I used
SELECT USER_CONS_COLUMNS.CONSTRAINT_NAME,
COLUMN_NAME,
CONSTRAINT_TYPE,
[Code]...
to create a parent key table sort of thing, but for some reason there are rows that display multiple times
CONSTRAINT_NAME COLUMN_NAME CONSTRAINT_TYPE R_CONSTRAINT_NAME DELETE_RU
-------------------- -------------------- --------------- ------------------------------ ---------
SYS_C00135225 PATIENT_STATUS C
SYS_C00135226 BALANCE C
SYS_C00135227 PATIENT_STATUS C
PK_PATIENT PATIENT_NUMBER C
[Code] ..........
is it something to do with the join command
how do I count a list of number value eg 1,1,1,1,3,3,6,4 and find the one with maximum number which is 1
View 5 Replies View Related