Relationship - Table Creation With Keys Looks?
Feb 24, 2007
the relationship on my script.What I want to do is make it possible to assign many courses to a student.But I have read a few books on foreign keys and primary keys, and I still dont get how to go on doing this....
This is how the table creation with the keys looks right now...
CREATE TABLE CAMPUS (
CAMPUSID NUMBER(4) NOT NULL,
NAME VARCHAR2(80) NOT NULL,
CONSTRAINT CAMPUS_PK PRIMARY KEY (CAMPUSID));
[code]...
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Feb 6, 2012
Would there be any problem / error when we import the dump file (which has parent table) on target database ?
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Feb 19, 2013
I need to copy the changed and deleted data in an other table. I have searched this site ,asktom and other sites also. I found the following solution from asktom website. But it gives me the changed columns data only and i need the primary key with changed data and deleted rows also.
DROP TABLE emp;
CREATE TABLE emp AS (SELECT * FROM scott.emp);
CREATE TABLE audit_table
[Code].....
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Jun 9, 2011
I used
SELECT USER_CONS_COLUMNS.CONSTRAINT_NAME,
COLUMN_NAME,
CONSTRAINT_TYPE,
[Code]...
to create a parent key table sort of thing, but for some reason there are rows that display multiple times
CONSTRAINT_NAME COLUMN_NAME CONSTRAINT_TYPE R_CONSTRAINT_NAME DELETE_RU
-------------------- -------------------- --------------- ------------------------------ ---------
SYS_C00135225 PATIENT_STATUS C
SYS_C00135226 BALANCE C
SYS_C00135227 PATIENT_STATUS C
PK_PATIENT PATIENT_NUMBER C
[Code] ..........
is it something to do with the join command
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May 17, 2011
is there any query to find number of primary keys present in a table.
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Jul 9, 2012
During ASM Disk Groups creation after the ASM instance creation, receive the following error: Disk Group ORAASMGROUP2 already exists. Cannot be created again
The Grid infrastructure was deinstall one time and still the same issue.
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Apr 9, 2013
I have two tables having same name in two different databases.i have to create a new table with these two tables in a new database.
But if one table have 2 columns and another table having three columns I have to create a new table with three columns..
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May 23, 2011
i had small query on external tables. i had (.csv) file outside the database. In this file, one column will be added monthly. i need to create the external table dynamically by adding the column for every month.
How the procedure can be created for this requirement.
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May 23, 2009
I created a table but I want to add the Unique check to it as I forgot to apply it to the table when I created it.Is it possible to make the field Unique after having created the table or do I have to drop the table and re-create it?
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Feb 25, 2012
i am trying to create table inside function where in after creating table when am trying to access the table with select statement oracle is throwing error 'Table/view doesnot exist -00942', below is the code snippet
create or replace function example (mkey in varchar2) return varchar2
is
g_key varchar2(100);
l_tbl_ntext exception;
pragma exception_init(l_tbl_ntext , -942);
begin
begin
execute immediate 'select * from example1';
exception
when l_tbl_ntext then
null;
end;
execute immediate 'create table example1(skey varchar2, g_key varchar2) storage(buffer_pool, keep)';
end example;
/
select * from example;
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Aug 17, 2010
I need to create a temp table within a stored procedure. I want to apply some logic on the table, and then delete it when it is completed in runtime -- all inside the stored procedure.
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Nov 28, 2010
I have a requirement to create the table monthly.The tablename will be the o/p of the following select query.
select 'TBR_AND_SECURITY_DEPOSIT'||TO_CHAR(sysdate, 'Monyy') from dual
I am trying to create the table for creating the backup of the existing table TBR_AND_SECURITY_DEPOSIT.
create table (select 'TBR_AND_SECURITY_DEPOSIT'||TO_CHAR(sysdate, 'Monyy') from dual) select * from TBR_AND_SECURITY_DEPOSIT
but it is throwing error as invalid table name.
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May 6, 2010
I want to create a table, whose first column , patient_id, should be a sequence.
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Aug 22, 2011
is it Possible to Assign the Sequence Name During the Table Creation.
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Feb 20, 2012
I have table property and flat , in both of these tables I have cvp_id common colomn .Now I want to add cluster on this colomn so how can I add cluster to table which is already exists.
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Apr 12, 2010
I am getting compilation error when create nested table type depend on table structure
SQL> CREATE OR REPLACE TYPE typ$nttb$1 IS TABLE OF emp%rowtype
2 ;
3 /
Warning: Type created with compilation errors.
SQL> show error
Errors for TYPE TYP$NTTB$1:
LINE/COL ERROR
-------- -----------------------------------------------------------------
0/0 PL/SQL: Compilation unit analysis terminated
1/29 PLS-00329: schema-level type has illegal reference to SCOTT.EMP
SQL>
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Apr 22, 2013
declare
vnum number;
vname varchar2(50):='t1';
begin
begin
select count(*) into vnum from dba_tables where table_name=vname;
dbms_output.put_line('table count '||vnum);
exception
when others then
vnum := 0;
end;
begin
if vnum>0 then
execute immediate 'drop table '||vname;
dbms_output.put_line('table dropped');
end if;
exception
when others then
dbms_output.put_line('table does not exists');
end;
execute immediate 'create table '||vname ||' ( n number)';
dbms_output.put_line('table created');
end;
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Jul 20, 2012
Facts:
Oracle 10.1.0.5
AIX 5.3
My table, HMTX have 10 partitions each of one have 6 millions of rows (average). We have 7 partitioned LOCAL indexes in that table.
Every month we load data into a new partition (6 million of rows aprox) and drop the oldest partition in table HMTX.
In order to do that we have a script that contain the next statements:
drop of all indexes
drop index n1;
drop index n...;
drop index n7;
[Code]...
create indexes again with tha same storage and degree parameters
CREATE INDEX hmtx_TST_N1 ON hmtx (campo1, campo2, campo3 .... campo8)
TABLESPACE xxxx
PCTFREE 0
INITRANS 2
[Code]....
My problem is in rhe index creation section, despite use parallel with degree 8 and nologging the index was created in :
Elapsed: 02:43:50.85.
In past months that index was created in :
Elapsed: 01:43:36.94
Elapsed: 04:48:31.24
Elapsed: 00:57:16.28
there are another way in order speed the index creation ?? o another way to disable ths index ??
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Oct 31, 2010
I have 2 tables , which can be mapped with a common column and the second table's rest of the columns should become like columns(like pivot) and in the second table itself 1 more column called value , this sum of the value becomes a value to the pivot column value. For this I am using CASE structure and I am writing the individual case for each column , but I am sure after some extent case don't work at all and I would like to do it dynamically( when ever the new entry will come into the source table , my proc has to pick automatically the new value and put the new value as part of pivot structure) , so pls share your inputs and if possible provide some sample code.
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Aug 2, 2010
Check table creation script
CREATE TABLE "SCOTT"."TEST_USER"
("TX_SID" VARCHAR2(30 BYTE) NOT NULL ENABLE,
"TX_FIRST_NAME" VARCHAR2(30 BYTE) NOT NULL ENABLE,
"TX_LAST_NAME" VARCHAR2(30 BYTE) NOT NULL ENABLE,
[code]...
Here i'm loading data into these three tables through sql loader. Here is the control file
OPTIONS (SKIP=1,ROWS=5)
LOAD DATA
INFILE 'C:SQL LOADER DEMO estuser_data_lat.csv'
INTO TABLE TEST_USER
[code]...
Here are the two function which i'm calling from sql loader control file
CREATE OR REPLACE FUNCTION get_role_id(p_role_name VARCHAR2)
RETURN NUMBER IS
lv_role_id NUMBER;
BEGIN
[code]..
i'hv attached the testuser_data_lat.csv file, which is the data file.Command line
C:SQL LOADER DEMO>SQLLDR scott/sc CONTROL=rd_users_control.ctl
Now let me tell u what is happening Whem i'm running the above sqlldr, log is generating saying
Record 1: Rejected - Error on table TEST_ROLE, column ID_ROLE.
ORA-01400: cannot insert NULL into ("SCOTT"."TEST_ROLE"."ID_ROLE")
Record 2: Rejected - Error on table TEST_ROLE, column ID_ROLE.
ORA-01400: cannot insert NULL into ("SCOTT"."TEST_ROLE"."ID_ROLE")
[code]...
But when i remove
INTO TABLE TEST_ROLE(
TX_SID POSITION(1:3) CHAR,
ID_ROLE "get_role_id(:ROLE_NAME)" ,
TX_CREATED_BY CONSTANT "SYSTEM",
[code]...
from Control file, data is getting popupalated in TEST_USER and TEST_TITLE similarly if remove
INTO TABLE TEST_TITLE(
TX_SID POSITION(1:3) CHAR,
ID_TITLE "get_title_id(:TITLE_NAME)" ,
[code]...
from Control file, TEST_USER and TEST_ROLE is getting populated.
Here RD_ROLE_MASTER script
CREATE TABLE RD_ROLE_MASTER (
"ID_ROLE" NUMBER(38,0) NOT NULL ENABLE,
"TX_ROLE_NAME" VARCHAR2(20 BYTE) NOT NULL ENABLE
[code]...
Here is RD_TITLE_MASTER script
CREATE TABLE RD_TITLE_MASTER(
"ID_TITLE" NUMBER(38,0) NOT NULL ENABLE,
"TX_TITLE_NAME" VARCHAR2(25 BYTE) NOT NULL ENABLE);
Insert into RD_TITLE_MASTER (ID_TITLE,TX_TITLE_NAME) values (7,'RED_LOB_ESCALATION_L1'); what is the problem?
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Feb 12, 2013
i am trying to create Procedure which will create the partitions based on the other table date values one per each day.
CREATE OR REPLACE PROCEDURE PARTITION_TEST(PART_DATE_TABLE IN VARCHAR2, TABLE_NAME IN VARCHAR2,SCHEMA_NAME IN VARCHAR2)
AS
V_PART_NM VARCHAR2(20);
V_PART_CNT NUMBER;
V_DATE DATE;
V_SCHEMA_NAME VARCHAR(15);
[Code]..
It is not creating the partitions and even not giving any errors.
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Nov 7, 2013
I have a table which contains some data. But we are dropped and recreated the same table several times. Now I wanted to know that when this table created initially. How to findout the date of creation(very first time).
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Oct 18, 2012
i want to create a table to perform a task when i insert client account details in this table then check the account type is in(S,C,R) and balance should be also check when account type S then balance >=5000, account type C then balance >=10000 and account type R then balance >=5000 but when i run this query then facing error "ORA-02438: Column check constraint cannot reference other columns"
SQL> ed
Wrote file afiedt.buf
1 create table kcb_acc_tab
2 (
3 accno varchar2(20) constraint accno_pk primary key,
4 name varchar2(20) constraint name_nn not null
5 constraint name_chk check((substr(name,1,1) between 'A' and 'Z') and name=upper(name)),
[code]....
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Sep 20, 2012
i have 1 xcel sheet in formatted data i want to import data in oracle table .. how do i do dat??
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Mar 23, 2010
i'm new to oracle environment.how can i specify NONCLUSTERD INDEX on Primary cloumn during table creation.By default it will create clusterd index but i need non-clusterd index on it.
I'm using following stmt to create normal primary constarint during table creation,
CONSTRAINT PKFORM_PROPS PRIMARY KEY (FORM_PROPS_PK) USING INDEX TABLESPACE DB123_INDEX
how can i change the above query, so that it should create NONCLUSTERED INDEX on Primary key column.
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Feb 22, 2010
I have a stored proc SP_INSERT_TRAINEES.Here sTraineeNo is provided as input which has count of trainee needs to be inserted in table aaa_foc.user_profile. The sequence is used to generate ids as :
CREATE SEQUENCE AAA_FOC.TRAINEE_ID INCREMENT BY 1 MINVALUE 0 MAXVALUE 999 NOCACHE NOCYCLE NOORDER
I want the values for ids to be inserted as 001,002,003,.......010,011,................099,100,101,............999.So that the values in the table would be like TRAINEE001,002.......
I have tried to use LPAD to it but the values are getting insertes as TRAINEE1,2,3...........
The code is given below:
CREATE OR REPLACE PROCEDURE AAA_FOC9.SP_INSERT_TRAINEES
(sTraineeNo IN NUMBER,
nReturned_O OUT NUMBER)
IS
ln_insert_cnt PLS_INTEGER :=0;
nSequence NUMBER:=0;
[code]......
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Dec 11, 2012
Static Tables Creation In oracle & Diff Between Static table ,Dynamic table
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Oct 18, 2012
I want to know how many managers have employees under him?
I mean to say one manager may have multiple employees from employees table.
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Mar 7, 2013
I have one RDBMS concept question.if i have 2 tables with 0 to many realtionship. can i create referential integrity constraint between them?
In other words how can i tell whether the records in table A(child table) are not orphan records and have 0 to many relationship with table B(parent table) ? Right not there is no constraint defined on both tables.
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Apr 29, 2011
I've a table (RelationshipX) with two columns with following values. The table represents the relationships. When I run the following query, It will give me all the combination of relationships...however, I need to get 15 unique as defined below.
Col1Col2
1106011060
1106011640
1106011142
1106011095
1106013029
1106014058
I run the following query to get below of all the combinaiton (note, I am opting out those six rows which matches to each other) select a.Col2 as Col1, b.Col2 as Col2 from RelationshipX a, RelationshipX b
where a.Col1 = 11060
and a.Col1=b.Col1
and a.Col2 <> b.Col2
order by Col1, Col2
[code]....
HOW can I modify my SQl so I get only 15 unique relationship records. (For example two UNDERLINE rows are technically same, and there are total 15 of them)???.
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