Dynamic Pivot Table (Partition) Creation

Oct 31, 2010

I have 2 tables , which can be mapped with a common column and the second table's rest of the columns should become like columns(like pivot) and in the second table itself 1 more column called value , this sum of the value becomes a value to the pivot column value. For this I am using CASE structure and I am writing the individual case for each column , but I am sure after some extent case don't work at all and I would like to do it dynamically( when ever the new entry will come into the source table , my proc has to pick automatically the new value and put the new value as part of pivot structure) , so pls share your inputs and if possible provide some sample code.

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SQL & PL/SQL :: Dynamic Table Creation Using Timestamps?

Nov 28, 2010

I have a requirement to create the table monthly.The tablename will be the o/p of the following select query.

select 'TBR_AND_SECURITY_DEPOSIT'||TO_CHAR(sysdate, 'Monyy') from dual

I am trying to create the table for creating the backup of the existing table TBR_AND_SECURITY_DEPOSIT.

create table (select 'TBR_AND_SECURITY_DEPOSIT'||TO_CHAR(sysdate, 'Monyy') from dual) select * from TBR_AND_SECURITY_DEPOSIT

but it is throwing error as invalid table name.

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SQL & PL/SQL :: Partition Creation Based On Other Table Values

Feb 12, 2013

i am trying to create Procedure which will create the partitions based on the other table date values one per each day.

CREATE OR REPLACE PROCEDURE PARTITION_TEST(PART_DATE_TABLE IN VARCHAR2, TABLE_NAME IN VARCHAR2,SCHEMA_NAME IN VARCHAR2)
AS
V_PART_NM VARCHAR2(20);
V_PART_CNT NUMBER;
V_DATE DATE;
V_SCHEMA_NAME VARCHAR(15);

[Code]..

It is not creating the partitions and even not giving any errors.

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PL/SQL :: Static Table Creation In Oracle - Difference Between Static And Dynamic Table

Dec 11, 2012

Static Tables Creation In oracle & Diff Between Static table ,Dynamic table

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Application Express :: IR With Dynamic Pivot?

Oct 9, 2013

 We have been designing resource management system and want to provide flexible way to extend resource properties at runtime. So we are storing resource properties in a single table,

e.g. select * from _kvID K V---- ----- -----  1  name Bob  1  age  30  1  gender male  2  name Susan  2  status married convert to+-----+-------+--------+----------+| key | color | height | whatever |+-----+-------+--------+----------+| 1   | green | 15     | ---      || 2   | ---   | ---    | lol      |+-----+-------+--------+----------+example of dynamic pivot Dynamic SQL Pivoting &#8211; Stealing Anton&#8217;s Thunder</title> //<title>AMIS Technology Blog…

 Is it possible to create interactive report with dynamic columns updated when _kv will be changed?Is it possible to create add/edit dynamic form depends on key set if we add value type description? 

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Performance Tuning :: How To Assure Partition Table Is Better Than Non-partition Table

Mar 25, 2011

I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?

I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?

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Performance Tuning :: Select Partition Table With Non-partition Key Condition?

Jun 26, 2010

I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk

when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)

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SQL & PL/SQL :: Dynamic Column Creation / Create Column Based On Number Of Child In Hierarchy

Oct 15, 2013

I have one hirarchical query which return the parent to child hirarch level data. it has 11 level child data. i want to create column based on number of child in hirarchy. though i know it is 11 but it can change also.Is there any way i can create the column dynamically

ORG_UNITCOST_CENTERORG_UNIT_NAMEPARENT_ORG_UNITLLSYS_CONNECT_BY_PATH(ORG_UNIT,'/')

500171960000022000Managing Director - LUL500169965/00000001/50000001/50017588/50016996/50017196
500018370000021241FSO500171966/00000001/50000001/50017588/50016996/50017196/50001837
502894940000021241Knowledge Management500018377/00000001/50000001/50017588/50016996/50017196/50001837/50289494
508014980000021241Finance500018377/00000001/50000001/50017588/50016996/50017196/50001837/50801498

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SQL & PL/SQL :: Alter Table To Create Partition On Non-partition Table?

Jun 19, 2012

Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.

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SQL & PL/SQL :: Add Range Sub-Partition To Hash Partition Table

Jan 2, 2013

Can I add range sub partition to a hash partition table. Example like this.

CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);

When Tried, I am getting syntax error as invalid option.

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SQL & PL/SQL :: Adding A New Partition To Existing Partition Table

Jun 14, 2011

i want to create a new partition for version 2

existing table is as below

create table test
(
name varchar2(100),
version NUMBER(12)
)

[Code]....

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SQL & PL/SQL :: Partitioned Table - Inserted Partition Key Does Not Map To Any Partition

Jul 10, 2012

I have two tables in which one is partitioned table with the following details.

CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),

[code].....

When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error

SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition

AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.

ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198

[code].....

I also tried to upload the same data using sqlldr.

sqlldr log file contents is as follows:

Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37

[code].....

So some sqlldr bad file contents is as follows.

100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,

[code].....

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PL/SQL :: Pivot The Table

Sep 24, 2013

pivot the table. Table

dataNAMELINE_TYPE_REF_IDClassCreateShipmentServiceAdapterImplMethodgetContactsAndSitesForAccountUserskkondNode NamePB15CKYNum Contacts3ClassCreateShipmentServiceAdapterImplMethodgetContactsAndSitesForAccountUserdrcoulNode NameC4F6JJ1Num Contacts21ClassCreateShipmentServiceAdapterImplMethodgetContactsAndSitesForAccountUserdrcoulNode NameC4F6JJ1Num

[Code]....

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PL/SQL :: Pivot Table Sql

Apr 18, 2013

i have a table which looks like this

TRANS_ID TRANS_TYPE CONNECTION_DATE CLOSED_DATE
LK490 4 01-01-2009 01-01-2011
LK490 3 01-01-2010 01-01-2012

SELECT TRANS_ID, TRANS_TYPE, CONNECTION_DATE , CLOSED_DATE FROM TABLE_A

and want to pivot it like this

TRANS_ID 4_CONNECTION_DATE 4_ CLOSED_DATE 3_CONNECTION_DATE 3_ CLOSED_DATE
LK490 01-01-2009 01-01-2011 01-01-2010 01-01-2012

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SQL & PL/SQL :: Transpose (Not Pivot) A Table

Aug 18, 2010

I have a table in the following format:

CTitle1, CTitle2, CTitle3, CTitle 4, CTitle5
Row1Val1,Row1Val2,Row1Val3,Row1Val4,Row1Val5
Row2Val1,Row2Val2,Row2Val3,Row2Val4,Row2Val5
Row3Val1,Row3Val2,Row3Val3,Row3Val4,Row3Val5
Row4Val1,Row4Val2,Row4Val3,Row4Val4,Row4Val5
Row5Val1,Row5Val2,Row5Val3,Row5Val4,Row5Val5

I have an application that requires the data to be in the following format:

CTitle1, Row1Val1,Row2,Val1,Row3Val1,Row4Val1,Row5Val1
CTitle2, Row1Val2,Row2,Val2,Row3Val2,Row4Val2,Row5Val2
CTitle3, Row1Val3,Row2,Val3,Row3Val3,Row4Val3,Row5Val3
CTitle4, Row1Val4,Row2,Val4,Row3Val4,Row4Val4,Row5Val4
CTitle5, Row1Val5,Row2,Val5,Row3Val5,Row4Val5,Row5Val5

So I am truly trying to transpose the columns and rows and not doing a traditional pivot. How I can do this in Oracle 9i?

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SQL & PL/SQL :: Report Using Pivot Table

Jul 19, 2013

I have a table tab1 which contains columns Cust, ProdSeq, StartDat, EndDat, AttrId, AttrValue. I can have different attributes represented by attrId (say 1,2,3,4..etc.,) and its value by AttrValue respectively.

My question is for a given a customer, prodSeq and date range say 01-Jan-2013 to 31-Jan-2013, I want a report like below

Example input data
----------------------------------------------------------------
|CUST | PRODSEQ | STARTDAT | ENDDAT |ATTRID |ATTRVALUE |
----------------------------------------------------------------
|C1 | 1 | 1/1/2013 | 1/15/2013 | 1 | 1 |
|C1 | 1 | 1/1/2013 | 1/10/2013 | 2 | A |
|C1 | 1 | 1/1/2013 | | 3 | X |
|C1 | 1 | 1/1/2013 | | 4 | G |
|C1 | 1 | 1/11/2013 | 1/31/2013 | 2 | B |
|C1 | 1 | 1/16/2013 | 1/20/2013 | 1 | 2 |
|C1 | 1 | 1/21/2013 | 1/31/2013 | 1 | 3 |
----------------------------------------------------------------

Expected output
----------------------------------------------------------------------------------------
|CUST | PRODSEQ | STARTDAT | ENDDAT | ATTR1VAL | ATTR2VAL | ATTR3VAL | ATTR4VAL|
----------------------------------------------------------------------------------------
| 1 | 1 | 01-JAN-2013 | 10-01-2013 | 1 | A | X | G |
| 1 | 1 | 11-JAN-2013 | 15-01-2013 | 1 | B | X | G |
| 1 | 1 | 16-JAN-2013 | 20-01-2013 | 2 | B | X | G |
| 1 | 1 | 21-JAN-2013 | 31-01-2013 | 3 | B | X | G |
----------------------------------------------------------------------------------------

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SQL & PL/SQL :: Pivot Table Using UNIX Timestamp

Feb 23, 2010

I am trying to produce results in pivot format. I want to know how many entries per day per month. In other words how many entries on a Monday for each month, how many on a Tuesday for each month and so on.

The main problem I have is that the date column in the database uses UNIX time stamp. I have managed to get the results I want for a particular month. This code selects the entries for last month.

select
max(decode(pdayno, 1, cnt, null)) Sunday,
max(decode(pdayno, 2, cnt, null)) Monday,
max(decode(pdayno, 3, cnt, null)) Tuesday,
max(decode(pdayno, 4, cnt, null)) Wednesday,
[code].......

This code produces the result:

What I need is for another column at the start of the results to give the month so I end up with 12 rows, 1 for each month.

I did try to group by PENTERED(which is the unix time stamp column)
select pentered,
max(decode(pdayno, 1, cnt, null)) Sunday,
max(decode(pdayno, 2, cnt, null)) Monday,
max(decode(pdayno, 3, cnt, null)) Tuesday,
max(decode(pdayno, 4, cnt, null)) Wednesday,
[code]......

This gave me thousands of rows as each UNIX time stamp is unique. Is there a way of grouping on UNIX time stamp.

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SQL & PL/SQL :: Pivot Table Comparison Between Months

Jun 28, 2010

SQL> select * from query;

CUSTO SWITCH DATE_X METRIC COUNT_X SEQUENCE_NO FILE
------- ------- --------- ------- ---------- ----------- ----
JCI S1 28-JUN-10 PORT1 10 4 TNB
JCI S1 28-JUN-10 PORT2 4 4 TNB
JCI S1 28-JUN-10 PORT3 8 4 TNB
JCI S2 28-JUN-10 PORT1 1 2 TNB
JCI S2 28-JUN-10 PORT2 5 2 TNB
JCI S3 28-JUN-10 PORT1 6 8 TNB
JCI S5 28-JUN-10 PORT2 2 4 TNB

------->s5 only in the current month-it was not in the previous month data collection
-----------------------------------------------------------------------------
JCI S1 28-MAY-10 PORT1 10 3 TNB
JCI S1 28-MAY-10 PORT3 5 3 TNB
JCI S2 28-MAY-10 PORT1 4 1 TNB
JCI S2 28-MAY-10 PORT2 2 1 TNB
JCI S2 28-MAY-10 PORT3 8 1 TNB
JCI S3 28-MAY-10 PORT2 7 7 TNB
JCI S3 28-MAY-10 PORT3 5 7 TNB
JCI S4 28-MAY-10 PORT1 2 10 TNB
------->s4 in the previous month data

15 rows selected.

1 SELECT A.CUSTO,A.SWITCH,
2 A.PORT1-B.PORT1,
3 A.PORT2-B.PORT2,
4 A.PORT3-B.PORT3
5 FROM (SELECT
6 A.CUSTO

[Code] ......

CUSTO SWITCH A.PORT1-B.PORT1 A.PORT2-B.PORT2 A.PORT3-B.PORT3
------- ------- --------------- --------------- ---------------
JCI S1 0 4 3
JCI S2 -3 3 -8
JCI S3 6 -7 -5

How to include the Switch S4 and S5 in the output. how implemented FULL OUTER JOIN

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PL/SQL :: Pivot Table With Variables Columns

Aug 27, 2013

I need a helo to pivot table with variable columns, I have a pivot table :

 SELECT a.*FROM (SELECT codigo_aluno,nome_aluno , id_curso,dia FROM c_frequencia where dia like '201308%') PIVOT (sum(null)   FOR dia IN ('20130805' ,'20130812','20130819','20130826'))

a but I need to run the select with values for dia , getting from a other table : 

SELECT a.*FROM (SELECT codigo_aluno,nome_aluno , id_curso,dia FROM c_frequencia where dia like '201308%') PIVOT (sum(null)   FOR dia IN (select dia from v_dia_mes ))

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Partition Size In A Partition Table

Jun 8, 2011

How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')

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PIVOT XML Results To HTML Table In SQLPlus?

Jul 27, 2012

I have a PIVOT XML query that returns results that I want to display as an HTML report from SQLPlus. Is there a way that this can be done readily? I have searched the net an found references to XML Publisher but in my current situation we do not have the product available.

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SQL & PL/SQL :: How To Pivot Table So That Rows Become Column Names

May 9, 2012

Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bit
PL/SQL Release 10.2.0.5.0 - Production
"CORE10.2.0.5.0Production"
TNS for Linux: Version 10.2.0.5.0 - Production
NLSRTL Version 10.2.0.5.0 - Production

See attachment for table creation and table data.

The table tbl_completed has two columns, id and completed. I have created a query that does provide me with the result set that I need, but I need to pivot the rows into columns. So instead of a result set to look like this:

select completed, count(completed) as theCount from tbl_completed group by completed;

COMPLETED THECOUNT
Y 772
N 720

I need a result set to look like this:

COMPLETED,Y,N
THECOUNT,772,720

The best solution that I have discovered is this, but I figuring their might be a better way.

select
(select 'THECOUNT' from dual) as COMPLETED,
(select count(completed) from tbl_completed where completed = 'Y') as Y,
(select count(completed) from tbl_completed where completed = 'N') as N
from dual;

COMPLETED,Y,N
THECOUNT,772,720

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Forms :: Pivot Table Inside Group

Mar 21, 2011

I want to use the pivot table inside the group.

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SQL & PL/SQL :: Show Result Of Query Just Like Pivot Table?

Jul 20, 2011

me in building a query. I want to show the result of the query just like pivot table.
Test case
CREATE TABLE CPF_YEAR_PAYCODE
(
CPF_NO NUMBER(5),
INC_DATE DATE,
PAYCODE_TYPE CHAR(1 BYTE),

[code]...

I want that my query should look like the format as attached in the xls sheet.

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Application Express :: Pivot Table Layout?

Nov 5, 2012

in my application i have a requirement as follows

1) column 1 indicator
2) column 2 important.

and the other columns are target actual and current year, previous year and next year.the layout should be in pivot table lay out as follows here the three columns will be saved dynamically as 2012,2011,2013 and the respecitive percentage in target and actual column

current_year previous_year next_year
target 10% 12% 5%
actual 5% 8% 5%

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How To Assure Partition Table Is Better Than Non-partition Table

Mar 25, 2011

I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?

I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?

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ASM Disk Groups Creation After ASM Instance Creation

Jul 9, 2012

During ASM Disk Groups creation after the ASM instance creation, receive the following error: Disk Group ORAASMGROUP2 already exists. Cannot be created again

The Grid infrastructure was deinstall one time and still the same issue.

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SQL & PL/SQL :: New Table Creation From Different Databases?

Apr 9, 2013

I have two tables having same name in two different databases.i have to create a new table with these two tables in a new database.

But if one table have 2 columns and another table having three columns I have to create a new table with three columns..

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SQL & PL/SQL :: External Table Creation

May 23, 2011

i had small query on external tables. i had (.csv) file outside the database. In this file, one column will be added monthly. i need to create the external table dynamically by adding the column for every month.

How the procedure can be created for this requirement.

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SQL & PL/SQL :: Add Partition To Table Without Partition?

May 5, 2011

I am trying to add partition to table without partition

with following code

ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))

it will raise error ora-14020

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