SQL & PL/SQL :: How To Pivot Table So That Rows Become Column Names
May 9, 2012
Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bit
PL/SQL Release 10.2.0.5.0 - Production
"CORE10.2.0.5.0Production"
TNS for Linux: Version 10.2.0.5.0 - Production
NLSRTL Version 10.2.0.5.0 - Production
See attachment for table creation and table data.
The table tbl_completed has two columns, id and completed. I have created a query that does provide me with the result set that I need, but I need to pivot the rows into columns. So instead of a result set to look like this:
select completed, count(completed) as theCount from tbl_completed group by completed;
COMPLETED THECOUNT
Y 772
N 720
I need a result set to look like this:
COMPLETED,Y,N
THECOUNT,772,720
The best solution that I have discovered is this, but I figuring their might be a better way.
select
(select 'THECOUNT' from dual) as COMPLETED,
(select count(completed) from tbl_completed where completed = 'Y') as Y,
(select count(completed) from tbl_completed where completed = 'N') as N
from dual;
I am a junior DBA. I want to check how many columns are under PRIMARY KEY constraint.
I used dba_constraints view. Please find below details.
SQL> select OWNER,CONSTRAINT_NAME,CONSTRAINT_TYPE,TABLE_NAME from dba_constraints 2 where TABLE_NAME='DSET_PRODUCT_S'; OWNER CONSTRAINT_NAME C TABLE_NAME ------------------------------ ------------------------------ - ---------------------------------------- SCOTT SYS_C10202456 C EMPLOYEE SCOTT SYS_C234576 C DEPT
I am trying to join column names from a table with data from a different table. I think i should be able to pass the parameter to a 'select list' in a query. Look at my sample data below. And the data in sales table can grow till 15 rows and similarly corresponding columns in saleshist.
I have a requirement that i should list out all the table names which are all using timestamp datatype in a specified schema. Is there any way to find those table names by using any system tables.
I have 20 tables. In all 20 tables, some of column names are same and some are different. I need to find all column names in all 20 tables that have same names.
What I am trying to do is print out page that displays all of the column titles and the data under them for a query given by the user. It is then going to be put into an excel spreadsheet.
I've done this before with Java, simply by using the getMetaData function, but I can't seem to find an alternative for PL/SQL. It seems at the very least I need to know the number of columns in a query, but that would defeat the purpose of this.
Is what I am trying to do even possible or is knowing the column names an absolute necessity when printing table data?
I'm trying to do a pivot query in oracle to get the years from a column and make a separate column for each. I found an example of the code to use on the internet and i changed it for my own tables but i'm getting errors. Namely a "FROM keyword not where expected" error at the beginning of the 'avg(...' statements.
I have copied the code used in
select stud_id, 2006, 2007, 2008, 2009 from ( select stud_id, avg(case when year=2006 then ((present/poss)*100) else null end) 2006, avg(case when year=2007 then ((present/poss)*100) else null end) 2007, avg(case when year=2008 then ((present/poss)*100) else null end) 2008, avg(case when year=2009 then ((present/poss)*100) else null end) 2009 from attendance.vw_all_attendance_perc group by stud_id );
I've tried for pivot query feature of Oracle 11g, but I'm trying for pivot result on multiple column.
Herewith I'm displaying my try on single column pivot query.
SQL> select * from 2 (select deptno,job,sal 3 --,comm 4 from emp) 5 pivot (sum(sal) as payment for job in('CLERK','SALESMAN','MANAGER')) 6 order by 1;
[code]....
I've tried this one also, but it didn't seems to be working.
SQL> select * from 2 (select deptno,job,sal,comm 3 from emp) 4 pivot (sum(sal) as payment_sal,sum(comm) as payment_comm for job in('CLERK','SALESMAN','MANAGER')) 5 order by 1;
I want my query to return the rows of the table where a column contains a specific values first in a certain order, and then return the rest of the rows alphabetized.
For Example:
Country ALBANIA ARGENTINA AUSTRALIA .... CANADA .... USA ....
Now i want USA and CANADA on top in that order and then other in alphabetized order.
I need encrypt column in the table (TDE) with 160 rows (PK) i'd like know what impact if i rn in time production this procedure. And as will be behavior the oracle database if this column is FK.
trying to update a column in a table which has 3 columns of 16million rows from column in another table which has 1million rows, there is no relationship between the 2 tables.
Table A has 3 columns of 16million rows, the first two columns have 16million ID numbers, the 3rd colunm is currently NULL.
Table B has 1million Numbers, i need to somehow update column 3 in table A using the numbers in table B, it doesnt how many times each of the 1 million numbers are used but i dont want it to just update every row to the same value.
I have a tmp table with 6 cols, and data to be inserted is from two other tables. My problem is there the cols of the table are
sid varchar2(10), cob_dt varchar2(10), deal_id varchar2(10), new_val varchar2(10), old_val varchar2(30), amend_col v archar2(50), i have return a proc create or replace
Name Null? Type ----------------------------------------------------- -------- ------------------------------------ C1 NOT NULL VARCHAR2(15) C2 VARCHAR2(254) C3 NOT NULL NUMBER(15) C4 VARCHAR2(254) C5 NOT NULL VARCHAR2(254) C6 NOT NULL NUMBER(15) C7 NOT NULL NUMBER(15) C8 NOT NULL VARCHAR2(254)
[Code]...
But, till yday it was showing the orignal column name..
I am trying to build an array that contains known column names, 63 columns in all.The idea is to search backwards from 63 down to say 10 to find the first non-blank column.
Then using a loop with the known number of lines print from 1 to last non-blank column.The problem is that it only shows the column names and not the values of the columns.So I am getting 63 lines every time, instead of 20, 30, 40 or however how many fields actually have something.
Here is my declare to_num number; field_name varchar2(15); [code]....
I wonder if there is any way to return the columns of an select with its letters lowercase?
I have a piece of code that creates an script wich returns an SQL result to be confronted with some templates. My template have the column names in lowercase and because It is case sensitive the Uppercase returned by Oracle,
i have list item populated with many table names from a schema. i have grid in oracle forms 10g and i want to fill the grid with at least four/more columns.I want to fire the list change trigger when each time any one table name is selected.
how can i find the columns names dynamically for filling the grid.
I'm writing a procedure that takes a table name as a parameter and I would like to print out the column name with the supporting row entry for each row. I know the logic I'd like to use, but how do you query the metadata to return the column names and store them.
CREATE OR REPLACE PROCEDURE COMP_RECORDS IS l_query VARCHAR2 (10000) := '';
CURSOR TBL1 IS SELECT TABLE_NAME, COLUMN_NAME FROM COLS_TO_COMP WHERE TABLE_NAME='ACE_HIST'; TBL1_REC APP.COLS_TO_COMP%rowtype;
[Code]..
However I am getting an ORA-00923 exception with message as "FROM keyword not found where expected". know if I can/cannot use a cursor to fetch column names for a table?
I have limited permissions and am unable to create temp tables.So I would like to use a cursor to "create" a table of sorts then access/query it. But this "table"/cursor would have no column names so how do I refer to the columns? Is there a way to refer to a column by column number rather than column name in a query:
select column1 from tablename where column2 = 'abc'?
Is there a way in a query/update/insert to refer to a column by column number rather than column name?
declare cursor c1 is select 'abc', '8-Apr-2013', pk_id from EMPLOYEE where pk_id = '153' UNION select '1xyz', '4-10-2013', pk_id from EMPLOYEE where pk_id = '154' c1_val number;
I need to rename only two names in column report_headings1. But in order for me to see all other names I need to use all of them in decode function. Is there an easier way to write this Select Statement.
select days_start, days_to, decode(report_heading1,'31 Or More days', 'Future', '00 Dispute/Pend', 'Dispute or Pend', '1 to 30 Days', '1 to 30 Days', '31 to 60 Days', '31 to 60 Days','61 to 90 Days', '61 to 90 Days', '91 Or More Days', '91 Or More Days' ) report_heading1, report_heading2, type from ar_aging_bucket_lines lines, ar_aging_buckets buckets where lines.aging_bucket_id = buckets.aging_bucket_id;
I have written an SQL which will dynamically generate the Select statement with from and where clause in it. But that select statement when executed will get me hundreds of rows and i want to insert each row separately into one more table.
For that i have used a ref cursor to open and insert the table.
In the select list the column names will also be as follows: COLUMN1, COLUMN2, COLUMN3,....COLUMNn
find below the sample
TYPE ref_csr IS REF CURSOR; insert_csr ref_csr; v_select VARCHAR2 (4000) := NULL;
