during application migration, i got one table from MS Access, and have situation where two events are splited into 4 columns (start: date1 time1 and stop: dat2 and time2). How to properly calculate duration between these two events, and show it in format: hh:mi ?
CREATE TABLE ACCBTP_DCZASTOJ
(ID NUMBER(11,0),
NASTANAK_KVARA DATE,
VRIJ_NASTKVARA DATE,
VRIJEME_OPRAVKE DATE,
DATUM_OPRAVKE DATE);
[Code]....
I want to calculate time difference b/w two time clocks, just like we calculate the date difference and answer is in days, In the same way i like to have answer in hrs,min and ss.
View 4 Replies View RelatedI have two different date in my payroll software,
1-Shift_date shift date *used to contain shift timings
2-Attendace_datedate *used to contain employee IN timings
As you all know that shift is a setup form, where user input data once in the starting of software so the shift_date can be "01/jan/2011 16:00 pm" but attendance loads daily and attendance field data can be in this form "24/mar/2011 16:15 pm"..Now I want to calculate difference time between these two fields therefore I used this statement
SQL> Select to_char(attendance_date,'HH24:MI') to_char(shift_date,'HH24:MI') from dual;
but it is showing error: ORA-01722: invalid number...I used hours/minutes format mask in my query because you can see there is a difference of dates between these fields and it will be increase in the coming future and I need late hours and minutes.
how to calculate the difference between multiple dates at the same time..
Select to_date('10/10/2011','mm/dd/yyyy')
- to_date('09/10/2011','mm/dd/yyyy')
- to_date('08/10/2011','mm/dd/yyyy') from dual;
Giving me an error...
ORA 00932 : inconsisten data types:expected DATE Julkian got DATE..
Detail table will look like below:
Product_id issue_date action_date Force_date
1 10/10/2012 10/10/2012 10/10/2012
2 10/10/2012 10/10/2012 10/10/2012
3 10/10/2012 13/10/2012 15/10/2012
[code]....
Need the data like
Issue_date count_action_date count_Force_date (diff(action_date,force_date) 1 2 3 4 5 6(days since over)
10/10/2012 3 4 1 4 2 1 0 0
How to get the data like this? automatically how to get 123.... and how to calculate the difference by which day the count of difference is going?
I need to subtract multiple numbers to get the difference between each numbers, the amount of numbers to subtract between each others can vary between 2 and 10.
create table table_1 (
col1 varchar2(5),
col2 number(6,0),
col3 number(12,0)
)
insert into table_1 values ('AAA', 34379, 11111);
insert into table_1 values ('AAA', 39032, 11111);
insert into table_1 values ('AAA', 54337, 11111);
insert into table_1 values ('AAA', 78005, 11111);
insert into table_1 values ('AAA', 66793, 22222);
insert into table_1 values ('AAA', 74323, 22222);
insert into table_1 values ('AAA', 81426, 22222);
Expected Output:
col1 col2 col3
AAA -4653 11111
AAA -15305 11111
AAA -23668 11111
AAA -7530 22222
AAA -7103 22222
setting up the query/correcting the syntax below so that it calculates the 'number of days difference' between whatever the 'Biggest Date' field value is and whatever the 'current date' is using the 'sysdate'. So far, I've only managed to get the query to calculate the number of days difference (days past due) between the 'need date' and 'estimated delivery date'.
CODESELECT
To_Date(need_date, 'YYYYMMDD') Need_Dt,
To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Biggest_Date,
To_Date(need_date, 'YYYYMMDD') - To_Date(Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END, 'YYYYMMDD') Date_Diff
FROM tableT
WHERE
need_date <= (Case when estimated_delivery > ' ' THEN estimated_delivery ELSE need_date END)
ORDER BY Date_Diff ASC
I need the query to calculate minutes from difference of to number fields. Test case is as below.
DROP TABLE tmp;
CREATE TABLE tmp
(
code NUMBER(4),
stime NUMBER(4,2),
otime NUMBER(4,2)
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
NOMONITORING;
[code]......
CODE STIME OTIME
---------- ---------- ----------
1065 20 19.49
1082 20 18.57
1279 19.3 18.59
2075 19.3 15.32
Required output is
CODE STIME OTIME HR_MIN MINUTES
---------- ---------- ---------- ------------- --------
1065 20 19.49 00 HR 21 MIN 21
1082 20 18.57 01 HR 03 MIN 63
1279 19.3 18.59 00 HR 31 MIN 31
2075 19.3 15.32 03 HR 58 MIN 238
create or replace function getDate(p_joing_date Date,p_sysdate)
Return Date;
IS
v_compltd_mnths;
BEGIN
SELECT into v_compltd_mnths MONTHS_BETWEEN(TO_DATE('sysdate','MM-DD-YYYY'), TO_DATE('joing_date','MM-DD-YYYY') ) "Months"FROM DUAL;
return v_compltd_mnths;
END;
that i have worte..
We have a table which contains the outage data as below,
TAG CI_NAME OUTAGE_START OUTAGE_END
IM10366 FD0004 06-jul-2010 10:00:00 10-jul-2010 10:00:00
so from the above record, the outage is from 6th - 10th July. So for the given TAG & CI_NAME, we have to calculate the outage for day. So the above record should be split as below
TAG CI_NAME O_START O_END TA_PERIOD OUT_HRS
IM10366 FD0004 06-jul-2010 10-jul-2010 06-jul-2010 14HRS
IM10366 FD0004 06-jul-2010 10-jul-2010 07-jul-2010 24HRS
IM10366 FD0004 06-jul-2010 10-jul-2010 08-jul-2010 24HRS
IM10366 FD0004 06-jul-2010 10-jul-2010 09-jul-2010 24HRS
IM10366 FD0004 06-jul-2010 10-jul-2010 10-jul-2010 10HRS
Oracle Version = 8.1.7.4
How to change the SQL below to include a calculated datetime diff between two consecutive dates?
I believe I should be using what SQL gurus will call hierarchichal/analytical queries? Any good website/link to learn hierarchical/analytical queries.
select last_analyzed, monitoring
from dba_tables where owner = 'TEST'
LAST_ANALYZED MON
-------------------- ---
24-MAY-2011 18:25:05 YES
24-MAY-2011 19:15:34 YES
24-MAY-2011 22:21:33 YES
24-MAY-2011 23:10:42 YES
24-MAY-2011 23:51:10 YES
25-MAY-2011 01:43:56 YES
25-MAY-2011 02:39:11 YES
25-MAY-2011 03:10:26 YES
25-MAY-2011 04:15:15 YES
25-MAY-2011 04:23:26 YES
28-MAY-2011 03:58:02 YES
28-MAY-2011 03:58:11 YES
28-MAY-2011 03:58:11 YES
28-MAY-2011 03:58:12 YES
28-MAY-2011 03:58:13 YES
28-MAY-2011 04:00:16 YES
28-MAY-2011 04:04:24 YES
28-MAY-2011 04:04:27 YES
28-MAY-2011 04:04:33 YES
28-MAY-2011 04:04:36 YES
i want to find out the last refresh elasped time for materialized view. i do not see last refresh elapsed time in data dictionary. i see only last refresh date in data dictionary.
how to find the last refresh elapsed time for materialized view.
Following is the scenario:
CREATE TABLE EMP_VACATION(
EMP_NO NUMBER(3),
VAC_TYPE NUMBER(1),
START_DATE DATE,
END_DATE DATE,
START_PERIOD_DATE DATE,
END_PERIOD_DATE DATE,
PRIMARY KEY (EMP_NO,VAC_TYPE,START_DATE))
[code]....
--How to calculate START_PERIOD_DATE and END_PERIOD_DATE for every time insert reocrd, like for 4 cases?
--I need to check start_date with last period date for same employee.
And based upon calculate START_PERIOD_DATE and END_PERIOD_DATE,,,,,
select to_date('28-FEB-2013') - TO_DATE('01-FEB-2013') FROM DUAL
gives me 27 days, what should I do to get 28 ? meaning include both the start and end dates in the range ?
I have a table with a date time column which actually stores the data as and when it is inserted. I need to calculate the time the machine has worked hourly wise. For example the table contains records from 13:00 to 13:15 and 13:45 to 14:00 i should get 30 mins as working time..
View 2 Replies View RelatedI need a pl/sql function to calculate the financial month from an date... For eg. If i enter input date as '21-sep-2012' the function should return me the output value in months as 6. so it should calculate from april to september of that year...
View 13 Replies View Related I've got the following table:
ID.................Date...........................number...period.....termination
434473......2012-04-18 00:00:00.000...............6.......month(s)...end of month
443080......2012-02-26 00:00:00.000...............36......month(s).....end of quarter
Now it's getting complicated. Date is the start date of a contract.
I need to calculate a date when the contract can be terminated and must compare it with the current date. Lets take the first row. In column "termination" is the termination date. A contract can be terminated at "end of month" (I need to check the last day of a month. In order to get the real termination date we need to subtract the column "number".
example 30.01.2012 - 7 month = 30.06. 2011
The thing I can do it, but my logic works only if the date is in the same year. I've been thinking a lot...sql is not important first....Have you got a theoretical solution?
Find the sample data and table.
CREATE TABLE table_x
( arrival_time VARCHAR2 (8),
post_arrival_time VARCHAR2 (8),
arrival_date date
);
INSERT INTO table_x VALUES ('3:50 PM', '3:50 AM',trunc(sysdate)); -- Post arrival date = trunc(sysdate) - 1
INSERT INTO table_x VALUES ('3:50 AM', '1:00 AM',trunc(sysdate)); -- Post arrival date = trunc(sysdate)
INSERT INTO table_x VALUES ('11:59 AM','11:59 PM',trunc(sysdate)); -- Post arrival date = trunc(sysdate) - 1
Need to calculate Post arrival date .. which will be always < = Arrival date
I need to calcuate balance for last two cooprative years on input date.
example
if input date is-->"01-AUG-2012" if (month >=7) -->then i need to calculate from 01-july-2010 to 30-june-2011 and 01-july-2011 to 30-june-2012 and 01-july-2012 to input date.
if input date is-->"01-june-2012" if (month<7) -->then i need to calculate from 01-july-2009 to 30-june-2010 and 01-july-2010 to 30-june-2011 and 01-july-2011 to input date.
how to achieve this logic
When I try to extract the date tag value from XML data, the time stored in 20120602153021 format i.e., YYYYMMDD24HHMISS format. The following statement extracts only date as 02-JUN-12 however do not extract the time part.
If I try the same in SQLplus with to_date it works however fails in PL/SQL.
XML data:
<?xml version="1.0"?>
<RECORD>
<REGTIMESTAMP>20120601130010</REGTIMESTAMP>
</RECORD>
PL/SQL Extract:
CURSOR c_xml_record
IS
SELECT extract(value(d), '//ACTIVATIONTS/text()').getStringVal() AS REGTIMESTAMP,
FROM t_xml_data x,
[code].......
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)
I want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
i am using this query to get the time difference between two dates.
select to_timestamp('2012-10-03 12:00:00','YYYY-MM-DD HH:mi:ss') - to_timestamp('2012-10-03 11:00:00','YYYY-MM-DD HH:mi:ss') as diff from dual;
but not getting the correct result.
I need to convert the type of GMT to Local time, during data entry. I have a source table and a target table.
To make the insert get the most value, I have no problems:
insert into destination (SELECT * FROM WHERE source pointnumber = (SELECT MAX (pointnumber) FROM source));
But since times are different between the tables, I want to convert the data obtained to GMT -4:30 Time (Caracas - Venezuela), before inserting it.
I can use a function?
I am having problems with the XMLTable function. I cant get it to see the entire date/time value in a date field. This wont work
select x1.* from XMLTABLE('/DOCUMENT' passing xmltype('<DOCUMENT><STR>abc def ghi</STR><NUM>1234</NUM><DT>2013-02-17T04:24:02</DT></DOCUMENT>') columns STR varchar2(25), NUM number, DT date) x1;
However if I change the DT tag to just the date only "2013-02-17" it works. Why wont Oracle see the entire date/time format even if its ISO 8601 compliant?
Oracle DB: 11.2.0.3.0
I need to query a table to get the time difference based on different dates.
SAMPLE DATA:
JOB ID start_time end_time
1 201008190056 19/08/2010 01:23:12
2 201008190123 19/08/2010 01:50:12
2 201008200045 19/08/2010 01:50:12
3 201008070345 7/08/2010 04:50:12
3 201008070345 7/08/2010 04:50:12
1 201008070003 7/08/2010 00:30:12
in the above, for job 1 ,on 19/08/2010 the time difference should be calculated as
01:23:12-00:56:00 and the difference should be in minutes.
for end_time. i can't take the substring as the length of the date varies for 19 and 7. In case of start date, the time has to be in format, hh:mm:ss, to calculate the difference.
How one can get date difference in days between two dates in Oracle reports ?
View 2 Replies View RelatedIn my application I show the Date in Hijri using the NLS setting. but the issue that "i face a deference between the real hijri date with oracle hijri date"
Assume that the real hijri date on 18-SEP-2012 was 02/11/1433 in hijri but in oracle was 03/11/1433
when I execute the following query it shows me "1433/11/03", but the actual Hijri date is "1433/11/02"
select to_char(to_date('20120918','YYYYMMDD'),'YYYY/MM/DD', 'NLS_calendar='''||'ARABIC hijrah') FROM DUAL;
How to get Time Difference between two DateTime Columns in Oracle 10g ?
View 10 Replies View RelatedI'm having trouble comparing and subtract two date type fields, can not get a significant result.
e.g.
select id, date.started, date.closed, datediff (day, date.started, date.closed) differences diference from Table1 order by desc;