How To Get Date Difference
Jul 20, 2007How one can get date difference in days between two dates in Oracle reports ?
View 2 RepliesHow one can get date difference in days between two dates in Oracle reports ?
View 2 Repliesselect to_date('28-FEB-2013') - TO_DATE('01-FEB-2013') FROM DUAL
gives me 27 days, what should I do to get 28 ? meaning include both the start and end dates in the range ?
In my application I show the Date in Hijri using the NLS setting. but the issue that "i face a deference between the real hijri date with oracle hijri date"
Assume that the real hijri date on 18-SEP-2012 was 02/11/1433 in hijri but in oracle was 03/11/1433
when I execute the following query it shows me "1433/11/03", but the actual Hijri date is "1433/11/02"
select to_char(to_date('20120918','YYYYMMDD'),'YYYY/MM/DD', 'NLS_calendar='''||'ARABIC hijrah') FROM DUAL;
I'm having trouble comparing and subtract two date type fields, can not get a significant result.
e.g.
select id, date.started, date.closed, datediff (day, date.started, date.closed) differences diference from Table1 order by desc;
Tables
--------
ROWID START_DATEEND_DATE
101/26/2012 00:00:0001/31/2012 00:00:00
201/26/2012 00:00:0002/02/2012 00:00:00
302/03/2012 00:00:0003/31/2012 00:00:00
How to find out the days difference in sql query, start date of next records and end date of previous records as highlighted on blue color
query out put should give as below
start_date + next record ,end_date - Previous records should give the difference of
6
1
during application migration, i got one table from MS Access, and have situation where two events are splited into 4 columns (start: date1 time1 and stop: dat2 and time2). How to properly calculate duration between these two events, and show it in format: hh:mi ?
CREATE TABLE ACCBTP_DCZASTOJ
(ID NUMBER(11,0),
NASTANAK_KVARA DATE,
VRIJ_NASTKVARA DATE,
VRIJEME_OPRAVKE DATE,
DATUM_OPRAVKE DATE);
[Code]....
I just want to calculate difference between two dates in YY MM DD HH:MI:SS format through a SQL Query (not function).
Sample data is as follows-
to_timestamp('11-Feb-2008 12:23:00','DD-MON-YYYY HH24:MI:SS')
to_timestamp('2-Dec-2010 04:23:22','DD-MON-YYYY HH24:MI:SS')
or
how to calculate age in YY MM Day HH:MI:SS format. Suppose my DOB is '2-Feb-1988 11:10:15 AM'
In my server , already 10g r2 is installated , now am installaling 11r2, during this, at final stage while running root.sh , it will propmt to override 3 files, oraenv,dbhome .. etc under /usr/local/bin in solaris sys, as these files are already owned by 10g owner ,what i have to select (y or n)?
what if i select y? it will override three files
what if i select n? default option
i want to find out difference between two dates in day-month-year. How can i do it?
For example how many days,months are years are between '01-jul-1979' and '08-jul-2010'
I have an attribute in my DB called start_date of type date.I want a query that return the difference between the start_date and the current date.for example if start_date = 2/14/2013 *2*:35:00 PM and the current date = 2/14/2013 *1*:35:00 PM the query returns 1.
I want the result in hours.
Find the date difference. I need to find that how many days the task is pending, if ACT_NAME field switching from 'SET PENDING%' to 'RESUME PENDING%' by using ACTIONTAKENDATETEXT field in the History table.
Example as needed:
NoPendingDays = 23 (8+15)
I have attached Create table and Insert table values sample as SQL file.
What is the difference between the following . In my schema all are giving the same results with some different format
SQL> SELECT sysdate , current_date , current_timestamp , localtimestamp from dual;
SYSDATE CURRENT_DATE CURRENT_TIMESTAMP LOCALTIMESTAMP
----------- ------------ ------------------------------------------------- -------------------------------------------------
5/30/2012 8 5/30/2012 8: 30-MAY-12 08.27.22.037703 AM -04:00 30-MAY-12 08.27.22.037703 AM
Detail table will look like below:
Product_id issue_date action_date Force_date
1 10/10/2012 10/10/2012 10/10/2012
2 10/10/2012 10/10/2012 10/10/2012
3 10/10/2012 13/10/2012 15/10/2012
[code]....
Need the data like
Issue_date count_action_date count_Force_date (diff(action_date,force_date) 1 2 3 4 5 6(days since over)
10/10/2012 3 4 1 4 2 1 0 0
How to get the data like this? automatically how to get 123.... and how to calculate the difference by which day the count of difference is going?
I'm trying to work out how to take a table like this:
IDDate
12502-Feb-07
12516-Mar-07
12523-May-07
12524-May-07
12525-May-07
33302-Jan-09
33303-Jan-09
33304-Jan-09
33317-Mar-09
And display the data like this:
IDPeriodPeriod StartPeriod End
125102-Feb-0702-Feb-07
125216-Mar-0716-Mar-07
125323-May-0725-May-07
333102-Jan-0904-Jan-09
333217-Mar-0917-Mar-09
As you can see, it's split the entries into date ranges. If there is a 'lone' date, the 'period start' and the 'period end' are the same date.
I have a two date fields in my form; valid from date and expiry date.
Currently my valid from date has an inital value property of $$date$$ which automaitcally brings up todays date.
I need my expiry date to automatically show a date 15 years after this date?
Version : 4.1.1, I have a tabular form on a DB table. One of the columns is a date field. When the user hits the "add Row" button on the tabular form, I want the Date field to be defaulted to sysdate. Here is what I have tried so far,
1. Created a "hidden" item P1_SYSDATE and populated the default value with sysdate. After this, under the DB tabular report date field, I used default type - Item/application on this page and entered P1_sYSDATE
2. Instead of populating the default value of the P1_SYSDATE hidden item, I created a before regions process and added
:P1_SYSDATE := sysdate
and added P1_SYSDATE to default type of the tabular date field with default type as "ITem/application on this page.
I get the error
ORA-01790: expression must have same datatype as corresponding expression
I tried to_Char(sysdate,'dd-mon-yyyy') and then converting it back to to_date. still no luck.
When I run a query form the the Query Window in Visuial Studios 2012 all the date fields truncated to 'mm/dd/yyyy', but i need the full date returned. I am able to get full date from TO_char(MyDateField, 'yyyy-mm-dd hh24:mi:ss'), but if I do TO_DATE(MyDateField, 'yyyy-mm-dd hh24:mi:ss') it only returns 'mm/dd/yyyy'. I'm sure this is a simple setting in Visual studios but I cant find it to save my life. Is there there a way to have the full date returned by default?
View 0 Replies View RelatedI am a novice in oracle
I have 2 columns in my table
->Col1 with experience in years entered as an integer
->Col2 with current date
I need to add another column as a date value adn for that i need to subtract Currentdate-Col1 when i tried currentdate-Col1 it just subtracted the days i need the formula to subtract years and give a date
I have worked in DB2 and all u need to do there was add the keyword years at the end but in oracle the same does not work
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)
I would like to inquire how do I code my select statement if my user enter a search date range(search startDt: 01/08/2012 and search endDt :30/09/2012) and I will like to retrieve only the 7records out from my table as shown below ?
STARTDT_ ENDDT_
01/08/2012 01/08/2012
01/06/2012 31/12/2012
01/08/2012 01/08/2012
01/09/2012 01/09/2012
01/09/2012 31/12/2012
01/07/2012 01/07/2012->not retrieved out
01/08/2012 01/08/2012
01/01/2012 31/12/2012
Write a program to declare a date variable and assign it to the current system date. Depending on the day of the month the program should print the following:
If day is 1-10 then print "It is day<day number> of <month name>. It is early in the month".
If day is 11-20 then print "It is day<day number> of <month name>. It is the middle of the month".
If day is 21-31 then print "It is day<day number> of <month name>. It is nearly the end of the month".
For example, if the day is November 30, then print "It is day 30 of November. It is nearly the end of the month".
How can we partition a table based on date if it does not have a date column.
Actually I have to compare two tables on daily basis and fetch few rows from those two tables and enter it to a third table.But both these tables does not have a date column.
I am confused if i need to alter those tables and add date column or if there is some way in which i can compare the data from the two tables for that particular day only and not the whole table data.
I have a small prolem thats best described like this....
a table called TONY with a field named VISITED (date as YYYYMMDD).
We want to populate the field TIMESTAMP (Last visited timestamp, 18 digits) using midnight or 00:00:00 on VISITED value.
Something like:
UPDATE TONY SET TIMESTAMP = �(whatever the formula is involving VISITED).
but i cannot figure out the best way to derive the TIMESTAMP value...
it's a date to epoch conversion, and i can find many examples of Epoch to date, but thats the wrong way around for me i'm afraid!
Oracle 11gR2 by the way...
i have a table with the following description
create table gl_periods(period_name varchar2(10),transactions number (2) );
with the data as :
period_name transactions
------------ --------------
JAN-10 12
FEB-10 12
MAR-10 8
APR-10 23
ADJ_TOM-10 25
MAY-10 37
JUN-10 41
JUL-10 10
PHY_JAY-10 6
AUG-10 14
SEP-10 22
My requirment is to find out the period names and transactions which are in valid date formats and are less than sysdate and the non date formats are adjustments made by different users for their transactions
I want to load data from a file using sqlldr.I have a table commissions
(
technician_id char(5)
, tech_name char(30)
, Comm_rcd_date DATE
, Comm_Paid_date DATE
, comm_amt number(10,2)
)
my file is
00001,TIMOTHY TROENDLY,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0007,123.56
00002,KENNETH KLEMENZ,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0009,123.56
00003,SHUNDAR ARDERY,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0005,123.56
write a ctl file to load this data.
I want to get data for month to date. For example, If I pass today or any day date as parameter then i should get data for that month(month of passing date) up to passing(parameter) date. As well as i have to get year to date.For example, If I pass today or any day date as parameter then i should get data for that financial year(year of passing date) up to passing(parameter) date. how to get month to date and year to date data.
View 3 Replies View RelatedA field named xxx_date is a text item which we have to enter manually so as to update a record in that particular date. This is a mandatory field without which we cannot continue the data entry..
I am getting this error while trying to update the record
FRM-40509 :Oracle error :unable to update record
I have kept the enabled = yes
required=no
data type=Date.. in the property pallet
I want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
I need to convert the type of GMT to Local time, during data entry. I have a source table and a target table.
To make the insert get the most value, I have no problems:
insert into destination (SELECT * FROM WHERE source pointnumber = (SELECT MAX (pointnumber) FROM source));
But since times are different between the tables, I want to convert the data obtained to GMT -4:30 Time (Caracas - Venezuela), before inserting it.
I can use a function?
I have a date field that should be filled everyday with today's date and I need to get the days that were not entered.
i.e. :
CREATE TABLE TRY_F (DAT DATE);
INSERT ALL
INTO TRY_F VALUES (to_date('01/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('02/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('04/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('05/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('06/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('08/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('10/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('14/01/2011','DD/MM/YYYY'))
SELECT * FROM DUAL;
I need a smart way of getting the dates that were missed in DAT.