I have a two date fields in my form; valid from date and expiry date.
Currently my valid from date has an inital value property of $$date$$ which automaitcally brings up todays date.
I need my expiry date to automatically show a date 15 years after this date?
I am a novice in oracle
I have 2 columns in my table
->Col1 with experience in years entered as an integer
->Col2 with current date
I need to add another column as a date value adn for that i need to subtract Currentdate-Col1 when i tried currentdate-Col1 it just subtracted the days i need the formula to subtract years and give a date
I have worked in DB2 and all u need to do there was add the keyword years at the end but in oracle the same does not work
I am trying to set a item to system date + 18 years. What type of formula or where to put such a thing. i tried putting- select add_months(sysdate,216) from dual; into the calculation-formula in property palette with no success.
View 1 Replies View RelatedI'm trying to work out how to take a table like this:
IDDate
12502-Feb-07
12516-Mar-07
12523-May-07
12524-May-07
12525-May-07
33302-Jan-09
33303-Jan-09
33304-Jan-09
33317-Mar-09
And display the data like this:
IDPeriodPeriod StartPeriod End
125102-Feb-0702-Feb-07
125216-Mar-0716-Mar-07
125323-May-0725-May-07
333102-Jan-0904-Jan-09
333217-Mar-0917-Mar-09
As you can see, it's split the entries into date ranges. If there is a 'lone' date, the 'period start' and the 'period end' are the same date.
i have emp table of 5 columns empno,ename,dept,sal,edit_timing(edit timing datatype is timestamp).and my form contains empno,ename,dept,sal. is if i insert a record into forms it automatically insert the date and timing into edit_timing columns.
View 2 Replies View RelatedI require to find the years between any given date range. For example what are the years between the dates '01/12/2010' and '01/02/2012'? Answer must be '2010,2011,2012'. how to code the query for this result?
View 2 Replies View RelatedA field named xxx_date is a text item which we have to enter manually so as to update a record in that particular date. This is a mandatory field without which we cannot continue the data entry..
I am getting this error while trying to update the record
FRM-40509 :Oracle error :unable to update record
I have kept the enabled = yes
required=no
data type=Date.. in the property pallet
I need to calcuate balance for last two cooprative years on input date.
example
if input date is-->"01-AUG-2012" if (month >=7) -->then i need to calculate from 01-july-2010 to 30-june-2011 and 01-july-2011 to 30-june-2012 and 01-july-2012 to input date.
if input date is-->"01-june-2012" if (month<7) -->then i need to calculate from 01-july-2009 to 30-june-2010 and 01-july-2010 to 30-june-2011 and 01-july-2011 to input date.
how to achieve this logic
I have a table which contains some data. But we are dropped and recreated the same table several times. Now I wanted to know that when this table created initially. How to findout the date of creation(very first time).
View 13 Replies View RelatedI have these table :
create table mvt
(
id number(1) ,
dat date
)
/
insert into mvt values (1, '2.10.1999');
insert into mvt values (1, '1.08.2005');
insert into mvt values (1, '24.09.2008');
commit;
I want to build a query for id = 1 that retrieves this :
START END
-------- --------
02/10/99 31/07/05
01/08/05 23/09/08
24/09/08 {sysdate}
{sysdate} represents the current date.
I've tried with these query :
select
old.dat
, next.dat - 1
from mvt old, mvt next
where 1 = 1
and old.id = 1
and old.id = next.id
and next.dat in (select min(dat) from mvt where id = old.id and dat > old.dat)
/
But it delivers only this :
DAT NEXT.DAT
-------- --------
02/10/99 31/07/05
01/08/05 23/09/08
Is there a way to retrieve all what I want in one query (without unions or functions that gives the last date for id) ?
Version : 4.1.1, I have a tabular form on a DB table. One of the columns is a date field. When the user hits the "add Row" button on the tabular form, I want the Date field to be defaulted to sysdate. Here is what I have tried so far,
1. Created a "hidden" item P1_SYSDATE and populated the default value with sysdate. After this, under the DB tabular report date field, I used default type - Item/application on this page and entered P1_sYSDATE
2. Instead of populating the default value of the P1_SYSDATE hidden item, I created a before regions process and added
:P1_SYSDATE := sysdate
and added P1_SYSDATE to default type of the tabular date field with default type as "ITem/application on this page.
I get the error
ORA-01790: expression must have same datatype as corresponding expression
I tried to_Char(sysdate,'dd-mon-yyyy') and then converting it back to to_date. still no luck.
When I run a query form the the Query Window in Visuial Studios 2012 all the date fields truncated to 'mm/dd/yyyy', but i need the full date returned. I am able to get full date from TO_char(MyDateField, 'yyyy-mm-dd hh24:mi:ss'), but if I do TO_DATE(MyDateField, 'yyyy-mm-dd hh24:mi:ss') it only returns 'mm/dd/yyyy'. I'm sure this is a simple setting in Visual studios but I cant find it to save my life. Is there there a way to have the full date returned by default?
View 0 Replies View RelatedHow to write a single query for the below scenario?I got only start date column, but I need show the end date based on next (start date-1). For the last row, need to show the same date in the end date column.
For Example:I have the data as shown below,
Start date End date
1-Jan-10
3-Mar-10
3-May-10
5-Jul-10
1-Aug-10
I wanted to output as shown below
Start date End date
1-Jan-10 2-Mar-10
3-Mar-10 2-May-10
3-May-10 4-Jul-10
5-Jul-10 31-Jul-10
1-Aug-10 1-Aug-10
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)
I would like to inquire how do I code my select statement if my user enter a search date range(search startDt: 01/08/2012 and search endDt :30/09/2012) and I will like to retrieve only the 7records out from my table as shown below ?
STARTDT_ ENDDT_
01/08/2012 01/08/2012
01/06/2012 31/12/2012
01/08/2012 01/08/2012
01/09/2012 01/09/2012
01/09/2012 31/12/2012
01/07/2012 01/07/2012->not retrieved out
01/08/2012 01/08/2012
01/01/2012 31/12/2012
Write a program to declare a date variable and assign it to the current system date. Depending on the day of the month the program should print the following:
If day is 1-10 then print "It is day<day number> of <month name>. It is early in the month".
If day is 11-20 then print "It is day<day number> of <month name>. It is the middle of the month".
If day is 21-31 then print "It is day<day number> of <month name>. It is nearly the end of the month".
For example, if the day is November 30, then print "It is day 30 of November. It is nearly the end of the month".
i want to show the date exactly in following format:
00:16:15 Wed 1st Dec 2010
I have tried :
select to_char(to_date('01/12/2010 00:16:15' , 'dd/mm/yyyy hh24:mi:ss'), 'hh24:mi:ss Day dd Mon yyyy')
from dual
Result it is giving
00:16:15 Wednesday 01 Dec 2010
How to show date in form 1st 2nd 3rd and so on?
How to show Abbreviated name of the day?
How can we partition a table based on date if it does not have a date column.
Actually I have to compare two tables on daily basis and fetch few rows from those two tables and enter it to a third table.But both these tables does not have a date column.
I am confused if i need to alter those tables and add date column or if there is some way in which i can compare the data from the two tables for that particular day only and not the whole table data.
I have a small prolem thats best described like this....
a table called TONY with a field named VISITED (date as YYYYMMDD).
We want to populate the field TIMESTAMP (Last visited timestamp, 18 digits) using midnight or 00:00:00 on VISITED value.
Something like:
UPDATE TONY SET TIMESTAMP = �(whatever the formula is involving VISITED).
but i cannot figure out the best way to derive the TIMESTAMP value...
it's a date to epoch conversion, and i can find many examples of Epoch to date, but thats the wrong way around for me i'm afraid!
Oracle 11gR2 by the way...
i have a table with the following description
create table gl_periods(period_name varchar2(10),transactions number (2) );
with the data as :
period_name transactions
------------ --------------
JAN-10 12
FEB-10 12
MAR-10 8
APR-10 23
ADJ_TOM-10 25
MAY-10 37
JUN-10 41
JUL-10 10
PHY_JAY-10 6
AUG-10 14
SEP-10 22
My requirment is to find out the period names and transactions which are in valid date formats and are less than sysdate and the non date formats are adjustments made by different users for their transactions
I want to load data from a file using sqlldr.I have a table commissions
(
technician_id char(5)
, tech_name char(30)
, Comm_rcd_date DATE
, Comm_Paid_date DATE
, comm_amt number(10,2)
)
my file is
00001,TIMOTHY TROENDLY,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0007,123.56
00002,KENNETH KLEMENZ,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0009,123.56
00003,SHUNDAR ARDERY,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0005,123.56
write a ctl file to load this data.
I want to get data for month to date. For example, If I pass today or any day date as parameter then i should get data for that month(month of passing date) up to passing(parameter) date. As well as i have to get year to date.For example, If I pass today or any day date as parameter then i should get data for that financial year(year of passing date) up to passing(parameter) date. how to get month to date and year to date data.
View 3 Replies View RelatedI want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
select to_date('28-FEB-2013') - TO_DATE('01-FEB-2013') FROM DUAL
gives me 27 days, what should I do to get 28 ? meaning include both the start and end dates in the range ?
I have set up a view that pulls news & events records.
SELECTc.priority, c.startDate, p.headline, p.newsID, p.kicker, p.category, p.webPath, p.makePopup, p.thumbnail, p.shortDesc, p.storyType
FROM(so_news p LEFT OUTER JOIN so_news_deptLevel c ON p.newsID = c.newsID) LEFT OUTER JOIN so_departments d ON d.deptID = c.deptID
[Code].....
For events I want only the events that have a p.startDate equal to today. I have tried setting that line up a few different ways.
p.startDate = sysDate didn't provide any records for events
p.startDate = TO_CHAR(sysDate, 'MM/DD/YYYY') freaked the system out and nothing appeared for either parts of the union
how to output only events that are for today?
I need to convert the type of GMT to Local time, during data entry. I have a source table and a target table.
To make the insert get the most value, I have no problems:
insert into destination (SELECT * FROM WHERE source pointnumber = (SELECT MAX (pointnumber) FROM source));
But since times are different between the tables, I want to convert the data obtained to GMT -4:30 Time (Caracas - Venezuela), before inserting it.
I can use a function?
I have a date field that should be filled everyday with today's date and I need to get the days that were not entered.
i.e. :
CREATE TABLE TRY_F (DAT DATE);
INSERT ALL
INTO TRY_F VALUES (to_date('01/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('02/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('04/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('05/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('06/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('08/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('10/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('14/01/2011','DD/MM/YYYY'))
SELECT * FROM DUAL;
I need a smart way of getting the dates that were missed in DAT.
Lets say the contents of the table are like this -
key dte_start(number) dte_end(number)
1 20010101 20011231
1 20020101 20081231
1 20030601 20071231
1 20100101 20101231
2 20090101 20091231
2 20090401 20101231
2 20101231 20111231
2 20140101 20141231
3 20080101 20091231
3 20070101 20081231
3 20100101 20101231
3 20120101 20120630
I want the query to resolve overlapping dates as well as merge contiguous segment and leave non-contiguous segments as is. The final result of the query should be like this.
key dte_start(number) dte_end(number)
1 20010101 20081231
1 20100101 20101231
2 20090101 20111231
2 20140101 20141231
3 20070101 20101231
3 20120101 20120630
I tried using the lead over partition along with the standard overlap query and case logic to get the results but couldn't get it to work.
I am having problems with the XMLTable function. I cant get it to see the entire date/time value in a date field. This wont work
select x1.* from XMLTABLE('/DOCUMENT' passing xmltype('<DOCUMENT><STR>abc def ghi</STR><NUM>1234</NUM><DT>2013-02-17T04:24:02</DT></DOCUMENT>') columns STR varchar2(25), NUM number, DT date) x1;
However if I change the DT tag to just the date only "2013-02-17" it works. Why wont Oracle see the entire date/time format even if its ISO 8601 compliant?
Oracle DB: 11.2.0.3.0
I have a date column , and i want to show the date in 'DD/MM/YYYY' format for eg days with 2 digit or comming properly but when it comes to single digit the 0 is not comming for example 4/11/2012 should come as 04/11/2012 like 16/11/2012 , i even did the conversion like to_char(rh_dt,'DD/MM/RRRR').
View 4 Replies View Related