I am rebuilding some UNUSABLE local index partitions on Oracle 8.1.7.4.0 (64bit) database . The platform is a HPUX machine.
The DDL of the partition table/indexes:
=========================
CREATE TABLE TESTME
( INST_NO CHAR(3) NOT NULL,
ACCT_NO CHAR(16) NOT NULL,
REC_NO CHAR(9) NOT NULL,
TRAN_TYPE CHAR(2) DEFAULT ' ',
STAT CHAR(2) DEFAULT ' ',
[code]...
Let's consider such table that all rows fit into single block:
SQL> create table test as select rownum id, '$'||rownum name from dual connect by level <= 530;
Table created.
SQL> create index i_test on test(id);
Index created.
SQL>
SQL> begin
[code].....
why does approach with full scan take longer even if table occupies only one data block? PS. 11gR2
I have created an non unique index lk_fein on lookup_fein( code,map_id,trash). When I check the explain plan it does a full table scan on lookup_fein. if I force it to use index by it does and the cost also decreases.
SQL> SELECT WORK_FEIN,
2 NON_FEIN ,
3 FI_FEIN ,
4 MFEIN ,
5 TOTAL_FEIN ,
[code]...
when i am Executing the following statement
SELECT DISTINCT EXPOSURE_REF FROM KBNAS.VW_EXPOSUREDETS_FOR_CCYREVAL
WHERE EXPOSURE_CURRENCY='THB' AND BASE_TXN_CCY='USD' AND BRANCH_CODE='7000'
AND (REVAL_STATUS='O') AND CONV_RATE<>'62' AND (EXPOSURE_AMOUNT<>0)
UNION
SELECT DISTINCT ED.EXPOSURE_REF FROM KBNAS.EXPOSURE_DETAILS ED,
[code].....
I have attached DDL for table EXPOSURE_DETAIL(PARTITION),LEDGERCARD,LEDGERCARDDETAILS, DDL for INDEX on those tables and DDL for Views..
Issue: we have created the Indexes but when we check the explain plain .. full table scan is going on..I have attached the explain plan ..
2day i was dropping few unwanted index from the data base, By mistake i removed the local partitioned index , So i want to recreate that index.i create the index, will the partitioned index updates when we add partitioned to the tables.
View 2 Replies View Relatedif i have local index, does query which uses this index always have to scan all partitions?
For example, I have hash-partitioned table on column A. There is local index on column B. I am querying:
select * from my_table where A='ABC' and B>123.
I know that records with A='ABC' are in 2nd partition. Does only 2nd partition of local index will be scanned or all of them must be scanned?
Index with following PARTITIONS. Index rebuild is extremely slow. Below 2 Alter index ..rebuild... took 10 hours to complete. Because of this queries which based on this index are really slow.
SYS@DB AS SYSDBA> select partition_name,tablespace_name,bytes/1024 KB from dba_segments where segment_name='KSTN';
PARTITION_NAME TABLESPACE_NAME KB
------------------------------ ------------------------------ ----------
REB_IDX_1 TS_REB 64
REB_IDX_2 TS_REB 64
REB_IDX_3 INDEX 64
REB_IDX_4 TS_REB 64
[code]....
What is the difference between index rebuild and index rebuild online.
View 3 Replies View RelatedWhat is the use of Local and Global Partition Index?
View 1 Replies View RelatedI'm trying to split a table partition.
whether the below syntax are correct.
If local index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
update indexes;
(per http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1401247200346349807)
=================================================================
If Global index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
UPDATE GLOBAL INDEXES;
I�m Using Oracle 11.I have a table with 16 million rows and an index (let's call it the employee table with an index on department). I need to select all the employees whose departments are located in the uk. I achieve this by selecting all the department numbers from departments where location = 'UK' in a sub select then plug this into the main query as follows:
SELECT *
FROM employees
WHERE department IN (SELECT department from departments where location = 'UK');
It takes ages, 25 seconds or more, the explain plan shows its doing a full table scan on emplyees. I need it to use the index. The sub query is instant and returns only 5 rows. If I explicitly put the 5 numbers in the IN clause the query uses the index and executes in 0.04 seconds. See below:
SELECT *
FROM employees
WHERE department IN (1,2,3,4,5);
I need it to use the subquery once and then use the index on the main table.
Below query is degrading the performance of database. As we know that, without where clause, query do full table scan.Now, it is written to generate the sequence no.
SQL> explain plan for
2 SELECT NVL(MAX(P.NUM_SERIAL_NO), 0) + 1 FROM CNFGTR_IRDA_ENVELOPE_DTLS P
3 /
Explained.
SQL> select * from table(dbms_xplan.display());
PLAN_TABLE_OUTPUT
----------------------------------------------------------------------------------------------------
Plan hash value: 3345343365
------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
------------------------------------------------------------------------------------------------
[code].....
Index is not created on the column.
I have a huge table (about 60 gb) partition over range. The index on this table is global index created on 4 columns together. I have a query which is running very slowly. The explain plan is showing the use of this global index.Explain plan is not showing pstart and pend because the index is global.
View 6 Replies View RelatedThe best way to rebuild index and table and also give the reason as why we need to use this method?
View 10 Replies View RelatedI have created a table below, my TL asked me to create a local unique constraint for the below table.
I went through all sites and could not find the correct solution, how to create LOCAL UNIQUE CONSTRAINT ON SUB PARTITION TABLE and LOCAL UNIQUE INDEX ON PARTITION TABLE. Creating Local Unique constraint should take care of creating local unique index creation.
Unique key columns are DET,GDS,ARRIVE_DT
CREATE TABLE SUB_PAR_TAB
(
ID VARCHAR2(100) NOT NULL,
REGION VARCHAR2(40) NOT NULL,
SOURCE VARCHAR2(80) NOT NULL,
DET VARCHAR2(80) NOT NULL,
GDS VARCHAR2(40) NOT NULL,
ARRIVE_DTDATE,
SYS_SOURCE VARCHAR2(25) ,
[code]........
I have table with 4 partition by range partition. I am loading the table in bulk mode to latest partition. Before I load , I dropped the index and after Load I will be creating index. So when I am dropping index, it is dropping index from all the partitions and when creating the index, I am creating the index for all partitions. When I am creating index using local, it is telling you have to create local index for all partitions at the same time. because of that I have to drop and recreate all indexes again. Again I have to gather stats for whole table .
I was thinking we can build index for one partition and index should remain as is for old partitions If this is not the case, how do I plan my load for a partitioned table using bulk mode to latest partition.
I have a global index and I want to convert it to local index.Is there a way to recreate local index with out dropping the global index.
I can create a local index first and then drop the global index. But is there a way to create it with out dropping the global index, just convert it.
how to partition and index my table for a special problem.
The table:
CREATE TABLE TEST (
ID NUMBER PRIMARY KEY,
U_VALUE NUMBER NOT NULL, -- Ranges from 0 - 30.000.000
O_VALUE NUMBER NOT NULL, -- Ranges from U_VALUE - 30.000.000
CREATE_TS TIMESTAMP DEFAULT SYSTIMESTAMP NOT NULL,
UPDATE_TS TIMESTAMP NOT NULL,
ITEM_TYPE NUMBER NOT NULL --<< Only 4 different values >>
);
As you can see, U_VALUE is ALWAYS lower than O_VALUE.I need to have the CREATE_TS in either main- or subpartition do drop the partitions after some time so i don,t have to use DELETE statements. The table has 360 millions rows.
The application has only 8 query which will always use a WHERE clause like this:
SELECT * FROM TEST
WHERE U_VALUE <= :1 AND O_VALUE => :2 AND ITEM_TYPE = :3
1. Is there any good technique how to create a good index for the queries (application will execute 120 queries per second)?
2. how to partition this table?
I am trying to disable the index i am getting the error like
ORA-02243: invalid ALTER INDEX or ALTER MATERIALIZED VIEW option
the table have partition. how to disable the index in partition table.
I need to Analyze and Rebuild the indexes with a script at once for a schema.
View 30 Replies View RelatedBelow Table Index are rebuild,This table are relation with sys user or not?after rebuild index, getting error in alert log file
ORA-00600: internal error code, arguments: [psdnop-1], [1410], [], [], [], [], [], [], [], [], [], []
ORA-01410: invalid ROWID
when trying to select * from dba_network_acls getting error massage Rowid invalid
ALTER INDEX CTXSYS.SYS_C003684 REBUILD;
ALTER INDEX CTXSYS.SYS_C003683 REBUILD;
ALTER INDEX CTXSYS.SYS_C003682 REBUILD;
ALTER INDEX CTXSYS.SYS_C003681 REBUILD;
[code]...
It is possible to recreate this index again.......
oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - 64bit Production
PL/SQL Release 11.1.0.6.0 - Production
"CORE 11.1.0.6.0 Production"
I have a procedure that is run weekly to load the data, for which it calls another procedure. This weekly procedure, disables the index, load the data, and rebuilds the index. During rebuilding of index, its giving ORA-00054: resource busy and acquire with NOWAIT error. I dont have privileges to look for session id, and kill the session. How to avoid this error.
create or replace
PROCEDURE "WCL_WEEKLY_UPLOAD" (
p_event_id IN NUMBER
)
[code]....
As you can see, after the procedure wc_upload, COMMIT is issued, and then the rebuilding of the index is starting. So dont know what is causing the table to lock.
Oracle 11.1 version
Oracle sys Index rebuild list
CTXSYS
EXFSYS
FLOWS_030000
FLOWS_FILES
MDSYS
OLAPSYS
ORDSYS
OWBSYS
SI_INFORMTN_SCHEMA
TSMSYS
WKSYS
MDSYS
After rebuild above index im getting error while inserting,update,delete table rows
Error like 'INVALID ROWID'
I was comparing cost of rebuild vs create index...I carried out the following test
SQL> create table t4 as select * from t1;
Table created.
SQL> create table t5 as select * from t1 where 1=2;
Table created.
SQL> create index i5 on t5(id);
Index created. SQL> select bytes,extents,blocks from user_segments where segment_name='I5';
BYTES EXTENTS BLOCKS
---------- ---------- ----------
65536 1 8
SQL> alter index i5 unusable;
Index altered.
SQL> alter table t5 nologging;
Table altered.
SQL> Alter session set skip_unusable_indexes=True;
Session altered.
SQL> insert /*+ append */ into t5 select * from t1;
563904 rows created.
SQL> commit;
Commit complete.
Now I compared the cost (elapsed time, logical I/O) of the operations
create index i4 on t4(id);
Vs
alter index i5 rebuild online;
Following is the related trace of above 2 steps
create index i4 on t4(id)
call count cpu elapsed disk query current rows
------- ------ -------- ---------- ---------- ---------- ---------- ----------
Parse 1 0.00 0.00 0 1 0 0
Execute 1 1.17 3.38 9497 7869 335 0
Fetch 0 0.00 0.00 0 0 0 0
------- ------ -------- ---------- ---------- ---------- ---------- ----------
total 2 1.17 3.38 9497 7870 335 0
Misses in library cache during parse: 1
Optimizer goal: CHOOSE
Parsing user id: 5
[code]....
So which option we shall pick in such cases? {Of course I haven't set 'nologging' for the indices but it is same for both indices we are comparing}
In which condition it is required to rebuild the index and how can identified it?
View 12 Replies View RelatedWe have large tables 60-70 GB having 120 million records. We have to perform index rebuild frequently which takes significant time to complete and effects database performance too. how we can use index Coalesce? what are its benefits, coalesce results in performance gain?
View 10 Replies View RelatedWe have separate tablespaces for Tables and Indexes. Also Temp is in different temporary tablespace and UNDO also in UNDO tablespace and Index tablespace contains only Indexes. The tablespace usage for tables is 80% and Index is 91%.There is not enough disk space to allocate for the datafile on our system. I ran a rebuild on one of the Index but now notice the Index tablespace is 98% used soon after the rebuild finished.
How can i free up space for Index tablespace and why does the size of Index tablespace increased after the rebuild.
I was confused by partitioed table, when i select a partition of table, how does oracle to scan blocks? it scan all blocks of table or scan a single partition blocks only?
SQL> Explain Plan For
2 Select Count(1) From Tb_Hxl_List Partition(p_L3);
Explained.
SQL> Select * From Table(dbms_xplan.display);
PLAN_TABLE_OUTPUT
--------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 18 (0)| 00:00:01 |
| 1 | SORT AGGREGATE | | 1 | | |
| 2 | PARTITION LIST SINGLE| | 33115 | 18 (0)| 00:00:01 |
| 3 | TABLE ACCESS FULL | TB_HXL_LIST | 33115 | 18 (0)| 00:00:01 |
Our database size is 100GB and i removed few records from a table and rebuild the index.The size of Index reduced considerably after Index rebuild but now i see our database size increased to 115GB.I know online rebuild creates second index which is also removed after the build is finished then why the increase in database size?Is there a way so it shows up more space ?
select sum(bytes) from dba_segments where owner='abc' and segment_name='abc_index_1';
8GB
ALTER INDEX abc_index_1 REBUILD ONLINE ;
select sum(bytes) from dba_segments where owner='abc' and segment_name='abc_index_1';
2GB
How to verify if rebuild an index is required in database.
View 9 Replies View Related