How Does Local Index Work In Partitioned Table
Nov 28, 2012
I have table with 4 partition by range partition. I am loading the table in bulk mode to latest partition. Before I load , I dropped the index and after Load I will be creating index. So when I am dropping index, it is dropping index from all the partitions and when creating the index, I am creating the index for all partitions. When I am creating index using local, it is telling you have to create local index for all partitions at the same time. because of that I have to drop and recreate all indexes again. Again I have to gather stats for whole table .
I was thinking we can build index for one partition and index should remain as is for old partitions If this is not the case, how do I plan my load for a partitioned table using bulk mode to latest partition.
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Jun 28, 2011
I have a huge table (about 60 gb) partition over range. The index on this table is global index created on 4 columns together. I have a query which is running very slowly. The explain plan is showing the use of this global index.Explain plan is not showing pstart and pend because the index is global.
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Jan 29, 2013
2day i was dropping few unwanted index from the data base, By mistake i removed the local partitioned index , So i want to recreate that index.i create the index, will the partitioned index updates when we add partitioned to the tables.
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Mar 2, 2012
I have to create primary key using local on a partitioned table.
Since the table is huge it has to be done parallel. Following stmt is giving error
alter table XYZ add CONSTRAINT PKN_XYZ PRIMARY KEY (ID,LogDtTm)
USING INDEX LOCAL parallel 25 INITRANS 5 TABLESPACE OLTP_IDX_TS ;
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Jul 20, 2012
Facts:
Oracle 10.1.0.5
AIX 5.3
My table, HMTX have 10 partitions each of one have 6 millions of rows (average). We have 7 partitioned LOCAL indexes in that table.
Every month we load data into a new partition (6 million of rows aprox) and drop the oldest partition in table HMTX.
In order to do that we have a script that contain the next statements:
drop of all indexes
drop index n1;
drop index n...;
drop index n7;
[Code]...
create indexes again with tha same storage and degree parameters
CREATE INDEX hmtx_TST_N1 ON hmtx (campo1, campo2, campo3 .... campo8)
TABLESPACE xxxx
PCTFREE 0
INITRANS 2
[Code]....
My problem is in rhe index creation section, despite use parallel with degree 8 and nologging the index was created in :
Elapsed: 02:43:50.85.
In past months that index was created in :
Elapsed: 01:43:36.94
Elapsed: 04:48:31.24
Elapsed: 00:57:16.28
there are another way in order speed the index creation ?? o another way to disable ths index ??
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Apr 23, 2012
I am rebuilding some UNUSABLE local index partitions on Oracle 8.1.7.4.0 (64bit) database . The platform is a HPUX machine.
The DDL of the partition table/indexes:
=========================
CREATE TABLE TESTME
( INST_NO CHAR(3) NOT NULL,
ACCT_NO CHAR(16) NOT NULL,
REC_NO CHAR(9) NOT NULL,
TRAN_TYPE CHAR(2) DEFAULT ' ',
STAT CHAR(2) DEFAULT ' ',
[code]...
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Jan 11, 2013
I'm trying to find a way to ADD new partitions to local indexes and at the same time specify their tablespaces without having to DROP and RECREATE.
Here´s an example table based on yearly partitioning:
CREATE TABLE "TABL_ANOM"
(
ANOM_TS TIMESTAMP(6) NOT NULL
, ANOM_TIPO NUMBER(2, 0) NOT NULL
, ANOM_NIVEL NUMBER(2, 0) NOT NULL
, ANOM_ID NUMBER(10, 0) NOT NULL
[code]...
Here´s an index def for the table:
CREATE INDEX "TABL_ANOM_INDEX1" ON "TABL_ANOM" ("ANOM_NIVEL") LOCAL
(PARTITION DGSCOPSX_2011 TABLESPACE DGSCOPSX_2011
,PARTITION DGSCOPSX_2012 TABLESPACE DGSCOPSX_2012
)
OK. Now I want to add partitions for 2013 so for the table I use:
ALTER TABLE TABL_ANOM ADD
PARTITION DGSCOPS_2013 VALUES LESS THAN (TO_DATE('2014-01-01 00:00:00','YYYY-MM-DD HH24:MI:SS')) TABLESPACE DGSCOPS_2013;
and this works fine for the table but I can't find a similar command to simply add additional partitions to the indexes. I know that I can drop and recreate the indexes with the additional partition defs but on some of my tables, I'm dealing with hundreds of millions of rows and I think it would take way too long to drop and recreate all indexes on all partitions.
Also related is the PRIMARY KEY index partitions. Is there a way to add partitions (specifying the tablespaces) without having to DROP and re-ADD the CONSTRAINT with the additional partition for 2013?
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Jun 23, 2011
I have a global index and I want to convert it to local index.Is there a way to recreate local index with out dropping the global index.
I can create a local index first and then drop the global index. But is there a way to create it with out dropping the global index, just convert it.
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Feb 4, 2005
16:28:32 SQL> create bitmap index bp_idx_ag_id on transactions(type);
create bitmap index bp_idx_ag_id on transactions(type)
*
ERROR at line 1:ORA-25122: Only LOCAL bitmap indexes are permitted on partitioned tables
how to create bitmap index on partitiioned tables
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Apr 30, 2012
If we have not set parallel degree for a table then we can ( try to ) force parallel execution on a table using a parallel hint Does this 'parallelism' works on the index search in the query as well?
In which situations non-parallel non-partitioned table but parallel index (degree>2) will facilitate a query?
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Nov 1, 2012
what is the best way to partitioned a non-partitioned table to partitioned table date wise? I have data from last four year?
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Jan 2, 2013
I would like to ask about indexes in partitioned tables.I have indexes on a partitioned table, it is partitioned by range method i.e based on Creation date time.All select queries sent to the table use the Creation date time. I have an index on Creation date time.Here is an example:
SELECT col1, col2, col3
FROM table1 where
date_time BETWEEN TO_DATE ('20120117 10:00:00','YYYYMMDD HH24:MI:SS')
AND TO_DATE ('20120117 13:00:00','YYYYMMDD HH24:MI:SS')
AND frmt_name = 'XXXX'
AND sender = 'YYYYY'
AND nature = 'ZZZZ'
AND type LIKE '548'
ORDER BY date_time
WHERE ROWNUM <= 5000
[code]....
do I have to add DATE_TIME to all indexes (IX_NAME_FORMAT_TYPE,IX_CCY) or not?
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Oct 3, 2011
I have a partitioned index with a pctfree of 10 .I want to change pctfree to 20.How to change?
I tried this
alter index fnsonli.IG01PK rebuild partition SYS_P245 pctfree 20 ;
alter index fnsonli.IG01PK rebuild partition SYS_P245 pctfree 20
*
ERROR at line 1:ORA-14185: incorrect physical attribute specified for this index partition
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Jul 5, 2012
Today I found myself in a situation where I needed to compress an already existing, partitioned index. First I issued an alter table to rebuild and compress the whole index:
SQL> ALTER INDEX MY_INDEX REBUILD COMPRESS;
ERROR at line 1:ORA-14086: a partitioned index may not be rebuilt as a wholeSo next I tried to rebuild compress one of the partitions:
SQL> ALTER INDEX MY_INDEX REBUILD PARTITION PART1 COMPRESS;
ERROR at line 1:ORA-28659: COMPRESS must be specified at object level first
Turns out that there is no way you can do a rebuild compress on partitioned indexes. I did not realize that until I stumbled across document 312843.1 on Metalink. It says the only way to compress a partitioned index is to drop it and recreate it (through 11.2).
My question is do we have any new feature in Oracle 11gR2 to rebuild partition indexes?
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Jan 25, 2013
create table mypart(a number, b number, c number, p_key number) PARTITION BY RANGE (p_key)
( PARTITION p0 VALUES LESS THAN (18),
PARTITION p1 VALUES LESS THAN (29),
PARTITION p3 VALUES LESS THAN (MAXVALUE)
) ENABLE ROW MOVEMENT;
create index idx_mypart on mypart(p_key,a,b)
I want to create primary key on this table that will use the local partitioned index idx_mypart
can I do that ?
alter table mypart add constraint pk_mypart primary key using index (idx_mypart)
above syntax gives error
basically the primary key should make use of the local partitioned index.
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Aug 17, 2010
I have a partioned (by row_create_date) table, lets called it TABLE_X, which has about 300 million records. This table has 7 columns including the primary key and a non-unique, locally partitioned column called trace_id; 99% of queries access this table via this column.
Lately, querying TABLE_X via the trace_id has been very very bad. Queries run for over 1 hr in some cases. So we decided to change the index for trace_id to a global index. Now queries against TABLE_X return in seconds. So far so good.
However, when the query has to join TABLE_X to another table, the query sometimes runs for over 1 hours; back to the same old problem. Here is an illustration;
SELECT COUNT(1) FROM TABLE_X WHERE TRACE_ID = 'XXXXX';
-- returns in seconds
SELECT COUNT(1)
FROM TABLE_X,
TABLE_Y
WHERE TABLE_X.TRACE_ID = 'XXXXX'
AND TABLE_X.TRACE_D = TABLE_Y.TRACE_ID;
-- runs for over 1 hr, even when TABLE_Y.TRACE_ID is a primary key.
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Nov 17, 2012
if i have local index, does query which uses this index always have to scan all partitions?
For example, I have hash-partitioned table on column A. There is local index on column B. I am querying:
select * from my_table where A='ABC' and B>123.
I know that records with A='ABC' are in 2nd partition. Does only 2nd partition of local index will be scanned or all of them must be scanned?
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Aug 17, 2010
What is the use of Local and Global Partition Index?
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Nov 25, 2011
I Have created a interval partitioned table with local index.But when automatic partitions are created based record insertion, whether local indexes will be created for each newly created partition or not? If created, how to check
Below is the code which I tried
CREATE TABLE interval_date
(
date1 date,
days VARCHAR2(50)
)
PARTITION BY RANGE(date1)
INTERVAL (NUMTODSINTERVAL(45,'DAY'))
[code]....
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Jul 6, 2010
I have a table which if approc 5GB in size.I am trying to create a partition table from it. I created the new table,but when i am creating local indexes, i am getting an error when i create a unique key. I ll post the creation scripts:
CREATE TABLE A_PT_ORDREG
(
BUS_UNIT VARCHAR2(5) NOT NULL,
ORDER_NO VARCHAR2(15) NOT NULL,
PT_CODE VARCHAR2(15) NOT NULL,
REG_NO VARCHAR2(15) NOT NULL,
AS_APPLICATION VARCHAR2(5) NOT NULL,
[code].....
THE INDEX:
CREATE UNIQUE INDEX PK_A_PT_ORDREG ON A_PT_ORDREG (BUS_UNIT, ORDER_NO, SEQ_NO) local;
I am getting the following error:
ORA-14039: partitioning columns must form a subset of key columns of a UNIQUE index
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Jun 20, 2013
how data is distributed on a local non prefixed index.Let's say I have a table calles SALES and it holds data for the last year partitioned by a date column called month (So that's 12 partitions, one for each month).Now i'm creating the following index: CREATE INDEX TESTIDX ON SALES(salesman_id) local; What will happen is that I'll have 12 partitions on the index but to which partitions in the table are they referencing ?
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Aug 23, 2012
I'm trying to split a table partition.
whether the below syntax are correct.
If local index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
update indexes;
(per http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1401247200346349807)
=================================================================
If Global index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
UPDATE GLOBAL INDEXES;
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Feb 20, 2013
Version Info: 11.2 on Solaris 10
I have a partitioned table like below. I want to create a B-Tree index on SALES_RGN column which is neither the part of Primary key or the Partitioned key. Should I create this index as local or Global ?
CREATE TABLE sales_dtl
(
txn_id number (9),
salesman_id number(5),
salesman_name varchar2(30),
sales_rgn varchar2(10), -----------------------------> This column needs to be indexed
sales_amount number(10),
sales_date date,
constraint pk_sales_dtl primary key (txn_id)
[code]....
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Sep 10, 2012
RDBMS - 11.1.0.7, I it possible to convert indexes of a non-partitioned table to hash partitioned indexes by retaining table as non-partitioned?
If yes, is this what it is Creating a Hash-Partitioned Global Index - can be created for partitioned and non-partitioned tables?
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Apr 4, 2011
I was about to move some tables from one table space to another but it seems it is not possible to move partitioned tables between table spaces of different block sizes.
So far the only option I have is to export and then import back the data.
know if there is any way to move a partitioned table between table spaces of different block size?
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Jan 19, 2013
SNRCTL> stat LISTENER
Connecting to (DESCRIPTION=(ADDRESS=(PROTOCOL=IPC)(KEY=LISTENER)))
STATUS of the LISTENER
------------------------
Alias LISTENER
Version TNSLSNR for IBM/AIX RISC System/6000: Version 11.2.0.1.0 - Production
Start Date 19-JAN-2013 00:50:10
Uptime 0 days 0 hr. 29 min. 51 sec
Trace Level off
Security ON: Local OS Authentication
[code]....
In every oracle documentation for e.g:11.2 Scan and Node TNS Listener Setup Examples [ID 1070607.1] we found the local listener status showing both local-ip and vip. Why is not showing in our case?
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Oct 5, 2013
Let's consider such table that all rows fit into single block:
SQL> create table test as select rownum id, '$'||rownum name from dual connect by level <= 530;
Table created.
SQL> create index i_test on test(id);
Index created.
SQL>
SQL> begin
[code].....
why does approach with full scan take longer even if table occupies only one data block? PS. 11gR2
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Jan 8, 2013
How to know weather table is partitioned or not ? Is there any data dictionary view to know the information about the Partitioned type,keys on table ?
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Mar 14, 2013
I have a table like this:
CREATE TABLE CARGA_P_RECARGA_NEW1
(
TELE_NUM VARCHAR2(10) NOT NULL,
FECHA DATE NOT NULL,
[Code].....
Then I tried to insert some rows in that table, every insert statement is like this:
INSERT INTO CARGA_P_RECARGA_NEW1
VALUES
('3134769595','20/01/2013 07:22:50','1107','CONFB_20121121_20121122175002 60000000000000000090.TXT',0,16,'8327--7991284',1);
Every insert I executed had the month 01 because I expected to query results only from partittion p_0113 but nevermind how query I execute, the result is always the same. I mean if I excute this statement:
SELECT * FROM CARGA_P_RECARGA_NEW1 P_0113;
I get the same result when I execute any other like this:
SELECT * FROM CARGA_P_RECARGA_NEW1 P_0213
What is the error here ?
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Apr 26, 2013
We have a partitioned transaction table in our Datawarehouse environment which has the following partition strategy
SCHEME=DATE-HASH
GRAIN=DAILY
SUBGRAIN=NONE
HASH=8
FROM=31/12/2011
We recently had to delete data from the table. This was a simple delete statement with a where clause and without taking into consideration any partition/subpartition clauses. Post committing the delete we have a count mismatch problem with two queries in particular
select count(0) count_without_parallel FROM TRANSACTION_TABLE t;
--THIS RETRIEVES *15774811* ROWS
select /* parallel(t,default) */count(0) count_with_parallel FROM TRANSACTION_TABLE t+
--THIS RETRIEVES *15777617* ROWS WHICH IS THE ACTUAL EXPECTED COUNT.
I also ran the following just to summarize
select (select count_with_parallel from (
select /* parallel(t,default) */count(0) count_with_parallel FROM TRANSACTION_TABLE t))+
-
+(select count_without_parallel from (+
select count(0) count_without_parallel FROM TRANSACTION_TABLE t)) as false_difference
from dual;
The difference in *2806* rows as expected.To re-affirm my counts I ran
select /*+ parallel(t,default) */
'count_on_t',count(*) from TRANSACTION_TABLE t
group by 'count_on_t'
order by 1;
--THIS RETRIEVES *15777617* ROWS
Removing the parallel hint reverts back to the lesser count. Not sure what is wrong but something prevents the query from parsing the whole table and/or partitions and subpartitions.
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