I have a global index and I want to convert it to local index.Is there a way to recreate local index with out dropping the global index.
I can create a local index first and then drop the global index. But is there a way to create it with out dropping the global index, just convert it.
I have a huge table (about 60 gb) partition over range. The index on this table is global index created on 4 columns together. I have a query which is running very slowly. The explain plan is showing the use of this global index.Explain plan is not showing pstart and pend because the index is global.
View 6 Replies View RelatedWhat is the use of Local and Global Partition Index?
View 1 Replies View RelatedI'm trying to split a table partition.
whether the below syntax are correct.
If local index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
update indexes;
(per http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1401247200346349807)
=================================================================
If Global index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
UPDATE GLOBAL INDEXES;
Version Info: 11.2 on Solaris 10
I have a partitioned table like below. I want to create a B-Tree index on SALES_RGN column which is neither the part of Primary key or the Partitioned key. Should I create this index as local or Global ?
CREATE TABLE sales_dtl
(
txn_id number (9),
salesman_id number(5),
salesman_name varchar2(30),
sales_rgn varchar2(10), -----------------------------> This column needs to be indexed
sales_amount number(10),
sales_date date,
constraint pk_sales_dtl primary key (txn_id)
[code]....
if i have local index, does query which uses this index always have to scan all partitions?
For example, I have hash-partitioned table on column A. There is local index on column B. I am querying:
select * from my_table where A='ABC' and B>123.
I know that records with A='ABC' are in 2nd partition. Does only 2nd partition of local index will be scanned or all of them must be scanned?
I am trying to use Global temporary tables, and index on this table to get my results faster. I can see even if I run any query on this table, it does full table scan and not Index scan..
create global temporary table abc_tab on commit preserve rows
as select a,b,c from xyz;
create index lmn on abc_tab(a,b,c)
I Have created a interval partitioned table with local index.But when automatic partitions are created based record insertion, whether local indexes will be created for each newly created partition or not? If created, how to check
Below is the code which I tried
CREATE TABLE interval_date
(
date1 date,
days VARCHAR2(50)
)
PARTITION BY RANGE(date1)
INTERVAL (NUMTODSINTERVAL(45,'DAY'))
[code]....
2day i was dropping few unwanted index from the data base, By mistake i removed the local partitioned index , So i want to recreate that index.i create the index, will the partitioned index updates when we add partitioned to the tables.
View 2 Replies View RelatedI have a partioned (by row_create_date) table, lets called it TABLE_X, which has about 300 million records. This table has 7 columns including the primary key and a non-unique, locally partitioned column called trace_id; 99% of queries access this table via this column.
Lately, querying TABLE_X via the trace_id has been very very bad. Queries run for over 1 hr in some cases. So we decided to change the index for trace_id to a global index. Now queries against TABLE_X return in seconds. So far so good.
However, when the query has to join TABLE_X to another table, the query sometimes runs for over 1 hours; back to the same old problem. Here is an illustration;
SELECT COUNT(1) FROM TABLE_X WHERE TRACE_ID = 'XXXXX';
-- returns in seconds
SELECT COUNT(1)
FROM TABLE_X,
TABLE_Y
WHERE TABLE_X.TRACE_ID = 'XXXXX'
AND TABLE_X.TRACE_D = TABLE_Y.TRACE_ID;
-- runs for over 1 hr, even when TABLE_Y.TRACE_ID is a primary key.
I have table with 4 partition by range partition. I am loading the table in bulk mode to latest partition. Before I load , I dropped the index and after Load I will be creating index. So when I am dropping index, it is dropping index from all the partitions and when creating the index, I am creating the index for all partitions. When I am creating index using local, it is telling you have to create local index for all partitions at the same time. because of that I have to drop and recreate all indexes again. Again I have to gather stats for whole table .
I was thinking we can build index for one partition and index should remain as is for old partitions If this is not the case, how do I plan my load for a partitioned table using bulk mode to latest partition.
I have a table which if approc 5GB in size.I am trying to create a partition table from it. I created the new table,but when i am creating local indexes, i am getting an error when i create a unique key. I ll post the creation scripts:
CREATE TABLE A_PT_ORDREG
(
BUS_UNIT VARCHAR2(5) NOT NULL,
ORDER_NO VARCHAR2(15) NOT NULL,
PT_CODE VARCHAR2(15) NOT NULL,
REG_NO VARCHAR2(15) NOT NULL,
AS_APPLICATION VARCHAR2(5) NOT NULL,
[code].....
THE INDEX:
CREATE UNIQUE INDEX PK_A_PT_ORDREG ON A_PT_ORDREG (BUS_UNIT, ORDER_NO, SEQ_NO) local;
I am getting the following error:
ORA-14039: partitioning columns must form a subset of key columns of a UNIQUE index
how data is distributed on a local non prefixed index.Let's say I have a table calles SALES and it holds data for the last year partitioned by a date column called month (So that's 12 partitions, one for each month).Now i'm creating the following index: CREATE INDEX TESTIDX ON SALES(salesman_id) local; What will happen is that I'll have 12 partitions on the index but to which partitions in the table are they referencing ?
View 1 Replies View RelatedI am rebuilding some UNUSABLE local index partitions on Oracle 8.1.7.4.0 (64bit) database . The platform is a HPUX machine.
The DDL of the partition table/indexes:
=========================
CREATE TABLE TESTME
( INST_NO CHAR(3) NOT NULL,
ACCT_NO CHAR(16) NOT NULL,
REC_NO CHAR(9) NOT NULL,
TRAN_TYPE CHAR(2) DEFAULT ' ',
STAT CHAR(2) DEFAULT ' ',
[code]...
If i know a rowid of a row,how to get the block_number of index?
SQL> select rowid from hxl.tb_test where id=1;
ROWID
------------------
AAAMo/AAFAAAAAOAAA
we have 25 GB free space in Index tablespace, to avoid space issue i have added 10GB of space. Next shift DBA, rebuild INDEX of the from INDEX tablespace. Now i can check, only 27GB free space in INDEX tablespace...
Rebuilding of INDEX takes extra space.. ?
How to compress a index?
SQL> Create Table tb_compress_test
2 As
3 Select * From dba_objects;
Table created.
SQL> Create Index idx_object_id On tb_compress_test(object_id);
Index created.
SQL> Alter Index idx_object_id Move Compress;
Alter Index idx_object_id Move Compress
*
ERROR at line 1:
ORA-02243: invalid ALTER INDEX or ALTER MATERIALIZED VIEW option
What exactly mean density of the index in db meanings ? I mean when you configure rebuilt of the index and how do you determine the value of density? for e.g when I have density 40 what does it mean ? next question : how shall I determine which tables are included in index ?
View 5 Replies View RelatedOn a SAP system, am trying to drop six indexes, largest is 300MB and smallest is 50MB.
I tried running drop index sapusername.index_name on the 50MB index via SQL*Plus and it seems to be taking forever. anything I can check on the database on why it is taking such a long time?
I can leave it to run overnight but worried that when I come back the next day, it will still be hanged. Is there any quick way of dropping the index, .i.e. drop immediate ...
Am not using SAP's BRTOOLs as it is also hanging from there and the SAP-ADMIN had approved for the DBA to drop it from our end instead.
I am working on Index issue and need to validate the structure of the index. Does validation lock the Index ?
Do we need downtime or we can do it in normal working hours.
alter index index_name validate structure;
In our production database server Index tablespace is not growing now... On average index tablespace increases 200 MB to 250 MB per day. Last two weeks index tablespace does not increase..
I am giving you all a statistics of our production db Tablespace usage..
Date Globusdataxml(MB)Globusindexxml(MB)
23-4-2012 26321025 1581.94
24-4-2012 24633.31 1584.25
25-4-2012 23410.88 1576.25
26-4-2012 22186.19 1573.25
We are trying to create an index using parallelism. The table contains 24 Million row. But It takes very long time. Also we are unable to see any sessions confirming that the index creation is using parallelism. The creation goes on for more than 3 hours. SQL statement executed :
CREATE INDEX ANT.ANT_OM_TRAN ON APPS.ANT_OM_TRAN_INDX (last_update_date) PARALLEL 4 TABLESPACE APPS_TS_IDX;
I found out the session using the query
select sid,serial#,program,module,osuser,username,machine,inst_id,sql_id
from gv$session where type not in ( 'BACKGROUND') and machine='APCUSDE'
and osuser='applmgr' and program like 'sqlplus%' order by logon_time ;
select * from gv$sqltext where sql_id='akrr2ww1ukq5z';
The given queries were used to check if it was using parallelism, but i was unable to find anything.
SELECT QCSID, SID, INST_ID "Inst", SERVER_GROUP "Group", SERVER_SET "Set",
NAME "Stat Name", VALUE
FROM GV$PX_SESSTAT A, V$STATNAME B
WHERE A.STATISTIC# = B.STATISTIC# AND NAME LIKE 'PHYSICAL READS'
AND VALUE > 0 ORDER BY QCSID, QCINST_ID, SERVER_GROUP, SERVER_SET;
SELECT * FROM V$PX_PROCESS;
how can i make sure that, it is using parallelism.
When you create a MAV, you automatically get a hidden column and an index. Here's an example,drop user jon cascade;
grant dba to jon identified by jon;
conn jon/jon
create table emp as select * from scott.emp;
create materialized view mv1 enable query rewrite as
select deptno,sum(sal) from emp group by deptno;
select object_name,object_type from user_objects;
select index_name,column_name from user_ind_columns where table_name='MV1';
select column_name,hidden_column from user_tab_cols where table_name='MV1';
select deptno,"SUM(SAL)",sys_nc00003$ from mv1;
In which condition it is required to rebuild the index and how can identified it?
View 12 Replies View RelatedThe best way to rebuild index and table and also give the reason as why we need to use this method?
View 10 Replies View RelatedWe have separate tablespaces for Tables and Indexes. Also Temp is in different temporary tablespace and UNDO also in UNDO tablespace and Index tablespace contains only Indexes. The tablespace usage for tables is 80% and Index is 91%.There is not enough disk space to allocate for the datafile on our system. I ran a rebuild on one of the Index but now notice the Index tablespace is 98% used soon after the rebuild finished.
How can i free up space for Index tablespace and why does the size of Index tablespace increased after the rebuild.
We met unable to extend index exception.I have executed below mentioned query.
ERROR:ORA-01654: index
(128, tablespace USERS) You can not extend the OMS_SG_IT.TRN_BD_MNTHLY_OCF_SLT_PKC.
QUERY:
select db.FILE_NAME,
db.AUTOEXTENSIBLE,
db.INCREMENT_BY,
db.USER_BLOCKS,
[code]...
RESULT:
/u01/app/oracle/oradata/SCSKTRA/users01.dbf
YES
5
3872
65536
(null)
LOCAL
ANOTHER QUERY:
select tablespace_name,file_name,bytes/1024/1024 from dba_data_files where tablespace_name='USERS';
RESULT:
USERS
/u01/app/oracle/oradata/SCSKTRA/users01.dbf
31.25
Now what i have to do...
How to find which table or Index needs to be reorg..??
IS there any Query!!!.
While creating the index we are getting the error "ORA-00603: ORACLE server session terminated by fatal error".
We have the space in tablespaces and also in the file systesm.
Our database size is 100GB and i removed few records from a table and rebuild the index.The size of Index reduced considerably after Index rebuild but now i see our database size increased to 115GB.I know online rebuild creates second index which is also removed after the build is finished then why the increase in database size?Is there a way so it shows up more space ?
select sum(bytes) from dba_segments where owner='abc' and segment_name='abc_index_1';
8GB
ALTER INDEX abc_index_1 REBUILD ONLINE ;
select sum(bytes) from dba_segments where owner='abc' and segment_name='abc_index_1';
2GB