I Have created a interval partitioned table with local index.But when automatic partitions are created based record insertion, whether local indexes will be created for each newly created partition or not? If created, how to check
Below is the code which I tried
CREATE TABLE interval_date
(
date1 date,
days VARCHAR2(50)
)
PARTITION BY RANGE(date1)
INTERVAL (NUMTODSINTERVAL(45,'DAY'))
[code]....
I have a table which if approc 5GB in size.I am trying to create a partition table from it. I created the new table,but when i am creating local indexes, i am getting an error when i create a unique key. I ll post the creation scripts:
CREATE TABLE A_PT_ORDREG
(
BUS_UNIT VARCHAR2(5) NOT NULL,
ORDER_NO VARCHAR2(15) NOT NULL,
PT_CODE VARCHAR2(15) NOT NULL,
REG_NO VARCHAR2(15) NOT NULL,
AS_APPLICATION VARCHAR2(5) NOT NULL,
[code].....
THE INDEX:
CREATE UNIQUE INDEX PK_A_PT_ORDREG ON A_PT_ORDREG (BUS_UNIT, ORDER_NO, SEQ_NO) local;
I am getting the following error:
ORA-14039: partitioning columns must form a subset of key columns of a UNIQUE index
If a Interval Partitioning can be created on a table for every fortnight ? db version is 11g.
View 3 Replies View RelatedInterval partitioning I keep getting the below error on a table.A more discerning eye is needed
PARTITION DEC_2012 VALUES LESS THAN (TO_DATE('01-01-2013', 'DD-MM-YYYY')),
*
ERROR at line 26:
ORA-14037: partition bound of partition "DEC_2012" is too high
CREATE TABLE STATISTICS_PART
(
ID_KEY NUMBER(10) NOT NULL,
LUD DATE DEFAULT sysdate,
[code]....
Other than the obvious to me, where interval partitioning creates partitions as needed. Is there any performance benefit from using interval partitions vs date range partitions.
One draw back for me is that developers do access the partition name in some of their queries, so if I use date range partitioning this will not break their code. I could not find a way to assign a name to a partition when using intervals, is this always system generated or can this be over-ridden.
I am running Oracle 11.1.0.7 soon to be running on 11.2.0.0
I am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.
note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.
They want data type NOT to be altered.
create table product(
prod_id number,
prod_code varchar2(3),
release_date number)
partition by range(release_date)
interval(NUMTOYMINTERVAL (1,'MONTH'))
(partition p0 values less than (20120101))
11gr2, We need to do partition a existing table of size 20g, But partition key column is NUMBER type and data stored in unix date format.I would like to create a monthly partition table as below. But not able to create.
create table student ( ENTRY_ID number(5,1), NAME varchar2(30 BYTE) ) partition by range ( fun_unix_to_date (ENTRY_ID) ) --> fun_unix_to_date is a customized function to convert unix time stamp to date format.
INTERVAL (100) ( PARTITION CATCH_ALL values LESS THAN (to_date('01-MAR-12','DD-MON-YY')));
ERROR at line 5:ORA-00907: missing right parenthesis
Our organization is attempting to learn more about the partitioning features of Oracle 11g. I've been reading the partitioning manuals, and I have not found a clear answer on this topic, but I suspect I know the answer.
If you create a range partitioned table; using interval partitioning, say something like this:
CREATE table range_parti (
CODE NUMBER(5),
DESCRIPTION VARCHAR2(50),
CREATED_DATE DATE)
PARTITION BY RANGE (created_date)
INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))
(
PARTITION my_parti VALUES LESS THAN (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
);
but you try to insert a null value as the partition key, you get the following error:
SQL> INSERT INTO range_parti VALUES (1,'one',NULL);
INSERT INTO range_parti VALUES (1,'one',NULL)
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
Elapsed: 00:00:00.07
Is there no way to tell it to use a default partition for NULL values? Or specifically designate a partition for NULL values WITHOUT having to manually list out each partition? It seems it works if you don't use the INTERVAL keyword, list out your partitions, and use MAXVALUE. However, our hope to avoid having that as it creates monstrously huge DDL statements for tables that have lots of date ranges, and we will be forced to manually add new partitions each month as data is added/time passes.
It appears from my experience so far, if your column can allow nulls, you cannot use interval range partitioning on that column.
I am using Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production.I have a range partitioned table having lobs as basicfile. Due to storage issue and other business constraints , it is determined not to change existing lobs to securefile.
However ,we want new lobs to be in securefile and alter table to have interval partition+.While researching, I found sql to change lob in range partition to securefile by using
alter table t1 add partition t1_p2 value less than (10000) lob (col3) store as securefile (tablespace tbs_sf1)
What to do similar in case of interval partition.
I have created an Interval Partition Table as show below, Is their any way, i can drop the partition dynamically when i truncate the table as oracle creates them with system generated name? Instead Alter table drop partition !
Create Table Script :
------------------------------------------------------------------------------------------------------------------------------------------------
CREATE TABLE TBL_EMP_SALES
(
EMP_ID NUMBER(38),
EMPNAME VARCHAR2(9),
EMP_SALES_AMOUNT NUMBER(5),
EMP_SALES_DATE DATE,
[Code]....
Insert Script :
------------------------------------------------------------------------------------------------------------------------------------------------
INSERT INTO TBL_EMP_SALES VALUES (1001,'A',50,SYSDATE);
INSERT INTO TBL_EMP_SALES VALUES (1002,'B',100,SYSDATE+1);
INSERT INTO TBL_EMP_SALES VALUES (1003,'C',80,SYSDATE+2);
[Code]....
Partitions Created :
-------------------------------------------------------------------------------------------------------------------------------------------------
select segment_name,partition_name,bytes from user_segments where segment_name = 'TBL_EMP_SALES';
segment_name partition_name bytes
TBL_EMP_SALES P0 8388608
TBL_EMP_SALES SYS_P602 8388608
TBL_EMP_SALES SYS_P603 8388608
[Code]....
I have a huge table (about 60 gb) partition over range. The index on this table is global index created on 4 columns together. I have a query which is running very slowly. The explain plan is showing the use of this global index.Explain plan is not showing pstart and pend because the index is global.
View 6 Replies View RelatedI have a global index and I want to convert it to local index.Is there a way to recreate local index with out dropping the global index.
I can create a local index first and then drop the global index. But is there a way to create it with out dropping the global index, just convert it.
There is a very large fact table that is range partitioned by a column DATE_KEY of type NUMBER(38), such that every hour is a different partition. There is a bitmap index BX$FACT#DATE_KEY on field DATE_KEY, which also is a foreign key referencing DATE_DIM (DATE_KEY). There is a different DATE_KEY for every hour, generated as YYYYMMDDHH24.
When I run
"SELECT * FROM FACT WHERE DATE_KEY >= 2012031207 AND DATE_KEY < 2012031208"
to get all the records for 7 am on March 12th, partition pruning kicks in and sees that only one partition is used. The CBO then decides to do a full scan of the partition. This behavior is correct/desired.
If, however, I run
"SELECT * FROM FACT WHERE DATE_KEY = 2012031207 AND DATE_KEY < 2012031209"
to get all the records for 7 and 8 am, Oracle knows that it will have to scan two partitions. The CBO then decides that using the BX$FACT#DATE_KEY must be a good idea and, instead of doing a full scan of the partitions, does access by local index rowid, which is many times slower.
I think I understand the cause - when more than a single partition is involved, Oracle has to use the global index stats (instead of the local ones, like in the first scenario) and the CBO decides to use it because that the selectivity for the global index is great, when in fact the query will return all the rows for that particular partition (no selectivity).
How to get the CBO to choose a full scan in the second scenario as well? I need to support ad-hoc queries generated by a BI tool, so I cannot add hints to the queries. I also can't get rid of the index on DATE_KEY, because in real life the predicates are on fields of the date dimension, not directly on the key, so I need to join on it.
if i have local index, does query which uses this index always have to scan all partitions?
For example, I have hash-partitioned table on column A. There is local index on column B. I am querying:
select * from my_table where A='ABC' and B>123.
I know that records with A='ABC' are in 2nd partition. Does only 2nd partition of local index will be scanned or all of them must be scanned?
What is the use of Local and Global Partition Index?
View 1 Replies View Related2day i was dropping few unwanted index from the data base, By mistake i removed the local partitioned index , So i want to recreate that index.i create the index, will the partitioned index updates when we add partitioned to the tables.
View 2 Replies View RelatedI have table with 4 partition by range partition. I am loading the table in bulk mode to latest partition. Before I load , I dropped the index and after Load I will be creating index. So when I am dropping index, it is dropping index from all the partitions and when creating the index, I am creating the index for all partitions. When I am creating index using local, it is telling you have to create local index for all partitions at the same time. because of that I have to drop and recreate all indexes again. Again I have to gather stats for whole table .
I was thinking we can build index for one partition and index should remain as is for old partitions If this is not the case, how do I plan my load for a partitioned table using bulk mode to latest partition.
how data is distributed on a local non prefixed index.Let's say I have a table calles SALES and it holds data for the last year partitioned by a date column called month (So that's 12 partitions, one for each month).Now i'm creating the following index: CREATE INDEX TESTIDX ON SALES(salesman_id) local; What will happen is that I'll have 12 partitions on the index but to which partitions in the table are they referencing ?
View 1 Replies View RelatedI'm trying to split a table partition.
whether the below syntax are correct.
If local index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
update indexes;
(per http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1401247200346349807)
=================================================================
If Global index used
ALTER TABLE SNYT.PART_ESTD
SPLIT PARTITION ESTD_M13_S22 AT ('ESTD', 13, '22')
INTO (PARTITION ESTD_M13_S21, PARTITION ESTD_M13_S22)
UPDATE GLOBAL INDEXES;
Version Info: 11.2 on Solaris 10
I have a partitioned table like below. I want to create a B-Tree index on SALES_RGN column which is neither the part of Primary key or the Partitioned key. Should I create this index as local or Global ?
CREATE TABLE sales_dtl
(
txn_id number (9),
salesman_id number(5),
salesman_name varchar2(30),
sales_rgn varchar2(10), -----------------------------> This column needs to be indexed
sales_amount number(10),
sales_date date,
constraint pk_sales_dtl primary key (txn_id)
[code]....
I am rebuilding some UNUSABLE local index partitions on Oracle 8.1.7.4.0 (64bit) database . The platform is a HPUX machine.
The DDL of the partition table/indexes:
=========================
CREATE TABLE TESTME
( INST_NO CHAR(3) NOT NULL,
ACCT_NO CHAR(16) NOT NULL,
REC_NO CHAR(9) NOT NULL,
TRAN_TYPE CHAR(2) DEFAULT ' ',
STAT CHAR(2) DEFAULT ' ',
[code]...
SNRCTL> stat LISTENER
Connecting to (DESCRIPTION=(ADDRESS=(PROTOCOL=IPC)(KEY=LISTENER)))
STATUS of the LISTENER
------------------------
Alias LISTENER
Version TNSLSNR for IBM/AIX RISC System/6000: Version 11.2.0.1.0 - Production
Start Date 19-JAN-2013 00:50:10
Uptime 0 days 0 hr. 29 min. 51 sec
Trace Level off
Security ON: Local OS Authentication
[code]....
In every oracle documentation for e.g:11.2 Scan and Node TNS Listener Setup Examples [ID 1070607.1] we found the local listener status showing both local-ip and vip. Why is not showing in our case?
I have problem to transfer data in non partitioning table to partitioning table.
I have non partitioning table and i create new table partitioning that have same column and type like in non partitioning. So how can i transfer data from table in non partitioning to table in partitioning?
I am on 11.2.0.3 Enterprise Edition. We are using the new feature "Composite Domain Index" for a Domain index on a very large table (>250.000.000 rows). It really works with mixed queries. We added two number columns using FILTER BY.We have lots of DML on this table. Therefore, we are executing synchronize and optimize once the week. The synch behaves pretty normal. But "optimize_index" takes a very very long time to complete. I have switsched on 'logging' for the optimize process. The $I table takes some time but is finished normally. But the optimization of the $S table (that is the table created for the CDI feature) is running over 12 hours now - and far from being finished. From the logfile, I can see that it optimizes 1000 rows every 20 minutes. Here is the output of the logfile:
Oracle Text, 11.2.0.3.0
14:33:05 06/26/12 begin logging
14:33:05 06/26/12 event
14:33:05 06/26/12 process $N for optimize: SEQDEV.GEN_GES_DESCRIPTION_CTX_I
14:33:16 06/26/12
14:33:16 06/26/12
[code]....
I haven't found a recommendation from Oracle not to use "optimize_index" for Domain Indexes with CDI. But in my case, it would be much faster just to drop and recreate the Domain Index in question.
I want to practice partitioning, I have schema which has sales table but that is already partitioned. I want to know if there are some schema available for download which has non partitioned tables and records more than 10000.
View 8 Replies View RelatedHow to partition a table which is already having data.I have a STUDENT table along with following fields which is having million of rows.
studentid name class Gender
Now I want to partition this table based on gender MALE and FEMALE.
I have a partitioned table with 1 lakh records
if i disable the partition feature im my database will it affect my table data.
I have a problem, we have some datas in a table for example 7500 rows in a table name called table1 upto 11:am today. but after 11:25 am i have only 5500 rows. in that table.
the table can be accessed by many users here. we dont know when the delete happended in that table. is there any query to find the transaction log of this particular table.
the deletion should be happended between 11:00 am to 11:30 am. but we have retrieved the data using timestamp query. but we need to know when the query issued and by which user the query has been issued.
How to set time interval in schedule job i need five minutes interval..
View 5 Replies View RelatedI have created a job using DBMS_SCHEDULER and I want it to run every 30 seconds:
begin
dbms_scheduler.create_job(job_name => 'jobu',
job_type => 'PLSQL_BLOCK',
[Code]....
My question is how can I take the value 30 from a configuration table? Let's say I have a query like select value from config_table where property = 'job_interval' that returns the number 30. How can I set this value to be the repeat interval for my job?