PL/SQL :: Dropping Partition Dynamically In Interval Partitioning
Aug 22, 2012
I have created an Interval Partition Table as show below, Is their any way, i can drop the partition dynamically when i truncate the table as oracle creates them with system generated name? Instead Alter table drop partition !
Create Table Script :
------------------------------------------------------------------------------------------------------------------------------------------------
CREATE TABLE TBL_EMP_SALES
(
EMP_ID NUMBER(38),
EMPNAME VARCHAR2(9),
EMP_SALES_AMOUNT NUMBER(5),
EMP_SALES_DATE DATE,
[Code]....
Insert Script :
------------------------------------------------------------------------------------------------------------------------------------------------
INSERT INTO TBL_EMP_SALES VALUES (1001,'A',50,SYSDATE);
INSERT INTO TBL_EMP_SALES VALUES (1002,'B',100,SYSDATE+1);
INSERT INTO TBL_EMP_SALES VALUES (1003,'C',80,SYSDATE+2);
[Code]....
Partitions Created :
-------------------------------------------------------------------------------------------------------------------------------------------------
select segment_name,partition_name,bytes from user_segments where segment_name = 'TBL_EMP_SALES';
segment_name partition_name bytes
TBL_EMP_SALES P0 8388608
TBL_EMP_SALES SYS_P602 8388608
TBL_EMP_SALES SYS_P603 8388608
[Code]....
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May 2, 2013
I am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.
note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.
They want data type NOT to be altered.
create table product(
prod_id number,
prod_code varchar2(3),
release_date number)
partition by range(release_date)
interval(NUMTOYMINTERVAL (1,'MONTH'))
(partition p0 values less than (20120101))
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May 28, 2010
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
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Mar 28, 2013
If a Interval Partitioning can be created on a table for every fortnight ? db version is 11g.
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Jan 7, 2013
Interval partitioning I keep getting the below error on a table.A more discerning eye is needed
PARTITION DEC_2012 VALUES LESS THAN (TO_DATE('01-01-2013', 'DD-MM-YYYY')),
*
ERROR at line 26:
ORA-14037: partition bound of partition "DEC_2012" is too high
CREATE TABLE STATISTICS_PART
(
ID_KEY NUMBER(10) NOT NULL,
LUD DATE DEFAULT sysdate,
[code]....
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Dec 16, 2010
Other than the obvious to me, where interval partitioning creates partitions as needed. Is there any performance benefit from using interval partitions vs date range partitions.
One draw back for me is that developers do access the partition name in some of their queries, so if I use date range partitioning this will not break their code. I could not find a way to assign a name to a partition when using intervals, is this always system generated or can this be over-ridden.
I am running Oracle 11.1.0.7 soon to be running on 11.2.0.0
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Nov 25, 2011
I Have created a interval partitioned table with local index.But when automatic partitions are created based record insertion, whether local indexes will be created for each newly created partition or not? If created, how to check
Below is the code which I tried
CREATE TABLE interval_date
(
date1 date,
days VARCHAR2(50)
)
PARTITION BY RANGE(date1)
INTERVAL (NUMTODSINTERVAL(45,'DAY'))
[code]....
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Sep 19, 2013
11gr2, We need to do partition a existing table of size 20g, But partition key column is NUMBER type and data stored in unix date format.I would like to create a monthly partition table as below. But not able to create.
create table student ( ENTRY_ID number(5,1), NAME varchar2(30 BYTE) ) partition by range ( fun_unix_to_date (ENTRY_ID) ) --> fun_unix_to_date is a customized function to convert unix time stamp to date format.
INTERVAL (100) ( PARTITION CATCH_ALL values LESS THAN (to_date('01-MAR-12','DD-MON-YY')));
ERROR at line 5:ORA-00907: missing right parenthesis
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Mar 12, 2010
Our organization is attempting to learn more about the partitioning features of Oracle 11g. I've been reading the partitioning manuals, and I have not found a clear answer on this topic, but I suspect I know the answer.
If you create a range partitioned table; using interval partitioning, say something like this:
CREATE table range_parti (
CODE NUMBER(5),
DESCRIPTION VARCHAR2(50),
CREATED_DATE DATE)
PARTITION BY RANGE (created_date)
INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))
(
PARTITION my_parti VALUES LESS THAN (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
);
but you try to insert a null value as the partition key, you get the following error:
SQL> INSERT INTO range_parti VALUES (1,'one',NULL);
INSERT INTO range_parti VALUES (1,'one',NULL)
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
Elapsed: 00:00:00.07
Is there no way to tell it to use a default partition for NULL values? Or specifically designate a partition for NULL values WITHOUT having to manually list out each partition? It seems it works if you don't use the INTERVAL keyword, list out your partitions, and use MAXVALUE. However, our hope to avoid having that as it creates monstrously huge DDL statements for tables that have lots of date ranges, and we will be forced to manually add new partitions each month as data is added/time passes.
It appears from my experience so far, if your column can allow nulls, you cannot use interval range partitioning on that column.
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Oct 19, 2012
I am using Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production.I have a range partitioned table having lobs as basicfile. Due to storage issue and other business constraints , it is determined not to change existing lobs to securefile.
However ,we want new lobs to be in securefile and alter table to have interval partition+.While researching, I found sql to change lob in range partition to securefile by using
alter table t1 add partition t1_p2 value less than (10000) lob (col3) store as securefile (tablespace tbs_sf1)
What to do similar in case of interval partition.
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Jul 7, 2012
Do i have to create indexes again if i drop a partition on a table?
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Jan 21, 2003
I have been trying to drop an unused column in a partitioned table, and the number of records stored in this unused column was very high. I kept on running into errors as follows:
ORA-01562: failed to extend rollback segment number 10
ORA-01650: unable to extend rollback segment R09 by 256 in tablespace RBS
I tried to "SET TRANSACTION USE ROLLBACK SEGMENT <name>" with a larger rollback segment, but it still did not work. Can I drop the "unused column" from each partition instead?
How to apply that? Or, what are my options besides increasing the size of the rollback segment?
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Dec 12, 2012
We have a table like below.
Create table Item_max
(
CCN varchar2(10),
Run_date date,
Item varchar2(10),
status varchar2(1)
[code].....
Currently we are inserting the cycle data for all Items every day into above table for all the CCN's.Currently there are 100k Items in our DB and gets inserted every day into above table with Different Rundates for all CCN's.
We need the above data for 6months and we would like to purge the data based on the RunDates.
We thought of creating a Partition on CCN and Interval Subpartition on Run_date with Interval of every 1 day but I could get any materials on the net to have List-Interval partitioning in Oracle 11G.
Also List - Range partitioning doesnt work here as the Dynamic partition used(using Maxused) will contain the data for all Run_dates instead of particular rundate.
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Sep 19, 2012
I have this requirement to pull the ACTIVE days that a participant holds true in a given month for a specific position he/she holds.The three date ranges here are: LOA dates(leave of absence), XFER dates(TRANSFER in/out of the position),Quality compliance(QUAL start/end dates).So,
INACTIVE DAYS = [(LOA + XFER + WW) - OVERLAPPING DAYS OF (LOA+XFER+QUAL)]
CREATE TABLE PAYEES
(
RUN_PERIOD DATE NOT NULL,
PAYEEID VARCHAR2(20 BYTE) NOT NULL,
LOA_START_DATE DATE,
LOA_END_DATE DATE,
[code]....
I am able to pull out the no of days on a individual basis(count of days for Xfer/LOA/Qual) but I am really not sure as to how should i go about determining the overlapping days between 3 date ranges to determine the ACTIVE/INactive days.
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Jan 23, 2011
I recently started working with legacy code and noticed that some huge tables (5 years worth of data, don't have more details on me right now but can post later if needed) are partitioned based on time sequence number column while majority of queries are done based on time (different column). Queries performance is degrading and I'd like to try to modify partitioning and run some tests to evaluate performance improvement.
My only concern is with so much live data I have to come up with solution on how to switch partitioning with the least impact on applications running 24 x 7. Something you have done in the same situation and it worked?
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Jun 6, 2012
We are using oracle 10g. with our code, Currently Oracle partitions are size the same way, each partition is using 10MB for data and 12MB for indexes (with the 6 default indexes); even of very few records are written in the partition.
We create partitions in advance as a part of nightly job with 10 minutes duration.Can some intelligence can be added where based on statistics we can decide the size of partition dynamically? Lot of space is getting wasted because of this reason.
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Apr 4, 2013
I have problem to transfer data in non partitioning table to partitioning table.
I have non partitioning table and i create new table partitioning that have same column and type like in non partitioning. So how can i transfer data from table in non partitioning to table in partitioning?
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Mar 17, 2011
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
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Jun 26, 2010
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
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Apr 3, 2013
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
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Jan 2, 2013
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
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Sep 22, 2011
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
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Jun 14, 2011
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
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Mar 3, 2011
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
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Jul 10, 2012
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
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Apr 12, 2010
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
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Mar 28, 2013
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
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Apr 13, 2008
I am unable to drop a snapshot , i tried even from sys, it is giving the following error,
drop snapshot adm.dup_resource_status
9:46:29 ORA-08103: object no longer exists
but, when i try to create a new snapshot with the same name
CREATE MATERIALIZED VIEW ADM.DUP_RESOURCE_STATUS
..............
I get
ORA-12006: a materialized view with the same user.name already exists.
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Nov 2, 2012
ALTER TABLE table_name DROP PARTITION (partition_1000);
ALTER TABLE table_name DROP PARTITION (partition_1001);
...
.........
......
ALTER TABLE table_name DROP PARTITION(partition_1320);(b
it is a delta partition,so trying to remove 320 partitions at once in pl/sql developer for a single table.
Like this i have to remove for more then 15 tables one by one, will this effect the database like filling up the archinve log destination by writing more logs.
kind of problems that i am going to face , as i am doing it on the production box directly.
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Jun 9, 2010
Would like to know:
When you drop a user profile, Oracle automatically assigns the default profile to that user - knowing that no other profile has been assigned to that user.
Does this happen in the same session or after a restart?
A user must have a profile at all times, so if a profile is dropped, then the default profile should be assigned in the same session because if not, then during that session the user has no assigned profile which shouldn't happen?
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