PL/SQL :: Dropping Partition Dynamically In Interval Partitioning

Aug 22, 2012

I have created an Interval Partition Table as show below, Is their any way, i can drop the partition dynamically when i truncate the table as oracle creates them with system generated name? Instead Alter table drop partition !

Create Table Script :
------------------------------------------------------------------------------------------------------------------------------------------------

CREATE TABLE TBL_EMP_SALES
(
EMP_ID NUMBER(38),
EMPNAME VARCHAR2(9),
EMP_SALES_AMOUNT NUMBER(5),
EMP_SALES_DATE DATE,

[Code]....

Insert Script :
------------------------------------------------------------------------------------------------------------------------------------------------
INSERT INTO TBL_EMP_SALES VALUES (1001,'A',50,SYSDATE);
INSERT INTO TBL_EMP_SALES VALUES (1002,'B',100,SYSDATE+1);
INSERT INTO TBL_EMP_SALES VALUES (1003,'C',80,SYSDATE+2);

[Code]....

Partitions Created :
-------------------------------------------------------------------------------------------------------------------------------------------------
select segment_name,partition_name,bytes from user_segments where segment_name = 'TBL_EMP_SALES';
segment_name partition_name bytes

TBL_EMP_SALES     P0     8388608
TBL_EMP_SALES     SYS_P602     8388608
TBL_EMP_SALES     SYS_P603     8388608

[Code]....

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PL/SQL :: Range Partition Using Interval Partitioning?

May 2, 2013

I am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.

note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.

They want data type NOT to be altered.

create table product(
prod_id number,
prod_code varchar2(3),
release_date number)
partition by range(release_date)
interval(NUMTOYMINTERVAL (1,'MONTH'))
(partition p0 values less than (20120101))

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May 28, 2010

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Jan 7, 2013

Interval partitioning I keep getting the below error on a table.A more discerning eye is needed

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*
ERROR at line 26:
ORA-14037: partition bound of partition "DEC_2012" is too high

CREATE TABLE STATISTICS_PART
(
ID_KEY NUMBER(10) NOT NULL,
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[code]....

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Dec 16, 2010

Other than the obvious to me, where interval partitioning creates partitions as needed. Is there any performance benefit from using interval partitions vs date range partitions.

One draw back for me is that developers do access the partition name in some of their queries, so if I use date range partitioning this will not break their code. I could not find a way to assign a name to a partition when using intervals, is this always system generated or can this be over-ridden.

I am running Oracle 11.1.0.7 soon to be running on 11.2.0.0

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Nov 25, 2011

I Have created a interval partitioned table with local index.But when automatic partitions are created based record insertion, whether local indexes will be created for each newly created partition or not? If created, how to check

Below is the code which I tried

CREATE TABLE interval_date
(
date1 date,
days VARCHAR2(50)
)
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[code]....

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Sep 19, 2013

11gr2, We need to do partition a existing table of size 20g, But partition key column is NUMBER type and data stored in unix date format.I would like to create a monthly partition table as below. But not able to create.

create table student (  ENTRY_ID number(5,1),  NAME varchar2(30 BYTE) )  partition by range ( fun_unix_to_date (ENTRY_ID) ) --> fun_unix_to_date is a customized function to convert unix time stamp to date format.   

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ERROR at line 5:ORA-00907: missing right parenthesis

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SQL & PL/SQL :: Interval Partitioning And NULL Column Values

Mar 12, 2010

Our organization is attempting to learn more about the partitioning features of Oracle 11g. I've been reading the partitioning manuals, and I have not found a clear answer on this topic, but I suspect I know the answer.

If you create a range partitioned table; using interval partitioning, say something like this:

CREATE table range_parti (
CODE NUMBER(5),
DESCRIPTION VARCHAR2(50),
CREATED_DATE DATE)
PARTITION BY RANGE (created_date)
INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))
(
PARTITION my_parti VALUES LESS THAN (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
);

but you try to insert a null value as the partition key, you get the following error:

SQL> INSERT INTO range_parti VALUES (1,'one',NULL);
INSERT INTO range_parti VALUES (1,'one',NULL)
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
Elapsed: 00:00:00.07

Is there no way to tell it to use a default partition for NULL values? Or specifically designate a partition for NULL values WITHOUT having to manually list out each partition? It seems it works if you don't use the INTERVAL keyword, list out your partitions, and use MAXVALUE. However, our hope to avoid having that as it creates monstrously huge DDL statements for tables that have lots of date ranges, and we will be forced to manually add new partitions each month as data is added/time passes.

It appears from my experience so far, if your column can allow nulls, you cannot use interval range partitioning on that column.

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Oct 19, 2012

I am using Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production.I have a range partitioned table having lobs as basicfile. Due to storage issue and other business constraints , it is determined not to change existing lobs to securefile.

However ,we want new lobs to be in securefile and alter table to have  interval partition+.While researching, I found sql to change lob in range partition to securefile by using

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What to do similar  in case of interval partition.

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Jul 7, 2012

Do i have to create indexes again if i drop a partition on a table?

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Jan 21, 2003

I have been trying to drop an unused column in a partitioned table, and the number of records stored in this unused column was very high. I kept on running into errors as follows:

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How to apply that? Or, what are my options besides increasing the size of the rollback segment?

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Dec 12, 2012

We have a table like below.

Create table Item_max
(
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[code].....

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Sep 19, 2012

I have this requirement to pull the ACTIVE days that a participant holds true in a given month for a specific position he/she holds.The three date ranges here are: LOA dates(leave of absence), XFER dates(TRANSFER in/out of the position),Quality compliance(QUAL start/end dates).So,

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(
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LOA_START_DATE DATE,
LOA_END_DATE DATE,
[code]....

I am able to pull out the no of days on a individual basis(count of days for Xfer/LOA/Qual) but I am really not sure as to how should i go about determining the overlapping days between 3 date ranges to determine the ACTIVE/INactive days.

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Apr 4, 2013

I have problem to transfer data in non partitioning table to partitioning table.

I have non partitioning table and i create new table partitioning that have same column and type like in non partitioning. So how can i transfer data from table in non partitioning to table in partitioning?

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Mar 17, 2011

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Jun 26, 2010

I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk

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Apr 3, 2013

At present we have a non partitioned table.

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Jan 2, 2013

Can I add range sub partition to a hash partition table. Example like this.

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Partitions 3
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Sep 22, 2011

I have two tables Activity and Activity1.

Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
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Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong

CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),

[code]....

Insert Statement

insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,

[code]....

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Jun 14, 2011

i want to create a new partition for version 2

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create table test
(
name varchar2(100),
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)

[Code]....

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Jul 10, 2012

I have two tables in which one is partitioned table with the following details.

CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),

[code].....

When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error

SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition

AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.

ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198

[code].....

I also tried to upload the same data using sqlldr.

sqlldr log file contents is as follows:

Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37

[code].....

So some sqlldr bad file contents is as follows.

100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,

[code].....

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table:
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901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null

For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set

studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5

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TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID"    NUMBER,
"MONTH_ID"      NUMBER,
"GROUP_ID"      NUMBER,
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..............
I get
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...
.........
......
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When you drop a user profile, Oracle automatically assigns the default profile to that user - knowing that no other profile has been assigned to that user.
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