i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 RepliesI Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies View RelatedAt present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
Do i have to create indexes again if i drop a partition on a table?
View 6 Replies View RelatedI have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
I have been trying to drop an unused column in a partitioned table, and the number of records stored in this unused column was very high. I kept on running into errors as follows:
ORA-01562: failed to extend rollback segment number 10
ORA-01650: unable to extend rollback segment R09 by 256 in tablespace RBS
I tried to "SET TRANSACTION USE ROLLBACK SEGMENT <name>" with a larger rollback segment, but it still did not work. Can I drop the "unused column" from each partition instead?
How to apply that? Or, what are my options besides increasing the size of the rollback segment?
I have created an Interval Partition Table as show below, Is their any way, i can drop the partition dynamically when i truncate the table as oracle creates them with system generated name? Instead Alter table drop partition !
Create Table Script :
------------------------------------------------------------------------------------------------------------------------------------------------
CREATE TABLE TBL_EMP_SALES
(
EMP_ID NUMBER(38),
EMPNAME VARCHAR2(9),
EMP_SALES_AMOUNT NUMBER(5),
EMP_SALES_DATE DATE,
[Code]....
Insert Script :
------------------------------------------------------------------------------------------------------------------------------------------------
INSERT INTO TBL_EMP_SALES VALUES (1001,'A',50,SYSDATE);
INSERT INTO TBL_EMP_SALES VALUES (1002,'B',100,SYSDATE+1);
INSERT INTO TBL_EMP_SALES VALUES (1003,'C',80,SYSDATE+2);
[Code]....
Partitions Created :
-------------------------------------------------------------------------------------------------------------------------------------------------
select segment_name,partition_name,bytes from user_segments where segment_name = 'TBL_EMP_SALES';
segment_name partition_name bytes
TBL_EMP_SALES P0 8388608
TBL_EMP_SALES SYS_P602 8388608
TBL_EMP_SALES SYS_P603 8388608
[Code]....
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies View RelatedI have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
In my prod table few partition need to be added.
I tried below both syntax, but I am getting error
1)
Alter table STS.DNA_ACCESSION add PARTITION DNA_ACC_P143 VALUES LESS THAN (286000000);
ORA-14074: partition bound must collate higher than that of the last partition
2)
ALTER TABLE STS_RO.DNA_ACCESSION
SPLIT PARTITION DNA_ACC_P999 AT VALUES LESS THAN (286000000)
INTO (PARTITION DNA_ACC_P143,
[Code]....
I have a table partitioned by Range and subparitioned by hash.
i am issuing the following query .Bcos of security purposes i cannot post the full query.
Select <most of the columns>
FROM qosTesthr PARTITION(PARTITION_ON_2011_11_17)
WHERE starttime BETWEEN to_date('1111170000', 'yymmddHH24mi') AND to_date('1111172359', 'yymmddHH24mi')
Explain plan is
---------------------------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop | TQ |IN-OUT| PQ Distrib
---------------------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 826K| 171M| 2330 (4)| 00:00:28 | | | | | |
|* 1 | PX COORDINATOR | | | | | | | | | | |
| 2 | PX SEND QC (RANDOM) | :TQ10000 | 826K| 171M| 2330 (4)| 00:00:28 | | | Q1,00 | P->S | QC (RAND)
[code]...
When i use INDEX_SS hint in the query then only the partition scan is happening.
---------------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
---------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 826K| 171M| 810K (1)| 02:42:06 | | |
|* 1 | FILTER | | | | | | | |
[code]...
Performance while using the index is very very slow.Is there any way without using the index and just the partition full scan can be forced by using some hint..
I have to create partition on 1 table where i have date field and id.
i want to create range parttion for both the column.
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies View RelatedI want to ask whether I can create range partition of like 10 minutes? Like I have data of 1 hour and I want to make 10 partition?
View 12 Replies View RelatedI am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.
note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.
They want data type NOT to be altered.
create table product(
prod_id number,
prod_code varchar2(3),
release_date number)
partition by range(release_date)
interval(NUMTOYMINTERVAL (1,'MONTH'))
(partition p0 values less than (20120101))
Script to add range partition automatically. This script should be running every month and add the partitions for next 3 months
View 3 Replies View RelatedCan i partition by list on multiple columns? i am trying the following code, and it is returning an error. Is there a way round this?
CREATE TABLE
(...)
PARTITION BY LIST (col1)
SUBPARTITION BY LIST (col2)
SUBPARTITION TEMPLATE (
SUBPARTITION DETAIL VALUES ('DETAIL')
SUBPARTITION ROLLUP VALUES ('ROLLUP'))
(
PARTITION RT VALUES('RT')
)
We have a table like below.
Create table Item_max
(
CCN varchar2(10),
Run_date date,
Item varchar2(10),
status varchar2(1)
[code].....
Currently we are inserting the cycle data for all Items every day into above table for all the CCN's.Currently there are 100k Items in our DB and gets inserted every day into above table with Different Rundates for all CCN's.
We need the above data for 6months and we would like to purge the data based on the RunDates.
We thought of creating a Partition on CCN and Interval Subpartition on Run_date with Interval of every 1 day but I could get any materials on the net to have List-Interval partitioning in Oracle 11G.
Also List - Range partitioning doesnt work here as the Dynamic partition used(using Maxused) will contain the data for all Run_dates instead of particular rundate.
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
As per Article mentioned in Oracle Base,I have converted non-partitioned table (1 million data) into range-partition table,but,I don't see performance improvement in explain .
View 9 Replies View RelatedI have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
View 8 Replies View RelatedI am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
We have a table which is already partitioned by list and now we would like to add a subpartition.
Create table Item_mst
(
ccn varchar2(10),
Flag varchar2(1),
Item varchar2(10),
status varchar2(1)
)
[Code]..
Now I could like to alter the above table for adding a new subpartition on each partition on status.
ALTER TABLE Item_mst
MODIFY PARTITION Item_mst_Test
ADD SUBPARTITION Item_mst_Test_A VALUES ('A');
Above alter gives ORA-14253: table is not partitioned by composite range method.
However dropping and recreating the table with subpartitions is working fine.
But Dropping and recreating the table in production is very cumbersome as it has huge data and many indices.
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
View 1 Replies View Related