I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies View RelatedAt present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
I have to create partition on 1 table where i have date field and id.
i want to create range parttion for both the column.
I want to ask whether I can create range partition of like 10 minutes? Like I have data of 1 hour and I want to make 10 partition?
View 12 Replies View RelatedCan I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
We have a table which is already partitioned by list and now we would like to add a subpartition.
Create table Item_mst
(
ccn varchar2(10),
Flag varchar2(1),
Item varchar2(10),
status varchar2(1)
)
[Code]..
Now I could like to alter the above table for adding a new subpartition on each partition on status.
ALTER TABLE Item_mst
MODIFY PARTITION Item_mst_Test
ADD SUBPARTITION Item_mst_Test_A VALUES ('A');
Above alter gives ORA-14253: table is not partitioned by composite range method.
However dropping and recreating the table with subpartitions is working fine.
But Dropping and recreating the table in production is very cumbersome as it has huge data and many indices.
In my prod table few partition need to be added.
I tried below both syntax, but I am getting error
1)
Alter table STS.DNA_ACCESSION add PARTITION DNA_ACC_P143 VALUES LESS THAN (286000000);
ORA-14074: partition bound must collate higher than that of the last partition
2)
ALTER TABLE STS_RO.DNA_ACCESSION
SPLIT PARTITION DNA_ACC_P999 AT VALUES LESS THAN (286000000)
INTO (PARTITION DNA_ACC_P143,
[Code]....
I have a table partitioned by Range and subparitioned by hash.
i am issuing the following query .Bcos of security purposes i cannot post the full query.
Select <most of the columns>
FROM qosTesthr PARTITION(PARTITION_ON_2011_11_17)
WHERE starttime BETWEEN to_date('1111170000', 'yymmddHH24mi') AND to_date('1111172359', 'yymmddHH24mi')
Explain plan is
---------------------------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop | TQ |IN-OUT| PQ Distrib
---------------------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 826K| 171M| 2330 (4)| 00:00:28 | | | | | |
|* 1 | PX COORDINATOR | | | | | | | | | | |
| 2 | PX SEND QC (RANDOM) | :TQ10000 | 826K| 171M| 2330 (4)| 00:00:28 | | | Q1,00 | P->S | QC (RAND)
[code]...
When i use INDEX_SS hint in the query then only the partition scan is happening.
---------------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
---------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 826K| 171M| 810K (1)| 02:42:06 | | |
|* 1 | FILTER | | | | | | | |
[code]...
Performance while using the index is very very slow.Is there any way without using the index and just the partition full scan can be forced by using some hint..
I am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.
note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.
They want data type NOT to be altered.
create table product(
prod_id number,
prod_code varchar2(3),
release_date number)
partition by range(release_date)
interval(NUMTOYMINTERVAL (1,'MONTH'))
(partition p0 values less than (20120101))
Script to add range partition automatically. This script should be running every month and add the partitions for next 3 months
View 3 Replies View RelatedCan i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
View 1 Replies View RelatedAs per Article mentioned in Oracle Base,I have converted non-partitioned table (1 million data) into range-partition table,but,I don't see performance improvement in explain .
View 9 Replies View RelatedI have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
Can i partition by list on multiple columns? i am trying the following code, and it is returning an error. Is there a way round this?
CREATE TABLE
(...)
PARTITION BY LIST (col1)
SUBPARTITION BY LIST (col2)
SUBPARTITION TEMPLATE (
SUBPARTITION DETAIL VALUES ('DETAIL')
SUBPARTITION ROLLUP VALUES ('ROLLUP'))
(
PARTITION RT VALUES('RT')
)
We have a table like below.
Create table Item_max
(
CCN varchar2(10),
Run_date date,
Item varchar2(10),
status varchar2(1)
[code].....
Currently we are inserting the cycle data for all Items every day into above table for all the CCN's.Currently there are 100k Items in our DB and gets inserted every day into above table with Different Rundates for all CCN's.
We need the above data for 6months and we would like to purge the data based on the RunDates.
We thought of creating a Partition on CCN and Interval Subpartition on Run_date with Interval of every 1 day but I could get any materials on the net to have List-Interval partitioning in Oracle 11G.
Also List - Range partitioning doesnt work here as the Dynamic partition used(using Maxused) will contain the data for all Run_dates instead of particular rundate.
How can we partition a table based on date if it does not have a date column.
Actually I have to compare two tables on daily basis and fetch few rows from those two tables and enter it to a third table.But both these tables does not have a date column.
I am confused if i need to alter those tables and add date column or if there is some way in which i can compare the data from the two tables for that particular day only and not the whole table data.
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies View RelatedI have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
I have table and it will contain huge data, so we have implemented as partitioned table. Every day when we load data into table there will be one partition created by the ETL Process by default with the Date Column(day wise). Now we may receive data for the previous days as well(Date column in table will have the date associated to the Data). No i would like the data should be inserted into partition which assocites to its own date.
View 5 Replies View RelatedHow to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies View RelatedWe have fact tables partitioned based on week.
We receive point of sale data on daily basis .
Some times we will receive data for previous week also.
In current system , we are analyzing only one partition(current partition).
Now , we want to analyze all old partitions also based on incoming old trading date.
how can i approach to find partitions for old data (trading_date s)
I plan to create a copy of original partition table as below in source database DB1.
create table tblname as select * from sourcetab;
The purpose i am creating copy of original tables is i want to have same partition tables with data in target database DB2 (where the partition feature is diabled).
So i am creating copy of original partition tables ,will then create dump of duplicate tables using export method and then load the dump into target database using import.
Both source and target database are in different servers. Partition is disabled in target database. Partition table size is 2GB and it has 5 partitions P1,P2,P3,P4,P5 .Each partition is of size 100 MB. Count of partition table is 15805412
1.My question is would there be any problem while loading dump into target database (where the partition feature is not enabled)?
2.Is it feasible to create a copy of partition tables using below statements in same database ?
create table tblname as select * from sourcetab;
I need to create partition on the non partition table without dropping a table.
Range partition on stage tables and hash partition on fact tables.
I have an IOT table with partitioned on list. I have p1,p2 and p3 partitions. Now I would like to create a bitmap index on partition key.
I gave ALTER TABLE .. MOVE MAPPING TABLE;
But getting the below error,
ORA-28660: Partitioned Index-Organized table may not be Moved as a whole.
Is there any rule in documentation, when create partition index? For tables, it is said to partition when table is greater than 2GB, but what about index? WHat size it should have to partition?
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