We want to find out difference of data for some tables between current day & previous day. We can use query with minus operation but it will take lot of time since table size is in range from 200 to 500 GB. We have to do this exercise every day.
View 5 RepliesHow to find the sid from v$session of my current session.
I want to ask:
Let say I have open 10 TOAD session and only in one toad session i have fired a sql query ( the rest 9 session are just blank), then the rest 9 status are in active status. Now, how i can figure out which sid ( from v$session ) belongs to which session as all the 9 session having nothing to run.
Quote: My main intention is to find out the current session sid as soon as it make connection with DB.
What is the difference between the following . In my schema all are giving the same results with some different format
SQL> SELECT sysdate , current_date , current_timestamp , localtimestamp from dual;
SYSDATE CURRENT_DATE CURRENT_TIMESTAMP LOCALTIMESTAMP
----------- ------------ ------------------------------------------------- -------------------------------------------------
5/30/2012 8 5/30/2012 8: 30-MAY-12 08.27.22.037703 AM -04:00 30-MAY-12 08.27.22.037703 AM
We have employee salary table which will have salary of an employee on daily basis (only working days). Below is the table structure:
CODEemp_salary
----------
emp_id NUMBER(15) NOT NULL
effective_date DATE NOT NULL
salary NUMBER(15) NOT NULL
Primary key - emp_id, effective_date..This table is yearly partitioned...I have to find out how long the salary is not changed for an employee from given date, and last salary. I am using below query to do this:
CODEWITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]....
For emp_id 1, if we ran this query for 10/31/2011, then it has to compare the 10/31 salary with 10/29 and do the same until the salary mismatches. In this case, salary salary mismatch occurs on 10/20, so the stale salary period is from 10/31 to 10/21 which is 7 days.Below query will give that result:
CODE
WITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]...
I am trying to set the min date if there is no gap between dates.compare previous date2 value with current date1,if they are same then my new date will be min(date1).
source data
date1 iddate2 new_date
1/2/20111234/2/2011
4/2/20111237/2/2011
7/2/201112310/2/2011
10/2/20111231/2/2012
1/2/20121234/2/2012
4/2/20121237/2/2012
12/17/20121233/17/2013
3/17/20131236/17/2013
and I am expecting the out put like this
date1 id date2 new_date
1/2/20111234/2/20111/2/2011
4/2/20111237/2/20111/2/2011
7/2/201112310/2/20111/2/2011
10/2/20111231/2/20121/2/2011
1/2/20121234/2/20121/2/2011
4/2/20121237/2/20121/2/2011
12/17/20121233/17/201312/17/2012
3/17/20131236/17/201312/17/2012
how to achieve this with SQL
I need to update the current column with sum of the previous column values. Following are the creation scripts
DROP TABLE TEST_LOG;
CREATE TABLE TEST_LOG
(
[Code]....
Above query is working fine to retrieve the previous column values.But when we are updating the SUM_PRE_COLS column with those values it's not working fine.
I tried by using the following query
UPDATE TEST_LOG T SET SUM_PRE_COLS =
( SELECT LAG(T2.KEY0, 1, 0) OVER(ORDER BY T2.KEY0) + LAG(T2.KEY1, 1, 0) OVER(ORDER BY T2.KEY0)
FROM TEST_LOG T2 WHERE T2.ROWID= T.ROWID);
We have employee salary table which will have salary of an employee on daily basis (only working days). Below is the table structure:
emp_salary
----------
emp_id NUMBER(15) NOT NULL
effective_date DATE NOT NULL
salary NUMBER(15) NOT NULL
Primary key - emp_id, effective_date
This table is yearly partitioned
I have to find out how long the salary is not changed for an employee from given date, and last salary. I am using below query to do this:
WITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
)
THEN 0
ELSE 1
END
) changed_ind
FROM emp_salary
WHERE emp_id = 12345
[code]....
The cost of this query is 1677 and it is taking around 60 msec to complete. When I run this query for around 2000 employees in a loop it is taking around 3 minutes to complete.
The main bottleneck of this query is in the with clause where I am processing the entire history instead of stopping after first change.
Is it possible to create trigger on the various tables and views exists (i.e. dynamic performance views) in data dictionary, when ever any DML operations performs by Oracle it self?
View 6 Replies View RelatedWe are using Oracle 10g and have 10 tablespaces defined for our Database which have 108 tables. Size of 108 tables is around 251 MB as seen during importing the dump. While creating these 10 tablespaces I used below parameters for allocation of space
SIZE 1M REUSE AUTOEXTEND ON NEXT 1M MAXSIZE 1M;
which set the initial space for 10 tablespaces to around 1032Kb each. Now my Question is after importing the dump , how the disk space for 10 tablespaces increases to 398 MB in total ?
Is there any relation of Tablespace disk space and Actual Data present in the tables ?
I would like to know which of the above is faster for the same conditions.
i.e. If I am loading 1 million rows for the same conditions which will perform faster?
i want to find the duplicate data in my tables i have the below structure
SQL> desc x;
Name Null? Type
----------------------------------------- -------- ----------------------------
FILE_CODE NUMBER(20)
STREAMNUMBER VARCHAR2(50)
SERVICEKEY VARCHAR2(50)
CALLINGPARTYNUMBER VARCHAR2(50)
CALLEDPARTYNUMBER VARCHAR2(50)
CHARGEPARTYINDICATOR VARCHAR2(50)
[Code] ......
i found the below query it's right
SELECT * x
WHERE ROWID NOT IN (SELECT MIN(ROWID) FROM x
GROUP by FILE_CODE,..........................,SEQ_NO ); all the column
query to find out common data from 2 columns in two different tables??
View 6 Replies View RelatedCREATE TABLE F_TIME( PERIOD_ID NUMBER, PERIOD_NAME VARCHAR2(30 CHAR), PERIOD_YEAR NUMBER, PERIOD_TYPE VARCHAR2(30 CHAR), CREATION_DATE DATE, UPDATE_DATE DATE, UPDATE_BY NUMBER); SET DEFINE OFF;Insert into F_TIME (PERIOD_ID, PERIOD_NAME, PERIOD_YEAR, PERIOD_TYPE, CREATION_DATE, UPDATE_DATE) Values (16, 'Q4', 2012, 'q', TO_DATE('04/20/2013 17:41:28', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('04/20/2013 17:41:28', 'MM/DD/YYYY HH24:MI:SS'));Insert into F_TIME
[code]...
if i pass 30 then it will return period id=16 data
We have one primary oracle database 10.2 and standby by database with no data guard. Initially we have 2 redo log group in primary and standby database.
We have recently add 2 more redo log and increase the size of log member from 50m to 200m in primary database. We don't have any problem in primary database.but in standby database we face a problem because we cannot open it. It always in mount stage in which . How we change the size of current redo log because we can't run. Alter system switch logfile command in mount stage.
I want to list the tables in a schema which contains a particular value or data.
View 2 Replies View RelatedWhat are the differences of;
1. ALTER SYSTEM SWITCH LOGFILE;
2. ALTER SYSTEM ARCHIVE LOG ALL;
3. ALTER SYSTEM ARCHIVE LOG CURRENT;
I read Oracle's document but still didn't understand the difference in real life-use.
If you were writing a hotbackup script, which would you use at the end of datafile copy?
I take a select into a cursor and process it record by record.I have to do sum based on a column and display row by row by using dbms_output.put_line .... So the sum has to happen based on a column. Based on the column value i need to display the cumulative sum as well.
Example:-
col1 col2 amount
DL AADD 25
DL BBCC 10
DL BBRR 15
Sum value for DL ----- 50
TX ADED 20
TX EDWW 60
Sum value for TX ----- 80
All the above data should be displayed using DBMS_OUTPUT.PUT_LINE in a pl/sql code. I use cursor to take the values from the table but the problem i face is .... I am not able to display the sum based in the col1 values.
Since i use the cursor .. i took the col1 values in to a variable and checked every time
old_variable = new_variable
if yes then continue the sum
else
display the sum value.
once i get the above check satisfied i am loosing a new col1 row in the check. The next loop only run for the new col1 values -1( which is used in the check loop).So is there any better way to get the solution or is there a facility to store the previous loop values in a cursor ? so that i dont have to loose that one row of data.
I am not able to come up with proper loop so which can identify that the col1 has changed and you have to display the sum value.
I have a stat table that got info like login_date,user_id etc.For a specific user, i have a requirement based on the no of days difference between the current login date and last login date.
For example, Tom logged in on June 4th 2013. His previous login was May 31. So no_of_days_difference is 5 days.How to programmatically get this for each user inside a pl-sql sub block.
difference between V$ and V_$ views. It looks same to me. lets take the example of V$LOG and V_$LOG , both views returns same set of columns when described.
SQL> desc V$LOG
Name Null? Type
----------------------------------------- -------- -----------------
GROUP# NUMBER
THREAD# NUMBER
SEQUENCE# NUMBER
BYTES NUMBER
MEMBERS NUMBER
ARCHIVED VARCHAR2(3)
STATUS VARCHAR2(16)
FIRST_CHANGE# NUMBER
FIRST_TIME DATE
SQL> desc V_$LOG
Name Null? Type
----------------------------------------- -------- -----------------
GROUP# NUMBER
THREAD# NUMBER
SEQUENCE# NUMBER
BYTES NUMBER
MEMBERS NUMBER
ARCHIVED VARCHAR2(3)
STATUS VARCHAR2(16)
FIRST_CHANGE# NUMBER
FIRST_TIME DATE
I have an attribute in my DB called start_date of type date.I want a query that return the difference between the start_date and the current date.for example if start_date = 2/14/2013 *2*:35:00 PM and the current date = 2/14/2013 *1*:35:00 PM the query returns 1.
I want the result in hours.
Practicing in VM. My question is, I deleted the physical files of the database on Sunday but I'm having physical files backup on Friday. firstly i done restore, Performing incomplete recovery , I'm getting error like "Cannot open Archive log"
On Saturday, I changed path of archive log but I'm not aware of archive previous path location. How can we find previous path location of archive log?
I am using compress partition for a large table.During the process I have used the below command for compress---
1. ALTER TABLE <TABLE_NAME> MODIFY PARTITION P1 COMPRESS;
However I found there are different command as below:-
2. ALTER TABLE <TABLE_NAME> MOVE PARTITION P1 COMPRESS;
What is the basic difference between these two as the compression is happening for both command.
what is
ORACLE_HOME
ORACLE_BASE
difference between ORACLE_HOME and ORACLE_BASE
a table can have many schema or just 1 schema which is the table owner?
View 5 Replies View RelatedWHAT IS THE DIFFERENCE BETWEEN ORA ERROR AND LRM ERROR?
View 9 Replies View Relatedtwo columns of dba_data_files (Bytes & user_bytes).
select bytes/1024/1024, maxbytes/1024/1024, user_bytes/1024/1024 from dba_data_files;
1532767.9843754.9375
249032767.984375489.9375
39032767.98437589.9375
453032767.984375529.9375
5204832767.9843752047.9375
6204832767.9843752047.9375
7204802047.9375
difference between a user and schema on Oracle.By difference, I do not mean what is a user and what is a schema.
I understand that if we create a user, the schema gets created by default for that user. Does that mean that we cannot create a user/schema alone.
What if I just want to create a user and grant him some read access on an existing schema or just want to create a schema.
I've migrated from Oracle 9i to Oracle 11gR2, when i'm checking my application on Oracle 11gR2, i found that some of the query result are differed from the previous version of Oracle 9i, which is very illogical to me. I've checked the data for all related tables which are involved in one of the query. I've checked all indexes also. Still i'm not convinced that Oracle is doing anything wrong. I cannot recreate the whole scenario here, because of many tables involved in that query.
One of the sample query code.
select 'ProductMaster' producttype,e.schemecd,e.SCHEMESHORTDESC as SCHEMEDESC,to_char(e.schemefrdate,'dd/MM/yyyy')as schemefrdate, to_char(e.schemetodate,'dd/MM/yyyy') as schemetodate,e.mkid ,e.countrycd,e.statecd,e.districtcd,f.schemetype, a.productcd,a.packsizecd,a.packtypecd,a.sortorder1, a.countrycd,a.statecd,a.districtcd,a.p_uniqueid,a.mrp, (a.productcd ||'-'||b.countryname||'-'||c.statename||'-'||d.districtname|| ' -pkt.prc:'||a.pktprice ||' -mrp:'||a.mrp) as pcode
from wb.wbproductdetails a
[code]......
The Table having 3 columns
col0col1 , col2
P112
P112
P102
P113
P115
I want to retrieve the changes rows only.
Output like
col0col1 , col2
P112
P102
P113
P115
I am trying to find the unix process for one of my application in the database but I am unable to view the same. To simulate, I did the following.
1. My database runs on different server.
2. I invoked "sqlplus" from another unix box to login to the database.
3. I found that the process id (ps -ef |grep sqlplus).
4. When I execute the below mentioned query it does not display the process id that I am looking for. But the osuser, username, program and machine details are correct. How can I know the process details from the database?
SELECT SYS.GV_$SESSION.OSUSER, SYS.GV_$SESSION.USERNAME, SYS.GV_$PROCESS.SPID,
SYS.GV_$SESSION.MACHINE, SYS.GV_$SESSION.PROGRAM,
SYS.GV_$PROCESS.PROGRAM ,SYS.GV_$SESSION.SQL_ID
FROM
SYS.GV_$PROCESS, SYS.GV_$SESSION
WHERE
SYS.GV_$PROCESS.ADDR=SYS.GV_$SESSION.PADDR and SYS.GV_$SESSION.USERNAME='TEST'
and SYS.GV_$SESSION.MACHINE like '%hostname%'